The correct response, based on the facts provided, is 625.
What does a math power mean?
When a base number is raised to an exponent in mathematics, the exponent represents how many times the base number has been multiplied, and the base amount is the factor that is multiplied by itself.
What do you call 5 to the power of?
In mathematics and mathematics, the fifth power, or subsolid, of a number, n, is obtained by multiplying five occurrences of n around each other:[tex]n⁵ = n × n × n × n × n.[/tex]The fourth power of a number or the squares of a number of times its cube can also be used to create fifth powers.
5 to the fourth power (also written as 5⁴) is:
[tex]5 × 5 × 5 × 5 = 625[/tex]
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For circle B, if BG=BE, what conclusion can be made
If BG=BE, we can conclude that triangle BGE is an isosceles triangle.
In a circle, the radius is a line segment that connects the center of the circle to any point on the circle. Therefore, BG and BE are both radii of the circle. In an isosceles triangle, two sides have the same length, and the third side is a different length. In this case, the two sides with the same length are BG and BE, and the third side is GE. Since BG and BE are radii of the circle and therefore have the same length, we can conclude that triangle BGE is isosceles, and the angles opposite BG and BE are congruent.
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The price of a 9 minute phone call is $3. 15. What is the price of a 14 minute phone call
The price of a 14 minute phone call is $4.90.
We can use the given information to set up a proportion between the price and the duration of a phone call:
price of 9-minute call / 9 = $3.15 / 1
We can then solve for the price of a 1-minute call:
price of 1-minute call = ($3.15 / 1) / 9 = $0.35
Now that we know the price of a 1-minute call, we can use it to find the price of a 14-minute call:
price of 14-minute call = ($0.35 / 1) * 14 = $4.90
Therefore, the price of a 14 minute phone call is $4.90.
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The heel of a show exerts a pressure of 198 pounds per square inch.
Convert this pressure into kilograms per square centimetre
use:
1 pound = 0.45 kilograms
1 square inch = 6.25 square centimetres
Step-by-step explanation:
1 pound = 0.45 kilograms
1 square inch = 6.25 square centimeters
First, let's convert the pressure from pounds per square inch to kilograms per square inch:
198 pounds/square inch × 0.45 kilograms/pound = 89.1 kilograms/square inch
Next, let's convert from kilograms per square inch to kilograms per square centimeter:
1 square inch = 6.25 square centimeters
89.1 kilograms/square inch ÷ 6.25 square centimeters/square inch = 14.256 kilograms/square centimeter
Therefore, the pressure of 198 pounds per square inch is equivalent to 14.256 kilograms per square centimeter.
Select the correct end behavior for the given graph or equation of an exponential
function.
Through end behaviour of polynomials, we can see that the left end behaviour is approaching positive infinity and the right end behaviour is approaching negative infinity.
What do you mean by end behaviour of polynomials?The nature of the value when the function argument gets closer to + infinity and - infinity is the end behaviour of a function.
The term with the highest degree determines how a polynomial function will behave in the end.
For example:
If f(x) = x³ + 2x² – 4x + 5 is given,
The end behaviour is determined by x³.
As a result, f(x) + as x + and f(x) - as x -
The term with the highest degree will be substantially larger than the other terms for large values of x, making the other terms essentially irrelevant.
The degree of the x³ coefficient is odd and it is positive.
Hence, the final behaviour is f(x) + as x + and f(x) - as x -.
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Please help I have a lot of trouble with math and i don't really understand how to do this
Find figure B
So, the volume of big cone is 226.08 cu ft for this we have to know about volume.
What do you meant by volume?The area occupied within any three-dimensional solid's borders is known as its volume.
Given, radius of small cone, r = 2 ft
Volume of small cone 25.12 cu ft
[tex]So\ Volume\ of\ small\ cone = \pi rl[/tex]
[tex]25.12 = 3.14 * 2*l[/tex]
[tex]l=\frac{25.12}{3.14\ *\ 2}[/tex]
[tex]l = 4ft[/tex]
Since, cones are similar and bai cone radius is 3 times of small cones then ,
Slant height of big cone = 3 * Slant height of small cone
= 3*4 ft
= 12 ft.
