Work out volume of this sphere leave your answer in terms of pi

Answer:

51/100

Step-by-step explanation:

Answer:

a) The z-score for a backyard structure costing $2300 is -0.57.

b) The z-score for a backyard structure costing $4900 is 1.29

c) A backyard structure costing $2300 costs 0.57 standard deviations below the mean, while a backyard structure costing $4900 costs 1.29 standard deviations above the mean. Since both are within 2 standard deviations of the mean, none is an outlier.

d) Since this combination costs more than 2 standard deviations from the mean, yes, it should be considered an outlier.

Step-by-step explanation:

Z-score:

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If the z-score is more than two standard deviations from the mean(lesser than -2 or more than 2), the score X is considered an outlier.

In this question, we have that:

[tex]\mu = 3100, \sigma = 1400[/tex]

a. What is the z-score for a backyard structure costing $2300?

We have to find Z when [tex]X = 2300[/tex]. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{2300 - 3100}{1400}[/tex]

[tex]Z = -0.57[/tex]

The z-score for a backyard structure costing $2300 is -0.57.

b. What is the z-score for a backyard structure costing $4900?

We have to find Z when [tex]X = 2300[/tex]. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{4900 - 3100}{1400}[/tex]

[tex]Z = 1.29[/tex]

The z-score for a backyard structure costing $4900 is 1.29

c. Interpret the z-scores in parts (a) and (b). Comment on whether either should be considered an outlier.

A backyard structure costing $2300 costs 0.57 standard deviations below the mean, while a backyard structure costing $4900 costs 1.29 standard deviations above the mean. Since both are within 2 standard deviations of the mean, none is an outlier.

d. If the cost for a backyard shed-office combination built in Albany, California, is $13,000, should this structure be considered an outlier?

We have to find the z-score when X = 13000. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{13000 - 3100}{1400}[/tex]

[tex]Z = 7.07[/tex]

Since this combination costs more than 2 standard deviations from the mean, yes, it should be considered an outlier.

Answer:

Step-by-step explanation:

Solution :

Let the three places be 1, 2, 3, 4, 5, 6, 7, 8

a). Number of the cases when a general manager is the next to a vice president is equal to 7 and the these 2 can be arranged in 21 ways. So the total number of ways = 7 x 2

                  = 14

[(1,2)(2,1) (2,3)(3,2) (3,4)(4,3) (4,5)(5,4) (5,6)(6,5) (6,7)(7,8) (8,7)(7,6)]

Therefore the required probability is

  [tex]$=\frac{14}{8!}$[/tex]

 = [tex]$\frac{14}{40320} = 0.000347$[/tex]

b). The probability that the marketing director to be placed in the leftmost position is

   [tex]$=\frac{7!}{8!}$[/tex]

  [tex]$=\frac{1}{8} = 0.125$[/tex]

c). The two events are not independent because

   [tex]$P(A \cap B) \neq P(A) \times P(B)$[/tex]

  [tex]$\frac{12}{8!} \neq \frac{14}{8!} \times \frac{1}{8}$[/tex]

where A is the case a and B is the case b.

(a) The possibility of the general manager is next to the vice president is [tex]\frac{1}{4}[/tex].

(b) The possibility of the marketing director is in the leftmost position is [tex]\frac{1}{8}[/tex].

(c) So, the two events are dependent on each other.

Probability is a measure of the likelihood of an event to occur. Many events cannot be predicted with total certainty. We can predict only the chance of an event to occur i.e. how likely they are to happen, using it. The probability of all the events in a sample space adds up to 1.

Total people in company A and company B is [tex]=8[/tex]

Overall ways in which these [tex]8[/tex] people can be lined up[tex]=8![/tex]

                                                                                        [tex]=40320[/tex]

(a) The probability that the general manager is next to the vice president is[tex]=P(A)[/tex]

Now, we can combine the general manager and vice president as one, then the total people in both the company will become [tex]7[/tex].

by arranging these [tex]7[/tex] people in one line [tex]=7![/tex]

                                                                [tex]=5040[/tex]

Again, combine the general manager and vice president in one line[tex]=2![/tex]

                                                                                                                [tex]=2[/tex]

Therefore, [tex]P(A)=\frac{5040\times 2}{40320}[/tex]

                          [tex]=\frac{10080}{40320}[/tex]

[tex]P(A)=\frac{1}{4}[/tex]

(b) The probability that the marketing director is in the leftmost position is[tex]=P(B)[/tex]

Now, fixing the position of marketing director in the leftmost.

arranging the [tex]7[/tex] other people in [tex]7![/tex] ways [tex]=5040[/tex]

Therefore,[tex]P(B)=\frac{5040}{40320}[/tex]

                          [tex]=\frac{1}{8}[/tex]

[tex]P(B)=\frac{1}{8}[/tex]

(c) Assuming event B already occurred which means that the position of marketing director is already fixed in the leftmost position.

Now, trying to find out the probability of the general manager next to the vice president is event A. it comes different because we are not allowed to arrange rest [tex]7[/tex] people, we have to fix the position of one person that causes the repetition of probability.

