Write the Java classes for the following classes. Make sure each includes 1. instance variables 2. constructor 3. copy constructor Submit a PDF with the code The classes are as follows: Character has-a name : String has-a health : integer has-a (Many) weapons : ArrayList has-a parent : Character has-a level : Level (this should not be a deep copy) Level has-a name : String has-a levelNumber : int has-a previousLevel : Level has-a nextLevel : Level Weapon has-a name : String has-a strength : double Monster is-a Character has-a angryness : double has-a weakness : Weakness Weakness has-a name : String has-a description: String has-a amount : int
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Answer:
Explanation:
The following code is written in Java. It is attached as a PDF as requested and contains all of the classes, with the instance variables as described. Each variable has a setter/getter method and each class has a constructor. The image attached is a glimpse of the code.
Related Questions
Animation timing is does not affect the
speed of the presentation
Select one:
True
False
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Answer:
True
Explanation:
I think it's true.....
This lab was designed to teach you more about using Scanner to chop up Strings. Lab Description : Take a group of numbers all on the same line and average the numbers. First, total up all of the numbers. Then, take the total and divide that by the number of numbers. Format the average to three decimal places Sample Data : 9 10 5 20 11 22 33 44 55 66 77 4B 52 29 10D 50 29 D 100 90 95 98 100 97 Files Needed :: Average.java AverageRunner.java Sample Output: 9 10 5 20 average = 11.000 11 22 33 44 55 66 77 average = 44.000 48 52 29 100 50 29 average - 51.333 0 average - 0.000 100 90 95 98 100 97 average - 96.667
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Answer:
The program is as follows:
import java.util.*;
public class Main{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String score;
System.out.print("Scores: ");
score = input.nextLine();
String[] scores_string = score.split(" ");
double total = 0;
for(int i = 0; i<scores_string.length;i++){
total+= Double.parseDouble(scores_string[i]); }
double average = total/scores_string.length;
System.out.format("Average: %.3f", average); }
}
Explanation:
This declares score as string
String score;
This prompts the user for scores
System.out.print("Scores: ");
This gets the input from the user
score = input.nextLine();
This splits the scores into an array
String[] scores_string = score.split(" ");
This initializes total to 0
double total = 0;
This iterates through the scores
for(int i = 0; i<scores_string.length;i++){
This calculates the sum by first converting each entry to double
total+= Double.parseDouble(scores_string[i]); }
The average is calculated here
double average = total/scores_string.length;
This prints the average
System.out.format("Average: %.3f", average); }
}
Acróstico sobre mouse
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Suppose you are choosing between the following three algorithms:
• Algorithm A solves problems by dividing them into five subproblems of half the size, recursively solving each subproblem, and then combining the solutions in linear time.
• Algorithm B solves problems of size n by recursively solving two subproblems of size n − 1 and then combining the solutions in constant time.
• Algorithm C solves problems of size n by dividing them into nine sub-problems of size n=3, recursively solving each sub-problem, and then combining the solutions in O(n2) time.
What are the running times of each of these algorithms (in big-O notation), and which would you choose?
Answers
Answer:
Algorithm C is chosen
Explanation:
For Algorithm A
T(n) = 5 * T ( n/2 ) + 0(n)
where : a = 5 , b = 2 , ∝ = 1
attached below is the remaining part of the solution