Answer:
option A
a variable is a number which is always changing
an expression doesn't have an equal sign
a quadratic equation is an equation which has one variable but the highest power of that variable is 2
so the answer is a literal equation or linear equation in two variables
A hobby store pays $20 wholesale for drones and marks them up 40%. What is the retail price of each drone?
Answer:
$28.00
Step-by-step explanation:
20 x 1.4
Answer:
$28
Step-by-step explanation:
To find the retail price you have to find 40% of 20 and then add that value to 20.
To find 40% of 20 let's convert 40% into decimal form: 0.4
Then you multiply: 20 * 0.4 = 8
Now you add 8 to the original 20: 20 + 8 = 28
The retail price of each drone is $28.
I hope this helps :)
What is the result of 4 divided by one-half? A number line going from 0 to 4. 2 8 12 16
Answer:
2
4/.5 = 2
Therefore, your answer is 2, or A. Hope this helped!
Answer:
the answer is B) 8
Step-by-step explanation:
hope this helped sorry if it didn't and if it's wrong sorry for that also.
4x-3=2x+7 Someone Help Please
Answer:
x=5
Step-by-step explanation:
4x-3=2x+7
subtract 2x from both sides
2x-3=7
add 3 to both sides
2x=10
divide both sides by 2
x=5
Answer:
x = 5
Step-by-step explanation:
Original Equation:
4x - 3 = 2x + 7
Add 3 to both sides
4x = 2x + 10
Subtract 2x from both sides
2x = 10
Divide both sides by 2
x = 5
Hope this helps :)
Please consider Brainliest :)
16.9 and 1.7 and 0.17 and 2.0 added up
Answer:
20.77
Step-by-step explanation:
Answer:
20.77
Step-by-step explanation:
Simplify 16.9+ 1.7 to 18.6
18.6 +0.17+2.0
Simplify 18.6+0.17 to 18.77
18.77+2.0
Simplify.
ANddddd the answer is
20.77
You have fit a regression model with two regressors to a data set that has 20 observations. The total sum of squares is 1000 and the model sum of squares is 750.(a) What is the value of R2 for this model?(b) What is the adjusted R2 for this model?(c) What is the value of the F-statistic for testing the significance of regression? What conclusions would you draw about this model if α = 0.05? What if α = 0.01?(d) Suppose that you add a third regressor to the model and as a result, the model sum of squares is now 785. Does it seem to you that adding this factor has improved the model?
Answer:
0.75
0.7205882
25.5
Result is significant at α = 0.01 and α = 0.05
Model improved
Step-by-step explanation:
Given that:
Number of observations (n) = 20
Total sum of squares (SST) = 1000
Model sum of squares (SSR) = 750
1) R² = SSR / SST = 750 / 1000 = 0.75
2.)
Adjusted R² = [(SST - SSR) /(n-k-1)] / (SST ÷ (n - 1))
k = number of regressors = 2
Adj R² = 1 - ((1000 - 750) / (20-2-1)) / (1000 / (20 - 1))
1 - 0.2794117 = 0.7205882
3.) Fstat = (SSR / k) / ((SST - SSR) / (n - k-1))
= (750 /2) / ((1000 - 750) / (20 - 2 - 1))
= 25.5
4.) At α = 0.05
Fα,k,(n - k-1) = F0.05, 2, (20 - 2 - 1) = F0.05,2, 17 = 3.5915 (f distribution calculator)
Fstat > F0.05, 2, (20 - 2 - 1)
25.5 > 3.5915 (Hence result is significant at α = 0.05
At α = 0.01
Fα,k,(n - k-1) = F0.01, 2, (20 - 2 - 1) = F0.01,2, 17 = 6.112 (f distribution calculator)
Fstat > F0.01, 2, (20 - 2 - 1)
25.5 > 6.112 (Hence result is significant at α = 0.01
Adjusted R² if a 3rd regressors is added : k = 3
Adjusted R² = [(SST - SSR) /(n-k-1)] / (SST ÷ (n - 1))
k = number of regressors = 3
SSR = 785
Adj R² = 1 - ((1000 - 785) / (20-3-1)) / (1000 / (20 - 1))
1 - 0.2553125 = 0.7446875
Adjusted R² value is now 0.7446875 which is greater than with 2 regressors,. Hence, adding a third regressors improved the model.
