Which type of electromagnetic waves make up the colors of a rainbow seen after a storm?

A. visible light
B. infrared light
C. X-rays
D. ultraviolet light

Answers

Answer 1

Answer:

we conclude that visible light is that electromagnetic wave that makes up the colors of a rainbow seen after a storm.

Hence, option A is correct.

Explanation:

Generally, after the storm, we can witness the presence of a rainbow with our naked eyes. Rainbow, visible to our eyes, consists of all the seven constituent colors of white light. Those seven colors range from violet to red, all having different wavelengths. When water particles present in our atmosphere get exposed to light, all the constituent colors of a white light tend to deviate at a variety of angles. It happens due to their refraction through water particles; thus, a spectrum is obtained.

As we cannot see X-rays, UV rays, and infrared waves through our naked eye, visible light is the kind of electromagnetic wave that makes anyone able to see the objects.  

Please note that all the constitute colors of a beautiful rainbow associate with the visible region of the electromagnetic spectrum.

Therefore, we conclude that visible light is that electromagnetic wave that makes up the colors of a rainbow seen after a storm.

Hence, option A is correct.

Answer 2

Answer: A.) Visible light

Explanation: Edge 2020 good luck friend ^__^


Related Questions

A dog pulls on a leash with a force of 15 23 is a big dog. The leash makes an angle of 36.7 degrees to the horizontal. What are the x

and y components of the force?

Answers

Answer:

[tex]x = 12.027N[/tex] and [tex]y = 8.964N[/tex]

Explanation:

The first sentence of this question is not explanatory enough. However, I'll assume the force to be 15N

[tex]Force = 15N[/tex]

[tex]\theta = 36.7[/tex] to the horizontal

Required

Solve for the x and y components

Since the given angle is to the horizontal, the x and y coordinates are calculated using the following illustrations.

[tex]Sin\theta = \frac{y}{Force}[/tex] ---- y component

[tex]Cos\theta = \frac{x}{Force}[/tex] ---- x component

Calculating the y component.

Substitute 15 for Force and 36.7 for [tex]\theta[/tex]

[tex]Sin\theta = \frac{y}{Force}[/tex] becomes

[tex]Sin(36.7) = \frac{y}{15}[/tex]

Make y the subject

[tex]y = 15 * Sin(36.7)[/tex]

[tex]y = 15 * 0.5976[/tex]

[tex]y = 8.964N[/tex]

Calculating the x component.

Substitute 15 for Force and 36.7 for [tex]\theta[/tex]

[tex]Cos\theta = \frac{x}{Force}[/tex] becomes

[tex]Cos(36.7) = \frac{x}{15}[/tex]

Make y the subject

[tex]x = 15 * Cos(36.7)[/tex]

[tex]x = 15 * 0.8018[/tex]

[tex]x = 12.027N[/tex]

Hence, the x and y components of the force are: 8.964N and 12.027N respectively.

A rock has a mass of 3.1 kg. What is its weight on earth

Answers

Answer:

W = 30.38 N

Explanation:

Given that,

Mass of a rock, m = 3.1 kg

We need to find the weight of the rock on the surface of Earth. Weight of an object is given by :

W = mg

g is the acceleration due to gravity, g = 9.8 m/s²

W = 3.1 kg × 9.8 m/s²

= 30.38 N

So, the weight of the rock on the Earth is 30.38 N.

. If the kinetic energy is given in units of
g.cm/swhat units must the slope have?
A. g.cm/s
B. 8 cm/s?
C. s.cm/g
D. s? /(g.cm)

Answers

B this is the correct answer


An object starts at 16 m/s with an acceleration of 4.5 m/s? How far does it go in 9.0 seconds?

Answers

648 because 16 times 4.5 is 72 and that times 9 is 648

A fish that lives near the surface of the ocean most likely has a swim bladder (or a body cavity) that is full of

Answers

Answer:

A fish that lives near the surface of the ocean most likely has a swim bladder (or body cavity) that is full of oxygen

Explanation:

The swim bladder is the organ present in the majority of bony fishes that provides buoyancy. The swim bladder is a bladder filled with oxygen and found in the in the body of the fish

The function of the swim bladder is to provide adequate ballast or hydrostatic balance to enable a fish to keep to a certain depth in a body of water thereby the fish does not float to the surface or sinks further

The swim bladder is also used as a sound communicating organ.

