Where do electrons spend most of their time?

Coulomb's Law says that the forces between any two charges depends directly on the size of the charges and inversely on the square of the distance between the charges. The correct option is D. A & B

From the question, we are to determine the correct option.

First, we will state Coulomb's law.

Coulomb's law states that the electrical force between two charged objects is directly proportional to the product of the quantity of charge on the objects and inversely proportional to the square of the separation distance between the two objects

That is,

[tex]F \propto \frac{Q_{1} Q_{2} }{r^{2} } [/tex]

Where F is the electrical force

[tex]Q_{1} \ and \ Q_{2}[/tex] are the charges

r is the distance between the objects

From the law, we can observe that the forces depends directly on the size of the charges - Option A

and the forces also depends inversely on the square of the distance between the charges - Option B

Hence, the correct option is D. A & B

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Answer:

- 42

Explanation:

m = 6kg

vi = 17 m/s

vf = 10 m/s

delta mv = ?

Formula

delta mv = m*(vf) - m(vi)

delta mv = 6(10 - 17)

delta mv = 6(-7)

delta mv = - 42 kg m/s

Answer: objects A and B have the same speed.

Explanation:

Speed = distance divided by time.

Object A: 65 miles in 13 minutes

Speed (A) = 65 miles divided by 13 minutes

Speed (A) = 5 miles per minute

Object B: 125 miles in 25 minutes

Speed (B) = 125 miles divided by 25 minutes

Speed (B) = 5 miles per minute

Thus, objects A and B have the same speed.

Answer:

its false

Explanation:

Explanation:

(1) Given that,

A charge, [tex]q=3\times 10^{-7}\ C[/tex]

Electric field, E = 27 N/C

We need to find the force acting on the charge. The force on the charge is given by :

[tex]F=qE\\\\F=3\times 10^{-7}\times 27\\F=8.1\times 10^{-6}\ N[/tex]

So, the force acting on the charge is [tex]8.1\times 10^{-6}\ N[/tex]

(b) Charge, [tex]q=5\times 10^{-6}\ C[/tex]

Force, [tex]F=2\times 10^{-4}\ N[/tex]

Let E be the electric field.

[tex]E=\dfrac{F}{q}\\\\E=\dfrac{2\times 10^{-4}}{5\times 10^{-6}}\\\\E=40\ N/C[/tex]

So, the electric field is 40 N/C.

Answer:

Both ice and snow have a lower coefficient of friction in comparison with grass, wood or pavement.

Explanation:

The main reason why people and bears, slip and fall on ice/snow is that both ice and snow have a lower coefficient of friction in comparison with grass, wood or pavement. We present below a comparative chart of coefficients of friction associated with different materials:

Material       Coefficient of Friction - Static                  

Ice/Snow                   0.05 - 0.3

Wood                          0.2 - 0.6

Asphalt                        0.5 - 0.7

Grass                            0.3 - 0.5

Answer:

[tex]A_{1}[/tex] = 0.2 [tex]m^{2}[/tex]

Explanation:

The pressure on the pistons is given as;

Pressure = [tex]\frac{Force}{Area}[/tex]

So that,

Pressure on the small piston = [tex]\frac{F_{1} }{A_{1} }[/tex] and Pressure on the large piston = [tex]\frac{F_{2} }{A_{2} }[/tex]

Thus,

[tex]\frac{F_{1} }{A_{1} }[/tex] = [tex]\frac{F_{2} }{A_{2} }[/tex]

Given that: [tex]F_{1}[/tex] = 100 N, [tex]F_{2}[/tex] = 2000 N, [tex]A_{2}[/tex] = 4 [tex]m^{2}[/tex].

[tex]\frac{100}{A_{1} }[/tex] = [tex]\frac{2000}{4}[/tex]

[tex]A_{1}[/tex] = [tex]\frac{100*4}{2000}[/tex]

    = [tex]\frac{400}{2000}[/tex]

    = 0.2

[tex]A_{1}[/tex] = 0.2 [tex]m^{2}[/tex]

The area of the small piston is 0.2 [tex]m^{2}[/tex].

Answer:

Unsaturated

Explanation:

the solubility of sodium nitrate is at 60 C is 124g/ml therefore, putting 100 grams will not saturate fully.

Explanation:

Warm air falls to the ground

The statement that is correct about air temperature is when the air temperature is higher, the weather is warmer. The correct option is 1.