A 0.8-liter bottle of Mexican wine costs 100 pesos. At that price, how much would a halfgallon jug of the same wine cost in dollars? Mexican peso Dollars per foreign: 0.07855 Foreign per dollar: 12.73
Answer:
$11.83
Step-by-step explanation:
1 gallon = 3.785 litres
0.5(1/2gallon) = x liters
x = 0.5 × 3.785 liters
x = 1.89271 liters
0.8 liter = 100 pesos
1.89271 liters = x pesos
x = 1.89271 × 100/0.8
x = 236.58875 pesos
Converting to dollars
1 mexican peso = $0.050
236.58875 pesos = x
x = 236.58875 × $0.050
x = $11.8294375
Approximately = $11.83
A half gallon jug of the same wine cost in dollars $11.83
PLZZ help thxxxxxx..........
Answer:
A
Step-by-step explanation:
A concession stand sell hot dogs and hamburgers. At a football game, 84 hot dogs and 36 hamburgers were sold for $276. At another football game, 60 hotdogs and 18 hamburgers were sold for $174. Wrote a system of equations to represent this situation. Then solve the system of equations.
Answer:
84x + 36y =$276
60x + 18y =$174
then solve
Step-by-step explanation:
x- hot dogs, y- hamburgers
1st football game- 84x + 36y =$276
2nd football game- 60x + 18y =$174
What is the quotient in simplest form?
Three-fourths divided by StartFraction 5 Over 16 EndFraction
StartFraction 15 Over 64 EndFraction
StartFraction 15 Over 16 EndFraction
2 and two-fifths
2 and StartFraction 8 Over 20 EndFraction
Answer:
2 and 2/5
Step-by-step explanation:
Trust me on this, also can I have brainlest please? Hope you do well!
2 and two fifths i took the test 6 years ago
Write 7/25 as a decimal show your work
Answer:
0.28 is a decimal and 28/100 or 28% is the percentage for 7/25.
Step-by-step explanation:
i needhelp one more little crown plzz
25x4=100
7x4=28
28/100
0.28
28%
i barely remember how to do this
should b a decimal in between 7 and 00 i think idk
In what quadrant of the complex plane is -30-40i
Emile is a long-distance runner. He runs at a constant speed of six miles/hour. His goal is to run nine miles on each practice run, but he normally runs a distance that varies three miles more or less than that. Select the correct answer from each drop-down menu. The equation that can be used to find the minimum and maximum time (in hours) Emile runs is_____. For each practice run, the minimum number of hours Emile runs is______ and the maximum number of hours he runs is ______.
Answer:
[tex]t=\dfrac{9\pm 3}{6}[/tex]
[tex]1\ \text{hour}[/tex]
[tex]2\ \text{hour}[/tex]
Step-by-step explanation:
s = Speed of Emile = 6 miles/hour
d = Distance traveled by Emile = [tex](9\pm 3)\ \text{miles}[/tex]
Time taken to find the minimum and maximum time Emile ran for is
[tex]t=\dfrac{d}{s}\\\Rightarrow t=\dfrac{9\pm 3}{6}[/tex]
The required equation is [tex]t=\dfrac{9\pm 3}{6}[/tex]
The time taken is
[tex]t=\dfrac{9-3}{6}\\\Rightarrow t=\dfrac{6}{6}\\\Rightarrow t=1\ \text{hour}[/tex]
The minimum number of hours Emile runs is 1 hour.
[tex]t=\dfrac{9+3}{6}\\\Rightarrow t=\dfrac{12}{6}\\\Rightarrow t=2\ \text{hour}[/tex]
The maximum number of hours Emile runs is [tex]2\ \text{hour}[/tex].
