Explanation:
Refractive Index is a value calculated from the ratio of the speed of light in a vacuum to that in a second medium of greater density. The refractive index variable is most commonly symbolized by the letter ‘n’ or n’ in a descriptive text and mathematical equations.
is 468km per minute describing speed or velocity
Example of kinetic to thermal? And explain how the energy is changing forms? Please help
Answer:
Indeed
Explanation:
Answer:
A roller coaster that is running heating up the rails
Explanation:
the enery is changing forms due to friction and cunduction
which term describes when a substance is changed from a liquid to a gas
Answer:
vasporisation
Explanation:
process used to change liquid to gass
Answer:
I believe it's Evaportation or another word would be Vaporisation.
Explanation:
hope this helps! ^^
Sodium and phosphorus combine to form Na3P. What is the name of this compound? phosphorus sodiate phosphorus sodide sodium phosphate sodium phosphide
Answer:
Sodium phosphide
Explanation:
Answer:
sodium phosphide
Explanation:
i just took the test. Good luck!! Have a great day!!
A tennis ball covers a distance of 12 meters in 0.4 seconds what is the velocity of the tennis ball?
Answer:
30m/s
Explanation:
Given parameters:
Distance = 12m
Time taken = 0.4s
Unknown:
Velocity of the tennis ball = ?
Solution:
Velocity of a body is the displacement per unit of time.
Velocity = [tex]\frac{displacement}{time}[/tex]
So;
Velocity = [tex]\frac{12}{0.4}[/tex] = 30m/s
The net force acting on this object is 200N to the left. What is the force of friction and air resistance combined if the thrust force is 500N?
Answer:
Explanation:
Force of friction and air resistance acts against the external force . Let it be f .
net force = external force - frictional force and air resistance
Putting the given values
200 = 500 - f
f = 500 - 200 = 300 N .
Hence force of friction = 300 N .
A 1.5 kg block moves at 4 m/s
Answer:
12 joules
Explanation:
I'm assuming you're looking for kinetic energy?? Kinetic energy is 1/2 mv^2. 4 squared is 16, 16 times 1.5 = 24. 24/2 = 12.
A car drives in a circle at 56 km/hr. Which of
the following accurately describes the
motion of the car? The car's -
speed and velocity are both constant.
velocity is constant but speed is changing.
speed is constant but velocity is changing.
speed and velocity are both changing.
Answer:
Speed is constant but velocity is changing
Explanation:
Speed is a scalar quantity, meaning magnitude only. Velocity is a vector quantity, meaning magnitude and direction. If you're moving in a circle at a constant speed, the speed is constant but the direction is constantly changing. Therefore, the speed is constant but velocity changes.
What does AS>0 mean?|
I
Answer:
Significant Other
Explanation:
that comes to mind when I see that
1) Li + ČI>LICI
How many atoms are in this?
Answer:
2 atoms
Explanation:
A 50 kg bumper car with a 40 kg child and it is at rest when a 60 kg child in her own bumper car slams into it the collision last point1 seconds and the rubber bumpers are perfectly bouncy with no heating from the collision what is the force experienced by the first car
Answer:
F = 99 v₂₀
v₂₀ = 1 m / s, F = 99 N
Explanation:
In this exercise it is asked to find the force during the collision, for this we use the relationship between the momentum and the momentum of car 1
I = Δp
F t = p_f- p₀
F t = m (v_f -v₀) (1)
We must find the final speed of car 1, for this we define a system formed by the two cars, in this case the forces during the collision are internal and the moment is conserved
initial instant. Before the crash
p₀ = 0 + m₂ v₂₀
final instant. After the crash
p_f = m₁ v₁ + m₂ v_{2f}
the moment is preserved
p₀ = p_f
m₂ v₂₀ = m₁ v_{1f} + m₂ v_{2f} (2)
m₂ (v₂₀ - v_2f}) = m₁ v_{1f}
as the collision is elastic the kinetic energy is also conserved
K₀ = K_f
½ m₂ v₂₀² = ½ m₁ v_{1f}² + ½ m₂ v_{2f}²
m₂ (v₂₀² -v_{2f}²) = m₁ v_{1f}²
let's write our system of equations, using
a² - b² = (a + b) (a-b)
m₂ (v₂₀ - v_{2f}) = m₁ v_{1f}
m₂ (v₂₀ -v_{2f}) (v₂₀ + v_{2f}) = m₁ v_{1f}²
to solve we divide the equations
v₂₀ + v_{2f} = v_{1f}
with this we substitute in equation 2 and find the speed of each car, in this case we need the speed of car 1
m₂ v₂₀ = m₁ v_{1f} + m₂ (v_{1f}-v₂₀)
2m₂ v₂₀ = (m₁ + m₂) v_{1f}
v_{1f} = [tex]\frac{2m_2}{m_1+m_2} v_{2o}[/tex]
We substitute in the drive ratio of car 1
F t = m (v_f -v₀)
F = m₁ (\frac{2m_2}{m_1+m_2} v_{2o} - 0) / t
F = [tex]\frac{2m_1 m_2 }{m_1+m_2} \ \frac{v_{2o}}{t}[/tex]
the mass of each car is the mass of the car plus the mass of the boy
m₁ = 50 +40 = 90 kg
m₂ = 50 +60 = 110 kg
time is t = 1
we substitute the values
F = [tex]\frac{ 2\ 90 \ 110}{90+110} \ \frac{v_{2o}}{1}[/tex]2 90 100/90 + 110 vo2 / 1
F = 99 v₂₀
The value of the initial velocity of car 2 is not indicated in the problem, if this velocity is known it can be included and the force value is obtained, suppose that the initial velocity v₂₀ = 1 m / s
F = 99 N
A force of 900 N pushes a wedge 0.10 m into a log. If the work done on the log is 50 J, what is the efficiency of the wedge?
Answer:
I'm fairly certain it's 1,800
Explanation:
The efficiency of the wedge with force F=900 N displaces the wedge 0.10 m is 55.55% or 56%.
What is the efficiency of the machine?The efficiency of the machine equals the ratio of output energy and input energy. It is also defined as the ratio of work done on a load by the machine to the work done on the effort by the machine.
A load is defined as the weight lifted by the machine. The effort is defined as the force applied to bring the desired change in the load. Work done is defined as the product of force and displacement.
The efficiency, η = Output power / Input power, and the highest efficiency of the machine is equal to one. The efficiency of the machine has no unit. The efficiency η = (Actual work done / Ideal work done) × 100.
From the given,
Force = 900 N
Displacement = 0.1 m
Work done = F × s = 900×0.1 = 90 J
Actual work done = 50 J
Efficiency,η = (50/90) × 100
η = 55.55 %
Thus, the efficiency of the wedge is 55.56%.
To learn more about the Efficiency of a machine:
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