Los muelles de un remolque están calibrados para soportar su peso, cuando se carga el remolque con 2100 kg, la fuerza ejercida es de 20580 N comprime los muelles de un remolque 5,5 cm a)Longitud que desciende el remolque si se carga con 28000 N b)Si ha descendido 4,2 cm la carga

Answers

Answer:

a) El remolque desciende 7.4 cm

b) La carga debe ser de 15715.6 N ó 1603.6 kg

Explanation:

Para los cálculos que involucren muelles, se aplica la Ley de Hooke, la cual relaciona el efecto de una Fuerza y el cambio de longitud que esta ejerce,  en un resorte de elasticidad dada.

Escrito en fórmula:

[tex]F=-k \cdot \Delta L[/tex]

Donde:

F es la fuerza ejercida

k es la constante elástica del muelle

ΔL es la variación de longitud del muelle

El problema indica que al cargar 2100 kg se ejerce una fuerza de 20580 N

Esto se corrobora con la 2da ley de Newton y asumiendo una aceleración de gravedad de 9.8 [tex]\frac{m}{s^{2} }[/tex]

[tex]F_{1} =m \cdot a\\F_{1}=2100kg \cdot 9.8\frac{m}{s^2}\\F_{1}=20580N[/tex]

Esta fuerza comprime o reduce la longitud del muelle en 5.5 cm. Usando estos datos en la Ley de Hooke, podemos obtener la constante elástica k:

[tex]F=-k \cdot \Delta L\\20580N=-k \cdot (-0.055m)\\\\k=\frac{20580N}{0.055m}\\k= 374181\frac{N}{m}[/tex]

Ahora ya tenemos los datos para resolver las preguntas:

a) Longitud que desciende el remolque si se carga con 28000 N

Aplicando directamente la formula de la Ley de Hooke:

[tex]F=-k \cdot \Delta L\\\Delta L=\frac{F}{-k} \\\Delta L= \frac{28000N}{-374181\frac{N}{m}} \\\Delta L=-0.074 m = -7.4cm[/tex]

b) Si ha descendido 4,2 cm la carga

En este caso debemos calcular la fuerza necesaria que haga descender el remolque 4.2cm. Nuevamente utilizando la Ley de Hooke con estos nuevos datos:

[tex]F=-k \cdot \Delta L\\F=-374181\frac{N}{m} \cdot (-0.042m)\\F=15715.6N[/tex]

Si queremos saber la carga en kilogramos:

[tex]F = m \cdot a\\m = \frac{F}{a} \\m = \frac{15715.6N}{9.8\frac{m}{s^2} }\\m= 1603.6 kg[/tex]

what makes up a atom

Answers

Answer:

They're typically made up of three main parts: protons, neutrons and electrons. Think of the protons and neutrons as together forming a “sun”, or nucleus, at the centre of the system. The electrons orbit this nucleus, like planets. If atoms are impossibly small, these subatomic particles are even more so.

Explanation:

hope i helped.

Answer:

Atoms consist of a nucleus made of protons and neutrons orbited by electrons. ... We now know that atoms are made up of three particles: protons, neutrons and electrons — which are composed of even smaller particles, such as quarks.

Explanation:

Calculate the average speed of a runner who runs to for 500 meters in 40 second

Answers

Answer:

12.5

Explanation:

if the volume of a cube is 100cm3. what's the measurement of one of its length​

Answers

Answer:

100 cm

Explanation:

Answer:

4.64

Explanation:

The cube root of 100 is 4.64.