Answer:
|6x – 9| = 3
1 Hour
2 Hours
Step-by-step explanation:
The equation that can be used to find the minimum and maximum time (in hours) Emile runs is_|6x – 9|= 3_. For each practice run, the minimum number of hours Emile runs is__1 hour_ and the maximum number of hours he runs is _2 hour.
At Green Island Farms the annual Turkey Trot is being held. This year’s contestants are Tom Turkey, Gary Gobbler and Donny Drumstick. The turkeys chase little RC cars loaded with feed. The buzzer sounds and the turkeys are off. Gary Gobbler chases his RC car trying to eat that sweet turkey feed for 15 feet before he manages to side swipe the RC car and knock it on its side. All the feed spills out and Gary Gobbler gobbles it down. That silly turkey happily eats his food for 1.75 seconds. A mouse comes out of the hay bale and tries to join Gary Gobbler in his feasting. But Gary Gobbler is scared of mice so when he sees the mouse he freaks out and tears down the racetrack.
Write a similar story for Tom Turkey making sure to include the different segments of the graph.
Answer:
The company is expected the company will receive
pls help i have pictures pls explain how you get your answer
Answer:
0.75
Step-by-step explanation:
To find the slope of the graph, you have to find the rise and the run by any two points on the graph. (I'm going to calculate using the two blue dots as shown in the picture)
[tex]\frac{rise}{run}[/tex] = [tex]\frac{(-2)-(-5)}{4-0}[/tex]
= [tex]\frac{-2+5}{4}[/tex]
= [tex]\frac{3}{4}[/tex]
= 0.75
50 points please help please see image below
Answer:
395.841Step-by-step explanation:
surface area = 2πrh + 2πr²
where r = 7 m radius
h = 2 m
plugin values into the formula
surface area = 2πrh + 2πr²
= 2π (7) 2 + 2π (7)²
= 87.965 + 307.867
= 395.841 m²
Answer:
395.841 m²
Step-by-step explanation:
surface area = 2πrh + 2πr² and r = 7 m radius
h = 2 m
Plugin
2π (7) 2 + 2π (7)²
multiply into itself than add
87.965 + 307.867
add
395.841 m²
Therefore your answer would be 395.841 m²
Ryanne is 14. Her brother’s age is three more than half her age. How old is her brother?
Answer:
Her brother is 10 years old
Step-by-step explanation:
14 ÷ 2 = 7
7 + 3 = 10
The answer is 10
Assume that the wavelengths of photosynthetically active radiations (PAR) are uniformly distributed at integer nanometers in the red spectrum from 675 to 695 nm. What is the mean, ?, and variance, ?2, of the wavelength distribution for this radiation? Round your answers to one decimal place.
mean, ? =
variance, ?2 =
Answer:
Mean=685
Variance=36.7
Step-by-step explanation:
The mean of uniform discrete distribution can be expressed as the average of the boundaries
mean=( b+a)/2
The variance of uniform discrete distribution can be expressed as the difference of the boundaries decreased by 1 and squared, decreased by 1 and divided by 12.
σ²=[(b-a+1)^2 - 1]/12
We were given the wavelength from from 675 to 695 nm which means
a= 675, b= 695
We can now calculate the mean by using the expresion below
mean=( b+a)/2
Mean=( 675 + 695)/2
=685
The variance can be calculated by using the expression below
σ²=[(b-a+1)^2 - 1]/12
σ²=[(695-675+1)^2 -1]/12
σ²=440/12
σ²=36.7
Therefore, the the mean and variance, of the wavelength distribution for this radiation are 685 and 36.7 respectively
write the equation of a line perpendicular to y=7 that passes through (2,13)
segment AB is dilated from the origin to create segment A prime B prime at A' (0, 6) and B' (6, 9). What scale factor was segment AB dilated by?
As you forgot to mention the diagram. I was able to find the diagram. Hence, I am attaching and solving the question based on that diagram, which anyways would clear your concept.
