What forces are included on a free-body diagram for a chosen object?

a.all the forces exerted on or by the object.

b.all the forces exerted by the object, but not on it

c. all the forces exerted on the object, but not by it

d. all forces that exist within the neighborhood of the object​

Answers

Answer 1

Answer:

C

Explanation:

A free-body diagram shows all the forces exerted or applied on an object.

Answer 2

A free-body diagram includes all the forces exerted on or by the object. Hence, option A is correct.

What is a free-body diagram?

A free-body diagram is a diagrammatic representation of a single body or a group of bodies that are separated from their surroundings and display all the forces acting on them. A free-body diagram (FBD; sometimes known as a force diagram) is a graphical representation used in physics and engineering to show the applied forces, moments, and consequent reactions on a body under a specific condition.

It shows a body or group of connected bodies along with all the applied forces, times, and reactions that the body experiences. The body could be compact or comprise several interior pieces (like a truss) (such as a beam). To answer difficult problems, a series of free bodies and other diagrams may be required.

Hence, all the forces exerted on or by the object are included in the free-body diagram.

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Related Questions

An object has an acceleration of 6m/s/s. If the net force was tripled and the mass was doubled, then the new acceleration would be ​

Answers

Acceleration = Force / mass
New acceleration = 3F / 2m = 1.5 x the old acc = 9 m/s/s

Two ropes are attached a wagon one horizontal to the west with a tension force of 75N and other east and at an angle of 38 degrees upward from horizontal with a lension force of 125 N Find the components of the net force on the cart Show your work

Answers

Answer:

The components of the net force acting on the cart are;

Horizontal force, Fₓ ≈ 23.5 N acting east

The vertical force, [tex]F_y[/tex] ≈ 76.96 N

Explanation:

The parameters given in the question are;

The magnitude of the force on the rope acting horizontally to the west = 75 N

The magnitude of the force on the other rope east acting at an angle to the horizontal = 125 N

The angle to the horizontal of the force on the other rope east to the horizontal = 38°

Therefore, we have;

The horizontal component of the force acting east = 125 × cos(38°) ≈ 98.5 N

The net sum of the horizontal forces, ∑Fₓ noting that the horizontal forces are acting in opposite direction is given as follows;

∑Fₓ = 75 - 125 × cos(38°) = 75 - 98.3 = -23.5N

Given that the difference in forces is negative, and hat we took the force acting east as negative, we have that the net horizontal force is acting east with a horizontal component of 23.5N

The net vertical force, ∑F[tex]_y[/tex], is given as follows;

∑F[tex]_y[/tex] = 125 × sin(38°) ≈ 76.96 N

Therefore, the components of the net force acting on the cart are;

Horizontal force, Fₓ ≈ 23.5 N, the vertical force, [tex]F_y[/tex] ≈ 76.96 N

The components of the net force on the cart are 23.5 Newton and 76.96 Newton.

Given the following data:

Tension force (horizontal) due west = 75 NTension force (horizontal) due east = 125 NAngle of inclination = 38°

To find the components of the net force on the cart:

First of all, we would determine the horizontal component of the force acting due east.

[tex]F_y = Fcos(\theta)\\\\F_y = 125cos(38)\\\\F_y = 125 \times 0.7880\\\\F_y = 98.5 \; Newton[/tex]

Next, we would find the resultant horizontal forces:

[tex]\sum F_y = F + F_y\\\\\sum F_y = 75 + (- 98.5)\\\\\sum F_y = -23.5 \;Newton[/tex]

Therefore, the horizontal component of the net force acts in the opposite direction due east.

Horizontal component of the net force = 23.5 Newton

For the vertical component of the net force:

[tex]\sum F_x = Fsin(\theta)\\\\\sum F_x = 125cos(38)\\\\ \sum F_x = 125 \times 0.6157\\\\ \sum F_x = 76.96\; Newton[/tex]

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Give reasons.
a. A stretched catapult has potential energy.
b A stone on ground has zero energy.
C. Rolling a drum is work against friction.
d. Lifting a stone is work against gravity.
e. Work and energy both have same unit.​

Answers

a. A stretched catapult can do work when released so it must have potential energy.

b. A stone on the ground will not move on its own ever again so it has zero energy.

c. In order to roll an object there must be a friction force between the object and the ground (otherwise it will slide)

d. To lift a stone you must overcome the weight which is the force due to gravity.

e. Work and energy are both measured in Joules.

Yodelin has fifty quarters and dimes. Their total value is $9.80. Which of these systems of equations can be used to find the number of quarters (q) and
dimes (d) Yodelin has?