So, the two events are dependent on each other.

Learn more about the topic of Probability: https://brainly.com/question/26959834

Answer:

quadrant 3

Step-by-step explanation:

Answer:

These two corners are [tex]\sqrt{13}[/tex] units apart.

Step-by-step explanation:

Distance between two points:

Suppose we have two points, [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]. The distance between them is given by:

[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Approximately how far apart are the two corners?

We have to find the distance between the points (-5,-2) and (-8-3). So

[tex]D = \sqrt{(5-(-8))^2+(-2-(-3))^2} = \sqrt{13}[/tex]

These two corners are [tex]\sqrt{13}[/tex] units apart.

Answer:

Step-by-step explanation:

I'm not sure about number 3, but I have the answer for number. The answer is 1:32.

3: 69

3/69

Then we reduce the fraction to the lowest term

3/69 = 1/32

1:32

Just divide 96/3 and you can see that one bus can hold 32 students

Answer:

you have to put -160 over -16 then divide and your answer will be 10

so x=10. I hope this helps :)

Answer:

a smart person is not me clearly lol

Step-by-step explanation:

apply distributive property AKA (A • 9b)+(A • 13)

9Ab + 13A

I hope this helps :)

Answer:

A

Step-by-step explanation:

It is letter A I got 100!

Answer:

A

Step-by-step explanation:

EDGE 2021

Answer: 4n^2

Step-by-step explanation: -3n^2 - (-7n^2) = -3n^2 + 7n^2= 4n^2. When adding and subtracting the exponents stay the same only the coefficients are subtracted or added

Answer:

a number 12

Step-by-step explanation:

duh bro

Answer:

[tex] {x}^{2} + {x}^{2} = {(8 \sqrt{2}) }^{2} \\ 2 {x}^{2} = 128 \\ {x}^{2} = 64 \\ \boxed{x = 8}[/tex]

Answer:

Amount contributed by Oscar = $8

Step-by-step explanation:

Given that:

Amount spent on gift = $36

Amount contributed by Moriah = $12

Let,

x be the amount contributed by each of them.

Thus,

Gift total = Contribution of all

36 = x+x+x+12

36 = 3x+12

3x+12 = 36

3x=36-12

3x=24

Dividing both sides by 3

[tex]\frac{3x}{3}=\frac{24}{3}\\x=8[/tex]

Hence,

Amount contributed by Oscar = $8

Answer: 3.2x = 48

Step-by-step explanation: So that means x = 15.

Answer:

Step-by-step explanation:

(a) [tex]\int x^n e^{5x^4+1} \ dx[/tex]

Suppose [tex]5x^4 + 1 = f[/tex]

by differentiation;

[tex]\implies \ 20 x^3 dx = df --- (1)[/tex]

Suppose n = 3

Then, the integral

[tex]I = \int x^ 3 e^{5x^4 + 1} \ dx[/tex]

[tex]= \int e^f \ \dfrac{df}{20}[/tex]

[tex]= \dfrac{1}{20} \int e^f \ dt[/tex]

[tex]= \dfrac{1}{20} e^f + C[/tex]

recall that [tex]f = 5x^4 + 1[/tex]

Then;

[tex]\mathbf{ I = \dfrac{1}{20}e^{5x^4+1}+C}[/tex]

(b) [tex]\int \dfrac{cos (\dfrac{1}{x^3})}{x^n } \ dx[/tex]

suppose; [tex]\dfrac{1}{x^3} = f[/tex]

[tex]x^3 = f[/tex]

[tex]\implies -3x^{-4} \ dx = df[/tex]

[tex]\implies \dfrac{1}{x^4} \ dx =-\dfrac{1}{3} df[/tex]

If n = u, then the integration is:

[tex]I = \int \dfrac{1}{x^4} \ cos (\dfrac{1}{x^4}) \ dx[/tex]

[tex]= \int -\dfrac{1}{3} \ cos \ f \ df[/tex]

[tex]= -\dfrac{1}{3} \int \ cos \ f \ df[/tex]

[tex]= -\dfrac{1}{3} \ sin \ f + C[/tex]

Since;  [tex]x^3 = f[/tex]

Then;

[tex]\mathbf {I = -\dfrac{1}{3} \ sin \ \Big( \dfrac{1}{x^3}\Big) + C}[/tex]

(c) [tex]\int \dfrac{x+n}{x^2 + 8x -4} \ dx[/tex]

Suppose  [tex]x^2 + 8x - 4 = f[/tex]

Then, by differentiation of both sides

[tex](2x + 8) \ dx = df[/tex]

[tex](x + 4) \ dx = \dfrac{1}{2} \ df[/tex]

Suppose n = 4 in integration, then:

[tex]I = \int \dfrac{(x + 4) }{x^2 +8x -4} \ dx[/tex]

By substitution;

[tex]I = \int \dfrac{1}{2}\dfrac{1}{f} \ df[/tex]

[tex]= \dfrac{1}{2} \ \ { In |f|} + C[/tex]

[tex]\mathbf{= \dfrac{1}{2} \ \ { In |x^2+8x -4|} + C}[/tex]

The suitable substitutions of n are 3,4,4 respectively.