Answer:
we conclude that the segment AB was dilated by scale factor 3.
Step-by-step explanation:
From the diagram, it is clear that the original points A and B are located
at (0, 2) and (2, 3) respectively.
i.e.
A(0, 2)B(2, 3)As the coordinates of the dilated segment A'B' are given as:
A'(0, 6)B'(6, 9)A scale factor is basically a number that multiplies an object or quantity.
For instance, the 'D' in [tex]y = Dx[/tex] is the scale factor for x.
If the equation were y = 7x, then the factor would have been 5.
As the coordinates of the dilated segment A'(0, 6) and B'(6, 9) are 3 times the coordinates of the original segment A(0, 2) and B(2, 3).
i.e.
A(0, 2) → (0×3, 2×3) = A'(0, 6)
B(2, 3) → (2×3, 3×3) = B'(6, 9)
Therefore, we conclude that the segment AB was dilated by scale factor 3.
Answer:
Segment AB was dilated by scale factor 3.
Step-by-step explanation:
The person above is correct tahnk you!!!
What is the equation in slope-intercept from of the line that passes through the point (3, 1) and is parallel to the line represented by y = 2.4x + 6.5?
Solve the system of equations.
−2x+5y =−35
7x+2y =25
Answer:
The equations have one solution at (5, -5).
Step-by-step explanation:
We are given a system of equations:
[tex]\displaystyle{\left \{ {{-2x+5y=-35} \atop {7x+2y=25}} \right.}[/tex]
This system of equations can be solved in three different ways:
Graphing the equations (method used)Substituting values into the equationsEliminating variables from the equationsGraphing the Equations
We need to solve each equation and place it in slope-intercept form first. Slope-intercept form is [tex]\text{y = mx + b}[/tex].
Equation 1 is [tex]-2x+5y = -35[/tex]. We need to isolate y.
[tex]\displaystyle{-2x + 5y = -35}\\\\5y = 2x - 35\\\\\frac{5y}{5} = \frac{2x - 35}{5}\\\\y = \frac{2}{5}x - 7[/tex]
Equation 1 is now [tex]y=\frac{2}{5}x-7[/tex].
Equation 2 also needs y to be isolated.
[tex]\displaystyle{7x+2y=25}\\\\2y=-7x+25\\\\\frac{2y}{2}=\frac{-7x+25}{2}\\\\y = -\frac{7}{2}x + \frac{25}{2}[/tex]
Equation 2 is now [tex]y=-\frac{7}{2}x+\frac{25}{2}[/tex].
Now, we can graph both of these using a data table and plotting points on the graph. If the two lines intersect at a point, this is a solution for the system of equations.
The table below has unsolved y-values - we need to insert the value of x and solve for y and input these values in the table.
[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & a \\ \cline{1-2} 1 & b \\ \cline{1-2} 2 & c \\ \cline{1-2} 3 & d \\ \cline{1-2} 4 & e \\ \cline{1-2} 5 & f \\ \cline{1-2} \end{array}[/tex]
[tex]\bullet \ \text{For x = 0,}[/tex]
[tex]\displaystyle{y = \frac{2}{5}(0) - 7}\\\\y = 0 - 7\\\\y = -7[/tex]
[tex]\bullet \ \text{For x = 1,}[/tex]
[tex]\displaystyle{y=\frac{2}{5}(1)-7}\\\\y=\frac{2}{5}-7\\\\y = -\frac{33}{5}[/tex]
[tex]\bullet \ \text{For x = 2,}[/tex]
[tex]\displaystyle{y=\frac{2}{5}(2)-7}\\\\y = \frac{4}{5}-7\\\\y = -\frac{31}{5}[/tex]
[tex]\bullet \ \text{For x = 3,}[/tex]
[tex]\displaystyle{y=\frac{2}{5}(3)-7}\\\\y= \frac{6}{5}-7\\\\y=-\frac{29}{5}[/tex]
[tex]\bullet \ \text{For x = 4,}[/tex]
[tex]\displaystyle{y=\frac{2}{5}(4)-7}\\\\y = \frac{8}{5}-7\\\\y=-\frac{27}{5}[/tex]
[tex]\bullet \ \text{For x = 5,}[/tex]
[tex]\displaystyle{y=\frac{2}{5}(5)-7}\\\\y=2-7\\\\y=-5[/tex]
Now, we can place these values in our table.
