what is the index of refraction of a substance that has a critical angle of 68.4º when submerged in water (n

The correct answer is 0.024cm.

The density of a substance determines how heavy it will be in a given volume. It is technically the mass of that material per unit volume. It is implied by this that a specific material weighs a specific quantity relative to its volume.

A substance's density determined how heavy it would be at a particular size. It is an inherent quality that is not affected by geography, such as a shift in the globe.

density of copper =  8.93 g/cm3

mass = 3.1118 g

Density= mass/volume

8.93= 3.1118 /volume

volume=3.1118/8.93

=0.348 cm^3

Volume = l×b×t

T= volume/ l×b

=0.348 cm^3/12.10×11.67

=0.348 /141.2

=0.0024×10mm

=0.024cm

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73.5 kilojoules are the answer. Since we can compute potential energy, we can convert 250 into 9.8 into 30 into 73500 joules, or u equal to m g h. Consequently, the body's potential energy will be 73500 joules, which is the necessary amount.

This potential energy calculator allows us to calculate the amount of energy that an elevated object has stored inside it. The full name of this effect is gravitational potential energy, and it refers to the energy that an item stores as a result of its height or vertical position.

The great wrecking ball of the crane. The ball's gravitational potential energy depends on both its mass and how high it is elevated. The relationship between gravitational potential energy and an object's mass and height is seen in the following equation:

PE Gravity equals (m, h, and g). The formula is rather simple to comprehend. The height of a non-raised object will be zero, and as a result, it will have no potential energy.

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The lowest 19.152 [tex]\frac{w}{m^{2} }[/tex] frequency that will produce the maximum intensity (Imax) at the observer, assuming the observer will still hear an intensity of 6 w/m2 when [tex]S_{1}[/tex] or [tex]S_{2}[/tex] is heard alone.

We have [tex]I_{1} =I_{2}[/tex]

[tex]= 6 w/m^{2}[/tex]

Path difference

δ = 5.6568 - 4

δ = 1.6568 m

v = 335 m/s

Intensity I = [tex]4I_{1} cos^{2}[/tex](πδ/λ)

[tex]= 4I_{1} cos^{2}[/tex](πδf/v)

[tex]= 4 * 6 cos^{2}(\frac{\pi *1.6568*30}{335} )[/tex]

I = 19.152 [tex]\frac{w}{m^{2} }[/tex]

the lowest frequency is selected to cowl the N-point signal at its coarsest scale with the aid of the default wavelet's two-time popular deviations. the very best frequency wavelet bandpass filter out loses half of of its height importance at the Nyquist frequency because of the most frequency.

guy's voice has the lowest frequency in comparison to other sounds seeing that frequency and pitch cross hand in hand. Pitch denotes the voice's shrillness. the man's voice is the selection with the least strident tone. It, therefore, has the bottom pitch of all and for this reason the bottom frequency.

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The correct answer is 47 units.

Arrows typically serve as a vector's geometric representation. The magnitude of the vector is determined by its length and the direction in which the arrow is pointing. When two vectors have the same magnitude and direction, they are said to be equal. Additionally, the magnitude and direction of vectors are unaffected by the vector's position.

A quantity with both magnitude and direction is referred to as a vector quantity. One example of a vector quantity is velocity. A two-dimensional vector can be expressed as,

A=A_Xi+A_Yj

Vector A=31 j

A+B=-16 j

Thus vector B is

B=(A+B)-A

B=(-16j)-31j

B=(-47)j

As a result, vector B has a magnitude of 47 units and is oriented in a negative Y direction.

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The g - string will stretch by 0.0016 mm.

We have a g - string of a guitar with given specifications.

We have to determine how many mm does a 75-cm-long g - string stretch when it’s first tuned.

According to the question -

The force of tension in the string -

[tex]$v = \sqrt{\frac{T}{\mu} }[/tex]

T = [tex]$v^{2} \mu[/tex] = 250 x 250 x 0.0011 = 68.75 N

The Yung modulus of steel = 2 x [tex]10^{11}[/tex] N/[tex]m^{2}[/tex]

the amount by which the g - string will be stretched is given by -

[tex]$\delta L = \frac{LT}{Y(\pi r^{2})}[/tex]

Substituting the values -

[tex]$\delta L = \frac{0.75\times 68.75 }{(2\times 10^{11} )\times (\pi (2.2 \times 10^{-4}\times 2.2\times 10^{-4}) )}[/tex]

[tex]\delta L=[/tex] 0.0016mm

Hence, the g - string will stretch by 0.0016 mm.