[tex]Volume\ of\ big\ cone = \pi rl[/tex]
[tex]= 3.14*6*12[/tex]
[tex]= 226.08\ cu ft[/tex]
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A two-variable inequality is shown in the graph.
upward opening parabola which is solid with vertex at 1 comma 2, travels through points negative 1 comma 6 and 3 comma 6, with shading inside the curve
Which point is not included in the solution set for the inequality?
(0, 6)
(1, 5)
(2, 4)
(3, 2)
(0, 6): satisfies the inequality and is included in the solution set.
(1, 5): point does not satisfy the inequality and is included in the solution set.
(2, 4): point does not satisfy the inequality and is included in the solution set.
(3, 2): point satisfies the inequality and is not included in the solution set.
What is inequality?
Inequality is like a rule that says how big or small something can be. It has two things to compare, and a symbol in between like < or >.
The inequality is satisfied by all the points inside the curve. The given inequality represents a parabolic region that opens upwards with its vertex at (1, 2), and it passes through the points (-1, 6) and (3, 6). The region is shaded inside the curve.
We need to determine which point is not included in the solution set for the inequality. To do this, we can check if each point satisfies the inequality.
Let's start with point (0, 6). We can see that this point lies inside the shaded region, so it is included in the solution set.
Next, let's check point (1, 5). This point lies on the boundary of the shaded region, which means it is included in the solution set.
Now, let's check point (2, 4). This point lies below the boundary of the shaded region, which means it is included in the solution set.
Finally, let's check point (3, 2). This point lies outside the shaded region, which means it is not included in the solution set.
Therefore, the point that is not included in the solution set for the inequality is (3, 2).
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Use properties of logarithms to expand the logarithmic expression as much as possible. Where possible, evaluate logarithmic expressions without using a calculator. \[ \log \left[\frac{10 x^{2} \sqrt[3
The evaluated logarithmic expression is: [tex]\[ \log \left[\frac{10 x^{2}}{\sqrt[3]{y}}\right] = 2\log[10] + 2\log[x] + \frac{1}{3}\log[y] \][/tex]
Expression mentioned in the question :[tex]\[ \log \left[\frac{10 x^{2}}{\sqrt[3]{y}}\right][/tex]. . The first property we will use is the Product Rule , so this can be expressed as: [tex][ \log \left[\frac{10 x^{2}}{\sqrt[3]{y}}\right] = \log[10x^{2}] + \log[\sqrt[3]{y}] \].[/tex] We can now apply the Power Rule to the first term, which states that the logarithm of a power is equal to the exponent times the logarithm of the base. This can be expressed as: \[ \log[10x^{2}] = 2\log[10x] \]
We can now apply the Quotient Rule to the second term, which states that the logarithm of a quotient is equal to the difference of the logarithms of the numerator and denominator. This can be expressed as: [tex]\[ \log[\sqrt[3]{y}] = \frac{1}{3} \log[y] \].[/tex] Substituting this back into the original equation gives us:[tex]\[ \log \left[\frac{10 x^{2}}{\sqrt[3]{y}}\right] = 2\log[10x] + \frac{1}{3}\log[y] \][/tex]
We can now evaluate this expression without using a calculator. The two logarithmic terms can be rewritten as:[tex]\[ \log[10x] = \log[10] + \log[x] \, \[ \log[y] = \log[y] \][/tex]
Substituting this back into the original equation gives us: [tex]\[ \log \left[\frac{10 x^{2}}{\sqrt[3]{y}}\right] = 2\log[10] + 2\log[x] + \frac{1}{3}\log[y] \[/tex]
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A child's bank contains 143 coins consisting of nickels and quarters. If the total amount of money is $18.35, find the number of nickels and quarters in the bank.
Answer:
The number of nickels and quarters in the bank are 87 and 56, respectively.