Electromagnetic radiation is emitted by accelerating charges. The rate at which energy is emitted from an accelerating charge that has charge q and acceleration a is given by dEdt=q2a26πϵ0c3 where c is the speed of light.Part AIf a proton with a kinetic energy of 5.0 MeV is traveling in a particle accelerator in a circular orbit with a radius of 0.530 m , what fraction of its energy does it radiate per second?(dE/dt)⋅1sE =

Answers

Answer:

 P /K = 1,997 10⁻³⁶  s⁻¹

Explanation:

For this exercise let's start by finding the radiation emitted from the accelerator

       [tex]\frac{dE}{dt}[/tex] = [tex]\frac{q^{2} a^{2} }{6\pi \epsilon_{o} c^{2} }[/tex]

the radius of the orbit is the radius of the accelerator a = r = 0.530 m

let's calculate

       \frac{dE}{dt} = [(1.6 10⁻¹⁹)² 0.530²] / [6π 8.85 10⁻¹² (3 108)³]

      P= \frac{dE}{dt}= 1.597 10⁻⁵⁴ W

Now let's reduce the kinetic energy to SI units

       K = 5.0 10⁶ eV (1.6 10⁻¹⁹ J / 1 eV) = 8.0 10⁻¹⁹ J

the fraction of energy emitted is

      P / K = 1.597 10⁻⁵⁴ / 8.0 10⁻¹⁹

      P /K = 1,997 10⁻³⁶  s⁻¹

why is thouching the live wire of an appliane when it is connecfed to the mains dangerous

Answers

Answer: The live wire is the most dangerous one, since it is at 230 V. it should never touch the earth wire (unless the insulation is between them, of course!), because this would make a complete circuit from your mains supply to the ground (earth). A shock or fire would be highly likely.

Explanation:

What are some examples of X-Ray waves

Answers

Answer:

X - Rays

Explanation:

Hope it Helps!

:)

Answer: Black holes, sun, stars, neutron stars

Explanation:

Carbon is stored in leaves in various forms, such as sugar. When leaves decay, they lose mass. Which of the following sentences explains what happens to the carbon that is stored in leaves when they decay?
a. The carbon evaporates.
b. The carbon is destroyed as the leaves decompose.
c. The carbon is converted into nitrogen by bacteria in the soil.
d. The carbon is converted into carbon dioxide and released into the atmosphere.

Answers

Answer:either D or C

Explanation:

The carbon is converted into carbon dioxide and released into the atmosphere. therefore the correct answer is option D

What is a Chemical compound?

A chemical compound is a combination of two or more either similar or dissimilar chemical elements, for example, H₂O is a chemical compound made up of two oxygen atoms and a single hydrogen atom.

These chemical compounds are formed because of different types of bonds between the constituent's elements, the chemical bonds are mainly ionic bonds, covalent bonds,s, and hydrogen bonds.

Carbon is stored in leaves in various forms, such as sugar. When leaves decay, they lose mass.

The carbon is converted into carbon dioxide and released into the atmosphere is the sentence that explains what happens to the carbon that is stored in leaves when they decay.

Thus, the carbon is converted into carbon dioxide and released into the atmosphere. the correct answer is option D.

Learn more about a chemical compound from here

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In 1989 Carl Lewis established a world record when he ran the hundred meter dash in 9.92 seconds. What was his average speed (in M/S) for the race? Remember to include your data, equation, and work on solving the problem.

Answers

Answer:

10.08 m/s

Explanation:

The average speed of a body or an object can be calculated from the ratio of the total distance traveled by the body/object to that of the time taken to cover the distance.

Mathematically,

Average speed = total distance/total time

The total distance covered by Carl Lewis = 100 m

The total time taken = 9.92 s

Hence,

Average speed of Carl Lewis = 100/9.92

                                         = 10.08 m/s

Which of the following charts correctly compares plant and animal cells?

Answers

Answer:

Wheres the charts??

Explanation:

I need the charts so I can help

Which physical property is best measured using only a balance? A. Density B. Volume C. Color D. Mass​

Answers

Answer:

D. Mass

hope it helps

Explanation:

Mass is commonly measured with a balance

When the 9-kg pendulum bob is swinging, it reaches its maximum speed at its lowest position at v = 7 m/s. calculate the pendulum bob's kinetic energy at the moment it passes the lowest position. (Round your answer to hundredth, keep two decimal digits. Fill the numerical value in the box without unit.)