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[ The given question is incomplete. The complete question is

" The G string on a guitar is a 0.46-mm-diameter steel string

with a linear density of 1.1 g/m. When the string is properly

tuned to 196 Hz, the wave speed on the string is 250 m/s. Tuning

is done by turning the tuning screw, which slowly tightens—and

stretches—the string. By how many mm does a 75-cm-long G

string stretch when it’s first tuned? "]

The part of river's current moves at a 1.486 m/s speed.

the distance between two points, objects, lines, etc. Remoteness is the quality of being physically separated from another thing or person. a line drawn in the universe. To walk seven miles in one hour would be too time-consuming.

The difference between the change in distance and the change in time is used to compute the rate of change.

Rate: times the distance Time

The distance is 16.5 miles, and the time is 5.5 hours.

If we enter this into the formula above, it yields:

16.5 - 5.5 / 10.9 - 3.5 = 11/7.4 = 1.486 m/s is the rate of change.

Calculations show that the constant rate of change is 1.486 m/s.

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The correct answer is 5.64.

Since the analogue signal is divided every 100 mV for accuracy of 50 mV, we have 50 discrete observations from 0 to 5V. Thus

It's given that the accuracy is +/- 50mV. This essentially means that the length of interval of permissible accuracy is 100mV.

Now, it's given that the analog voltage range is 0-5 V. So, the number of discrete points in 0-5V will be as follows:

50V/100mV.

Upon solving, it comes out to be 50.

The number of bits is defined by the formula log_2n, where n is the number of discrete points.

In this case, n = 50. Putting the value in the formula,

No of bits = log_2 50

Upon solving,

No of bits = 5.64

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The distance travelled or how far the car has travelled in 3.3 second at constant speed of 86.4 km/h is 79.2 m.

The speed of an object, also known as v in kinematics, is a scalar quantity that refers to the size of the change in that object's position over time. The average speed of an object over a period of time is calculated by dividing its distance traveled by the length of the interval. Velocity and speed are different concepts. Distance divided by time is the dimension of speed. The meter per second (m/s) is the metric unit used to measure speed.

Speed of car= 86.4 km/h

Since time is given in seconds, converting to km/h to m/s. For converting km/h to m/s, dividing the value given in km/h by 3.6

86.4 km/h= 86.4/3.6 m/s

= 24 m/s

Distance travelled= Velocity* Time

= 24 * 3.3

= 79.2 m

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The number of electrons is 1.9 * 10^20 electrons.

We know that it is possible to obtain the charge that the electron carries by the use of the formula;

Q = It

Q = magnitude of charge

I = current

t = time taken

Now we have the charge as;

Q = 0.5 A * 60 s = 30 C

Given that;

Q = ne

Q = charge

n = number of electrons

e = magnitude of electronic charge

n = Q /e = 30 C / 1.6 x 10-¹⁹ C​

n = 1.9 * 10^20 electrons

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Answer:

b. Observation

Explanation:

You see ice melt in an experiment, so you record that as one of your observations.

The calculated value is 2.5×10⁷ m.

Velocity is a term that describes the speed and direction of a point's motion. For example, a circular path's direction is always perpendicular to a line from the point to the circle's center. A point always moves in a direction that is tangent to its path (a radius). A vector measurement of the rate and direction of motion is what is meant by the term "velocity." Simply said, velocity is the rate of movement in a single direction.

From energy conservation, since the velocity will be 0 at highest point,

1/2 m (10000) ²− GMm/R

=− GMm/d

=10⁸/2 −(9.8) (6400000)

=−(9.8) *(6400000) ²/d

d≈2.5×107 m

Answer is 2.5×10⁷ m.

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The velocity component due north of the cheetah is 14.56 m/s.

The velocity component due west is 10.58 m/s.

The component's of the cheetah's velocity is calculated as follows;

Vy = V sinθ

Vy = 18 m/s x sin(54)

Vy = 14.56 m/s

Vx = V cosθ

Vx = 18 m/s x cos(54)

Vx = 10.58 m/s

Thus, the velocity component due north of the cheetah is 14.56 m/s.

The velocity component due west is 10.58 m/s.

