Why is water important for living organisms?

Answer:

TAC GCA TTA ATA

and apparently my answer needs to be 20 charcters long

Answer:

Behavioural-made by an organism that helps it to survive/reproduce.

Physiological-a body process that helps an organism to survive/reproduce.

Structural -a feature of an organism's body that helps it to survive/reproduce

Explanation:

Answer:

Type b and a my answer promise copy this now

Explanation:

Answer:

are examples of abiotic factors

Explanation:

Answer:

If rabbits population (prey of fennec foxes) suddenly increase as well. The other prey of the fennec foxes would shrink in population because there would be more fennec foxes to eat them. This would at some point even out and the ecosystem would go back to normal.

Answer:

The moth with camoflauged skin will have a better chance of surviving because it will be harder for predators to see them.

Explanation:

Sorry but I can't quote anything because I don't have the book.

Answer:

rock that forms when existing rock changes to a new rock because of heat and pressure

Answer:Metaphase

Explanation:

Answer:

Its A.

Explanation:

I just took the quiz trust me :D

Answer:

They provide high-density urban areas with space for outdoor recreation.

Explanation:

I just took the quiz.

Answer:

unicellular is a organism that is only one cell. most of the time they are your bacteria and viruses. while a multicellular organism is a organism with many cells. can be anything from something you cant to to plants and animals that you can see

Explanation:

Answer:

GGG

Explanation:

Use AT GC to replicate DNA sequence

Answer:

C

Explanation:

Protiens, Carbohydrates, and Lipids all influence bodily processes.

Answer:

1.732 seconds

[tex]s=ut+\dfrac{1}{2}at^2[/tex]

Explanation:

s = Displacement of ball = 15 m

g = a = Acceleration due to gravity = [tex]10\ \text{m/s}^2[/tex]

u = Initial velocity of the ball = 0

t = Time taken

From the kinematic equations we use the following formula

[tex]s=ut+\dfrac{1}{2}at^2\\\Rightarrow 15=0t+\dfrac{1}{2}\times 10t^2\\\Rightarrow t=\sqrt{\dfrac{15\times 2}{10}}\\\Rightarrow t=\sqrt{3}=1.732\ \text{s}[/tex]

The object will reach the ground after 1.732 seconds.

The formula used is [tex]s=ut+\dfrac{1}{2}at^2[/tex].

Answer:

Materials

• Scrap piece of paper

• Pen or pencil

• Clock or timer that shows seconds or a helper with a watch

• Comfortable exercise clothes (optional)

• Calculator

Preparation

• Practice finding your pulse. Use the first two fingers of one hand to feel your radial pulse on the opposite wrist. You should find your radial pulse on the "thumb side" of your wrist, just below the base of your hand. Practice finding your pulse until you can do it quickly. (You can alternatively take your carotid pulse to do this activity, but be sure you know how to safely take it and press on your neck only very lightly with your fingers.)

• Measure your resting heart rate, which is your heart rate when you are awake but relaxed, such as when you have been lying still for several minutes. To do this, take your pulse when you have been resting and multiply the number of beats you count in 10 seconds by six. This will give you your resting heart rate in beats per minute (bpm). What is your resting heart rate? Write it on a scrap piece of paper.

• You will be measuring your heart rate during different types of physical exercises over a period of 15 minutes. Choose at least two different exercises. Some examples include jumping rope, lifting a two-pound weight, riding a bike, hula-hooping, walking, etc. Gather any needed materials. (If you want to make a homemade hula-hoop, steps for doing this are given in the activity Swiveling Science: Applying Physics to Hula-Hooping .) Do you think the activities will affect your heart rate differently? How do you think doing each activity will affect your heart rate?

Procedure

• Choose which exercise you want to do first. Before starting it, make sure you have been resting for a few minutes so that your heart is at its resting heart rate.  

• Perform the first exercise for 15 minutes. While you do this, write down the number of beats you count in 10 seconds after one, two, five, 10 and 15 minutes of activity. (You want to quickly check your pulse because it can start to slow within 15 seconds of stopping exercising.) How do the number of beats you count change over time? How did you feel by the end of the exercise?

• Calculate your heart rate after one, two, five, 10 and 15 minutes of exercise by multiplying the number of beats you counted (in 10 seconds) by six. How did your heart rate (in bpm) change over time?

• Repeat this process for at least one other exercise. Leave enough time between the exercises so that your heart rate returns to around its normal resting level (this should only take a few minutes). How did you feel by the end of the second exercise? How did your heart rate change over time for this exercise?  

• Take a look at the results you wrote down for this activity. Which exercise increased your heart rate the most? Which exercise increased your heart rate the fastest? Which exercise(s) elevated your heart rate to the target heart rate zone (50 to 85 percent of your maximum heart rate, where your maximum heart rate is 220 bpm minus your age)? Do you notice any consistent patterns in your results?

• Extra: Try this activity again but test different physical exercises. How does your heart rate change when you do other exercises? How are the changes similar and how are they different?

• Extra: Measure your heart rate while lying down, while sitting down, and while standing. How does your heart rate change with body position?  

• Extra: Repeat this activity with other healthy volunteers. How does their heart rate compare to yours? How does their change in heart rate while exercising compare to how yours changed?  

