Answer:
Explanation:
The concept of a new strong nuclear force was introduced. In 1935, the first theory for this new force was developed by the Japanese physicist Hideki Yukawa, who suggested that the nucleons would exchange particles between each other and this mechanism would create the force.
A current of 2.0 A flows through a flashlight bulb when it is connected
across the terminals of a 5 V battery. What is the energy dissipated by this
bulb during 1 hour of continuous working?*
Using Joules law
[tex]\\ \sf\Rrightarrow H=VIt[/tex]
[tex]\\ \sf\Rrightarrow H=5(2)(1)[/tex]
[tex]\\ \sf\Rrightarrow H=10Kwh[/tex]
what has to increase in order for an object to accelerate?
Answer:
Answer: B. Explanation: For an object to accelerate the force on it must be increased. According to Newton's second law of motion.
Explanation:
I do Accelerate to good luck
Can someone help me with this physics question? I don't know which answer is correct.
3. Distance is a quantity that is always a vector.
B.
A 2,000 kg car, initially traveling at a speed of 15 m/s, is accelerated by a constant force of 10,000 N for 3 seconds. The new speed of the car is
Answer:
The new speed of the car is 30 m/s.
Hope you could get an idea from here.
Doubt clarification - use comment section.
The frequency of a wave is 4hz. If the wavelength is 2m how fast is the water moving?
I need the Formula,Known,Substitute & Solve Answer with Units
Answer:
This is the answer that I got
Explanation:
Hope it is right.
define nuclear energy
Answer:
Nuclear energy is the energy stored in atoms that can produce electricity.
Hope that helps. x
How do you un rewrap something?
what planets experience an eclipse from the sun
Answer:
Earth
Explanation:
The sun and the moon come together and they seem like one bonded.
The velocity of an ocean wave is 5m/s. The distance between crests is 3m. What is the frequency of the wave
I need the Formula,Known,Substitute & Solve Answer with Units
Answer:
1.67m
5m/s
Explanation:
Wavelength of the wave = 3m
Speed of the wave = 5m/s
The distance between crest and the adjacent trough of water waves is known as the wavelength of a wave.
To find the frequency ;
V = f∧
V is the speed of the wave
f is the frequency
∧ is the wavelength
Insert the parameters and find the frequency;
f = V/ ∧ = 5 / 3 = 1.67Hz
The rate at which the wave passed a given point is the speed of the wave and it is 5m/s
How much power is used in question #2 if the power time was 100secs
I really need the Formula, substitute & solve , answer with units.
Answer:
I just put a random number for the work
Explanation:
I hope it is ok.
what are the three elements that can be used to make a magnet?
Answer:
Iron, cobalt, and nickel are the only three naturally occurring elements that are magnetic.
Explanation:
hope it helps
correct me if I'm wrong thank you
brainliest please
Answer:
The three elements that can be used to make a magnet are :
Aluminum, nickel and cobalt
SOMEONE, PLEASE HELP ME AS FAST AS YOU CAN, I WOULD GIVE MORE POINTS BUT THIS IS THE REST OF MY POINT, PLEASE SOMEONE WHO IS SUPER KIND HELP ME.
Answer:
1. The formula for speed is speed = distance ÷ time. To work out what the units are for speed, you need to know the units for distance and time
2. 36÷4= 9
(formula) Speed = distance ÷ time
3. Meter (M) centimeter (cm) kilometers (km)
4. Seconds , Hour, Minute
5. 65÷13=5 (object A)
125÷ 25= 5 (object B)
their both Equal of the amount of speed, so they are travelling at the same speed
Hope I helped
what is the capaceter
Answer:
capacitor, device for storing electrical energy, consisting of two conductors in close proximity and insulated from each other. A simple example of such a storage device is the parallel-plate capacitor.
Explanation:
Hope it's help
please brainless me :)
Hope you could get an idea from here.
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Which design of the walls would be most desirable help avoid echoes?
A
They should use bumpy walls for all four sides.
