A body with mass 2 kg absorbs heat 418.4J when its temperature raises from 293K to 343K . What is the specific heat of the body?
Answer:
C M (change in T) = heat absorbed thermal equation for heat gained
C = 418.4 J / (2 kg * 50 deg K) = 4.184 J / kg * deg K specific heat
Note: 1 gm =.001 kg
So C = .004184J / gm * deg K
Also, 1 J = .239 cal so in conventional terms
C = .001 cal / gm deg K (very low, water would be 1 cal / gm deg C
5
A cyclist travels 125 km in 5 hours. How fast is the cyclist moving?
Answer:
25 km/h
Explanation:
speed=distance÷time
125÷5=speed
125÷5=25 (then add units)
substances found in the food that the body needs
Answer:
There are six major nutrients: Carbohydrates (CHO), Lipids (fats), Proteins, Vitamins, Minerals, Water.
Explanation:
the mass of the car is 1400 kg. The car , initially at rest is moved along a level road by a resultant force of 3500N.The car reaches speed of 30m/s ... calculate the average acceleration and use newtons seconds law , F=m×a
Answer:
2.5m/s²
Explanation:
Given parameters:
Mass of car = 1400kg
Resultant force = 3500N
Speed = 30m/s
Unknown:
Average acceleration = ?
Solution:
According to the Newton's second law of motion:
Force = mass x acceleration
Now;
3500 = 1400 x acceleration
Acceleration = [tex]\frac{3500}{1400}[/tex] = 2.5m/s²
A dog playing fetch starts at rest and accelerates at 4.5m/s2 north. It takes the dog 7 seconds to catch the ball. What was the speed of the dog when he caught the ball?
Answer:
31.5m/s
Explanation:
Given the following
acceleration a = 4.5m/s²
Time t= 7secs
Required
Final speed v = ?
Using the equation of motion
v = u+at
v = 0+4.5(7)
v = 31.5m/s
Hence the speed of the dog is 31.5m/s
velocity of sound in solid is more than that in liquid.why?
Velocity of sound travels faster in solids than in liquids, and faster in liquids than in gases because "the density of solids is higher than that of liquids, meaning that the particles are closer together."
Answer:
Explanation:
Due to the fact that sound is caused by vibrations, it's more noticeable in liquid because the vibrations may cause ripples in the liquid
An empty airplane with a mass of 200,000 kg must have a speed of 82 m/s to achieve takeoff. Once it is fully loaded, the airplane has a mass of 350,000 kg. It has 3200 m of runway. a) How much force is needed to get the full airplane safely in the air?
b) How much runway would the empty airplane use if its engines generated the same force?
Answer:
a) A force of 367718.75 newtons is needed to get the full airplane safely in the air.
b) The empty airplane would need a runway of 1828.571 meters.
Explanation:
a) This problem can be solved by using the Work-Energy Theorem, which states that work needed by the airplane to get minimum speed is equal to its change in translational kinetic energy, both measured in joules. The resulting formula is presented below:
[tex]F\cdot \Delta s = \frac{1}{2}\cdot m \cdot (v_{f}^{2}-v_{o}^{2})[/tex] (1)
Where:
[tex]F[/tex] - Minimum net force, measured in newtons.
[tex]\Delta s[/tex] - Runway length, measured in meters.
[tex]m[/tex] - Mass of the airplane, measured in kilograms.
[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds of the airplane, measured in meters per second.
If we know that [tex]m = 350000\,kg[/tex], [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]v_{f} = 82\,\frac{m}{s}[/tex] and [tex]\Delta s = 3200\,m[/tex], then the minimum net force needed by the airplane to get itself safely in the air:
[tex]F = \frac{m\cdot (v_{f}^{2}-v_{o}^{2})}{2\cdot \Delta s}[/tex]
[tex]F = \frac{(350000\,kg)\cdot \left[\left(82\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right]}{2\cdot (3200\,m)}[/tex]
[tex]F = 367718.75\,N[/tex]
A force of 367718.75 newtons is needed to get the full airplane safely in the air.
b) If we know that [tex]m = 200000\,kg[/tex], [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]v_{f} = 82\,\frac{m}{s}[/tex] and [tex]F = 367718.75\,N[/tex], then the length of the runway is:
[tex]\Delta s = \frac{m\cdot (v_{f}^{2}-v_{o}^{2})}{2\cdot F}[/tex]
[tex]\Delta s = \frac{(200000\,kg)\cdot \left[\left(82\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right]}{2\cdot (367718.75\,N)}[/tex]
[tex]\Delta s = 1828.571\,m[/tex]
The empty airplane would need a runway of 1828.571 meters.
