Which of the following statements is correct about air temperature?

1. When air temperature is higher, the weather is warmer.
2. Warm air falls to the ground.
3. Freezing air temperatures increase the chances of rain.
4. When air temperature is higher, the weather is colder.

Answer:

Both ice and snow have a lower coefficient of friction in comparison with grass, wood or pavement.

Explanation:

The main reason why people and bears, slip and fall on ice/snow is that both ice and snow have a lower coefficient of friction in comparison with grass, wood or pavement. We present below a comparative chart of coefficients of friction associated with different materials:

Material       Coefficient of Friction - Static                  

Ice/Snow                   0.05 - 0.3

Wood                          0.2 - 0.6

Asphalt                        0.5 - 0.7

Grass                            0.3 - 0.5

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The isotopes of any element have same number of protons inside them.

Cadmium is a chemical element with the symbol Cd and atomic number 48. It is soft, silvery and white metal.

Given is about Cadmium that it has eight naturally occurring isotopes.

Isotopes are the atoms of the same element which have same number of protons in them but the number of neutrons are different. Isotopes usually have same chemical properties, but they have different physical properties. Their can be stable and unstable isotopes. These unstable isotopes are also called radioisotopes, since they emit radiation. Thus, the isotopes have same number of protons.

Therefore, the isotopes of any element have same number of protons inside them.

To solve more questions on isotopes, visit the link below-

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Explanation:

(1) Given that,

A charge, [tex]q=3\times 10^{-7}\ C[/tex]

Electric field, E = 27 N/C

We need to find the force acting on the charge. The force on the charge is given by :

[tex]F=qE\\\\F=3\times 10^{-7}\times 27\\F=8.1\times 10^{-6}\ N[/tex]

So, the force acting on the charge is [tex]8.1\times 10^{-6}\ N[/tex]

(b) Charge, [tex]q=5\times 10^{-6}\ C[/tex]

Force, [tex]F=2\times 10^{-4}\ N[/tex]

Let E be the electric field.

[tex]E=\dfrac{F}{q}\\\\E=\dfrac{2\times 10^{-4}}{5\times 10^{-6}}\\\\E=40\ N/C[/tex]

So, the electric field is 40 N/C.

Answer:

Mass, in physics, quantitative measure of inertia, a fundamental property of all matter. It is, in effect, the resistance that a body of matter offers to a change in its speed or position upon the application of a force. The greater the mass of a body, the smaller the change produced by an applied force.

Explanation:

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Answer:

Mass, in physics, quantitative measure of inertia, a fundamental property of all matter. It is, in effect, the resistance that a body of matter offers to a change in its speed or position upon the application of a force. The greater the mass of a body, the smaller the change produced by an applied force.

Explanation:

Hope that helps! :)

Answer:

The quadriceps consists of four muscles: the skinny rectus femoris and the three huge “vasti” — vastus lateralis/intermedius/medialis. The vasti are only elongated by knee flexion, which is limited to about 120˚ when the calf hits the hamstrings. The vasti cannot be stretched strongly.

Answer:Masseter and temporalis

Why it’s unstretchable: The jaw can only open so far.

Why it’s a dang shame: Jaw tension is epidemic, and trigger points in these muscles cause a wide array of strange face and head pains, including toothaches, headaches, and earaches.

Answer:

5.17 x 10^5

Explanation

The correct answer is (b) [tex]5.17*10^{5}m[/tex]

Let us consider an object of mass m on the planet Q.

On planet Q, let the acceleration due to gravity be g = 2.24 m/[tex]s^{2}[/tex]

Mass of the planet is M = [tex]8.96*10^{21} kg[/tex]

Let its radius be R

and the universal gravitational constant G = [tex]6.67*10^{-11} m/kg[/tex]

Gravitational Force acting on the object:

[tex]mg=\frac{GMm}{R^{2} }[/tex]

[tex]R=\sqrt{\frac{GM}{g} } \\R=\sqrt{\frac{6.67*10^{-11}*8.96*10^{21} }{2.24} }\\R=5.17*10^{5} m[/tex] is the radius of the planet Q.

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evaporation, condensation, precipitation, runoff, collection

it absorbs all ligj colour except black

Answer:

 a = 40.937 m / s²

Explanation:

For this exercise let's use the relationship between momentum and momentum variation

          I  = Δp

          F t = m v_f - mv₀

          F = m (v_f -v₀) / t

let's reduce the magnitudes to the SI system

          v_f = 47 km / h (1000m / 1 km) (1h / 3600 s) = 13.056 m / s

          v₀ = - 65 km / h = -18.056 m / s

the negative sign is bearing the speed is west

let's calculate

          F = m (13.056 + 18.056) / 0.76

          F = m 40.937

now we can use Newton's second law

          F = m a

          m 40.937 = m a

          a = 40.937 m / s²

Answer:

6.44pie

Explanation:

[tex]2\pirh[/tex]

Answer:

when a ray of light is incident normally on a plane mirror the angle between incident and reflected ray is 0 degree or 180 degree

Explanation:

Answer:

9 ohms

Explanation:

P = V²/R

R = v²/p = 6²/4 = 36/4 = 9 ohms.

The resistance is 9 Ohm.

To find the resistance, we need to know about the power in term of resistance and voltage.

Thus, we can conclude that the resistance is 9 Ohm.

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Answer:

hello your question is incomplete hence I will give you a general answer on how a stunt cyclist performs his stunts successfully

answer ;

The stunt cyclist trying to perform some sort of stunt with the bicycle will be faced with some forces like the static fiction between the tires of the bicycle and wall and also a centripetal force.

In order to overcome the centripetal force the minimal grip of the bicycle must be equal to the weight and the speed at which the cyclist must go can be represented as :

[tex]V_{min} = \sqrt{\frac{r.g}{u} }[/tex]

Explanation:

The stunt cyclist trying to perform some sort of stunt with the bicycle will be faced with some forces like the static fiction between the tires of the bicycle and wall and also a centripetal force.

In order to overcome the centripetal force the minimal grip of the bicycle must be equal to the weight and the speed at which the cyclist must go can be represented as :

[tex]V_{min} = \sqrt{\frac{r.g}{u} }[/tex]

where ; r = radius of the tunnel where the stunt is to be performed

            g = gravitational speed

            u = coefficient of static friction

Answer:

- 42

Explanation:

m = 6kg

vi = 17 m/s

vf = 10 m/s

delta mv = ?

Formula

delta mv = m*(vf) - m(vi)

delta mv = 6(10 - 17)

delta mv = 6(-7)

delta mv = - 42 kg m/s

Coulomb's Law says that the forces between any two charges depends directly on the size of the charges and inversely on the square of the distance between the charges. The correct option is D. A & B

From the question, we are to determine the correct option.

First, we will state Coulomb's law.

Coulomb's law states that the electrical force between two charged objects is directly proportional to the product of the quantity of charge on the objects and inversely proportional to the square of the separation distance between the two objects

That is,

[tex]F \propto \frac{Q_{1} Q_{2} }{r^{2} } [/tex]

Where F is the electrical force

[tex]Q_{1} \ and \ Q_{2}[/tex] are the charges

r is the distance between the objects

From the law, we can observe that the forces depends directly on the size of the charges - Option A

and the forces also depends inversely on the square of the distance between the charges - Option B

Hence, the correct option is D. A & B

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Answer:

s orbital

Explanation:

that the answer

Answer:

Unsaturated

Explanation:

the solubility of sodium nitrate is at 60 C is 124g/ml therefore, putting 100 grams will not saturate fully.

Answer:

H=Hydrogen, PO4=Phosphate

Explanation:

Reactions are on the left side of arrow and products are on the right side of arrow.

Answer:

[tex]A_{1}[/tex] = 0.2 [tex]m^{2}[/tex]

Explanation:

The pressure on the pistons is given as;

Pressure = [tex]\frac{Force}{Area}[/tex]

So that,

Pressure on the small piston = [tex]\frac{F_{1} }{A_{1} }[/tex] and Pressure on the large piston = [tex]\frac{F_{2} }{A_{2} }[/tex]

Thus,

[tex]\frac{F_{1} }{A_{1} }[/tex] = [tex]\frac{F_{2} }{A_{2} }[/tex]

Given that: [tex]F_{1}[/tex] = 100 N, [tex]F_{2}[/tex] = 2000 N, [tex]A_{2}[/tex] = 4 [tex]m^{2}[/tex].

[tex]\frac{100}{A_{1} }[/tex] = [tex]\frac{2000}{4}[/tex]

[tex]A_{1}[/tex] = [tex]\frac{100*4}{2000}[/tex]

    = [tex]\frac{400}{2000}[/tex]

    = 0.2

[tex]A_{1}[/tex] = 0.2 [tex]m^{2}[/tex]

The area of the small piston is 0.2 [tex]m^{2}[/tex].

Answer:

B

Explanation:

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