Electrons are transferred from oxygen atoms to iron atoms is a redox reaction. Option B is correct.
What is a redox reaction?A redox reaction is a type of chemical reaction in which two species exchange electrons.
Any chemical process in which the oxidation number of a molecule, atom, or ion changes by gaining or losing an electron is known as an oxidation-reduction reaction.
A redox reaction can result in the creation of hydrogen fluoride. The creation of hydrogen fluoride is another example of a redox reaction.
We can evaluate the oxidation and reduction of reactants by breaking down the process. Each hydrogen turns positive after being oxidized and losing two electrons.
Electrons are transferred from oxygen atoms to iron atoms is a redox reaction.
Hence, the option B is correct.
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Answer: D) Electrons are transferred from iron atoms to oxygen atoms
If anyone else needs it
Explanation: the iron is increasing in oxidation number (losing electrons) and oxygen is decreasing in oxidation number (gaining electrons). This tells us that we have oxidation (or rusting) taking place.
Image credit: The Hubble Heritage Team (AURASTSCI/NASA)
To which category does galaxy #2 belong? Why does it belong in this category?
WRITER
Can i ask u a question
how to do the next ques for moreBrainliest me please
A block with initial velocity of 3 m/s slides 9 m across a rough horizontal surface before coming to rest. What is the coefficient of kinetic
friction?
The coefficient of kinetic friction between the block and the horizontal surface is 0.051.
The given parameters;
initial velocity, u = 3 m/sdistance traveled by the block, s = 9 mThe acceleration of the block is calculated as follows;
[tex]v^2 = u^2 + 2(-a)s\\\\v^2 = u^2 - 2as\\\\a = \frac{u^2 - v^2}{2s} \\\\a = \frac{3^2 - 0^2}{2\times 9} \\\\a =0.5 \ m/s^2[/tex]
The coefficient of kinetic friction between the block and the horizontal surface is calculated as follows;
[tex]\mu_k mg = ma\\\\\mu_k = \frac{a}{g} \\\\\mu_k = \frac{0.5}{9.8} \\\\\mu_k = 0.051[/tex]
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3. What happens if an object has a negative acceleration?
Answer:
They will go backwards?
Explanation:
If positive they go forward but is negative they go backwards.
2hrt 20 min +60 sec
Answer:
2hr 21 min
Explanation:
0 days 2 hours 20 minutes 0 seconds
+ 0 days 0 hours 0 minutes 60 seconds
= 0 days 2 hours 21 minutes 0 seconds
A car goes from 60 m/s to 75 m/s in 10 seconds.calculate the car’s acceleration?
Explanation:
Uhhhh here is an example
a=vt. =27 m/s10 s. =2.7 m/s2.
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
Acceleration of the car is ~
[tex] \boxed{1.5 \: \: m/s}[/tex]
[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]
We know that,
Acceleration = rate of change in velocity ~
that is ~
[tex]a = \dfrac{v - u}{t} [/tex]where,
v = final velocityu = initial velocity t = time taken ~now, let's solve ~
[tex]a = \dfrac{75 - 60}{10} [/tex][tex]a = \dfrac{15}{10} [/tex][tex]a = 1.5 \: \: m/s[/tex]Fuses of ________________________
a. same kind are used for different purposes
b. different kind are used for different purposes
c. both of the above are correct
d. none of these
Answer:
C
Explanation:
fuses of same kind can be used for different things, and of different kinds could be used for different things as well.
How much work is done when a force of 33 N pulls a wagon 13 meters?
*Round your answer to the nearest whole number.
Answer:
Work = (force) x (distance)
Work = (33N) x (13m) = 429 N-m = 429 joules
IF the force is in exactly the same direction as the motion of the wagon.
Explanation:
pa mark ng brainliest
if you exert a force on an object, but the object remains stationary as you apply the force, then how much work have you done on the object?
Answer:
no work done
Explanation:
unless you moved the object
When we apply a force on an object, but the object remains at rest when the force is applied, then we have zero work done on the object because the object does not move.
What is Work done?Work done by a force is defined as the product of the displacement and the component of the force exerted by the object in the direction of displacement. Work done is expressed as:
Work done= Force* Displacement
When an object is at rest, there is no external force on it except gravity acting on it, in which case work will be zero because the force acting on it is perpendicular. Thus displacement is zero and if displacement is zero then work done will be zero.
Suppose that displacement is zero then,
W=f×0
Work done is zero
Thus, the work done is zero.