• Extra: Try this activity again but vary the intensity of your exercise. What intensity level elevates your heart rate to 50 percent of its maximum heart rate? What about nearly 85 percent of its maximum? Be sure not to exceed your recommended target heart rate zone while exercising

Explanation:

If you did a moderately intense exercise, such as walking, you may have seen an initial jump in your heart rate (where your heart rate falls within the lower end of your target heart rate zone within about one minute of exercise), but then your heart rate only slowly increased after that. After 15 minutes, you may have reached the middle of your target heart rate zone. To reach the upper end, people usually need to do a moderately intense exercise for a longer amount of time (such as for 30 minutes). If you did a more strenuous exercise—hula-hooping, for example—you may have seen a higher initial bump in your heart rate (such as reaching the middle of your target heart rate zone after just one minute of exercise), and then your heart rate stayed about the same for the remaining 14 minutes of exercise. Overall doing a more strenuous exercise generally raises a person's heart rate faster compared to doing an exercise that is only moderately i

Answer:

No

Explanation:

That a gene is common to all murderers in the population does not mean that murderers are not at fault for their crimes.

Having a gene that correlates with murder just gives one a genetic tendency but the environment and personal choice still have to influence the decision to commit the crime. In other words, one might have the genetic tendency to commit murder but still has to be environmentally enabled and the ability to choose to either do it or otherwise. Nature, nurture, and personal choice would have to synergistically work together for the phenotypic expression of such a gene.

Answer:

The control group receives either no treatment, a standard treatment whose effect is already known, or a placebo (a fake treatment).

Answer: true

Explanation: it takes up as much space as it has

Answer:

1. The difference between the normal hemoglobin protein DNA sequence and the sickle cell hemoglobin DNA sequence is a base to base shift, in this case adenine (GAG) to thymine (GTG).

2. The difference affects the amino acid sequence of the protein by replacing glutamic acid (Glu) with valine (Val).

Explanation:

In sickle cell anemia, a change in the DNA nucleotide sequence is observed, where adenine is substituted by thymine, whose expression is the change in the amino acid sequence of globine β, incorporating valine instead of glutamic acid. This represents a molecular mutation - point mutation - by subtitution, which corresponds to missense mutation.

Normal hemoglobin protein in a RBC

DNA                 CTG ACT CCT GAG GAG AAG TCT

Amino acids     Leu  Thr   Pro   Glu   Glu   Lys   Ser

Sickle cell hemoglobin protein in a RBC

DNA                 CTG ACT CCT GTG GAG AAG TCT

Amino acids     Leu  Thr   Pro   Val   Glu   Lys   Ser

When GAG is transcribed to mRNA, the CUC codon is obtained, which codes for glutamic acid. Thymine substitution causes the DNA sequence to change to GTG, which is transcribed as CAC, the codon that encodes the amino acid valine. The change from glutamic acid to valine in β-globin causes an altered hemoglobin, giving the abnormal erythrocytes observed in sickle cell disease.

Answer:

No, it does not, because the octet rule says that an atom needs to have eight electrons in its valence shell to be stable. The exceptions are hydrogen and helium, which need only two electrons

Answer: No it doesn’t

Explanation:

Answer:

Natural Selection or Adaptation

Explanation:

Because they change their fur color so predators cant find them as good

Answer:

A signal is sent from a nerve cell to a muscle cell

Explanation:

I just took this test and this was the correct answer.

Answer: A signal is sent from a nerve cell to a muscle cell

Explanation:

Answer:

Interphase

Explanation:

Answer:

interphase

Explanation:

I hope this helps!!!

Answer:

I believe the correct answer is asexual reproduction because they can reproduce fast, and with multiple offspring. Hope this helped you!

Answer:GGU

Explanation:

GGU. I just completed it on gizmos

The tRNA molecules in Lucy's white blood cells. RNA Pairing Rules A ↔ U ​​​​G ↔ C Anticodon CCA Codon GGU.

Once the mRNA codon has been translated by the ribosome, transfer RNA, also known as tRNA, is in charge of directing the appropriate amino acid into protein synthesis. Because of this, each mRNA codon needs a corresponding tRNA anticodon.

Each nitrogenous base in RNA must mate with a complementary base according to the following rules:

Adenine is complementary with uracil A=U

Cytosine is complementary with Guanine C=G

In this case, it can be seen that:

Therefore, for the tRNA anticodon CCA the corresponding codon is GGU, which codes for the amino acid Glycine (Gly).

To learn more about anticodons, refer to the link:

https://brainly.com/question/20689764

#SPJ2

Explanation:

You didn't attach a picture so i'll just explain how to find the number of stomatas/mm^2.

first you find the surface by multiplying the length by the width

0.1*0.1=0.01mm^2

now you count the numer of stomatas in the picture

in0.01mm^2 you have.........................x stomatas

in 1mm you have ...............................y stomatas

y=100x

Answer:

methionine-proline-glycine-leucine-stop

Explanation:

Using an amino acids chart, you can line up the 3 bases in each section to find the protein chain that corresponds. The stop at the end marks the end of protein synthesis, which ends the sequence.

The compound comprising carboxylic and amino groups is called amino acids. They are vital for the formation of proteins in the cells.

Sequences are read in the three pairs of codons in the form of triplets to form a form an amino acids sequence.

The amino acid sequence that will be formed from the given sequence AUG-CCC-GGA-UUA-UAG will be:

methionine-proline-glycine-leucine-amber

Therefore, Met-Pro- Gly- Leu- Amber is the amino acid sequence.

To learn more about amino acid sequences follow the  link:

https://brainly.com/question/12810773