[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & -7 \\ \cline{1-2} 1 & -33/5 \\ \cline{1-2} 2 & -31/5 \\ \cline{1-2} 3 & -29/5 \\ \cline{1-2} 4 & -27/5 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}[/tex]
As we can see in our table, the rate of decrease is [tex]-\frac{2}{5}[/tex]. In case we need to determine more values, we can easily either replace x with a new value in the equation or just subtract [tex]-\frac{2}{5}[/tex] from the previous value.
For Equation 2, we need to use the same process. Equation 2 has been resolved to be [tex]y=-\frac{7}{2}x+\frac{25}{2}[/tex]. Therefore, we just use the same process as before to solve for the values.
[tex]\bullet \ \text{For x = 0,}[/tex]
[tex]\displaystyle{y=-\frac{7}{2}(0)+\frac{25}{2}}\\\\y = 0 + \frac{25}{2}\\\\y = \frac{25}{2}[/tex]
[tex]\bullet \ \text{For x = 1,}[/tex]
[tex]\displaystyle{y=-\frac{7}{2}(1)+\frac{25}{2}}\\\\y = -\frac{7}{2} + \frac{25}{2}\\\\y = 9[/tex]
[tex]\bullet \ \text{For x = 2,}[/tex]
[tex]\displaystyle{y=-\frac{7}{2}(2)+\frac{25}{2}}\\\\y = -7+\frac{25}{2}\\\\y = \frac{11}{2}[/tex]
[tex]\bullet \ \text{For x = 3,}[/tex]
[tex]\displaystyle{y=-\frac{7}{2}(3)+\frac{25}{2}}\\\\y = -\frac{21}{2}+\frac{25}{2}\\\\y = 2[/tex]
[tex]\bullet \ \text{For x = 4,}[/tex]
[tex]\displaystyle{y=-\frac{7}{2}(4)+\frac{25}{2}}\\\\y=-14+\frac{25}{2}\\\\y = -\frac{3}{2}[/tex]
[tex]\bullet \ \text{For x = 5,}[/tex]
[tex]\displaystyle{y=-\frac{7}{2}(5)+\frac{25}{2}}\\\\y = -\frac{35}{2}+\frac{25}{2}\\\\y = -5[/tex]
And now, we place these values into the table.
[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & 25/2 \\ \cline{1-2} 1 & 9 \\ \cline{1-2} 2 & 11/2 \\ \cline{1-2} 3 & 2 \\ \cline{1-2} 4 & -3/2 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}[/tex]
When we compare our two tables, we can see that we have one similarity - the points are the same at x = 5.
Equation 1 Equation 2
[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & -7 \\ \cline{1-2} 1 & -33/5 \\ \cline{1-2} 2 & -31/5 \\ \cline{1-2} 3 & -29/5 \\ \cline{1-2} 4 & -27/5 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}[/tex] [tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & 25/2 \\ \cline{1-2} 1 & 9 \\ \cline{1-2} 2 & 11/2 \\ \cline{1-2} 3 & 2 \\ \cline{1-2} 4 & -3/2 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}[/tex]
Therefore, using this data, we have one solution at (5, -5).
If x = 3 + 2√2, then the value of (x - 1/x) is
a) 4√2
b) 2√4
c) 8
Consider functions f and g.
What is the value of ?
The words don't actually matter, it is the picture that has the question.
Answer:
we get [tex]\mathbf{(g \ o \ f)(4)=9}[/tex]
Option C is correct.