Answers

Answer:

q + d = 50

25q + 10d = 980

Explanation:

The equation that can be employed to determine the number of quarters(q), as well as, dimes(d) that Yodelin has would be:

q + d = 50...(1)

25q + 10d = 980...(2)

Multiplying (1) by 25

25q + 25d = 1250 ...(3)

25q + 10d = 980...(4)

subtracting (4) from (3)

15d = 270

d = 18

q = 50 - 18

    = 32

The system of the equations could be

q + d = 50

25q + 10d = 980

Calculation of the equation and the number of quarters and dimes:

Since Yodelin has fifty quarters and dimes. Their total value is $9.80.

So here the equations be

q + d = 50...(1)

25q + 10d = 980...(2)

Now we have to Multiplying (1) by 25

So,

25q + 25d = 1250 ...(3)

25q + 10d = 980...(4)

Now

subtracting (4) from (3)

15d = 270

d = 18

So,

q = 50 - 18

   = 32

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Select ALL the correct answers.
Which of these factors make hydrogen fuel cells a better option than burning fossil fuels?
1.Hydrogen fuel cells have a higher energy efficiency.
2.Hydrogen fuel cells create less pollution.
3.Burning fossil fuels relies on outdated devices and technology.
4.Hydrogen is the most abundant element in the universe.
5.Hydrogen fuel cells are more expensive than fossil fuels.

Answers

Answer:

1) and 2)

Explanation:

Hydrogen fuel is very efficient. More energy is extracted from this fuel source than with conventional power technologies, according to Tobin Smith for Billion Dollar Green. Fossil fuels have a high combustion rate and are capable of releasing tremendous amount of energy.

Which property describes the number of waves that move past a point each second.
A) Speed
B) Frequency
C) Period
D) Wavelength

Answers

Answer:B) Frequency

Explanation:

Answer:

B) Frequency

Explanation:

A skydiver jumps from an airplane traveling 120. km/hr at a height of 1000. m. If his parachute must open 500. m above the ground, how long does he have for the chute to open?

Answers

Answer:

The parachute to open in 15 sec.

Explanation:

Given that,

Velocity = 120 km/hr

Height = 1000 m

If his parachute must open 500. m above the ground.

We need to calculate the time for parachute to open

Using formula of time

[tex]v=\dfrac{d}{t}[/tex]

[tex]t=\dfrac{d}{v}[/tex]

Where, d = distance

t = time

v = velocity

Put the value into the formula

[tex]t=\dfrac{500}{120\times\dfrac{5}{18}}[/tex]

[tex]t=15\ sec[/tex]

Hence, The parachute will be open in 15 sec.

Explain how if a solid, liquid, and gas are put into individual containers how they fill the container.

Answers

Answer:

serial in which container is filled

Solid -base of container

Liquid- above solid

Gas- above liquid

Explanation:

If any mixture of  matter in different state (that solid , liquid or gas )are kept in any container, then substance with higher density will be settled at lowest surface first and similarly the substance with lowest density will be at upper part of container.

In the given container we have to keep solid, liquid and gas

sold has the highest density,gas the lowest density andliquid has the density higher than gas but less than solid.

based on this

solid will be at surface of container

above sold will be liquid

above liquid will be presence of Gas

serial in which container is filled

Solid -base of container

Liquid- above solid

Gas- above liquid

Molten (melted) iron and carbon monoxide are produced in a blast furnace by the reaction of iron(III) oxide and pure carbon. Fe2O3 + 3C ---> 2Fe + 3CO If 4 moles of Fe2O3 are used, how many moles of Carbon Monoxide (CO) can be produced?

Answers

Answer:

Explanation:

Fe₂O₃ + 3C ---> 2Fe + 3CO

1 mole                          3 moles

From the balanced equation above , we see that , 1 mole of Fe₂O₃ reacts with carbon to form 3 moles of CO .

So , 4 moles of  Fe₂O₃ will react with carbon to form 3 x 4  moles of CO .

moles of CO formed = 3 x 4 moles = 12 moles.

Newton's first law of motion is also called the law of
.

Answers

Answer:

The focus of Lesson 1 is Newton's first law of motion - sometimes referred to as the law of inertia. Newton's first law of motion is often stated as. An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

Explanation:

Answer:

Newton's first law is also called the law of Inertia.

Explanation:

What is inertia ?

The property of a body by virtue of which it wants to remain in its position, is called inertia.

Mainly there ae three types of inertia-

Inertia of restInertia of motion Inertia of direction

Inertia was discovered by Galileo and it was modified by Newton.

What is Newton's first law of motion ?

If a body is in motion or in rest, it wants to remain in its position unless any external force is applied.

Thus Newton's first law of motion is also called law of inertia.