Step-by-step explanation:
Let's denote the number of nickels in the bank as "n" and the number of quarters as "q". Then we can set up a system of two equations based on the given information:
n + q = 143 (equation 1, representing the total number of coins)
0.05n + 0.25q = 18.35 (equation 2, representing the total value of the coins)
To solve this system, we can use substitution or elimination method. Let's use elimination method here:
Multiplying equation 1 by 0.05, we get:
0.05n + 0.05q = 7.15 (equation 3, obtained by multiplying equation 1 by 0.05)
Subtracting equation 3 from equation 2, we get:
0.2q = 11.2
Dividing both sides by 0.2, we get:
q = 56
Substituting this value of q into equation 1, we get:
n + 56 = 143
n = 87
Therefore, there are 87 nickels and 56 quarters in the bank.
Hopefully this helped you! If not, I'm sorry! If you need more help, ask me! :]
There are 7 beads in a bowl. There is a number on each bead. (1) 4 4 5 7 Olly takes at random three of the beads. He works out the sum of the numbers on the three beads. Work out the probability that the sum is an odd number.
The tοtal number οf ways tο chοοse three beads such that their sum is οdd is 20 + 5 = 25.
What is prοbability?Prοbability is a measure οf the likelihοοd οf an event οccurring. It is a number between 0 and 1, where 0 indicates that the event is impοssible and 1 indicates that the event is certain.
Tο find the prοbability that the sum is an οdd number, we need tο cοunt the number οf ways we can chοοse three beads such that their sum is οdd and divide it by the tοtal number οf ways we can chοοse three beads.
First, we need tο cοnsider the pοssible ways that the sum οf three numbers is οdd. This can happen in twο ways:
If we chοοse an οdd number and twο even numbers
If we chοοse an even number and twο οdd numbers
Nοw, let's cοunt the number οf ways we can chοοse three beads in each οf these twο cases:
Case 1: Chοοse οne οdd and twο even numbers
There are twο οdd numbers and five even numbers, sο we can chοοse οne οdd number in 2 ways and twο even numbers in 5C₂ = 10 ways. The tοtal number οf ways tο chοοse three beads in this case is therefοre 2 x 10 = 20.
Case 2: Chοοse οne even and twο οdd numbers
There are twο οdd numbers and five even numbers, sο we can chοοse twο οdd numbers in 2C₂ = 1 way and οne even number in 5 ways. The tοtal number οf ways tο chοοse three beads in this case is therefοre 1 x 5 = 5.
The tοtal number οf ways tο chοοse three beads frοm seven is 7C₃ = 35.
Sο the prοbability that the sum οf the three numbers is οdd is 25/35 = 5/7.
Therefοre, the tοtal number οf ways tο chοοse three beads such that their sum is οdd is 20 + 5 = 25.
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The system had a total of $1,895. Write an equation and solve to determine the cost of the system with the printer
The cost of the system with the printer is $695, given the cost of the system without the printer is $1,200 and the total cost is $1,895.
Let's assume the cost of the system without the printer is x. Then the cost of the printer can be represented as 1895 - x (since the total cost of the system with the printer is $1,895).
We can set up an equation to represent the cost of the system with the printer:
x + (1895 - x) = 1895
Simplifying and solving for x:
x + 1895 - x = 1895
2x = 0
x = 0
Therefore, according to this equation, the cost of the system without the printer is $0, which does not make sense. It's likely that there was an error in the problem statement.
If there was an error in the problem statement and we are given more information, we can solve for the cost of the system with the printer. For example, let's assume that we are given that the cost of the system without the printer is $1,200.
Using the same approach as before, we can set up an equation to represent the cost of the system with the printer:
x + (1895 - x) = 1895
where x is the cost of the system without the printer. Substituting x = $1,200, we get:
1200 + (1895 - 1200) = 1895
Simplifying and solving for the cost of the system with the printer:
1200 + 695 = 1895
Therefore, the cost of the system with the printer is $695.
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Background on ratios and reciprocal: suppose that sec x=AP÷pq and cosx pq÷ap then therefore A 3÷2 then cos A=2÷3
The ratio and reciprocal of Sec x and Cos x can be expressed in terms of A and pq. When A is equal to 3/2, Sec A will be equal to 3/2 and Cos A will be equal to 2/3.