Questions
1 A stone falls from rest from the top of a high tower. Ignore
air resistance and take g = 10 m/s2
a What is its velocity after
() 15
(ii) 25,
(iii) 35,
(iv) 5s?
b How far has it fallen after
(i) 15,
(ii) 2s,
(iii) 35,
(iv) 5s?
2 An object falls from a hovering helicopter and hits the
ground at a speed of 30 m/s. How long does it take the
object to reach the ground and how far does it fall? Sketch
a velocity-time graph for the object (ignore air resistance).
Answer:
I am sorry i don't do physics
describe four uses of the heating effect of electricity in the home.
Answer:
Explanation:
Electric Bulb: In an electric bulb, the filament of bulb gives light because of heating effect of electricity. The filament of bulb is generally made of tungsten metal; having melting point equal to 3380°C.
Electric iron: The element of electric iron is made of alloys having high melting point. Electric heater and geyser work on the same mechanism.
Electric fuse: Electric fuse is used to protect the electric appliances from high voltage; if any. Electric fuse is made of metal or alloy of metals, such as aluminium, copper, iron, lead, etc. In the case of flow of higher voltage than specified, fuse wire melts and protects the electric appliances.
Explain how we perceive objects as they are
pls help, I will mark u as the brainliest
The lens present in our eyes forms a real and inverted image on the retina. The optic nerves carry this image from the retina to the brain. The brain then processes this info to generate clear and virtual images. That's how we perceive objects as they are.
When the image is formed on our "Retina", the light sensitive cells of our Retina gets activated and they generate electric signals. These signals are send to brain by the optic nerves. The brain interprets the electric signals in such a way that we see an image in erect and of the same size as the object... MÅRK ÅS THE ẞRÅÏÑLÏËST.......
A 5.0 kg chunk of putty moving at 10m/s collides and sticks to a 7.0 kg bowling ball that is initially at rest.What is the total momentum of the bowling ball and the putty after they collide?
Answer:
Total momentum = 50kgm/s
Explanation:
Given the following data;
Mass, M1 = 5kg
Mass, M2 = 7kg
Velocity, V1 = 10m/s
Velocity, V2 = 0m/s (since it's at rest).
To find the total momentum;
Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.
Mathematically, momentum is given by the formula;
[tex] Momentum = Mass * Velocity [/tex]
The law of conservation of momentum states that the total linear momentum of any closed system would always remain constant with respect to time.
Total momentum = M1V1 + M2V2
Substituting into the equation, we have;
Total momentum = 5*10 + 7*0
Total momentum = 50 + 0
Total momentum = 50 kgm/s
Therefore, the total momentum of the bowling ball and the putty after they collide is 50 kgm/s.
someone please help with this
Answer:
The new force is 2/3 of the original force
Explanation:
Coulomb's Law
The electrical force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.
Written as a formula:
[tex]\displaystyle F=k\frac{q_1q_2}{d^2}[/tex]
Where:
[tex]k=9\cdot 10^9\ N.m^2/c^2[/tex]
q1, q2 = the objects' charge
d= The distance between the objects
Suppose the first charge is doubled (2q1) and the second charge is one-third of the original charge (q2/3). Now the force is:
[tex]\displaystyle F'=k\frac{2q_1*q_2/3}{d^2}[/tex]
Factoring out 2/3:
[tex]\displaystyle F'=\frac{2}{3}k\frac{q_1*q_2}{d^2}[/tex]
Substituting the original force:
[tex]F'=\frac{2}{3}F[/tex]
The new force is 2/3 of the original force
3. The velocity of sound is 332 m/s. Answer the following questions:
i) What is the minimum and maximum frequency of sound which
is heard to the human ear?
ii) What is the wavelength of the shortest and longest waves heard
to the human ear?
