Answer:its a play
Explanation:
Answer:
A. It is a play
Explanation:
Got the answer correct on the quiz
describe at least five ways in which information technology can help studying subjects other than computing
Answer:
I'd that IT can help in a great many different fields like
Mathematics, in a manner of solving complex math equations
Statistics, in a manner of creating complex graphs with millions of points
Modeling, in a manner of creating models from scratch, either for cars, personal projects or characters for video games and entertainment
Advertising, in a manner of using IT to create not only the advertisements themselves but also, spreading that advertisement to millions in a single click
Music/Audio, in a manner of creating new sounds and music that wouldn't be able to work in any practical manner
Explanation:
HELP URGENTLY!!!!!
Elly supervises an eye doctors office. The office recently received new equipment. To keep that equipment working accurately and dependably, she should:
(Select all that apply.)
Copy the users manual and distribute to all the employees
Identify individuals to complete the tasks
Create a log to document maintenance
Set up auto reminders
Read the manual
List the maintenance tasks
Establish the frequency of the maintenance tasks
Update the software in the office
Note that where Elly supervises an eye doctor's office, and the office recently received new equipment, to keep that equipment working accurately and dependably, she should:
Copy the users manual and distribute to all the employeesCreate a log to document maintenanceSet up auto remindersRead the manualList the maintenance tasksEstablish the frequency of the maintenance tasksUpdate the software in the office.What is the rationale for the above response?In order to ensure that the equipment is working properly and optimally, Elly should distribute the user manual to all employees.
In addition, she should identify individuals to complete maintenance tasks, create a log to document maintenance, set up auto reminders, read the manual, list the maintenance tasks, establish the frequency of the maintenance tasks, and update the software in the office to keep new equipment working accurately and dependably. This will ensure optimal equipment maintenance and lifetime.
Learn more about equipment maintenance:
https://brainly.com/question/21853224
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Write a function named power that accepts two parameters containing integer values (x and n, in that order) and recursively calculates and returns the value of x to the nth power.
Answer:
Following are the code to the given question:
int power(int x, int n)//defining a method power that accepts two integer parameters
{
if (n == 0)//defining if block to check n equal to 0
{
return 1; //return value 1
}
else//defining else block
{
x = x * power(x, --n); //use x variable to call method recursively
}
return x; //return x value
}
Explanation:
In the above-given code, a method power is defined that accepts two integer variable in its parameter, in the method a conditional statement is used which can be defined as follows:
In the if block, it checks "n" value, which is equal to 0. if the condition is true it will return value 1.In the else block, an integer variable x is defined that calls the method recursively and return x value.Write a function named findmax()that finds and displays the maximum values in a two dimensional array of integers. The array should be declared as a 10 row by 15 column array of integers in main()and populated with random numbers between 0 and 100.
Answer:
import java.util.*;
public class Main
{
public static void main(String[] args) {
Random r = new Random();
int[][] numbers = new int[10][15];
for (int i=0; i<10; i++){
for (int j=0; j<15; j++){
numbers[i][j] = new Random().nextInt(101);
}
}
for (int i=0; i<10; i++){
for (int j=0; j<15; j++){
System.out.print(numbers[i][j] + " ");
}
System.out.println();
}
findmax(numbers);
}
public static void findmax(int[][] numbers){
int max = numbers[0][0];
for (int i=0; i<10; i++){
for (int j=0; j<15; j++){
if(numbers[i][j] > max)
max = numbers[i][j];
}
}
System.out.println("The max is " + max);
}
}
Explanation:
*The code is in Java.
Create a function called findmax() that takes one parameter, numbers array
Inside the function:
Initialize the max as first number in the array
Create a nested for loop that iterates through the array. Inside the second for loop, check if a number is greater than the max. If it is set it as the new max
When the loop is done, print the max
Inside the main:
Initialize a 2D array called numbers
Create a nested for loop that sets the random numbers to the numbers array. Note that to generate random integers, nextInt() function in the Random class is used
Create another nested for loop that displays the content of the numbers array
Call the findmax() function passing the numbers array as a parameter
Are Dogs are better than video games?
Answer:
In some cases yes.
Explanation:
Some days I really enjoy my video games and other days I enjoy being with my dog but sometimes they are annoying especially if they have way more energy than you
Write a program that contains three methods:
Method max (int x, int y, int z) returns the maximum value of three integer values.
Method min (int X, int y, int z) returns the minimum value of three integer values.
Method average (int x, int y, int z) returns the average of three integer values.
Answer:
#include <stdio.h>//defining header file
int max (int x, int y, int z) //defining a method max that hold three parameters
{
if(x>=y && x>=z)//defining if block that checks x is greater then y and x is greater then z
{
return x;//return the value x
}
else if(y>z)//defining else if block it check y is greater then z
{
return y;//return the value y
}
else//else block
{
return z;//return the value z
}
}
int min (int x, int y, int z) //defining a method max that holds three parameters
{
if(x<=y && x<=z) //defining if block that check x value is less then equal to y and less then equal to z
{
return x;//return the value of x
}
if(y<=x && y<=z) //defining if block that check y value is less then equal to x and less then equal to z
{
return y;//return the value of y
}
if(z<=x && z<=x)//defining if block that check z value is less then equal to x
{
return z;//return the value of z
}
return x;//return the value of z
}
int average (int x, int y, int z) //defining average method that take three parameters
{
int avg= (x+y+z)/3;//defining integer variable avg that calculate the average
return avg;//return avg value
}
int main()//defining main method
{
int x,y,z;//defining integer variable
printf("Enter first value: ");//print message
scanf("%d",&x);//input value from the user end
printf("Enter Second value: ");//print message
scanf("%d",&y);//input value from the user end
printf("Enter third value: ");//print message
scanf("%d",&z);//input value from the user end
printf("The maximum value is: %d\n", max(x,y,z));//calling the method max
printf("The minimum value is: %d\n", min(x,y,z));//calling the method min
printf("The average value is: %d\n", average(x,y,z));//calling the method average
return 0;
}
Output:
Enter first value: 45
Enter Second value: 35
Enter third value: 10
The maximum value is: 45
The minimum value is: 10
The average value is: 30
Explanation:
In the above-given code, three methods "max, min, and average" is declared that holds three integer variable "x,y, and z" as a parameter and all the method work as their respective name.
In the max method, it uses a conditional statement to find the highest number among them.In the min method, it also uses the conditional statement to find the minimum value from them.In the average method, it defined an integer variable "avg" that holds the average value of the given parameter variable.In the main method, three variable is defined that inputs the value from the user end and passes to the method and print its value.