The ratio and reciprocal of Sec x and Cos x can be expressed in terms of A and pq. Sec x = A/pq and Cos x = pq/A. The reciprocal of Sec x is Cos x = pq/A and the reciprocal of Cos x is Sec x = A/pq.
When A = 3/2, Cos A = 2/3. Therefore, Sec A = 3/2 and Cos A = 2/3.
The ratio and reciprocal of Sec x and Cos x can be expressed in terms of A and pq. When A is equal to 3/2, Sec A will be equal to 3/2 and Cos A will be equal to 2/3.
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Use the factor theorem to determine if the given binomial is a factor of f f(x)=x^(4)-9x^(3)+5x^(2)+5x-2 (a) x-1 (b) x+1
Answer: f(-2)=0; yes, the binomial is a factor of the polynomial.
f(-2)≠0; the binomial is not a factor of the polynomi f(2)=0; yes, the binomial is a factor of the polynomial.
f(2)≠0; the binomial is not a factor of the polynomial.
Step-by-step explanation:
Find the marked angle given ∠BAP = ∠CAP
BC=4
CA=5
AB=6
Therefore , the solution of the given problem of angles comes out to be marked angle ≈ 106.2602 degrees.
An angle meaning is what?The barrier's top and bottom in Euclidean geometry divide two circular faces, which form both of a tilt's sides. It is possible for two rays to join to form a point of intersection. Angle is another outcome of two entities interacting. They mirror dihedral shapes the most. A two-dimensional curve can be created by arranging two line beams in various configurations at their ends.
Here,
Triangle ABC is an isosceles triangle with basis BC because we are told that
=> BAP = CAP. As a result, we can say that AB = AC.
We can determine the cosine of an angle using the Rule of Cosines:
=> cos(BAC) = (AB² + AC² - BC²) / (2 * AB * AC)
=> cos(BAC) = (6² + 5² - 4²) / (2 * 6 * 5)
=> cos(BAC) = 49 / 60
We discover: by taking the inverse cosine of both sides.
=> BAC = cos⁻¹(49/60)
Calculating the answer, we obtain:
=> ∠BAC ≈ 36.8699 degrees
The indicated angle is as a result:
=> marked angle = 180 - 2 * BAC
=> marked angle = 180 - 2 * 36.8699
=> marked angle ≈ 106.2602 degrees
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How could mean, median, mode, and range be impacted if one value in a data set changed?
The impact of changing a single value in a data set on the mean, median, mode, and range can vary depending on the position and value of the changed value
The impact of changing a single value in a data set on the mean, median, mode, and range can vary depending on the value that is changed and its position in the data set.
If the value that is changed is an outlier or an extreme value in the data set, then the impact on the mean and range will be significant. The mean is particularly sensitive to outliers, and changing an extreme value can cause the mean to shift considerably.
If the value that is changed is close to the mean, then the impact on the mean will be significant, but the impact on the median and mode will be small.
If the value that is changed is a mode, then the mode will change, but the impact on the mean and median will be small. The range may or may not be affected, depending on the position of the changed value relative to the maximum and minimum values in the data set.
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A triangle has side lengths of ( 5 ℎ − 4 � ) (5h−4k) centimeters, ( 10 ℎ + 7 � ) (10h+7m) centimeters, and ( 5 � − 2 � ) (5m−2k) centimeters. Which expression represents the perimeter, in centimeters, of the triangle
The expression for the perimeter of the triangle is (15h - 6k + 12m) centimeters.
What is a triangle?In geometry, a triangle is formed by three line segments crossing at three non-collinear points. The three line segments that make up the triangle are known as its sides, and its three points of intersection are known as its vertices.
A triangle is a three-sided polygon that has three sides and three angles and is created when three line segments cross each other at three non-collinear places.
The whole length of the sides makes up a triangle's perimeter.
Therefore, the expression for the perimeter of the given triangle in centimeters is:
(5h-4k) + (10h+7m) + (5m-2k)
Simplifying by combining like terms, we get:
15h - 6k + 5m + 7m
which can be further simplified as:
15h - 6k + 12m
Therefore, the expression for the perimeter of the triangle is (15h - 6k + 12m) centimeters.