B
They should use bumpy walls for only one side.
С
They should use smooth walls for all four sides.
D
They should use smooth walls for only one side.
Answer:
a
Explanation:
because the sound wont bounce off
BRAINLIST!!!
Two metallic balls A and B carry the charges QA= 16×10^-9C and QB=-8×10^-9C.
We fixed balls A and B 5cm apart. Given e=1.6×10^-9C and k=9×10^9 S.I unit.
1) identify the ball that has excess of electrons.
2) calculate the number of deficit and excess of electrons on both balls.
3) calculate the force exerted by A on B.
What is the change in velocity of a 1068 kg truck that experiences an impulse of 440 N ⋅ s? Include 2 decimal places in your answer.
Answer:
try 2.4136 as an answer/ good luck
yes that.
Read the excerpt below and then answer the question that follows:
The Book of Dragons
Chapter III The Deliverers of Their Country, an excerpt
By E. Nesbit
It all began with Effie's getting something in her eye. It hurt very much indeed, and it felt something like a red-hot spark—only it seemed to have legs as well, and wings like a fly. Effie rubbed and cried—not real crying, but the kind your eye does all by itself without your being miserable inside your mind—and then she went to her father to have the thing in her eye taken out. Effie's father was a doctor, so of course he knew how to take things out of eyes.
When he had gotten the thing out, he said: "This is very curious." Effie had often got things in her eye before, and her father had always seemed to think it was natural—rather tiresome and naughty perhaps, but still natural. He had never before thought it curious.
Effie stood holding her handkerchief to her eye, and said: "I don't believe it's out." People always say this when they have had something in their eyes.
"Oh, yes—it's out," said the doctor. "Here it is, on the brush. This is very interesting."
Effie had never heard her father say that about anything that she had any share in. She said: "What?"
The doctor carried the brush very carefully across the room, and held the point of it under his microscope—then he twisted the brass screws of the microscope, and looked through the top with one eye.
"Dear me," he said. "Dear, dear me! Four well-developed limbs; a long caudal appendage; five toes, unequal in lengths, almost like one of the Lacertidae, yet there are traces of wings." The creature under his eye wriggled a little in the castor oil, and he went on: "Yes; a bat-like wing. A new specimen, undoubtedly. Effie, run round to the professor and ask him to be kind enough to step in for a few minutes."
"You might give me sixpence, Daddy," said Effie, "because I did bring you the new specimen. I took great care of it inside my eye, and my eye does hurt."
The doctor was so pleased with the new specimen that he gave Effie a shilling, and presently the professor stepped round. He stayed to lunch, and he and the doctor quarreled very happily all the afternoon about the name and the family of the thing that had come out of Effie's eye.
But at teatime another thing happened. Effie's brother Harry fished something out of his tea, which he thought at first was an earwig. He was just getting ready to drop it on the floor, and end its life in the usual way, when it shook itself in the spoon—spread two wet wings, and flopped onto the tablecloth. There it sat, stroking itself with its feet and stretching its wings, and Harry said: "Why, it's a tiny newt!"
The professor leaned forward before the doctor could say a word. "I'll give you half a crown for it, Harry, my lad," he said, speaking very fast; and then he picked it up carefully on his handkerchief.
"It is a new specimen," he said, "and finer than yours, Doctor."
It was a tiny lizard, about half an inch long—with scales and wings.
So now the doctor and the professor each had a specimen, and they were both very pleased. But before long these specimens began to seem less valuable. For the next morning, when the knife-boy was cleaning the doctor's boots, he suddenly dropped the brushes and the boot and the blacking, and screamed out that he was burnt.
And from inside the boot came crawling a lizard as big as a kitten, with large, shiny wings.
"Why," said Effie, "I know what it is. It is a dragon like the one St. George killed."