Answers

Maximum because when moving in circular motion it move front to back

Find the kinetic energy of a 3.5 kg cat that has a momentum of 0.22 kg • m/s.
A) 3.98 x 10^-5 J
B) 4.32 x 10^-4 J
C) 6.91 x 10^-3 J
D) 7.22 x 10^-2 J

Answers

Answer:

6.19*10^-3 J

Explanation:

Just took the test. Kiss me

What do scientists hope to learn from missions to visit asteroids?

Answers

Answer:

The mission will help scientists investigate how planets formed and how life began, as well as improve our understanding of asteroids that could impact Earth.

Explanation:

Hope this helps :)

A car travels 3500 m in 200 seconds what is the car speed

Answers

Answer:

17.5 m/s

Explanation:

We can calculate the meters per second by dividing the distance by time. 3500 divided by 200 is 17.5, therefore the speed is 17.5 meters per second.

A football is kicked with a speed of 18 m/s at an angle of 65° to the horizontal. How far does the football travel horizontally before it hits the ground?

Answers

The horizontal distance traveled by the football is determined as 25.33 m.

Horizontal distance traveled by the football

The horizontal distance traveled by the football is calculated as follows;

X = u²sin(2θ)/g

where;

u is the initial speedg is acceleration due to gravity

X = (18² x sin(2 x 65))/9.8

X = 25.33 m

Thus, the horizontal distance traveled by the football is determined as 25.33 m.

Learn more about horizontal distance here: https://brainly.com/question/24784992

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Where are alkaline earth metals found on the periodic table?

Group 1
Group 2
Groups 3–12
Group 17

Answers

Answer:

B

Explanation:

Answer:

B

Explanation:

I had a feeling

an object with a mass of 6 kg accelerates 4 m/s2 when an unknown force is applied to it. what is the amount of the force?

Answers

24 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 6 × 4

We have the final answer as

24 N

Hope this helps you

Answer:

24 n is the answer

A horizontal pipe contains water at a pressure of 110 kPa flowing with a speed of 1.4 m/s. When the pipe narrows to one half its original diameter, what is (a) the speed and (b) the pressure of the water?

Answers

Answer:

a

  [tex]v_2 = 5.6 \ m/s[/tex]

b

   [tex]P_2 = 80600 \ Pa[/tex]

Explanation:

From the question we are told that  

     The pressure of the water in the pipe is  [tex]P_1= 110 \ kPa = 110 *10^{3 } \ Pa[/tex]

      The speed of the water  is [tex]v_1 = 1.4 \ m/s[/tex]

       The original area of the pipe is  [tex]A_1 = \pi \frac{d^2 }{4}[/tex]

       The  new area of the pipe is  [tex]A_2 = \pi * \frac{[\frac{d}{2} ]^2}{4} = \pi * \frac{\frac{d^2}{4} }{4} = \pi \frac{d^2}{16}[/tex]

         

Generally the continuity equation is mathematically represented as

       [tex]A_1 * v_1 = A_2 * v_2[/tex]

Here [tex]v_2[/tex] is the new velocity  

So

        [tex]\pi * \frac{d^2}{4} * 1.4 = \pi * \frac{d^2}{16} * v_2[/tex]

=>     [tex]\frac{d^2}{4} * 1.4 = \frac{d^2}{16} * v_2[/tex]

=>    [tex]d^2 * 1.4 = \frac{d^2}{4} * v_2[/tex]

=>    [tex]1.4 = 0.25 * v_2[/tex]

=>     [tex]v_2 = 5.6 \ m/s[/tex]

Generally given that the height of the original pipe and the narrower pipe are the same , then we will b making use of the  Bernoulli's equation for constant height to calculate the pressure

This is mathematically represented as

       

             [tex]P_1 + \frac{1}{2} * \rho * v_1 ^2 = P_2 + \frac{1}{2} * \rho * v_2 ^2[/tex]

Here [tex]\rho[/tex] is the density of water with value  [tex]\rho = 1000 \ kg /m^3[/tex]

             [tex]P_2 = P_1 + \frac{1}{2} * \rho [ v_1^2 - v_2^2 ][/tex]

