Answer:
The structure is called Propyl ethanoate
what is the half life of the element in the picture
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Answer:
6 days
Explanation:
The following data were obtained from the question:
Original amount (N₀) = 100 mg
Amount remaining (N) = 6. 25 mg
Time (t) = 24 days
Half life (t½) =?
Next, we shall determine the decay constant. This can be obtained as follow:
Original amount (N₀) = 100 mg
Amount remaining (N) = 6. 25 mg
Time (t) = 24 days
Decay constant (K) =?
Log (N₀/N) = kt / 2.303
Log (100/6.25) = k × 24 / 2.303
Log 16 = k × 24 / 2.303
1.2041 = k × 24 / 2.303
Cross multiply
k × 24 = 1.2041 × 2.303
Divide both side by 24
K = (1.2041 × 2.303) / 24
K = 0.1155 /day
Finally, we shall determine the half-life of the isotope as follow:
Decay constant (K) = 0.1155 /day
Half life (t½) =?
t½ = 0.693 / K
t½ = 0.693 / 0.1155
t½ = 6 days
Therefore, the half-life of the isotope is 6 days
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The answers are here
In which figure does Colin do work?
A. Figure A
B. Figure B
C. Both figures
D. Neither figure
PLS PLS SOMEONE HELP ME ANSWER THESE QUESTIONS PLEEEAAASSSE!!
(press on the picture so you can see the questions better!)
Answer:
1)conduction
2) convection
3) conduction
4) radiation
5) radiation
6) radiation
7) conduction
8) conduction
9) radiation
10) convection
Explanation:
not 100% sure