Chemistry College

What kind of waste is shown in the photograph?
A. Composted waste
B. E-waste
C. Hazardous waste
O D. Septic system waste

What Kind Of Waste Is Shown In The Photograph?A. Composted WasteB. E-wasteC. Hazardous WasteO D. Septic

Answers

Answer 1
it should be C. hazardous waste
hope this helps!!

Related Questions

wich strong nucleophil h2s or water??and why??

Answers

According to my notes, nucleophilicity order is directly proportional to basicity order in an aprotic medium, and is inversely proportional to basicity order in protic medium. And H2O is a stronger base than H2S, so it should be the strong nucleophile, but the answer is given as H2S is the stronger nucleophile.

hope this helped, good luck <3

A moving 10 kilogram object has 20 Joules of kinetic energy. What is its velocity?
4 m/s
2 m/s
10 m/s
200 m/s

Answers

It’s the second one you’re welcome

how many ions does magnesium phosphite have? how many of those are anions? please explain thought process.

Answers

Answer:

We can simply refer to the cation in the ionic compound as magnesium. Phosphorus, Pstart text, P, end text, is a group 15 element and therefore forms 3- anions.

Explanation:

Because it is an anion, we add the suffix -ide to its name to get phosphide as the name of the ion.

All chemical reactions use reactants in a specific proportion or stoichiometry to regulate the amount of products produced. The __________ reactant is consumed completely during the reaction but some of the __________ reactant is left over.
a. limiting, excess
b. excess, limiting
c. proportional, ideal
d. chemical, stoichiometric

Answers

Answer: The answer is a. limiting, excess. I took the test.

Explanation:

How many moles of magnesium nitrate are produced when he reacts 0.34 moles of nitric acid with excess magnesium?

Answers

Jeirurbekwiufbekwididjdeu


A gas occupies a volume of 2.4 L at 0.14 ATM. What volume will the gas occupy at 0.84 ATM?

Answers

Answer:

0.4 L

Explanation:

Calculate by using Boyle's Law P₁V₁=P₂V₂

(0.14atm)(2.4L) = (0.84atm)(V₂)

0.336 atmL = (0.84atm)(V₂)

V₂ = 0.336 atmL/0.84atm

V₂ = 0.4 L

4. What is the molarity of a solution that contains 65g of sodium nitrate in 750? ml of solution?

Answers

Answer:

1.02 M

Explanation:

Solution contains 65g of sodium nitrate

Volume of solution = 750 ml

Now, Molar mass of sodium nitrate from online values = 84.9947 g/mol

Thus, it means 84.9947 g/mol of sodium nitrate dissolved in 1000 mL of water will be equal to 1 M molarity.

Thus;

Molarity of solution = (65/750) × (1000) × (1/84.9947) = 1.02 M

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