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You and your friend are pushing a box at the same constant speed. You pushed 20 feet in 10 minutes, your friend was pushing for 5 minutes. What distance must she travel so the two of you can travel at the same speed?
Answer:
60 N.C
Explanation:
The box will move in the direction of the push and pull with a force of 60 N. C.
If you and your friend are pushing a box at the same constant speed. You pushed 20 feet in 10 minutes, your friend was pushing for 5 minutes. , then the distance must she travel so the two of you can travel at the same speed would be 30 feet.
What is speed?The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object.
As given in the problem If you and your friend are pushing a box at the same constant speed. You pushed 20 feet in 10 minutes, your friend was pushing for 5 minutes.
The distance traveled by box = 20 + 10
= 30 feets
Thus, the distance must she travel so the two of you can travel at the same speed would be 30 feet.
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A rock on the moon has 0.5kg. It is brought to Earth where the gravitational field is stronger. On Earth, the rock will have:
a) Less mass and same weight
b) The same mass and more weight
c) Less mass and less weight
d) The same mass and same weight
Answer:
Explanation:
It will be B.
The correct answer is the same mass and less weight.
What happens to the weight of an object when it is brought from the moon to the Earth?
The weight decreases. Your weight will be 1/6 of the weight on the moon that you had on Earth. This is because the mass of the moon is less hence the gravitational pull is very low compared to Earth.
What happens to the mass of an object when you take it to the moon?
Therefore, the mass of an object on the Moon remains the same as its mass on Earth. But its weight gets less because the gravity on the moon is less than on the Earth.
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HELPPPPPPPPPPPPPPPPPPP
Answer:
directly proportional
Explanation:
The spark plugs are threaded into the top of each cylinder and provide a place for the spark to jump within the ________.
Answer:
"the spark plug gap"
The plug provides a gap between the input voltage and the ground supplied by the car chassis.
Block 1, of mass m1, moves across a frictionless surface with speed ui. It collides elastically with block 2, of mass m2, which is at rest (vi=0). (Figure 1)After the collision, block 1 moves with speed uf, while block 2 moves with speed vf. Assume that m1>m2, so that after the collision, the two objects move off in the direction of the first object before the collision. What is the final speed vf of block 2?
The conservation of the momentum allows to find the velocity of the second body after the elastic collision is:
[tex]v_f = \frac{2u_o}{1- \frac{m_2}{m_1} }[/tex]
the momentum is defined by the product of the mass and the velocity of the body.
p = mv
The bold letters indicate vectors, p is the moment, m the mass and v the velocity of the body.
If the system is isolated, the forces during the collision are internal and the it is conserved. Let's find the momentum is two instants.
Initial instant. Before crash.
p₀ = m₁ u₀ + 0
Final moment. After crash.
[tex]p_f = m_1 u_f + m_2 v_f[/tex]
The momentum is preserved.
p₀ = [tex]p_f[/tex]
[tex]m_1 u_o = m_1 u_f + m_2 v_f[/tex]
Since the collision is elastic, the kinetic energy is conserved.
K₀ = [tex]K_f[/tex]
½ m₁ u₀² = ½ m₁ [tex]u_f^2[/tex] + ½ m₂ [tex]v_f^2[/tex]
Let's write our system of equations.
[tex]m_1 u_o = m_1 u_f + m_2 v_f \\m_1 u_o^2 = m_1 u_f^2 + m_2 v_f^2[/tex]
Let's solve
[tex]u_f = u_o - \frac{m_2}{m_2} \ v_f \\u_f^2 = u_o^2 - \frac{m_2}{m_1} \ v_f^2[/tex]
[tex]( u_o - \frac{m_2}{m_1} v_f)^2 = u_o - \frac{m_2}{m_1} \ v_f^2 \\u_o^2 - 2 \frac{m_2}{m_1} \ u_o v_f + (\frac{m_2}{m_1} )^2 v_f^2 = u_o^2 - \frac{m_2 }{m_1} \ v_f^2[/tex]
[tex]2 \frac{m_2}{m_1} \ u_o = \frac{m_2}{m_1} v_f \ ( 1 - \frac{m_2}{m_1}) \\v_f = \frac{2u_o}{1-\frac{m_2}{m_1} }[/tex]
In conclusion, using the conservation of momentum, we can find the velocity of the second body after the elastic collision is:
[tex]v_f = \frac{2u_o}{1-\frac{m_2}{m_1} }[/tex]
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1. A stone is thrown vertically upward with velocity of 15 m/s at the same time, 10 m vertically above a second stone is allowed to fall. After what time and at what height do they collide (take g = 10 ms^-2)
Let the ball at the ground be A and that at the top be B.