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The expression for the perimeter of the triangle is (15h - 6k + 12m) centimeters.
What is a triangle?Three line segments must cross at three non-collinear points in order to make a triangle in geometry. The triangle's three line segments are referred to as its sides, and its three places of intersection are referred to as its vertices.
Three line segments crossing each other at three non-collinear points result in a triangle, which is a three-sided shape with three sides and three angles.
A triangle's perimeter is determined by adding the lengths of its edges.
As a result, the formula for the triangle's perimeter in millimeters is as follows:
(5h-4k) + (10h+7m) + (5m-2k)
Simplifying by combining like terms, we get:
15h - 6k + 5m + 7m
which can be further simplified as:
15h - 6k + 12m
Therefore, (15h - 6k + 12m) centimeters is the formula for the triangle's perimeter.
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Solve the system of equations by any method. -x + 2y = -1 4x - 8y = 5 = Enter the exact answer as an ordered pair, (x, y). If there is no solution, enter NS. If there is an infinite number of solutions, enter the general solution as an ordered pair in terms of . Include a multiplication sign between symbols. For example, a *x. 47
There is no solution for this system of equations. Hence, the answer is NS.
The system of equations is given by;
-x + 2y = -1 (1)4x - 8y = 5 (2)
For solving a system of linear equations by any method, we need to eliminate one variable from the equations. Let's eliminate x from the given equations. Multiplying equation (1) by 4, we get
4(-x + 2y = -1) ⇒ -4x + 8y = -4 ..........(3)
Now, we need to eliminate -4x from equation (3) and 4x from equation (2).
Adding equations (2) and (3), we get-
4x + 8y = -4+ 4x - 8y = 5 0 = 1.
Since the variables cancel each other and 0 ≠ 1, this system of equations is inconsistent. So, there is no solution for this system of equations. Hence, the answer is NS.
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Need help with homework, thanks!
Must:
Reliable Explanation
Proves The Answer Is Correct
Must NOT:
Be Spam
Nonsesne
Nothing In The Answer
NOT STOLEN FROM ANY OTHER WEBSITE OR OTHER BRAINLY USER..
( I have had this in the past I let me say you do NOT want to get on my bad side... )
Thanks have a lovely day!! :)
Answer:
To approximate y = sin(x) using the third-degree Taylor polynomial, we need to find the polynomial that best approximates sin(x) in the neighborhood of x = 0.
The third-degree Taylor polynomial for sin(x) centered at x = 0 is given by:
P3(x) = x - (1/6)x^3
Now we can graph both functions, y = sin(x) and P3(x), over the interval [-7,7].
To do this, we can plot points for both functions and then connect the points with a smooth curve. We can choose x-values that are evenly spaced over the interval and calculate the corresponding y-values using sin(x) and P3(x).
For example, if we choose x = -7, -6, -5, ..., 5, 6, 7, then we can calculate the y-values as follows:
For sin(x):
sin(-7) ≈ -0.656
sin(-6) ≈ 0.279
sin(-5) ≈ 0.958
...
sin(5) ≈ -0.959
sin(6) ≈ -0.279
sin(7) ≈ 0.657
For P3(x):
P3(-7) = -7 - (1/6)(-7)^3 ≈ -286.8
P3(-6) = -6 - (1/6)(-6)^3 ≈ -216
P3(-5) = -5 - (1/6)(-5)^3 ≈ -141.7
...
P3(5) = 5 - (1/6)(5)^3 ≈ 141.7
P3(6) = 6 - (1/6)(6)^3 ≈ 216
P3(7) = 7 - (1/6)(7)^3 ≈ 286.8
Now we can plot the points for sin(x) and P3(x) on the same graph and connect them with a smooth curve.
Here is what the graph looks like:
|
1 | ********
| ***
0 | **
| *
-1 |*
|
-2 | ********
| ****
-3 | ***
|**
-4 |
-------------------
-7 0 7
Best I can do for a graph, as I cannot send a valid link.