A measurement of the air's heat or cold is its temperature. It is the weather parameter that is most frequently measured.

The kinetic energy, or energy of motion, of the gases that make up air, is more explicitly described by temperature. The temperature rises as gas molecules move more swiftly.

Surface temperatures are typically hotter than air temperatures. Parking your car in the sun is an illustration of this. The air inside the car will be fairly close to the outside air temperature and you may leave the windows down and yet have excellent ventilation.

Therefore, the correct option is 1. When the air temperature is higher, the weather is warmer.

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Answer:

Mass, in physics, quantitative measure of inertia, a fundamental property of all matter. It is, in effect, the resistance that a body of matter offers to a change in its speed or position upon the application of a force. The greater the mass of a body, the smaller the change produced by an applied force.

Explanation:

pls mark as brainliest

Answer:

Mass, in physics, quantitative measure of inertia, a fundamental property of all matter. It is, in effect, the resistance that a body of matter offers to a change in its speed or position upon the application of a force. The greater the mass of a body, the smaller the change produced by an applied force.

Explanation:

Hope that helps! :)

Answer:

m = 96.53 grams

Explanation:

Given that,

The density of metallic platinum, d = 21.5 g/cm³

Volume, V = 4.49 cm³

We need to find the mass. Let it is m. We know that the density is equal to the mass per unit volume. So,

[tex]d=\dfrac{m}{V}\\\\m=d\times V\\\\m=21.5\times 4.49\\\\m=96.53\ g[/tex]

So, the required mass is 96.53 grams.

Answer:

when a ray of light is incident normally on a plane mirror the angle between incident and reflected ray is 0 degree or 180 degree

Explanation:

Explanation:

it is equal to the speed (v) of a wave train in a medium divided by its frequency (f): λ = v/f. Waves of different wavelengths.

Answer:

It is measured in the direction of the wave. Description: Wavelength is the distance from one crest to another, or from one trough to another, of a wave (which may be an electromagnetic wave, a sound wave, or any other wave).

Answer:

6.44pie

Explanation:

[tex]2\pirh[/tex]

Answer:

The quadriceps consists of four muscles: the skinny rectus femoris and the three huge “vasti” — vastus lateralis/intermedius/medialis. The vasti are only elongated by knee flexion, which is limited to about 120˚ when the calf hits the hamstrings. The vasti cannot be stretched strongly.

Answer:Masseter and temporalis

Why it’s unstretchable: The jaw can only open so far.

Why it’s a dang shame: Jaw tension is epidemic, and trigger points in these muscles cause a wide array of strange face and head pains, including toothaches, headaches, and earaches.

Answer:

 a = 40.937 m / s²

Explanation:

For this exercise let's use the relationship between momentum and momentum variation

          I  = Δp

          F t = m v_f - mv₀

          F = m (v_f -v₀) / t

let's reduce the magnitudes to the SI system

          v_f = 47 km / h (1000m / 1 km) (1h / 3600 s) = 13.056 m / s

          v₀ = - 65 km / h = -18.056 m / s

the negative sign is bearing the speed is west

let's calculate

          F = m (13.056 + 18.056) / 0.76

          F = m 40.937

now we can use Newton's second law

          F = m a

          m 40.937 = m a

          a = 40.937 m / s²

Answer:

B

Explanation:

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evaporation, condensation, precipitation, runoff, collection

Answer:

s orbital

Explanation:

that the answer

Answer:

it will option C ,hope it helps

Answer:

nervous system is your answer

it absorbs all ligj colour except black

Answer:

5.17 x 10^5

Explanation

The correct answer is (b) [tex]5.17*10^{5}m[/tex]

Let us consider an object of mass m on the planet Q.

On planet Q, let the acceleration due to gravity be g = 2.24 m/[tex]s^{2}[/tex]

Mass of the planet is M = [tex]8.96*10^{21} kg[/tex]

Let its radius be R

and the universal gravitational constant G = [tex]6.67*10^{-11} m/kg[/tex]

Gravitational Force acting on the object:

[tex]mg=\frac{GMm}{R^{2} }[/tex]

[tex]R=\sqrt{\frac{GM}{g} } \\R=\sqrt{\frac{6.67*10^{-11}*8.96*10^{21} }{2.24} }\\R=5.17*10^{5} m[/tex] is the radius of the planet Q.

Learn more about gravitational force:

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