Answer:
If you mix equal amounts of a strong acid and a strong base, the two chemicals essentially cancel each other out and produce a salt and water. Mixing equal amounts of a strong acid with a strong base also produces a neutral pH (pH = 7) solution.
How many moles of aspirin (C9H8O4) are contained in 3.13 g of aspirin?
Answer:
The correct answer is - 0.0173888 moles.
Explanation:
Aspirin, C 9 H 8 O 4 , the atomic mass rounded to the nearest whole number, so: c- 12 h- 1 o - 16
now multiply these number by how many of each there are in the formula:
c - 12 x 9 = 108
h - 1 x 8 = 8
0 - 16 x 4 = 64
add these numbers up 108 + 8 + 64 = 180
aspirin has a molar mass of
180.g mol ^− 1 . This means that one mole of aspirin will have a mass of 180 g .
You're dealing with 3.13 g of aspirin, which will be equivalent to
3.13 g /180g
= 0.0173888 moles aspirin
which wet land is known for the large trees in the water known as bottomland hardwoods?
A. Central Texas
B.South Texas
C. East texas
how many atoms of carbon are in a diamond with a mass of 0.568 g?
Answer:
There are 2.85 x 10^22 atoms of carbon in a diamond with a mass of 0.568 g.
Hope this helps! :)
Methane and sulfur react to produce carbon disulfide (CS₂), a liquid often used in the production of cellophane.
2CH₄ + S₈ --> 2CS₂ + 4H₂S
Calculate the moles of H₂S produced when 2.25 mol S₈ is used.
Answer:
9 moles
Explanation:
The balanced chemical equation provided in this question is as follows:
2CH₄ + S₈ → 2CS₂ + 4H₂S
In accordance to the above balanced equation, 1 mole of sulphur (S8) produces 4 moles of hydrogen sulfide (H2S).
Therefore, if 2.25mol of S8 is used, 2.25 × 4 = 9 mol
9 moles of H2S is produced.
A 20 g granite boulder absorbs 300.2 Joules of energy from the Sun, resulting in its temperature
changing. Calculate this temperature change
Answer:
19 °C
Explanation:
Step 1: Given and required data
Mass of granite (m): 20 gHeat absorbed (Q): 300. 2 JSpecific heat capacity of granite (c): 0.790 J/g.°CStep 2: Calculate the temperature change (ΔT)
We will use the following expression.
Q = c × m × ΔT
ΔT = Q/c × m
ΔT = 300.2 J/(0.790 J/g.°C) × 20 g = 19 °C