=>          [tex]P_2 = 110 *10^{3} + \frac{1}{2} * 1000 * [ 1.4 ^2 - 5.6 ^2 ][/tex]

=>          [tex]P_2 = 80600 \ Pa[/tex]

Arrange Kepler's laws in order: a. The ratio of the squares of the periods of any two planets revolving around the sun is equal to the ratio of the cubes of their average distance from the sun. b. The path of each planet around the sun is an ellipse with the sun at one focus. c. As a planet moves in its orbit, a line from the sun to the planet sweeps out equal areas in equal times. a. 3, 2, 1 b. 2, 3, 1 c. 3, 1, 2 d. 1, 2, 3

Answers

Answer:

2,3,1

Explanation:

There are 3 laws of Kepler.

First law = The path of each planet around the sun is an ellipse with the sun at one focus.

Second law =  As a planet moves in its orbit, a line from the sun to the planet sweeps out equal areas in equal times.

Third law = The ratio of the squares of the periods of any two planets revolving around the sun is equal to the ratio of the cubes of their average distance from the sun.

Hence, the correct order for Kepler's law is: 2,3,1

Please help which one !!

Answers

Answer:

4th one

Explanation:

Jack jumped off a diving board and hit the water at 15.68 m/s downward. How long was he falling for before he hit the water?

Answers

Answer:

1.6 s

Explanation:

From the question given above, the following data were:

Velocity (v) = 15.68 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

Thus, we can calculate the time taken for Jack to hit the water by using the following formula:

v = gt

15.68 = 9.8 × t

Divide both side by 9.8

t = 15.68 / 9.8

t = 1.6 s

Therefore, it took Jack 1.6 s to hit the water.

Can someone help please I will give brainliest

Answers

Pretty sure it’s b but don’t hate on me

A fish is 4.7 cm from the front surface of a fish bowl of radius 21 cm. Where does the fish appear to be to someone in air viewing it from in front of the bowl? Do not forget the proper sign. (Give your answer in cm.)


______ cm


Where does the fish appear to be when it is 38.9 cm from the front surface of the bowl? (Give your answer in cm.)


______ cm

Answers

Answer:

Explanation:

From the information given:

We can properly determine the distance where the fish appear in the air viewing it from in front of the bowl by using the formula:

[tex]\dfrac{n_i}{d_o}+\dfrac{n_2}{d_1}= \dfrac{n_2-n_1}{r}[/tex]

where;

[tex]n_1[/tex] = refractive index in the air;  = 1.33  &

[tex]n_2[/tex] = refractive index in water. = 1

[tex]\dfrac{n_2}{d_i}= \dfrac{n_2-n_1}{r}-\dfrac{n_1}{d_o}[/tex]

[tex]\dfrac{1}{d_i}= \dfrac{1-1.33}{-21 \ cm}-\dfrac{1.33}{4.7\ cm}[/tex]

[tex]\dfrac{1}{d_i}= - 0.26726 \ cm[/tex]

[tex]d_i =\dfrac{1}{ - 0.26726 \ cm}[/tex]

[tex]\mathbf{d_i }[/tex] = - 3.74 cm

2)

To determine where the fish appear to be when it is  38.9 cm from the front surface of the bowl by using the formula:

[tex]\dfrac{n_2}{d_i}= \dfrac{n_2-n_1}{r}-\dfrac{n_1}{d_o}[/tex]

[tex]\dfrac{1}{d_i}= \dfrac{1-1.33}{-21 \ cm}-\dfrac{1.33}{38.9\ cm}[/tex]

[tex]\dfrac{1}{d_i}=- 0.0184759 \ cm[/tex]

[tex]d_i = \dfrac{1}{- 0.0184759 \ cm}[/tex]

[tex]\mathbf{d_i = }[/tex] -54.12  cm

1) A person riding their bike on a nice cloudy day travels 50 meters in 20 seconds.
How fast are they moving?

Answers

Answer:

5.59

Explanation:

50 meters in 10 seconds is 11.18, which is an easy way to remember. Just divided by 2

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