The process of finding integrals is called integration.

a)[tex]f(x)=\int\limits {x^3e^{5x^4+1} } \, dx[/tex]

Suppose

[tex]5x^4+1 =t\\20x^3 dx =dt[/tex]

So, we need n=3 for easy integration.

[tex]f(x)=\int\limits {x^3e^{5x^4+1} } \, dx[/tex]

[tex]I = \frac{1}{20} \int\limits {e^{t} } \, dt[/tex]

[tex]I=\frac{e^{t} }{20}[/tex]

[tex]I = e^{5x^{4}+1 }/20 +c[/tex]

b)Similarly for [tex]f(x) = \int\limits\frac{cos(\frac{1}{x^3} )}{x^n} \, dx[/tex]

n=4 is needed for easy integration.

I = [tex]\frac{-1}{3} sin(\frac{1}{x^3} ) +c[/tex]

c)For [tex]f(x) = \int\limits \frac{x+n}{x^{2} +8x-4} \, dx[/tex]

n=4 is needed for easy integration.

[tex]I = \frac{1}{2} log(x^{2} +8x-4)[/tex]

Hence, the suitable substitutions of n are 3,4,4 respectively.

To get more about integration visit:

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Answer:

Trigonometric equations are, as the name implies, equations that involve trigonometric functions. Similar in many ways to solving polynomial equations or rational equations, only specific values of the variable will be solutions, if there are solutions at all. Often we will solve a trigonometric equation over a specified interval. However, just as often, we will be asked to find all possible solutions, and as trigonometric functions are periodic, solutions are repeated within each period. In other words, trigonometric equations may have an infinite number of solutions. Additionally, like rational equations, the domain of the function must be considered before we assume that any solution is valid. The period of both the sine function and the cosine function is 2π. In other words, every 2π units, the y-values repeat. If we need to find all possible solutions, then we must add 2πk, where k is an integer, to the initial solution. Recall the rule that gives the format for stating all possible solutions for a function where the period is 2π:

sinθ=sin(θ±2kπ)

There are similar rules for indicating all possible solutions for the other trigonometric functions. Solving trigonometric equations requires the same techniques as solving algebraic equations. We read the equation from left to right, horizontally, like a sentence. We look for known patterns, factor, find common denominators, and substitute certain expressions with a variable to make solving a more straightforward process. However, with trigonometric equations, we also have the advantage of using the identities we developed in the previous sections.

Step-by-step explanation:

Trigonometric equations are, as the name implies, equations that involve trigonometric functions. Similar in many ways to solving polynomial equations or rational equations, only specific values of the variable will be solutions, if there are solutions at all. Often we will solve a trigonometric equation over a specified interval.  

Hi.. U should do like this

4/5 mile in 50 min

X mile in 60 min

X=5/4 mile

Answer:

5 milesss

:)))

Answer:

[tex](-4, 1) \: and \: (-4,7)[/tex]

Step-by-step explanation:

[tex]the \: shortest \: distance \: between \: two \: points \: can \: be \: used \: here \to \\ were : d = \sqrt{ (x_{2} -x_{1} ) {}^{2} + (y_{2} -y_{1} ) {}^{2} } \\checking \: for \: the \: pair \to \: (-4, 1) \: and \: (-4,7) \\ d = \sqrt{ (( - 4)-( - 4)) {}^{2} + (7 -1 ) {}^{2} } \\ d = \sqrt{ (- 4 + 4) {}^{2} + (6) {}^{2} } \\ d = \sqrt{ (0) {}^{2} + (6) {}^{2} } \\ d = \sqrt{ (6) {}^{2} } \\ \underline{ \boxed{d = 6}}[/tex]

Answer: It's the third one down

Step-by-step explanation:

Answer: Total cost would be 10,320

Step-by-step explanation: Hope this helps

Answer:

Hey

Step-by-step explanation:

Write the fraction in simplest form

[tex] - \frac{29}{18} [/tex]

[tex] \frac{8}{9} - \frac{5}{2} [/tex]

Find the difference between 8/9 and 5/-2

[tex] \frac{8}{9} - \frac{5}{2} [/tex]

[tex] \frac{8 \times 2}{9 \times 2} - \frac{5 \times 9}{2 \times 9} [/tex]

[tex] \frac{16}{18} - \frac{45}{18} [/tex]

[tex] \frac{16 - 45}{18} [/tex]

[tex] \frac{ - 29}{18} [/tex]

[tex] - \frac{29}{18} [/tex]

Answer:

carios has greater angle

Step-by-step explanation:

hope this helps

Step-by-step explanation:

Sum of interior angles in a polygon

= 180°(n - 2), where n is the number of sides.

Hence a convex polygon with 6 sides

=> 180°(6 - 2) = 720°.

Answer:

The answer is 154.8 ml

Step-by-step explanation:

In this question, the amount of pure acid is 18% of the total solution, that is, 18% of 860 milliliters. So

0.18*860 = 154.8 ml

The answer is 154.8 ml

Answer:

im sure its D.)

Step-by-step explanation: