Which inequality is graphed on the number line?

Which Inequality Is Graphed On The Number Line?

Answers

Answer 1
The answer is C
First you add 11 on both sides
So your left with
3a<= 18
Then divide by 3 on both sides to get
a<=6 which is plotted on the graph

Related Questions

Write 15.5 as a fraction in the simplest form and as a decimal

Answers

Fraction; 13/200
Decimal: 0.155

How i can answer this question

Answers

60m

How?

5m × 3m × 4m

5m × 3m = 15m

15m × 4m = 60m

Therefore

the answer is 60

Please help Tysm!! <3

Answers

Answer:

68 homes

Step-by-step explanation:

1. First, let's set up a proportional relating the home to the # of hours.

[tex]\frac{17}{49} = \frac{x}{196}[/tex]

2. Now, let's see if we can divide 196 by 49. If so, the quotient we get is the number we multiply 17 by to get x.

[tex]196/49 = 4[/tex] This means that we multiply 17 by 4 to get x.[tex]17 * 4 = 68[/tex]

Therefore, the answer is 68 homes.

Find the area of each figure

Answers

Answer:

54

Step-by-step explanation:

.5*9*12

54
Explanation ~
B•h/2
9•12=108
108/2=54
:)

1. Rosie orders dessert at the cafe. The total bill is $50. She tips the waiter 10%.
How much money does the waiter get?

Answers

Answer:

5

Step-by-step explanation:

this means it'll be $55

Which quantity of fruit contains an amount of vitamin C closest to the combined


amount of vitamin C in 50 g grams of acerola cherries and 150 g grams of


kiwifruit?


A. 2,000 g grams of black currants


B. 800 g grams of guava


C. 1,800 g grams of pineapple


D. 600 g grams of strawberries

Answers

Answer:

c would be the closest due to the total amount of vitamin c in the objects.

The quantity of fruit which contains an amount of vitamin C closest to the combined content is: C. 1,800 g grams of pineapple.

How to calculate the amount of vitamin.

In this exercise, we would determine the amount of vitamin C that is present in a combination of 50 grams of acerola cherries and 150 grams of kiwifruit.

For acerola cherries:

100 grams of acerola cherries = 1678 mg.

50 grams of acerola cherries = X mg.

Cross-mutiplying, we have:

X = 83,900/100 = 839 mg.

For kiwifruit:

100 grams of kiwifruit = 105 mg.

150 grams of kiwifruit = Y mg.

Cross-mutiplying, we have:

Y = 15,750/100 = 157.5 mg.

Combine vitamins = 157.5 + 839 = 996.5 mg.

Based on intuition, we would choose 1,800 grams of pineapple.

100 grams of pineapple = 56 mg

1,800 grams of pineapple = Z mg.

Cross-mutiplying, we have:

Z = 100,800/100 = 1008 mg.

Thus, 996.5 mg of vitamin C is closest to 1008 mg.

Note: If you do the above computations for other quantities of fruit, you'll get a value far from 996.5 mg.

Read more on vitamins here: https://brainly.com/question/9348916

Find the value of √1600×8²+√4225​

Answers

Step-by-step explanation:

√1600×8²+√4225

40 x 64 + 65

= 2625

Ok done. Thank to me :>

Can you please help me

Answers

Answer:  Attached.

Step-by-step explanation:

Either solve the equations directly, or graph them and look for the point of intersection.  

Can someone help me? ​

Answers

Answer:

I figure you could simplify it by multiplying both sides by 6, resulting in -31+23=-30+18-1+5

-8=-8

Step-by-step explanation:

Please help me with this question.

Answers

they are equivalent. combine like terms on the first one and 9x-4x+25 can be simplified to 5x+25.

Please solve this question

Answers

Answer:

46?

Step-by-step explanation:

23*2=46

Answer:

37.31 cm

Step-by-step explanation:

∡ AB = 180 - 148 = 32° = ∡ DE

∡ CD = 360 - ∡ AE - ∡ AB - ∡ BC - ∡ DE = 360 - 148 - 32 - 87 - 32 =61°

∡ CE = 61 + 32 = 93°

arc length = 2[tex]\pi[/tex]r [tex]\frac{angle}{360}[/tex] = 2×3.14×23×[tex]\frac{93}{360}\\[/tex] = 37.31 cm

A storage container leaks water at a rate of 15 gallons every 30 days.

What is the unit rate in gallons per week?

Enter your answer as a mixed number in simplest form in the box.

Answers

Answer:

i think 3.5 gallons per week

[tex]3 \frac{1}{2} [/tex]

Step-by-step explanation:

15 gallons every 30 days

x gallons per weeks (7 days)

15×7 = 30x

105 = 30x

105/30 = x

3.5 = x

answer as a mixed number in simplest form = 3 1/2

Answer: The answer is 3 1/2

Step-by-step explanation:

I took the quiz and did 100% :)

Can someone help me with this plis

Answers

Answer:

it is c

Step-by-step explanation:

what is the domain of the function

Answers

Answer:

  (a)  -∞ < x < ∞

Step-by-step explanation:

Unlike the square root function, the cube root function is defined for all values of its argument. Here, x can take on any value and the function will be defined for that value.

  -∞ < x < ∞

The population of a pigeons in a city is 100 and is growing exponentially at 20% per year. Write a function to represent the population of pigeons after
t
t years, where the monthly rate of change can be found from a constant in the function. Round all coefficients in the function to four decimal places. Also, determine the percentage rate of change per month, to the nearest hundredth of a percent

Answers

Answer:

p(t) = 100×1.0153^(12t)1.53% per month

Step-by-step explanation:

In general, the function will be written ...

  p(t) = (initial value)×(growth factor)^t

where t is in units comparable to those applicable to the growth factor. The growth factor is found from ...

  growth factor = 1 + growth rate

Here, the growth rate is given as 20% per year, so the growth factor per year is ...

  1 +20% = 1.20

The initial value is given as 100, so we can write the exponential function as ...

  p(t) = 100×1.20^t

__

The time period units for t are supposed to be years, but we want to find the growth rate for a month. We can do that by recognizing there are 12 months in a year. In the above equation, we can use (1/12)(12t) in place of t, then figure the growth factor (and growth rate) per month.

  p(t) = 100×(1.20^(1/12))^( 12t)

  p(t) = 100×1.0153^(12t) . . . . population exponential function

This shows the monthly growth factor is 1.0153, so the monthly rate of change (growth rate) is ...

  1.0153 -1 = 0.0153 = 1.53% . . . . monthly rate of change

Answers:

Function is [tex]P(t) = 100(1.0153)^{12t}\\\\[/tex]Monthly growth rate is roughly 1.53%

=====================================================

Explanation:

The population starts at 100 pigeons. After a year, the population goes up by 20%, meaning the population goes up by 20. It lands on 120 after a full year (100+20 = 120).

Dividing the "before" and "after" population amounts gets us 120/100 = 1.20

If we didn't worry about the monthly rate, and only cared about the annual rate of growth, then the population function would be

[tex]P(t) = 100(1.20)^t[/tex]

where t is the number of years and P(t) is the population for that year number. Notice how the 1.20 is the base of the exponential to quickly tell the reader the annual rate of growth. We read off the .20 portion and that converts to 20% after moving the decimal 2 spots to the right.

If we were to plug t = 0 into that function, then we'd get P(0) = 100. Inputting t = 1 leads to P(1) = 120. This helps confirm we have the correct annual growth rate function.

---------------------

Unfortunately, your teacher doesn't want the annual growth rate function. Instead, they want you to write a function where the reader can easily pick out the monthly rate of change without having to do any math. This is due to the instructions that "the monthly rate of change can be found from a constant in the function". Let m be this constant.

Since t is the number of years, this means t = 1/12 represents 1/12 of a year, aka 1 month. If you were to compute P(1/12), then you should get roughly 101.530947049973

Divide this amount over the initial population to find m.

m = 101.530947049973/100 = 1.01530947049973

So we get m = 1.0153 after rounding to four decimal places.

The number m is in the form 1+x. Solving 1+x = m will lead to x = 0.0153 to indicate a monthly rate of change is roughly 1.53% since we move the decimal point 2 spots to the right to go from 0.0153 to 1.53%

The pigeon population is increasing by roughly 1.53% each month.

This is why computing this m value leads to the reader able to spot the monthly rate of change without having to resort to a calculator. All they have to do is read the digits to the right of the decimal point and convert that to percentage form.

---------------------

An alternative way to compute this value is to use this formula

m = (1+r)^(1/12)

We'll plug in the annual rate r = 0.20 to get:

m = (1+r)^(1/12)

m = (1+0.20)^(1/12)

m = 1.01530947049973

m = 1.0153

We get the same approximate value as earlier.

---------------------

Whichever method you use, you should get roughly m = 1.0153

We're given that A = 100 is the initial population

So we'll then be able to form this function

[tex]P(t) = A*(m)^{12t}\\\\P(t) = 100(1.0153)^{12t}\\\\[/tex]

This represents the monthly growth of the population where t is in years. Note that after something like t = 3 years, we have 12t = 12*3 = 36 months pass by. So that's why the 12t is in the exponent rather than simply t.

Once again, for comparison we have...

[tex]P(t) = 100(1.20)^{t}\\\\[/tex] for annual growth[tex]P(t) = 100(1.0153)^{12t}\\\\[/tex] for monthly growth

Each function has t represent the number of years. The difference is the base of each exponential to tell us the respective annual or monthly growth rate. Also, the exponent up top must be adjusted depending on which you go for.

---------------------

You may be wondering: "what if the exponent in the monthly growth rate function wasn't 12t?". Let's find out. We'll assume the monthly growth rate function is [tex]P(t) = 100(1.0153)^{t}\\\\[/tex] and show that an error happens.

If we plugged in something like t = 1, we should get P(t) = 120 like mentioned earlier.

[tex]P(t) = 100(1.0153)^{t}\\\\P(1) = 100(1.0153)^{1}\\\\P(1) = 100(1.0153)\\\\P(1) = 101.53\\\\[/tex]

That value of 101.53 is the approximate population number after 1 month, rather than 1 year. Making the exponent 12t will fix the issue.

16x2 + 81y2 + 32x + 648y + 16 = 0 write instandard form

Answers

I can’t answer it doesn’t have enough information

-X + 2y= -3 and -8x — 3y= -5

Answers

Answer:

x=1, y=-1. (1, -1).

Step-by-step explanation:

-x+2y=-3

-8x-3y=-5

----------------

-8(-x+2y)=-8(-3)

-8x-3y=-5

------------------------

8x-16y=24

-8x-3y=-5

-----------------

-19y=19

y=19/-19

y=-1

-x+2(-1)=-3

-x-2=-3

-x=-3+2

-x=-1

x=1

(1, -1)

Answer:

x = 1, y = -1

or as an ordered pair, (1, -1).

Step-by-step explanation:

  -x  + 2y = -3

-8x — 3y = -5

Multiply first equation by -8:

8x - 16y = 24

Add this equation to the second equation:

-19y = 19

y = -1.

Plug y = -1 into the second equation:

-8x - 3(-1) = -5

-8x + 3 = -5

-8x = -8

x = 1.

Which set of numbers are ordered from least to greatest?
O A. 7,1-41, -7,0,-131, 3
B. -31, -7,0,3,7, 1-4]
C. -7,-131,0,3, 4,7
D. 7.1-41,3,0.-131, -7

Answers

The answer is B. -31, -7, 0 , 3, 7, 1, 4

Some information about a direct variation is given in the table below. If the equation
of this direct variation is y = kx , find the coefficient k and fill in the missing
information.

Answers

Answer:

Step-by-step explanation:

y = kx ;

k = [tex]\frac{y}{x}[/tex] ; x = [tex]\frac{y}{k}[/tex]

~~~~~~~~~~~~~

k = [tex]\frac{1}{2}[/tex] ÷ 1 = [tex]\frac{1}{2}[/tex]

[tex]y_{1}[/tex] = [tex]\frac{1}{2}[/tex] × ( - 8 ) = - 4

[tex]y_{2}[/tex] = [tex]\frac{1}{2}[/tex] × ( - 4 ) = - 2

[tex]y_{3}[/tex] = [tex]\frac{1}{2}[/tex] × 2 = 1

[tex]x_{5}[/tex] = [tex]\frac{1}{3}[/tex] ÷ [tex]\frac{1}{2}[/tex] = [tex]\frac{2}{3}[/tex]

[tex]x_{6}[/tex] = - [tex]\frac{1}{4}[/tex] ÷ [tex]\frac{1}{2}[/tex] = - [tex]\frac{1}{2}[/tex]

[tex]x_{7}[/tex] = 0

( x , y ) : ( - 8 , - 4 ), ( - 4 , - 2 ), ( 2 , 1 ), ( 1 , [tex]\frac{1}{2}[/tex] ), ( [tex]\frac{2}{3}[/tex] , [tex]\frac{1}{3}[/tex] ), ( - [tex]\frac{1}{2}[/tex] , - [tex]\frac{1}{4}[/tex] ), ( 0 , 0 )

Find the 62nd term of the arithmetic sequence
15, 13, 11, ...

Answers

Answer:

[tex]a_{62}=-107[/tex]

Step-by-step explanation:

This is an arithmetic sequence:

[tex]a_n=a_1+(n-1)d[/tex]

where d is the common difference and n is the index of any given term.

The common difference of the given sequence is -2:

[tex]13-15=-2\\11-13=-2[/tex]

Using the first term and the common difference, you can write the equation for this sequence:

[tex]a_n=15+(n-1)(-2)[/tex]

And using that equation, you can find the 62nd term:

[tex]a_{62}=15+(62-1)(-2)\\a_{62}=15+(61)(-2)\\a_{62}=15-122\\a_{62}=-107[/tex]

How I can apply the distribute property to this question?

Answers

Answer:

6(4c+6d+3)

Step-by-step explanation:

First, find the greatest common factor, which is 6, in this case.

24/6=4

36/6=6

18/6=3

6(4c+6d+3)

-hope it helps

13. This body system regulates body activities using homones. Slow response, tong lasting
A. Respiratory
C. Skeletal
B. Muscular
D. Endocrine

Answers

Answer:

hi

Step-by-step explanation:

Two forces X = 50N and Y = 60 N are acting on a wooden block and it moves to the left as

shown below in figure.

The force which causes motion is ?

Overnight the low temperature dropped to-6 degrees Fahrenheit. If the temperature during the was 11 degrees Fahrenheit, what was the difference between the high and low temperatures?

Answers

Answer:

17 degrees F

Step-by-step explanation:

11 - (-6) = 17

Subtracting a negative is the same as adding.

is (1, 3) a solution to the system of equations


8x + y = 11


12x + 2y = 18

Answers

Answer:

(1, 3) a solution to the system of equations

8x + y = 11

12x + 2y = 18

Step-by-step explanation:

ay están todos los deberes de la semana pasada gunnorni

Answer:

x=1 and y=3

Step-by-step explanation:

yes x=1 and y=3 is the solution for the equation.just by making y in the first equation subject of the formula and replacing in the second equation.

The weight of an object on moon is 1/6 of its weight on Earth. If weight of an object on Earth is 18/5 kg, what would be its weight on moon? ​Please help me!!!!​

Answers

Answer:

3/5 kg

Step-by-step explanation:

The weight of an object on Moon is 6 times smaller than same on Earth.

If it weights 18/5 kg on Earth then its weight  on Moon is:

18/5 * 1/6 = 3/5 kg

Answer:

Solution given:

weight of moon=1/6 th of Earth

If weight of Earth is 18/5 kg

weight of moon=?

we have

weight of moon: 1/6 of weight of Earth

=1/6*18/5

=3/5kg

Its weight on moon is 3/5 kg

For 18-20, factor each of the following and show work.

18. 5x^4 - 25x

19. 4x^2 - 9

20. x^2+8x+12

Answers

Step-by-step explanation:

20. x^2+8x+12

x^2 + 6x +2x + 12

X(X+6) + 2(X+6)

(X+2) (X+6)

18. 5x^4 - 25x

5x(x^3-5)

19. 4x^2 - 9

4x^2/4 -9/4 = 0/4

x^2 = 9/4

X=√9/4

3c+2=20
c
ok anwer this

Answers

Answer:

3c =20-2

3c = 18

c = 18÷3

=6

Answer:

Here is Your answer

Step-by-step explanation:

Hope u Like it

C = 2/17

Plz Mark me As Brainiest

A grocery store sells steak for $6.10 per pound. What would be the cost of 2 3/5 lb. of steak?

Answers

Answer:

$15.86

Step-by-step explanation:

Make 2 3/5 improper fraction (5 times 2 and add 3 equals 13)

13/5 times 6.1 ( or 6 1/10 or 61/10)

equals 793/50

divide

answer is 15.86

i need help with this question (3x56-7+76)/99=

Answers

Answer:

x^56+23/33

Step-by-step explanation:

The has the power of 56

a-y= b+y/a make y subject

Answers

Answer:

y = [tex]\frac{a^2-ab}{a+1}[/tex]

Step-by-step explanation:

a - y = b + [tex]\frac{y}{a}[/tex] ( multiply through by a to clear the fraction )

a² - ay = ab + y ( subtract y from both sides )

a² - ay - y = ab ( subtract a² from both sides )

- ay - y = ab - a² ← factor out y from each term on the left side

y(- a - 1) = ab - a² ( divide both sides by - a - 1 )

y = [tex]\frac{ab-a^2}{-a-1}[/tex] ( multiply numerator/ denominator by - 1 )

y = [tex]\frac{a^2-ab}{a+1}[/tex]

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