And Effie was right. That afternoon Towser was bitten in the garden by a dragon about the size of a rabbit, which he had tried to chase, and the next morning all the papers were full of the wonderful "winged lizards" that were appearing all over the country. The papers would not call them dragons, because, of course, no one believes in dragons nowadays—and at any rate the papers were not going to be so silly as to believe in fairy stories. At first there were only a few, but in a week or two the country was simply running alive with dragons of all sizes, and in the air you could sometimes see them as thick as a swarm of bees. They all looked alike except as to size. They were green with scales, and they had four legs and a long tail and great wings like bats' wings, only the wings were a pale, half-transparent yellow, like the gear-boxes on bicycles.
Based on the rising action in the bolded paragraphs, what do we know about Daddy? (5 points)
He is calm and curious.
He is angry and upset.
He is hysterical.
He is uninterested and bored.
believe in fairy stories. At first there were only a few, but in a week or two the country was simply running alive with dragons of all sizes, and in the air you could sometimes see them as thick as a swarm of bees. They all looked alike except as to size. They were green with scales, and they had four legs and a long tail.
Explanation:
YOUR WELCOME :)
Answer:
its "calm and curious"
Explanation:
hope tis helps!!!
What is the kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4 m/s? (Formula: ) 3 J 6 J 12 J 24 J.
The kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4m/s is 6J.
HOW TO CALCULATE KINETIC ENERGY:
The kinetic energy of a moving body can be calculated by using the following formula:
K.E = ½mv²
Where;
K.E = kinetic energy (J)m = mass (kg)v = velocity (m/s)According to this question, a toy truck has a mass of 0.75 kg and a velocity of 4 m/s. The kinetic energy is calculated as follows:
K.E = ½ × 0.75 × 4²
K.E = 8 × 0.75
K.E = 6J
Therefore, the kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4m/s is 6J.
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What type of bond is found in pure gold?
A) Metallic
B) Ionic
C)Covalent
D)Diatomic
The type of bond found in pure gold is metallic bonding, indicated by metallic bonds. Therefore option A is correct.
Metallic bonding occurs between metal atoms, such as gold, and is characterized by the sharing of electrons among a sea of delocalized electrons.
In metallic bonds, the valence electrons of metal atoms are not strongly bound to any particular atom but are free to move throughout the metal lattice.
This sharing of electrons gives rise to properties such as high electrical and thermal conductivity, malleability, and ductility, which are characteristic of metals like gold.
Unlike ionic or covalent bonds, metallic bonds do not involve the transfer or sharing of electrons between different elements.
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The strings in a compound bow behave approximately like a
spring. A bowstring is pulled back 0.60 m with a maximum force of
267 N (AKA a 60-pound draw weight) to shoot an 18 g arrow.
Assume energy is conserved.
a) At what speed would the arrow be launched? (Note: W = FΔd uses the average
force while F = -kx uses the instantaneous force.)
The speed at which the arrow would be launched is 133.42 m/s
The work-energy theorem asserts that the net work done applied by the forces on a particular object is equivalent to the change in its kinetic energy.
The equation for the work-energy theorem can be computed as:
[tex]\mathbf{W =\Delta K.E}[/tex]
[tex]\mathbf{F\Delta x =\dfrac{1}{2} mv^2}[/tex]
where;
Force (F) = 267 Ndistance Δx = 0.60 mmass (m) = 18 gspeed (v) = ???From the above equation, let make speed(v) the subject of the formula:
∴
[tex]\mathbf{v = \sqrt{\dfrac{2(F \Delta x)}{m}} }[/tex]
[tex]\mathbf{v = \sqrt{\dfrac{2(267 \times 0.60)}{0.018}} }[/tex]
v = 133.42 m/s
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How would you describe the motion of a transverse wave
Which would ba another example of newtons first law?
What happens to all light bulbs in a series circuit when one burns out?
Answer:
In a series circuit, every device must function for the whole circuit to be complete. One bulb burning out in a series circuit breaks the circuit. Even if you take a bulb out, the entire circuit will still stop operating. There is no closed-loop path for the current to flow through the circuit. For the whole series circuit to be complete, and on, every bulb must be working.