Assume that you see the motion of A while sitting at B.
You(B) are obviously at rest w.r.t. yourselves. However you(B) and A have the same acceleration in the same direction. Thus acceleration of A w.r.t. you(B) is 0.
Thus, to you, it will appear as if A is travelling towards you with an uniform speed of 20m/s.
Dividing the distance 20m with that speed, we get that A reaches you(B) in 1s.
Now, you have considered these motions and time by assuming you were stationed at B. However, the time taken for A to meet B shouldn't be dependent on which reference frame you assume. Thus, time taken for A and B to collide is 1s.
Since B falls freely, he covers a distance of 1/2(g)(1²)=5 (assuming g = 10m/s²)
Thus, they meet at a height of (20–5)m = 15m from the ground.
how can the motion of an object that is already moving change?
Answer: A force can change the direction in which an object is moving
Explanation: A bigger force of an object will produce a bigger change in motion
a tube of constant circular cross-section, sealed at on end, contains an ideal gas trapped by a cylinder of mercury of length 0.035m. The whole arrangement is in the Earth's atmosphere. The density of mercury is 1.36*10^4, more details provided in the images.
Answer:
P V = N R T ideal gas equation
V = .19 * A volume of enclosed gas
.19 P = N R T / A using volume of enclosed gas
P = Po + Phg pressure on gas = atmospheric (Po) + Phg pressure due to column of mercury
.19 (Po + Phg) = N R T / A which is what was asked
Note Phg = density of Hg * height of Hg * acceleration due to gravity
A tube of constant circular cross-section, sealed at on end, contains an ideal gas trapped by a cylinder of mercury of length 0.035m. There will atmospheric pressure and pressure due to mercury column on trapped gas column having length 0.19m which is given by,
(p₀+pm)×0.190 = nRT÷A.
What is Pressure?Pressure is defined as force per unit area. i.e. P = F/A it gives the force on unit area. its SI unit is Pascal (Pa) which is equal to N/m². is a scalar quantity. its dimensions are [M¹ L⁻¹ T⁻²].
Looking at the figure from top to bottom, we can see the top end of the tube is opened. There is 0.035m of mercury column below which we have a air 0.190m of gas column.
We can feel the physics behind this figure what is happening here, top of the tube is open so there is atmospheric pressure acting on the mercury column and mercury column is above the gas column, it means that both atmospheric pressure and mercury pressure will act on gas column.
i.e. (p₀+pm) = pressure on the air column
this (p₀+pm) is downward pressures, hence gas inside the tube gets compressed due to this pressure because bottom end is closed. it means that back pressure will be created inside the gas in upward direction and both pressures becomes equal at equilibrium.
i.e. (p₀+pm) = back pressure inside the gas column......1)
according to ideal gas equation, PV=nRT
pressure inside the air column is P = nRT÷V
where V is volume of gas that is A×0.190.
P = nRT÷(A×0.190).....( back pressure inside the gas column).
equation 1 becomes
(p₀+pm) = nRT÷(A×0.190).
Hence we get
(p₀+pm) ×0.190= nRT÷(A).
Hence proved.
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Which will be different on the moon than it is on Earth?
weight
mass
Answer:
Below
Explanation:
On the moon, an objects weight will be different than it is on earth. This is because we cannot change the mass of an object, the mass of an object is the measure of matter an object has. However the weight is depended on the gravitational pull of whatever planet you are on. In this case, weight will be lighter on the moon than it is on earth because the moon's gravitational pull is 1.62 m/s^2 while earths is around 9.8 m/s^2.
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if 20 boys can sweep the school compound in 8 minutes, how many boys can sweep it in 10minutes
Answer:
So this is just a ratio/proportion problem
so lets say its in boys:minutes
so in the first scenario
20:8
and we want to find
x:10
So proportion really
20/8=x/10
cross multiply
25
25 boys can sweep it in 10 minutes
Two cars a and b are moving along a straight road in the same direction with velocities of 25km/h and 40km/h . Find the velocity of car b relative to car a
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Which is the BEST example of physics in the body?
A. a single beat of the heart
B. how the circulatory system works
с. balance when the body is standing still
D. the movement of an arm throwing a ball
The best example of physics in the body is the movement of an arm throwing a ball. The correct option is D.