Step-by-step explanation:
We are given:
[tex]f(x)=-x^3\\g(x)= |\frac{1}{8}x-1|[/tex]
We need to find (g о f)(4)
For finding (g о f)(4) we will first find g(f(x)) i.e putting value of f(x) inside g(x) and then put x=4
[tex](g \ o \ f)(x)=g(f(x))\\(g \ o \ f)(x)=|\frac{1}{8}(-x^3)-1 |[/tex]
Now, putting x=4
[tex](g \ o \ f)(x)=|\frac{1}{8}(-x^3)-1 |\\Put \ x=4\\(g \ o \ f)(4)=|\frac{1}{8}(-(4)^3)-1 |\\(g \ o \ f)(4)=|\frac{1}{8}(-64)-1 |\\(g \ o \ f)(4)=|-8-1 |\\(g \ o \ f)(4)=|-9| \\\\We \ will \ use \ absolute \ value \ i.e \ 9 \\(g \ o \ f)(4)=9[/tex]
So, we get [tex]\mathbf{(g \ o \ f)(4)=9}[/tex]
Option C is correct
Answer:
c is correct answer
just use formula
Winston deposited $3,294 in a bank account with an annual interest rate of 2.6%. How much interest was earned in 5
years? Round your answer to two decimal places.
Answer:
FV= $3,725.07
Step-by-step explanation:
Giving the following information:
Initial investment (PV)= $3,294
Number of periods (n)= 5 years
Interest rate (i)= 2.6% = 0.026
To calculate the future value (FV), we need to use the following formula:
FV= PV*(1+i)^n
FV= 3,294*(1.026^5)
FV= $3,725.07
Miguel has $25. He spends $6.75 on a movie ticket, $3.70 for snacks, and $2.00 for bus fare each way.
How much money does Miguel have left?
Miguel has $_____
left.
Answer:
$12.55
Step-by-step explanation:
25-6.75=18.25
18.25-3.70=14.55
14.55-2=12.55
Miguel has $12.55 left
9) Use the spinner below to answer the following questions
What is the Expected Value of a single spln?
Answer:
is that paper or did you write on the screen?
What's the largest odd number you can make using all four digits 4, 5, 3, 6
Answer:
6543
Step-by-step explanation:
Not much to explain lol
Here,
Odd numbers are 3 and 5.
5>3The largest odd number =6543
Write the given trinomial if possible as a square of a binomial or as an expression opposite to a square of a binomial: 15ab-9a^2-6 1/4b^2
Answer:
[tex] - \bigg(3a - \frac{5}{2} b) \bigg)^{2} [/tex]
Step-by-step explanation:
[tex]15ab-9a^2-6 \frac{1}{4} b^2 \\ \\ = 15ab-(3a)^2-\frac{6 \times 4 + 1}{4} b^2 \\ \\ = 15ab-(3a)^2-\frac{24+ 1}{4} b^2 \\ \\ = 15ab-(3a)^2-\frac{25}{4} b^2 \\ \\ = 15ab- (3a)^2- \bigg(\frac{5}{2} b \bigg)^2 \\ \\ = - \{ - 15ab + (3a)^2 + \bigg(\frac{5}{2} b \bigg)^2 \} \\ \\ = - \{ (3a)^2 + \bigg(\frac{5}{2} b \bigg)^2 - 15ab \} \\ \\ = - \bigg(3a - \frac{5}{2} b \bigg)^{2} [/tex]
3) How many counting numbers less than 50 are multiples of both 3 and 5?
Answer: 3 numbers
Step-by-step explanation:
For this questions to be solved, we need to write the multiples of both 3 abd 5 that are less than 50. This will be:
Multiples of 3 = 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48
Multiples of 5 = 5, 10, 15, 20, 25, 30, 35, 40, 45.
Common multiples = 15, 30 and 45
Therefore, the numbers that is less than 50 that are multiples of both 3 and 5 are 3 numbers
I need the missing length help (10 points )
Answer:
5.38516480713
Step-by-step explanation:
a^2+b^2=c^2
5^2+2^2=c^2
25+4=c^2
c^2=square root of 29
c=5.38516480713