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Answer:the magnitude of the hikers resultant displacement

Explanation:

The kangaroo's minimum vertical speed when it leaves the ground is 5.94 m/s

From the question given above, the following data were obtained:

The inintial velocity of the kangaroo can be obtained as illustrated below:

v² = u² – 2gh (since the ball is going against gravity)

0² = u² – (2 × 9.8 × 1.8)

0 = u² – 35.28

Collect like terms

u² = 0 + 35.28

u² = 35.28

Take the square root of both side

u = √35.28

u = 5.94 m/s

Thus, the minimum vertical speed of the kangaroo when it leaves the ground is 5.94 m/s

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Explanation:

12:30pm -> 04:00pm = 3hrs 30mins

3hr 30mins= 3.5hrs

average speed=total distance/total time

=213÷3.5

=60.8571428571

round to 2 decimal places

=60.86 mph

Ecosystem A has more diversity, because it has greater species evenness than Ecosystem B.

All the organisms and the physical setting they interact with make up an ecosystem. The nutrient cycles and energy flows connect these biotic and abiotic elements. Photosynthesis is how energy reaches the system and is absorbed by plant tissue.

Forest Ecosystem.

Grassland Ecosystem.

Tundra Ecosystem.

Desert Ecosystem.

Fundamentally, the way an ecosystem works is through the transfer of nutrients and energy up the food chain. The planet's plant and animal life, as well as the breakdown of organic matter and the creation of biomass, are all supported by these exchanges.

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A 0.900 kg block that is attached to a spring with spring constant 13.0 n/m when hit with the hammer has the amplitude of oscillation as 11.637 x 10^-3 cm.

When an object’s motion repeats in a predetermined cycle, it is said to be in periodic motion. The motion described here is an oscillation.

Spring and pendulum motion are two straightforward instances of oscillations, but there are numerous additional instances as well.

The fact that the item is in a stable equilibrium position is a key characteristic of periodic motion. A restorative force that is pointed in that direction as well. The application of force occurs in spring.

If x is the compression of the spring after it is hit,

1/2 k x² = 1/2 m v²

13 x² = .90 x (41 x 10⁻²)² 1681

x² = 116.37 x 10⁻⁴

x = 11.637 x 10^-5m

11.637 x 10^-3 cm

Amplitude of oscillation = 11.637 x 10^-3 cm

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The mass of the box is 11.80N

F= 42.5

a=3.60 m/[tex]s^{2}[/tex]

m=?

F=ma

m=F/a = 42.5/3.60

m=11.80N

The definition of force in physics is: The push or pull on a massed object changes its velocity.

An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

Thrust, which increases an object’s velocity; drag, which decreases an object’s velocity; and torque, which causes changes in an object’s rotational speed, are all concepts connected to force.

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The correct answer is convection.

Convection is the physical movement of material particles that transfers heat from a location of greater temperature to a region of lower temperature.

Convection is a heat-transfer process in which heat energy is transferred by the mass movement of fluid molecules, such as those found in gases and liquids. Under normal circumstances, gases and liquids are poor heat conductors, yet they are nonetheless capable of transferring heat.

Other than through diffusion, advection, or both, convection is the method used to transfer heat. Solids don't experience convection because the particles that make them up don't move.

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There are C different ways to choose two different automobiles (12, 2).

In mathematics, a choice is made from a set of various components where the order of the choices is unimportant (unlike permutations).

For instance, there are three conceivable combinations of two given fruits, such as an apple, an orange, and a pear: an apple and a pear; an orange and an apple; or an orange and a pear. Formally speaking, a set S's k unique components make up a subset known as a k-combination. In other words, two combinations are same only if all of their members are the same.

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1905, Albert Einstein. The theory of special relativity explains how speed affects space, time, and mass. Small amounts of mass (m) can be interchangeable with large amounts of energy (E), as defined by the classic equation E = mc2, according to the theory, which offers a means for the speed of light to define the link between energy and matter.

When talking about extremely high energy, incredibly fast speeds, and astronomical distances without the difficulties of gravity, special relativity is typically employed. With the publication of his general relativity article in 1915, Einstein formally incorporated gravity into his ideas.

The mass of an object and the energy needed to move it both grow unlimited as it gets for any matter to go faster than light travels. This cosmic speed limit inspires new realms of physics and science fiction, as people consider travel across vast distance closer to the speed of light. Therefore, it is not possible.