Answer:
20 Hz, 20000 Hz
0.0166 m, 16.6 m
Explanation:
The minimum frequency that a human ear can hear is 20 Hz
The maximum frequency that a human ear can hear is 20000 Hz.
v = Velocity of sound = 332 m/s
Wavelength is given by
[tex]\lambda=\dfrac{v}{f}\\\Rightarrow \lambda=\dfrac{332}{20}\\\Rightarrow \lambda=16.6\ \text{m}[/tex]
The longest wavelength that can be heard by the human ear is 16.6 m
[tex]\lambda=\dfrac{332}{20000}\\\Rightarrow \lambda=0.0166\ \text{m}[/tex]
The shortest wavelength that can be heard by the human ear is 0.0166 m.
what are the importance of gravitation
Answer:
Gravity is very important to us. We could not live on Earth without it. The sun's gravity keeps Earth in orbit around it, keeping us at a comfortable distance to enjoy the sun's light and warmth. It holds down our atmosphere and the air we need to breathe.
Answer:
Newton's universal law of gravitation explains the attractive force between any two objects which have mass.It explains how we are able to stand on earth, why a body thrown up falls to the ground, why planets revolve around the sun and why the moon revolves around the earth, and so on.This law says that as the distance between two objects increases their force of attraction decreases. This explains why we are not pulled towards a distant star even though it is more massive than the Earth.This law leads to the derivation of an expresion for the acceleration due to gravity...With the help of gravitation, we can understand the force experience by various planets , stars etc. with each other.This law makes us understand why the planets revolve around the sun and why satellite revolve around the planets.Gravitation explains us how the planets are held by the sun and why don't they fall on it.It can also explain how tides are formed on earth. (Tides are due to the gravitational forces of the sun and the moon).Example:
Astronauts reach a distant planet and find it takes eight times as much force to lift objects there than it does on Earth. What is the acceleration due to gravity on this planet?
On this planet the force of gravity is eight times larger. Since the masses of objects are a fundamental property of those objects, they cannot change, that means the value of g must be eight times larger as well:
[tex]8F_{grav}=m(8g)8F[/tex]
[tex]=m(8g)[/tex]
The value of g on Earth is 9.8 m/s2, so 8 × 9.8 m/s2 = 78.4 m/s2.
A 50Kg girl jumps off a 5-meter-high diving board. What is her kinetic energy right before she
hits the water?
A. 0 J
B. 25 J
C. 1225 J
D. 2450 J
Answer:
D is the correct answer
Explanation:
Ek=m*g*h=50*9.8*5=2450
The kinetic energy right before she hits the water is 2450J. So, the correct option is D.
What is Kinetic energy?Kinetic energy is defined as the energy that is due to the motion of an object. If we want to accelerate an object, we must apply a force, by applying a force we need to do work. After the work is done, energy has been transferred to the object, and the object will continue to move with a new constant speed.
A 50Kg girl jumps off a 5-meter-high diving board.
We need to find the kinetic energy of the girl before she enters the water which means that the kinetic energy becomes equal to the potential energy such that,
P.E.=K.E. = mgh
where, m=mass of the object
g= acceleration due to gravity [tex](9.8m/s^2)[/tex]
h= height
So, K.E= 50* 9.8*5 = 2450 J
Thus, the kinetic energy right before she hits the water is 2450J. So, the correct option is D.
Learn more about Kinetic energy, here:
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Can anyone help me with these questions? TIA!
(Don’t actually answer please! :) )
[tex]\huge\text{Graphs:}[/tex]
The graph of
• The I-V for Ohmic Metal wire conductor at constant temperature always shows a straight line between the Current(I) plotted at Y axis and Voltage(V) plotted at X axis. Picture 1
• The I-V graph for Diode shows that first the current is zero but as we increase the potential difference(voltage), it results in the increase in the current. Picture 2
_____________________________________ Question 8:[tex]\Large\textbf{Diode:}[/tex]
A diode is a device that allows current to flow in only one direction.
[tex]\Large\textbf{Forward and Reverse Biasing:}[/tex]
Forward Bias, When a diode is forward bias (a voltage in the "forward" direction) then the P-side of the diode is attached to the positive terminal and N-side is fixed to the negative side of the battery which is connected, current flows freely through the device. The forward bias decreases the thickness of potential barrier(The potential barrier barrier in which the charge requires additional force for crossing the region)
Reverse Bias, When a diode is Reverse bias(a voltage in the "backward direction) then the P-side of the diode is connected to the negative terminal and N-side is connected to the positive terminal of the battery which is connected. The reverse bias increases the thickness of the potential barrier resulting in the flow of no current.
[tex]\Large\textbf{Answer to the Question "Resistance"}[/tex]
The Forward bias decreases the resistance of the diode whereas the reversed bias increases the resistance of the diode. As in forward biasing the current is easily flowing through the circuit whereas reverse bias does not allow the current to flow through it.
_____________________________________ Best Regards, 'Borz'A jet aircraft is traveling at 262 m/s in horizontal flight. The engine takes in air at a rate of 85.9 kg/s and burns fuel at a rate of 3.92 kg/s. The exhaust gases are ejected at 921 m/s relative to the aircraft. Find the thrust of the jet engine. Answer in units of N Find the delivered power. Answer in units of W.
Answer:
[tex]F_T=60132.52N[/tex]
[tex]P=15814852.76W[/tex]
Explanation:
From the question we are told that
Velocity of aircraft [tex]V=263m/s[/tex]
Engine air intake rate [tex]\triangle M_a=85.9kg/s[/tex]
Fuel burn rate [tex]\triangle M_f =3.92kg/s[/tex]
Velocity of exhaust gas [tex]V_e =921m/s[/tex]
Generally the Mass change rate of Rocket is mathematically given by
[tex]\triangle M = \triangle M_a+\triangle M_f[/tex]
[tex]\triangle M= 85.9+3.92[/tex]
[tex]\triangle M=89.82kg/s[/tex]
Generally the Trust of the rocket is given mathematically by
[tex]F_T=(\triangle M *V_e)-(dM_a/dt)*(V)[/tex]
[tex]F_T=(89.82 *921)-(85.9)*(263)[/tex]
[tex]F_T=60132.52N[/tex]
Generally the Rocket's delivered power is mathematically given by
Delivered power P
[tex]P=V*F_T[/tex]
[tex]P=263*60132.52N[/tex]
[tex]P=15814852.76W.[/tex]
A car starts from rest and accelerates at a constant rate of 3.5 m/s2. What is the car’s velocity after the car has traveled 800 m?
Answer:
Attached is the answer
Explanation:
The car’s velocity after the car has traveled 800 m is 74.83 m/sec.
What is velocity?When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.
Using equation of motion, initial velocity u = 0 and acceleration a = 3.5 unit and distance travelled is 800 m.
v² = u² + 2as
v² = 0 + 2*3.5*800
v² = 5600
v = 74.83 m/sec
The car’s velocity after the car has traveled 800 m is 74.83 m/sec.
To learn more about velocity refer to the link
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A negative charge of 20 x 10-6C and another charge of 15 x 10-6C are separated by as distance of 0.7 m.
What is the magnitude of the electrical force between the two charges:
answer to the closest 0.1 N
Answer:
Approximately [tex]5.5\; \rm N[/tex], assuming that the volume of these two charged objects is negligible.
Explanation:
Assume that the dimensions of these two charged objects is much smaller than the distance between them. Hence, Coulomb's Law would give a good estimate of the electrostatic force between these two objects regardless of their exact shapes.
Let [tex]q_1[/tex] and [tex]q_2[/tex] denote the magnitude of two point charges (where the volume of both charged object is negligible.) In this question, [tex]q_1 = 20 \times 10^{-6}\; \rm C[/tex] and [tex]q_2 = 15 \times 10^{-6}\; \rm C[/tex].
Let [tex]r[/tex] denote the distance between these two point charges. In this question, [tex]r = 0.7\; \rm m[/tex].
Let [tex]k[/tex] denote the Coulomb constant. In standard units, [tex]k \approx 8.98755\times 10^{9}\; \rm kg \cdot m^{3}\cdot s^{-2}\cdot C^{-2}[/tex].
By Coulomb's Law, the magnitude of electrostatic force (electric force) between these two point charges would be:
[tex]\begin{aligned}F &= \frac{k \cdot q_1 \cdot q_2}{r^{2}}\end{aligned}[/tex].
Substitute in the values and evaluate:
[tex]\begin{aligned}F &= \frac{k \cdot q_1 \cdot q_2}{r^{2}}\\ &\approx 8.98755 \times 10^{9}\; \rm kg \cdot m^{3}\cdot s^{-2}\cdot C^{-2} \\ &\quad \times 20\times 10^{-6}\; \rm C\\ &\quad \times 15\times 10^{-6}\; \rm C \\ &\quad \times \frac{1}{{(0.7\; \rm m)}^{2}}\\ &\approx 5.5\; \rm N \end{aligned}[/tex].
A cart falls from a track with an acceleration of 10 m/s2 (which is always the acceleration due to gravity). If it falls for 9 seconds before hitting the ground, what is it’s velocity at impact? (show work plz)
Answer:
90m/s
Explanation:
Given parameters:
Acceleration = 10m/s²
Time of fall = 9s
Unknown:
Final velocity = ?
Solution:
We can assume that the cart falls from rest.
Initial velocity = 0m/s
Using
v = u + gt
v is the final velocity
u is the initial velocity
g is the acceleration due to gravity
t is the time
v = 0 + 10 x 9 = 90m/s
Answer:
90m/s
Explanation:
Look at the atoms below
a. Atom W: 9 protons and 9 neutrons
b. Atom X: 8 protons and 9 neutrons
c. Atom Y: 9 protons and 9 neutrons
d. Atom Z: 9 protons and 10 neutrons
Which ones below are isotopes of each other and why?
element z are isotopes because number of netron are different and number of protons are same
What is the gravitational force of attraction between a 55 kg boy and a 40 kg girl if they are 0.10 meters apart?
Answer:
[tex]1.5\cdot 10^{-5}\:\mathrm{N}[/tex]
Explanation:
Newton's Law of Gravitation is given as:
[tex]F=G\frac{m_1m_2}{r^2}[/tex], where [tex]G[/tex] is gravitational constant [tex]6.67\cdot 10^{-11}[/tex] and [tex]r[/tex] is the distance between their centers of mass.
Therefore, the gravitational force between them is:
[tex]F=6.67\cdot 10^{-11}\frac{55\cdot40}{0.1^2}= \fbox{$1.5\cdot 10^{-5}\:\mathrm{N}$}[/tex] (two significant figures).
Calculate speed...
D=40 m
T=10 s
a
40 m/s
b
400 m/s
c
4 m/s
Answer:
c
Explanation:
speed=distance÷time
40÷10=4
Determine the force of gravitational attraction between the earth (m = 5.98 x 1024 kg) and a 70-kg physics student if the student is in an airplane at 40000 feet above earth's surface. This would place the student a distance of 6.39 x 106 m from earth's center.
Answer:
[tex]F=683.790939[/tex]N
Explanation:
From the Question we are told that
Earth mass [tex]m_1= 5.98 * 10^2^4 kg[/tex]
Students mass [tex]m_2=70kg[/tex]
Distance of student from earth center Radius [tex]r=6.39 * 10^6 m[/tex]
Generally the equation for Force of attraction b/w the earth and the boy is mathematically given by
[tex]F=\frac{Gm_1m_2}{r^2}[/tex]
[tex]F=\frac{6.67.10^-^1^1*( 5.98 x 10^2^4)(70)}{(6.39 *10^6)^2}[/tex]
Therefore the force of attraction b/w the student and the earth is
[tex]F=683.790939N[/tex]
[tex]F\approx 684N[/tex]
Einstein calculated that ripples of gravity travel at exactly the speed of _____
Answer:
299,792,458 m/s = speed of light
Explanation:
what is projectile motion
If an object is given an initial velocity in any direction and then allowed to travel freely under gravity, it is called a projectile motion.
It is basically 3 types.
horizontally projectile motion oblique projectile motion included plane projectile motionThe diagram shows a wave traveling through a medium.
Identify point B.
amplitude
crest
trough
wavelength
The point B represent the crest of the wave. The crest is the peak of the wave. While the trough is the lowest.
What is wavelength?The distance between two successive troughs or crests is known as the wavelength.
The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.
The point B represent the crest of the wave. The crest is the peak of the wave. While the trough is the lowest.
Hence, option B is correct.
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A bobsled has a momentum of 4000 kg•m/s to the south. Friction on the
track reduces its momentum to 2500 kg•m/s to the south. What impulse is
applied to the bobsled by the friction?
Answer:
1500 north
Explanation:
Answer: 1500 north
Explanation:
Impulse is change of momentum. Since the numbers are already in units of momentum, you just need to subtract one from the other to find the impulse. 4000 - 2500 = 1500. Because the bobsled is traveling south and slowing down, the impulse will be in the opposite direction, or north.
1500 north.
a.) Determine the work done by Zach on the bull.
Explanation:
Work done is a physical quantity that is defined as the force applied to move a body through a particular distance.
Work is only done when the force applied moves a body through a distance.
Work done = Force x distance
The maximum work is done when the force is parallel to the distance direction.
The minimum work is done when the force is at an angle of 90° to the distance direction.
So to solve this problem;
multiply the force applied by Zack and distance through which the bull was pulled.
Can someone please help?
Answer:
B
Explanation:
Speed is distance divided by time.