What is physics?Physics is the branch of science that studies the structure of matter and how the universe's fundamental constituents interact.
It investigates objects ranging from the very small to the entire universe using quantum mechanics and general relativity.
Physics is the natural science that investigates matter, its fundamental constituents, its motion and behavior in space and time, as well as the related entities of energy and force.
Physics is one of the most fundamental scientific disciplines, with the primary goal of understanding how the universe functions.
The movement of an arm throwing a ball is the best example of physics in the body.
Thus, the correct option is D.
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Look at the diagram shown below. The reading on ammeter 1 is 0.15 A. What will the reading on ammeter 2 be
There's no way to tell, without knowing the resistance of either X-1 or X-2, or the reading on A3.
What kind of feature results from the convergence of two oceanic plates?
A.
island arcs
B.
massive continental volcanoes
C
rift valleys
D.
tall mountain ranges
Answer:
A
Explanation:
Convergence is pushing them together so C is out of the question.
B and D are wrong because it is an oceanic plate. B and D are for continental plates.
A rock excerts a pressure of 20 N/cm^2 on the ground. what does 20N/cm^2 mean?
A force of __________ acts on each _________ of area
Answer:
A force of 20N acts on each cm^2 of area
the following can increase the amount of friction in the surface, except ______.
a. glue
b. paper
c. lubricant
d. foil
Answer:
c. lubricant..........
Suppose measure the mass of an orange. Then you peel the orange and separate out the slices. If you measure the orange peel and all the slices, will that mass equal the mass of the whole orange?
yes
no
The mass of the orange after it has been cut into pieces will still remain the same as the mass of the whole orange.
Let us recall that the law of conservation of mass states that, mass can neither be created nor destroyed but is converted from one form to another. In accordance with this law of conservation of mass. The mass of the orange must remain the same after it has been cut in pieces.
Hence, If the mass of an orange is measured after it has been cut into pieces, the mass of the orange after it has been cut into pieces will still remain the same as the mass of the whole orange.
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Mercury’s natural state is where the atoms are close to each other but are still free to pass by each other. In which state(s) could mercury naturally exist?
Answer:
Mercury's natural state is where the atoms are close to each other but are still free to pass by each other. In which state(s) could mercury naturally exist?
Liquid is the answer
Explanation:
Two cars A and B are moving along a straight road in the OPPOSITE direction with velocities of 25 km/h and 40 km/h, respectively. Find the velocity of car B relative to car
Answer:
65km/h
Explanation:
Here,
Relative velocity of car moving in different directions with different velocities =Va + Vb
=25+40
=65 km/h
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Which statement describes the flow of heat? Question 8 options: Heat moves from a warmer object to a cooler object. Heat moves from a cooler object to a warmer object. Heat moves from a cooler object to a warmer object. Heat moves only between two cold objects.
Answer:
A
Explanation:
A. Read these sentences carefully. Choose the correct form of adjectives.
1. Solomon is the
king of all.
a wise
b. wiser
c. wisest
2. Yogurt is
than candies.
a delicious b. more delicious c. most delicious
3. Mayon Volcano is the
volcano for me.
a most majestic b. more majestic
c. majestic
4 My father is an
man
a industrious b. more industrious c. most industrious
5. I was the
when my friend graduated with honors.
a happy b. happier
c. happiest
Answer:
1. wisest
2. more delicious
3. majestic (not sure about this one)
4. industrious
5. happiest
which is not a general characteristic of starburst galaxies?
Starburst galaxies is simply known as the rate at which the galaxy is now converting gas into stars. The statement that is not a general characteristic of starburst galaxies is that The "starburst" is thought to be caused by the presence of a supermassive black hole in the galaxy's center.
The starburst galaxy is also regarded as the free quantity of gas with which stars can be formed.They are known to be rare. A starburst is known to be an astrophysical process. It is the process of star formation happening at a rate that is large when compared to the rate that is often observed.
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Which is not a general characteristic of starburst galaxies?
The "starburst" is thought to be caused by the presence of a supermassive black hole in the galaxy's center. The observed features that us to classily a galaxy as a 'starburst" galaxy must be only temporaryphenomena in the galaxy' Supernovae occur so frequently that their effects combine to drive a galactic wind that blows material into intergalactic space. The galaxy's rate of star formation is many times higher than the rate of star formation in the Milky WayLearn more from
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