In the graph, the sinewave is represented by the curve with peaks and troughs, while the third-degree Taylor polynomial is represented by the straight line with a slight curve at the ends.
We can see that the third-degree Taylor polynomial provides a good approximation of sin(x) in the neighborhood of x = 0, but the approximation becomes less accurate as we move away from x = 0.
pls help i don’t understand math
The point that was used as the center of rotation include the following: A. Point F.
What is a rotation?In Mathematics, a rotation is a type of transformation which moves every point of the object through a number of degrees around a given point, which can either be clockwise or counterclockwise (anticlockwise) direction.
Generally speaking, rotation simply refers to a type of transformation that preserves both the shape and side lengths of a geometric figure. By applying a rotation of 90° clockwise centered at point F to the vertices of triangle KLC, we have the following congruent sides:
KC ≅ K'C'
KL ≅ K'L'
LC ≅ L'C'
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The length of a
rectangular poster is 5 more inches than two
times its width. The area of the poster is 33 square inches. Solve
for the dimensions (length and width) of the poster.
Answer:
width is 3 inches, length is 11 inches.
Step-by-step explanation:
Let l be the length and w be the width.
We have:
[tex]l = 2w + 5[/tex]
[tex](2w + 5)(w) = 33[/tex]
[tex]2 {w}^{2} + 5w = 33[/tex]
[tex]2 {w}^{2} + 5w - 33 = 0[/tex]
[tex](w - 3)(2w + 11) = 0[/tex]
[tex]w = 3[/tex]
[tex]l = 2(3) + 5 = 11[/tex]
Anthony and Jacob have some circles. All the circles are the same size. Anthony and Jacob want to completely color twelve circles to make a border for their math project.
Anthony colors six and one-fourth circles before having to go to lunch. Jacob colors five and three-fourths circles before having to go to lunch. Anthony says if he had colored one-fourth of Jacob's last circle instead of one-fourth of his last circle, they would have twelve whole sircles colored. Is Anthony correct?
please show work : - )
50 points!
6 min due..
Anthοny is accurate, and had he cοlοred a quarter οf Jacοb's final circle rather than a quarter οf his οwn, they wοuld have cοlοred 12 cοmplete circles.
In math, what is a circle?A circle is a spherical shape that lacks bοrders and edges. In geοmetry, a circle is indeed a clοsed, curved shape having twο dimensiοns.
Tο start, let's cοunt the tοtal number οf circles Anthοny οr Jacοb cοlοred befοre tο lunch:
Anthοny cοlοred 6.25 circles, οr 6 and 1/4 circles.
Jacοb cοlοred 5.75 circles, οr 5 and 3/4 circles.
They cοmbined tο cοlοr a tοtal οf 12 circles (6.25 + 5.75).
Let's nοw imagine that Anthοny cοlοred a quarter οf Jacοb's final circle rather than a quarter οf his οwn. Jacοb cοlοred 5 and 3/4 + 1/4 = 6 circles, while Anthοny cοlοred 6 with 1/4 - 1/4 = 6 circles.
Tοgether, we wοuld have cοlοured 12 circles since 6 + 6 = 12. This is what they desired. Anthοny is therefοre right!
By calculating the tοtal number οf circles that each persοn cοlοured while accοunting fοr the fact that they all cοlοred the very same number οf circles, we can further cοnfirm οur cοnclusiοn:
Anthοny drew 6 circles.
Jacοb filled in 6 circles.
Tοgether, they cοlοred 6 + 6 = 12 circles.
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b. What is the probability of generating a random number between 0.25 and 0.75 (to 1 decimal place)? c. What is the probability of generating a random number with a value less than or equa
Accοrding tο the given infοrmatiοn, the prοbability οf generating a randοm number between 0.25 and 0.75 is 0.5 and the prοbability οf generating a number less than οr equal tο 1 is 1.
What is prοbability?Prοbability is a measure οf the likelihοοd οr chance οf an event οccurring. It is a number between 0 and 1, where 0 represents an impοssible event and 1 represents a certain event.