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Answer:

The graph would increase constantly as shown above until it reached 50m/s. At 10s, the graph would be flat at 50m/s until 20s.

Explanation:

The value of matrix p will be[tex]\left[\begin{array}{ccc}9&1\\14&4\end{array}\right][/tex].

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The linear speed of the helicopter blade is 33.51 m.

The tangential speed of the helicopter blade is calculated as follows;

v = ωr

where;

ω  = 80 rev/min

ω = 80 x 2π rad/rev x 1 min/60s

ω = 8.378 rad/s

v =  8.378 rad/s x 4 m

v = 33.51 m

Thus, the linear speed of the helicopter blade is 33.51 m.

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The complete question is below:

Find the tangential speed of the helicopter's blade.

When a 2 kg ball is thrown with an acceleration of 40 m/s². The

force exerted on the ball is 80 N.

According to Newton's second law of motion

F = ma

where, F = force exerted on the object, m = mass of an object and a = acceleration of the object.

Here, m = 2 kg, a = 40 m/s². so, F = ?

Therefore, force (F) exerted on the ball = 40x2 = 80 N

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Answer:

I think it's 12.5s

Explanation:

Bare with me, because I just started physics, but I think I have the answer right... Hopefully.

starting with your knowns, we know velocity is 25 m/s from the problem. you also can figure out your acceleration, -2 m/s.

You're looking for the time it takes until the ball stops rolling. Your time is unknown.

Your equation would be a=v/t (acceleration being a, velocity being v, and time being t)

You have to solve for t giving you t=v/a

Now you have to fill in your numbers. t=25m/s divided by -2m/s^2

Your answer should end up as -12.5

You have to solve for your units, but since you're finding time it's pretty straightforward in knowing you're dealing with seconds.

Hope this helped... :) sorry if it didn't-

If h is the height of the water, then the volume of water is v = r2h. We get [tex]dv/dt[/tex] equal to 0.00994 m/min.

Here, radius = 8m

We have, [tex]V = \pir2h[/tex]

[tex]dV/dT= (\pir2) dh/dt[/tex]

[tex]dV/dT= (\pi82) dh/dt[/tex]

[tex]dV/dT= (\pi64) dh/dt[/tex]

Given [tex]dV/dT = 2[/tex]

Therefore, [tex]dh/dt = 2/(64\pi) = 0.00994 m/min[/tex]

From the definition = a by way of integrating the preliminary velocity, v(0), and the consistent acceleration, one might also find the velocity at a later time, t.

(value of acceleration) means the rate of change of significance of the speed with recognize to time. then again |

| approach the magnitude of the price of change in speed with recognize to time (i.e. the importance of acceleration).

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With the use of formula, the maximum height reached by the ball in term of h is 4h

A projectile is any object thrown into the space or atmosphere which take a trajectory path.

If you toss a ball straight up, and it reaches a maximum height h above the launch position, Then the maximum height reach will be

v² = u² - 2gh

But at maximum height, v = 0

u² = 2gh

h = u² / 2g ...... (1)

Also, the time taken will be;

v = u - gt

since v = 0,

u = gt

Substitute u into equation 1

h = (gt)² / 2g

If you want to double the length of the time interval during which the ball stays in the air above the launch position, then,

u = g2t and the maximum height will be

H = (g2t)² / 2g

H = 4g²t² / 2g

H = 4(gt)² / 2g

but h = (gt)² / 2g

H = 4h

Therefore, the maximum height you have to throw it in terms of h will be 4h.

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a) As carbon dioxide is formed the shorter candle's flame goes off first, followed by the taller candle. This shows, that in absence of air, the flame goes off. Hence, the air is necessary for combustion.

b) Although both reactants are common home chemicals and foods, care should be taken to avoid splashing in the eyes, and protective clothing should be used. The reaction's byproducts can be disposed of by thoroughly filling the sink with water and washing down the sink with no chemicals touched.

Baking soda and vinegar react with one another to create carbon dioxide gas. The carbon dioxide gas sinks to the bottom of the bowl because it is heavier than the air around it. More and more carbon dioxide gas is produced as the reaction progresses, progressively filling the bowl as it does so. The flame will go out owing to a shortage of oxygen once the level of carbon dioxide reaches that of the flame.

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