Explanation:
what is the second longest wavelength for a standing wave on a wire with one fixed end and one open end that is 3.0 m long?
A cheetah runs at an average speed of 60mph. find the distance it runs in 30 s
Answer:60mph means it runs every minute.
Explanation: because it makes sense.
Answer:
2640 ft, or 1/2 mile
Explanation:
Recognizing that 30 s = 0.5 min, we can convert the units like this.
distance = speed × time
distance = (60 mi/h) × (1 h/(60 min)) ×(0.5 min) = 0.5 mi
In feet, that is ...
(5280 ft/mi)(0.5 mi) = 2640 ft
A cheetah runs 1/2 mile, or 2640 feet in 30 s.
is atom on the offficial repository of ubuntu ?
Answer:
Atom, the cross-platform, open source code editor developed by Github, has become quite popular thanks to its plug-ins and embedded Git Control. ... There are, however, official Atom repositories for some Linux distributions, like Ubuntu, Debian, Fedora, Red Hat, CentOS, and open.
Classify the statement below as either Speed or Velocity?
A jeep was driving 40 mph
heading to the grocery store.
Answer:
Hello There!
It is Speed.
[tex]\Large\bold\red{Reason}[/tex]
Because in the question it is said that at which speed car is travelling.
Speed is a scalar quantity.
If it is velocity then first know this that it is a vector quantity.
It must include both magnitude and direction.
If it is velocity then it would be 40 mph east or west or north or south.
I hope it is helpful to you...Cheers!_____________a truck in a traffic circle travels in a circular path at constant speed v0 while passing through region x of the circle, as shown in figure 1 above. a diagram representing the forces exerted on the truck in region x is shown in figure 2. at a later time a car with less mass than the truck passes through region x at the same speed and the same distance from the center of the traffic circle as the truck. the coefficient of friction between the car’s tires and the ground is the same as that for the truck’s tires and the ground. which of the following diagrams could represent the forces exerted on the car in region x compared to the truck in region x ? assume that the length of each arrow is proportional to the magnitude of the force represented by the arrow.
The Diagram that represents the forces exerted on the car in region x when compared to the truck in region X is : Diagram C
Given that the mass of the car is less than the mass of the truck the force due to gravity will be greater on the truck than it could be on the car
i.e. | Fg |car < | Fg | truck
also : | Fₙ | car < | Fₙ | truck
Since the gravitational force on the car is less than the gravitational force on the truck
| Ff | car < | Ff | truck
where : Ff = frictional force
Fg = force due to gravity
Fn normal force
Therefore from the diagrams attached below the correct diagram that represents the forces exerted on the car in region x when compared to the truck in region X is : Diagram C.
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Attached below is the missing data related to your question
can someone explain please?
Hi there!
We can begin by solving for the velocity in which the ball was thrown at using the following:
[tex]v_f^2 = v_i^2 + 2ad[/tex]
At the top of the trajectory, the ball's velocity is equal to 0 m/s, so:
[tex]0 = v_i^2 + 2ad\\\\vi^2 = 2ad \\\\[/tex]
'a' = acceleration due to gravity and 'd' is the max height, so:
[tex]v_i^2 = 2(10)(5)\\\\v_i^2 = 10 m/s[/tex]
Now, we can use the same equation to calculate the final speed at 4.5 m. Remember, the acceleration is NEGATIVE in this instance (taking the negative direction to be in the direction of gravity).
[tex]v_f^2 = 10^2 - 2(10)(4.5)[/tex]
[tex]v_f^2 = 10^2 - 2(10)(4.5)\\\\v_f^2 = 100 - 90 \\\\v_f^2 = 10 \\\\v_f = \boxed{3.1 m/s}[/tex]
If the action force is the swimmer pushing water in the leftward direction, what is the reaction force?
PLEASE ANSWER
CORRECTLY PLS
Answer:
The reaction force is the water pushing the swimmer in the rightward direction.
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