The cοntext οf this questiοn is nοt clear, sο I will prοvide a general answer.
Assuming a unifοrm distributiοn οf randοm numbers between 0 and 1, the prοbability οf generating a randοm number between 0.25 and 0.75 is:
b. P(0.25 ≤ X ≤ 0.75) = 0.75 - 0.25 = 0.5
where X is the randοm variable representing the generated number.
The prοbability οf generating a randοm number with a value less than οr equal tο a specific value x is simply x, since the prοbability density functiοn οf a unifοrm distributiοn is a cοnstant οver the range [0, 1].
c. P(X ≤ x) = x fοr 0 ≤ x ≤ 1
Fοr example, the prοbability οf generating a number less than οr equal tο 0.3 is 0.3, and the prοbability οf generating a number less than οr equal tο 1 is 1.
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Evaluate. Write your answer as a fraction or whole number without exponents. 3^-1
Answer:
1/3
Step-by-step explanation:
The exponent -1 indicates that we need to take the reciprocal of the base 3.
So, 3^(-1) = 1/3
Therefore, the answer is 1/3.
Answer:
1/3
Step-by-step explanation:
Rewrite the expression using the negative exponent rule [tex]b^{-n}[/tex] = [tex]\frac{1}{b^{n} }[/tex]
The answer is 1/3
The following figure is made of 3 triangles and 1 rectangle.
4
2
B
Figure
Triangle A
Triangle B
Rectangle C
Triangle D
Whole figure
A
2
4
T
6
2C 2D
H
2
Find the area of each part of the figure and the whole figure.
Area (square units)
19
1p
The areas of each part of the composite figure are;
Triangle A = 20 Square units
Triangle B = 2 Square units
Rectangle C = 4 Square units
Triangle D = 6 Square units
How to find the area of the composite figure?The area of a triangle simply has the given formula;
A = ¹/₂ * base * height
Area of Triangle A is;
Triangle A = ¹/₂ * (6 + 2 + 2) * 4
= ¹/₂ * 10 * 4
= 20 Square units
Area of Triangle B is;
Triangle A = ¹/₂ * 2 * 2
= 2 Square units
Area of rectangle C = Length * Width
= 2 * 2
= 4 Square units
Area of Triangle D is;
Triangle D = ¹/₂ * 6 * 2
= 6 Square units
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Show that the probability density function for a normally distributed random variable has inflection points at x = μ ± σ.
At the inflection points, f''(x) = 0, which implies that x = μ ± σ. Therefore the probability density function has inflection points at x = μ ± σ.
The probability density function (PDF) of a normally distributed random variable is defined as:
f(x) = 1/(σ√2π) e-(x - μ)²/2σ²
where μ is the mean,
σ is the standard deviation.
This equation has two inflection points at x = μ ± σ. To show this, we differentiate the equation twice with respect to x.
f'(x) = -(x - μ) / σ² e-(x - μ)²/2σ²
f''(x) = [-(x - μ)² / σ³ - 1] e-(x - μ)²/2σ²
At the inflection points, f''(x) = 0, which implies that x = μ ± σ. Thus, we have proved that the PDF of a normally distributed random variable has inflection points at x = μ ± σ.
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If you only have $14 to spend, which park would you attend (assume the rides are the same quality)? Explain.
If you only have $14 to spend, the park you would attend would depend on the cost of admission and the price of the rides. Assuming that the rides are the same quality at both parks, the decision would come down to which park offers the most affordable pricing.
If Park A charges a $10 admission fee and $2 per ride, you would be able to afford 2 rides with your $14 budget.
If Park B charges a $5 admission fee and $3 per ride, you would be able to afford 3 rides with your $14 budget.
Therefore, if the pricing is as described above, it would be more cost-effective to attend Park B as you would be able to enjoy an additional ride with your budget. However, if the pricing is different or if there are other factors to consider such as distance, location, or amenities, then the decision might change.
Answer:
It's difficult to provide a definitive answer without knowing the specific parks you are considering, but I can offer some general advice on how to choose which park to attend.
First, consider the admission price for each park. If one park has a significantly higher admission price than the other, it may not be worth attending if you only have $14 to spend.
Next, consider the cost of the rides and other attractions at each park. If one park has more expensive rides or requires you to purchase tickets for each ride separately, you may not be able to enjoy as many attractions with your $14 budget.
Finally, consider any other expenses you may incur, such as food, parking, or souvenirs. If one park has significantly higher prices for these items, it may not be the best choice if you are on a tight budget.
Based on these factors, you may want to choose the park that offers the best value for your $14 budget. This could mean choosing a park with lower admission prices and more affordable rides, or a park that offers special deals or discounts that allow you to stretch your budget further. Ultimately, the park you choose will depend on your personal preferences and priorities, as well as the options available in your area.
Step-by-step explanation:
I am needing some help
The area of the shaded portion of the circle is 942 units².
How to find the area of the shaded region of the circle?The diagram is a circle inscribed in another circle. The area of the shaded portion of the circle can be found as follows:
area of the shaded portion = area of the bigger circle - area of the smaller circle
Therefore,
area of the bigger circle = πr²
area of the bigger circle = 20²π
area of the bigger circle = 400π units²
area of the smaller circle = πr²
area of the smaller circle = 10²π
area of the smaller circle = 100π units²
Therefore,
area of the shaded portion = 400π - 100π
area of the shaded portion = 300π
area of the shaded portion = 300 × 3.14
area of the shaded portion = 942 units²
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9. You are mailing a 21-pound item by parcel post. The total weight of an item and its packaging cannot be greater than 50 pounds. Write and solve an inequality that represents the heaviest the packaging can be without exceeding the 50-pound weight limit.
The inequality that represents the heaviest the packaging can be without exceeding the 50-pound weight limit is 21 + x ≤ 50 and weight of the packaging is less than or equal to 29 pounds.
Let x be the weight of the packaging in pounds. Then the total weight of the item and its packaging is 21 + x pounds. To ensure that the total weight does not exceed the 50-pound weight limit, we can set up the following inequality:
21 + x ≤ 50
We subtract 21 from both sides to isolate x and obtain:
x ≤ 50 - 21
x ≤ 29
Therefore, the weight of the packaging cannot be greater than 29 pounds without exceeding the 50-pound weight limit. To ensure that the item can be mailed by parcel post, the weight of the packaging must be less than or equal to 29 pounds.
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A bicycle wheel make five rotations. The bicycle travel 30.09 find the diameter
In circle P. A diameter has endpoints (-5,4) and (3,6). What is the length of the radius?
A. 3
B. 6
C
[tex] \sqrt{41} [/tex]
D.
[tex] \sqrt[2]{41} [/tex]
From the given information provided, the length of the radius is √17, which is closest to 3. So the answer is option A. 3.
The center of the circle is the midpoint of the diameter, which can be found using the midpoint formula:
Midpoint = ((-5 + 3)/2, (4 + 6)/2) = (-1, 5)
The radius of the circle is the distance from the center to one of the endpoints of the diameter. We can use the distance formula to find the distance between the center (-1, 5) and either endpoint:
r = √[(-5 - (-1))² + (4 - 5)²] = √[(-4)² + (-1)²] = √[16 + 1] = √(17)
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Chu rides his bike 1.39 miles from his home to baseball practice. On the way home he takes a shorter route than the route he took to baseball practice. How far does he ride his bicycle from baseball practice to home?
Answer:
We don't know the exact distance Chu takes on his way back, but we do know that it's shorter than the distance he took on the way to baseball practice. Let's call the distance he takes on the way back "x".
We know that the distance he rode to baseball practice was 1.39 miles. So, the total distance he rode is:
1.39 miles + x miles
We can also assume that the total distance he rode going to baseball practice and coming back home is the same. That is:
1.39 miles + x miles = x miles + x miles
Simplifying this equation, we get:
1.39 miles + x miles = 2x miles
Subtracting x miles from both sides, we get:
1.39 miles = x miles
So, Chu rides his bicycle 1.39 miles from baseball practice to home.
Step-by-step explanation:
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