Answer:
In Python:
cents = int(input("Cents: "))
dollars = int(cents/100)
quarters = int((cents - 100*dollars)/25)
dimes = int((cents - 100*dollars- 25*quarters)/10)
nickels = int((cents - 100*dollars- 25*quarters-10*dimes)/5)
pennies = cents - 100*dollars- 25*quarters-10*dimes-5*nickels
if not(dollars == 0):
if dollars > 1:
print(str(dollars)+" dollars")
else:
print(str(dollars)+" dollar")
if not(quarters == 0):
if quarters > 1:
print(str(quarters)+" quarters")
else:
print(str(quarters)+" quarter")
if not(dimes == 0):
if dimes > 1:
print(str(dimes)+" dimes")
else:
print(str(dimes)+" dime")
if not(nickels == 0):
if nickels > 1:
print(str(nickels)+" nickels")
else:
print(str(nickels)+" nickel")
if not(pennies == 0):
if pennies > 1:
print(str(pennies)+" pennies")
else:
print(str(pennies)+" penny")
Explanation:
A prompt to input amount in cents
cents = int(input("Cents: "))
Convert cents to dollars
dollars = int(cents/100)
Convert the remaining cents to quarters
quarters = int((cents - 100*dollars)/25)
Convert the remaining cents to dimes
dimes = int((cents - 100*dollars- 25*quarters)/10)
Convert the remaining cents to nickels
nickels = int((cents - 100*dollars- 25*quarters-10*dimes)/5)
Convert the remaining cents to pennies
pennies = cents - 100*dollars- 25*quarters-10*dimes-5*nickels
This checks if dollars is not 0
if not(dollars == 0):
If greater than 1, it prints dollars (plural)
if dollars > 1:
print(str(dollars)+" dollars")
Otherwise, prints dollar (singular)
else:
print(str(dollars)+" dollar")
This checks if quarters is not 0
if not(quarters == 0):
If greater than 1, it prints quarters (plural)
if quarters > 1:
print(str(quarters)+" quarters")
Otherwise, prints quarter (singular)
else:
print(str(quarters)+" quarter")
This checks if dimes is not 0
if not(dimes == 0):
If greater than 1, it prints dimes (plural)
if dimes > 1:
print(str(dimes)+" dimes")
Otherwise, prints dime (singular)
else:
print(str(dimes)+" dime")
This checks if nickels is not 0
if not(nickels == 0):
If greater than 1, it prints nickels (plural)
if nickels > 1:
print(str(nickels)+" nickels")
Otherwise, prints nickel (singular)
else:
print(str(nickels)+" nickel")
This checks if pennies is not 0
if not(pennies == 0):
If greater than 1, it prints pennies (plural)
if pennies > 1:
print(str(pennies)+" pennies")
Otherwise, prints penny (singular)
else:
print(str(pennies)+" penny")
Write VHDL code for the circuit corresponding to an 8-bit Carry Lookahead Adder (CLA) using structural VHDL (port maps). (To be completed before your lab session.)
Answer:
perdo si la pusiera es español te ayudo pero no esta en español
whats this oh _____
what is it
A) jane
B) juan.
C)juan
D) horse
Answer:
juan duhhhhh hehehe
Explanation:
The ABC box company makes square puzzle cubes that measure 4 inches along each edge. They shipped the cubes in a box 8 in x 12 in x 16 in. How many cubes can they ship in the box?
Answer: They can ship 32 puzzle cubes in the box.
Explanation: So the volume of each puzzle cubes = side³
=(4)³ cubic inches.
Then the volume of the box is= (8×12×16) cubic inches.
(8×12×16)/4^3= 32
Write a class called Dragon. A Dragon should have a name, a level, and a boolean variable, canBreatheFire, indicating whether or not the dragon can breathe fire. The class should have getter methods for all of these variables - getName, getLevel, and isFireBreather, respectively.
Answer: A dragon name could be name Holls and at level 14 and can breathe fire
Explanation: