What is the minimum diameter of a steel wire if it is to support a mass of 80 kg?

With the concept of Coulomb's Law, the net force acting on the 2μC charge is 2.06 × 10⁻² newton.

Coulomb's Law states that the force of attraction or repulsion exerted by a charged particle on another charged particle is given by,

F=kq₁q₂ / r²

Here q₁ and q₂ are the charges on the particles,

r is the separation between them

k is a constant known as Coulomb's constant, whose value is, k = 9 × 10⁹ N m²/C²

So here in the question, we have been given an equilateral triangle of side 2 meters with three-point charges at its vertices

q₁ = 1μC ,

q₂ = 2μC ,

q₃ = 3μC ,

r=2 m

From Coulomb's law,

F₂₁ = kq₁q₂/r²

F₂₁ = (9 × 10⁹ × 1 × 2 × 10⁻¹²) / 2²

F₂₁ =4.5 × 10⁻³ N

This is the force on charge q₂ because of q₁.

Similarly,

F₂₃ = kq₂q₃ / r²

F₂₃ = (9 × 10⁹ × 2 × 3 × 10⁻¹²) / 2²

F₂₃ = 18 × 10⁻³ N

Now, the resultant of the two forces will be,

F(net) = [tex]\sqrt{F_{21} ^2 + F_{23}^2 +2F_{21}F_{23}cos60}[/tex]

On substituting all the values the net force will be

F(net) = 2.06 × 10⁻² N

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Answer:

8.49673 minutes ≈ 8.5 minutes

Explanation:

Acceleration, a is defined as the rate of change in velocity divided by the change in time to attain that velocity

[tex]\mathsf a = \dfrac{\Delta v}{\Delta t} \\\\\textsf {where } \mathsf {\Delta v = v-v_0} \textsf{ v being final velocity and v_0 initial velocity}[/tex], v = final velocity and v₀ the initial velocity
and Δt is the time required to attain final velocity

Δt = number of seconds since launch = t since t₀ = 0

Therefore,
[tex]a = \dfrac{v-v_0}{t}[/tex]

The space shuttle's initial velocity is 0 m/s and its final velocity must be 7800 m/s to escape earth's gravity

So v - v₀ = 7800 - 0 = 7800 m/s, t - t₀ = t = 0 = t seconds
a = 15.3 m/s²

We have the equation

a = 7800/t

a is given as 15.3 m/s² so
15.3 = 7800/t

t  = 7800/15.3 = 509.80392 seconds

To convert to minutes, divide by 60
509.80392/60 = 8.49673 minutes ≈ 8.5 minutes

The athlete who jumps a vertical distance of 0.8 m has a initial speed of: 3.959 m/s and his total time in the air is: 0.8078 s

The formulas for the vertical launch upward and the procedures we will use are:

Where:

Information about the problem:

Applying the maximum height formula and clearing the initial velocity we get:

y max = v₀²/(2*g)

v₀ = √(y max * (2*g))

v₀ = √( 0.8 m * (2 * 9.8 m/s²))

v₀ = √( 0.8 m * 19.6 m/s²)

v₀ = √15.68 m²/s²

v₀ = 3.959 m/s

Applying  the maximum time formula we get::

t max = v₀ / g

t max =(3.959 m/s)/(9.8 m/s²)

t max = 0.4039 s

Applying  the time of flight formula we get::

t(of) =2 * t max

t(of) =2 * 0.4039 s

t(of) = 0.8078 s

In physics vertical launch upwards is the motion described by an object that has been launched vertically upwards in which the height and the effect of the earth's gravitational force on the launched object are taken into account.

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The frequency of light emitted is 24.63 x [tex]10^1^5[/tex] Hz when an electron jumps from the 2nd to the 1st orbit in a hydrogen atom.

According to Bohr, the electrons in the atom's structure are situated around the nucleus at particular energy levels. An electron must either acquire or lose energy as it transitions from one of these energy levels to another. It is known as an absorption when an electron obtains energy and as an emittance when it loses energy. Both processes involve the absorption or emission of a PHOTON energy particle, which in turn causes the absorption or emission of light. Because various elements have varying energies, they each emit or absorb light in varying quantities (wavelengths).

The wavelength or wave number is used to compute the frequency of light emitted. 

The frequency of light emitted is inversely proportional to its wavelength.

Given:

Jump from 2nd orbit to 1st orbit

Planck’s constant, h = 6.626 x [tex]10^-^3^4[/tex]

To find:

Frequency of light emitted, υ = ?

Formula:

E = hυ

Calculations:

[tex]E = 13.6 * Z^2( \frac{1}{n_1^2} - \frac{1}{n_2^2} )[/tex]

E = hυ = 13.6 x 1 x [tex](1 - \frac{1}{4})[/tex]

υ x 6.626 x [tex]10^-^3^4[/tex] = 10.2 x 1.6 x [tex]10^-^1^9[/tex]

υ = 24.63 x [tex]10^1^5[/tex] Hz

Result:

The frequency of light emitted is 24.63 x [tex]10^1^5[/tex] Hz.

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The distance travelled by the student is 1600m and the displacement is 0.

Displacement is the direction from the beginning point and the length of a straight path from the starting point to the finishing point, whereas distance is the length of a path that connects two places.

Displacement is a vector quantity that does not take into consideration the actual path taken; instead, it quantifies the distance between the beginning point and the finishing position.

Given:

Track length = 400m

No. of rounds = 4

To find:

Distance, d = ?

Displacement, D = ?

Formula:

Distance, d = Track length x No. of rounds

Displacement, D = End point – Start point

Calculations:

d = 400 x 4

d = 1600m

D = 0 since the start and end point are same.

Result:

The distance travelled is 1600m with 0 displacement.

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While the flashlight light has no effect, the UV source's light discharges the electroscope.

According to Planck's formula, the energy of the particles that make up a beam of light is connected to their frequencies. The photons and atoms collide when that beam strikes a metal. The photoelectric effect is created by a collision when a photon's frequency is high enough to remove an electron.

One electron interacts with each photon. The incident photon's energy is employed to both liberate the surface-bound electrons and give the expelled electrons energy.

Because it offers insights into the properties of solids as well as the properties of atoms and molecules, the photoelectric effect is extensively researched in the fields of quantum chemistry, condensed matter physics, and solid-state chemistry.

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Electron transport chain use NADH and FADH2 molecules formed in Glycolysis and Krebs Cycle processes.

The third stage of cellular respiration is the electron transport chain. In cellular respiration, high-energy electrons are transported by NADH and FADH2 to the electron transport chain. In photosynthesis, NADPH transports energetic electrons to the electron transport chain.

Krebs cycle or the TCA cycle, the process of oxidizing acetyl-CoA, which is produced from proteins, carbs, and lipids, releases stored energy.

The process by which glucose is broken down to provide energy is known as glycolysis. It generates two pyruvate molecules, ATP, NADH, and water. There is no need for oxygen throughout the process, which occurs in the cytoplasm of a cell. Both aerobic and anaerobic respiration experience it.

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In here E = 5.3 x 10^3 N/C, the potential difference (V) between the two plates is 116.6 V and if d is doubled, electric field E won't change but V gets doubled.

a) The electric field of infinite parallel plates can be formulated as

E= σ/2ε0 → eq1

Surface charge density is given as 47.0 nc/m2

So, the electric field is independent on d.

Hence the, so the net field is

E = E1 + E2 = σ/2ε0 + σ/2ε0 = σ/ε0

Substituting in eq 1,

E = [47 x 10^(-9) ] / 8.85 x 10^-12 = 5.3 x 10^3 N/C

b) Since the electric potential between them at any point and is given by.

V=Ed → eq 2

So, Substituting in eq 2 yields

V= 2.2 x 10^-2 x 5.3 x 10^3 = 116.6 V

c) If the distance between plates is doubled it will make no changes on the field because the field is independent on d.

For the voltage, according to equation 2 the voltage depends on d so if d is doubled then the potential between plates must be doubled.

Thus, magnitude of e in the region is 5.3 x 10^3 N/C.

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If the mirror is immersed in water whose index of refraction is 1.33 , No change in its focal distance . focal distance of mirrors does not depend on the external medium in which the mirror is immersed.

As the focal length of the convex mirror does not depend on the factor such as the refractive index of any medium. Hence even after the convex mirror is immersed in water, the focal distance remains unchanged. Hence the facility of the convex mirror also remains same.

Since from lens makers formula we will observe that focal length of lens is inversely proportional to refractive index of medium of lens . Hence net index of refraction of lens decreases when it is dipped in a denser medium than air, hence focal distance increases.

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Answer:

Explanation:

Given that

To find

So, according the question

We have,

The formula for the ball's height as a function of time is

         [tex]y_f = y_i - u_it - \frac{1}{2} gt^2[/tex]------------------(1)

where,

         [tex]y_f = final \;height=0\\y_i = initial \;height=29.6m\\u_i = initial \;velocity=8.35m/s\\\;\; g = acceleration \;due\; to\; gravity= 9.81m/s^2[/tex]

Now, putting the all given values ,

         [tex]y_f = y_i - u_it - \frac{1}{2} gt^2[/tex]------------------(1)

         [tex]0 = 29.6 - 8.35t - \frac{1}{2} \times9.81t^2[/tex]

or,

         [tex]9.81t^2 + 16.7t -59.2 = 0\\\\t = \frac{-16.7 \pm \sqrt{(16.7)^2-4\times 9.81\times (-59.2)}}{2}}\\t = \frac{-16.7 \pm \sqrt{278.89+4\times 9.81\times 59.2}}{2}}\\t = \frac{-16.7 \pm \sqrt{278.89+2087.57}}{2}}\\t = \frac{-16.7 \pm \sqrt{2366.46}}{2}}\\t = \frac{-16.7 \pm 48.65}{2}}\\now \; we \; know \; that\; time\;always \; in\;only\;positive\\so,\\t = \frac{-16.7 + 48.65}{2}\\t = \frac{31.95}{2}\\t = 15.98s[/tex]

Answer:

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The snapshot of light as the cart moves with constant velocity is represented by a graph with uniform displacement at each time interval.

The change in displacement with time is uniform at constant velocity. The displacement of the supplied moving item grows at the same pace.

The beginning velocity equals the ultimate velocity at constant velocity.

v₁ = v₂

The object's acceleration at constant velocity is zero since the velocity change with time is zero.

As a result, we may deduce that the graph with equal displacement at each time interval reflects a snapshot of light as the cart moves at a constant speed.

A moving object's displacement-time graph shows the distance traveled by a moving item as time passes. A vector quantity is displacement. The slope or gradient of this graph represents the velocity of the item. The displacement-time graph, also known as the position-time graph, describes an object's motion. In this graph, the displacement of the moving item is displayed on the y-axis as a dependent variable, while time is shown on the x-axis as an independent variable.

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An automobile traveling in the left lane at 60.1 km/h to overtake (become even with) another car that is traveling in the right lane at 38.1 km/h, when the cars' front bumpers are initially 105.2 m apart and the time taken is t = 17.21 seconds.

To find the time, the given values are,

Distance in,

Left lane = 60.1 km/hr

Right lane = 38.1 km/hr

Initial length d₀ = 105.2 m

The distance covered can be derived using the equation of motion with no acceleration.

distance d = speed v × time t

d = vt

For the first automobile,

v = 60.1 km/h

d₁ = 60.1

For the second automobile,

v = 38.1 km/h

Initial distance d = 105.2 m = 0.1052 km

d = vt + d₀.

d₂ = 38.1 t  + 0.1052

For them to meet/overtake each other,

Their distance at that time must be equal.

d₁ = d₂

60.1 t = 38.1 t + 0.1052

60.1 t - 38.1 t = 0.1052

22 t = 0.1052

t = 0.1052 / 22 hr

Converting to seconds

t = 0.1052 / 22 × 3600s

t = 17.21 seconds.

The time taken for an automobile to travel is 17.21 seconds.

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The apparent weight of the egg = 0.264N

Here the rocket is accelerating upward from the surface of the earth. The egg is on the rocket.

The acceleration due to gravity is 4.4m/[tex]s^{2}[/tex].

The mass of a chicken egg is 0.060 kg.

Form Newton's second law, the net force acting on a body is equal to the product of mass and acceleration due to gravity.

So form Newton's second law we know the formula i.e.,

                         F = m×a

                            = 0.06 × 4.4

                            = 0.264N

Therefore the apparent weight of the egg is 0.264N.

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The apparent weight of the egg is found to be 0.852 N.

Given here, the mass of the egg is m=0.06kg, acceleration due to gravity g =9.8m/s², acceleration of rocket a = 4.4m/s².

Now, we calculate apparent weight by the formula,

We = m (a + g)

= 0.06( 4.4+ 9.8)

= 0.8528 newton.

Thus, the apparent weight of the egg is found to be 0.8528N.

An object’s perceived weight, which reflects how heavy it is, is a quality. When the force of gravity acting on an object is not counter balanced by a force of equal but opposite normality, the apparent weight of the object will differ from the actual weight of the thing.

The buoyant force pushing up on the object is subtracted from the apparent weight, which is equal to the actual weight (w=mg). The apparent weight of the object at its lowest point would be equal to its normal force.

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Answer:

[tex]{ \tt{mass \: number = protons + neutrons}} \\ { \tt{7 = p + 3}} \\ { \tt{p = 4}}[/tex]

Answer: The Big Bang!

Answer:

the process of solving a mystery.

Explanation:

 r(t)=ti+5t²j+(4t²+50t⁴)k, For t∈ (-∞, ∞)

First plug the equation of y into the equation of z, so that we get their intersection:

We plug  

y=5x²

Into:

z=4x²+4y²

So, we get:

z=4x²+2(5x²)²

z=4x²+2(25x⁴)

z=4x²+50x⁴

Then we set  

x=t

And plug that in the equation [tex]y=5x^{2}[/tex] and z.

So that we get:

[tex]y=[/tex]5t², [tex]z=[/tex]4t²+50t⁴

Hence, the vector function r(t) that represents the curve of intersection is:

r(t)=ti+5t²j+(4t²+50t⁴)k, For t∈ (-∞, ∞)

A curve of intersection is made up of the common points of two transversally intersecting surfaces, which means that the surface normals are not parallel at any common point. This restriction applies only when the surfaces are touching or share surface sections.

The intersection of two non-parallel planes in Euclidean 3-space is a line in the simplest situation.

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Answer: Acceleration=Change in speed/time

=(20–8)/10

=1.2m/s²

We can find the distance travelled by using the kinematic equation

S=ut+½at²

S=8*10+½*1.2*100

S=80+0.6*100

S=80+60

S=140m

Explanation: hope this helps and good lucky!!

The speed of Olivia when she made it to the bottom of the hill is 14m/s.

Kinematics is the study of mechanical points, bodies, and systems in motion without taking into account the forces acting on them or the corresponding physical qualities.

Kinematics equations of motion define the fundamentals of an object's motion, such as its position, velocity, or acceleration over time. These three equations of motion control how an item moves in one, two, and three dimensions.

Kinetics considers physical forces as well as material characteristics such as mass stiffness and tensile or compressive strength. These characteristics can be used to take a theoretical model from kinematics and use physics and thermodynamics to determine how to construct a workable, dependable, and functional real-world system.

Given,

Initial velocity, u = 4m/s

Acceleration, a = 2m/s-2

Displacement, s= 45m

we know that,

[tex]v^{2}= u^{2} + 2as[/tex], where v= final velocity

substituting the value in the above equation, we got

[tex]v^{2}[/tex] = [tex]4^{2} + 2(2)(45)[/tex]

v = [tex]\sqrt{196}[/tex]

v = 14 m/s

Thus, the speed of Olivia going down the hill is 14m/s.

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A 60-kilogram individual ascends an 80 m-high building's roof by walking up from the ground. Once at the peak, the human has a potential energy of 44027.28 J.

This is our formula

Gravitational ability strength = mgh  

here (GPE = mgh)

mg = 60.0 kg

h = 80

mg = 60.0 kg

in view that we're searching for pressure and the SI Unit for force is "N," we must convert this to force (N).

consequently, we will multiply 60.0 via nine.81.

60.0 × 9.81 = 588.6

Now that will be

⇒ mg = 588.6 N

⇒ h = 80

GPE = (588.6) × (80) = 47088 J

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The oscillation angular frequency of a drop with half of the first drop's radius is 4ω

Surface tension is the tension force exerted on an object by the surface of a liquid.

Angular frequency is the frequency of oscillation of a rotating object. It is given in rad/s.

Given that

Since the energy of the drop is conserved, using the law of conservation of angular momentum, we have

Iω = I'ω' where

So, Iω = I'ω'

Making ω' subject of the formula, we have

ω' = Iω/I'

ω' = mr²ω/mr'²

ω' = r²ω/r'²

Given that the drop is half of the first drop's radius, r' = r/2

So, ω' = r²ω/r'²

ω' = r²ω/(r/2)²

ω' = r²ω/r²/4

ω' = 4ω

So, the oscillation angular frequency of a drop with half of the first drop's radius is 4ω

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Galileo disproved Aristotle’s idea that heavy objects fall faster than lighter objects through his findings as specified in his books.

The story goes that Galileo used this experiment to find that the objects fell with the same acceleration, disproving Aristotle’s theory of gravity (which states that objects fall at a speed proportional to their mass) and proving his prediction.

Before Galileo, Aristotle’s writings had been accepted as true for over a thousand years. He claimed that heavier objects fall faster than lighter ones and that an object that weighs twice as much as another will fall twice as fast.

In his book Two New Sciences, Galileo outlined his theories regarding falling objects and projectiles in general (1638).

The two disciplines were the study of motion, which helped establish physics as a discipline, and the science of materials and construction, which made significant contributions to engineering.

This theory of Galileo’s was totally based on a well-known thought experiment that he described in his book.

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Answer:

Q1: C

Q2: C

Q3: D

Q4: D

Code: Left, Down, Up, Right

Your welcome.

Answer: ctrl+U

ctrl+G

Explanation:

I don't know how else to help

The FitnessGram PACER Test is a multistage aerobic capacity test that progressively gets more difficult as it continues.

The test is used to measure a student's aerobic capacity as part of the FitnessGram assessment. Students run back and forth as many times as they can, each lap signaled by a beep sound. The test get progressively faster as it continues until the student reaches their max lap score.

The PACER Test score is combined in the FitnessGram software with scores for muscular strength, endurance, flexibility and body composition to determine whether a student is in the Healthy Fitness Zone™ or the Needs Improvement Zone™.

The unknown material is glass because the refractive index is found out to be 1.5

[tex]u_{water\\}[/tex]= 1.33

[tex]u_{x}[/tex]=?

[tex]u_{1}[/tex]sini=[tex]u_{2}[/tex]sin27°

[tex]u_{2}[/tex] = 1.33 x [tex]\frac{sin31}{sin27}[/tex]

= 1.33 x (0.51/0.45)

= 1.50

so, deducing from it, we have refractive index = 1.50

Hence the unknown material is glass.

What is index of refraction?

The refractive index (or refraction index) of an optical media in optics is a dimensionless quantity that indicates the capacity of that medium to bend light. The refractive index controls how much light is refracted or twisted when it enters a substance.

The angle of incidence and angle of refraction of a ray as it crosses the interface between two media with refractive indices of n1 and n2 are, respectively, n1 sin 1 and n2 sin 2, which describes this.

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The height of the utility pole she has climbed is 60 m

When an object is dropped under gravity, the initial velocity is zero. While at the maximum height reached by an object when thrown up, the final velocity will be zero.

Given that a utility line worker drops a screwdriver which takes 3.5 seconds to hit the ground. The height of the utility pole can be calculated by using the formula below

h = ut + 1/2gt²

but u = 0

h = 1/2gt²

Substitute all the parameters into the equation

h = 1/2 × 9.8 × 3.5²

h = 4.9 × 12.25

h = 60.025 m

Therefore, the height of the utility pole she has climbed is 60 m approximately.

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(a)The net charge on the sphere is 3.38×[tex]10^{-9}[/tex] C.

(b) The charge inside sphere is positive and distributed symetrically inside the sphere .

(a) As we know the electric field is given as,

E = kq / [tex]r^{2}[/tex]

Plugging in the values we get,

575 = 8.99×[tex]10^{9}[/tex] q / [tex]0.230^{2}[/tex]

8.99×[tex]10^{9}[/tex]q = 30.41

q = 3.38×[tex]10^{-9}[/tex] C

So, the net charge on the sphere is 3.38×[tex]10^{-9}[/tex] C.

(b) We can conclude that the charge inside sphere is positive and distributed symetrically inside the sphere .

The complete question is: The electric field everywhere on the surface of a charged sphere of radius 0.230 m has a magnitude of 575 N/C and points radially outward from the center of the sphere. (a) What is the net charge on the sphere? (b) What can you conclude about the nature and distribution of charge inside the sphere?

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The Angular momentum of mass m moving with a constant velocity about origin is constant.

L= momentum × perpendicular distance of line of action of the momentum from origin.

L=mv×y

Here it is seen that mvy is a constant, therefore the angular momentum is constant.

The rotational equivalent of linear momentum in physics is called angular momentum, also known as moment of momentum or rotational momentum.

Because it is a conserved quantity, while calculating the total angular momentum of a closed system, it stays constant—it is significant in physics.

The direction and the amplitude of angular momentum are all conserved. The functional characteristics of bicycles and motorbikes, frisbees, rifled bullets, and gyroscopes are due to the conservation of angular momentum.

The conservation of angular momentum also explains why neutron stars rotate rapidly and hurricanes, build spiral structures. In general, conservation restricts a system’s potential motion but does not completely define it.

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Yes, the statement is correct that keeping the flies in constant dark conditions abolish the light-emission oscillations

The electromagnetic radiation spectrum produced when an electron changes from a high energy state to a lower energy state is known as the emission spectrum of a chemical element or chemical compound. The energy difference between the two states is equal to the photon energy of the emitted photon. Each atom contains a large number of potential electron transitions, and each transition has a distinct energy difference. An emission spectrum is made up of a variety of transitions that result in various radiated wavelengths. The emission spectra of each element is distinct. Therefore, components in materials with an unknown composition can be identified via spectroscopy. Similar to this, chemical examination of substances may make use of the emission spectra of molecules.

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