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Activity 3. Let's Do The Mathi
Direction: Use Newton's second law equation to solve for force, mass, and acceleration
Problem 1- A ball with a mass of 0.5 kg is hit with a force of 2.5N. What is its acceleration?
Problem 2- What is the acceleration of a 15kg box that is pushed across a horizontal surface
with a force of 50N?
Problem 3- An object with a mass of 2.0 kg has a force of 5.0 N applied to it. What is the
resulting acceleration of the object?
Problem 4- An object with a mass of 3.0 kg accelerates 2.5 m/s2 when an unknown force is
applied to it. What is the amount of the force?
Problem 5- An object accelerates 12.0 m/s2 when a force of 6.0 N is applied to it. What is the
mass of the object?

Answers

Answer:

Problem 1-

The acceleration = 5 m/s²

Problem 2 -

The acceleration = 3.[tex]\overline 3[/tex] m/s²

Problem 3 -

The acceleration = 2.5 m/s²

Problem 4-

The force applied = 7.5 N

Problem 5-

The mass of the object,  = 0.5 kg.

Explanation:

Problem 1-

The mass of the ball, m = 0.5 kg

The force (applied) with which it was hit, F = 2.5 N

The acceleration, a = Force/Mass = 2.5 N/(0.5 kg) = 5 m/s²

The acceleration = 5 m/s²

Problem 2 -

The mass of the box, m = 15 kg

The force (applied) with which it was hit, F = 50 N

The acceleration, a = Force/Mass = 50 N/(15 kg) = 10/3 = 3.[tex]\overline 3[/tex] m/s²

The acceleration = 3.[tex]\overline 3[/tex] m/s²

Problem 3 -

The mass of the object, m = 2.0 kg

The force (applied) with which it was hit, F = 5.0 N

The acceleration, a = Force/Mass = 5.0 N/(2.0 kg) = 2.5 m/s²

The acceleration = 2.5 m/s²

Problem 4-

The mass of the object, m = 3.0 kg

The acceleration, a, of the object = 2.5 m/s²

The force applied to it, F = Mass × Acceleration = 3.0 kg × 2.5 m/s² = 7.5 N

The force applied = 7.5 N

Problem 5-

The acceleration, a, of the object = 12 m/s²

The force applied, F = 6.0 N

The mass of the object, m = Force/Acceleration = 6.0 N/(12 m/s²) = 0.5 kg

The mass of the object,  = 0.5 kg.

can you help me doing an essay about actual self​

Answers

Answer:

yes absolutely

Explanation:

why not

A football player kicks a football off a tee with a speed of 21 m/s at an angle of 51°. what is the horizontal component of the velocity?

Answers

Answer:

The horizontal component of the velocity is approximately 13.22 m/s

Explanation:

The velocity of the kick which the football player gives the ball = 21 m/s

The angle of the path taken by the ball = 51°

The velocity can be represented vectorially, showing the vertical and horizontal components as follows;

v = 21 × cos(51°)·[tex]\hat i[/tex] + 21 × sin(51°)·[tex]\hat j[/tex]

Where we have;

The horizontal component of the velocity = 21 × cos(51°)

The vertical component of the velocity = 21 × sin(51°)

Therefore;

The horizontal component of the velocity = 21 × cos(51°) ≈ 13.22 m/s

The horizontal component of the velocity ≈ 13.22 m/s.

chemical formulawhat is the chemical formula ​

Answers

a set of chemical symbols showing the elements present in a compound and their relative proportions, and in some cases the structure of the compound.

That’s the definition

Answer: A chemical formula is a way of showing and representing information about a chemical proportion of atoms that constitute a particular chemical compound or molecule

Determine the weight of a 10.0-kg person who is running with a speed of 5.0 m/s. Enter a
numerical answer.

Answers

Answer:

weight=mass*gravity

weight=10.0*10

so weight=100N

please can i have help with this question ​

Answers

Opposites attract so north goes to south and Vice versa. When the same poles are facing each other they push away when they are opposites they attract.

help do number 16 and 17​

Answers

Answer:

16 is d and i have no idea for 17

You and your friends are going on a picnic in a very small car. On your way, the car breaks down and you try to push it to get it to move but in vain. You ask your friends to help you and the car starts moving and revs up. How are you and your friends applying Newton's second law of motion here? What if the car you were traveling in was a large SUV?

Answers

Answer:

The pushing of the car by you and your friends is the applied force and when the car moves, it means that the velocity has changed thus causing the movement or acceleration.

Explanation:

Newton's work on forces regarding motion can never be neglected by scientists. Sir Isaac Newton when he was alive, among several of his works he proposed the three laws guiding the forces of motion. In this question we are only going to be treating only one out of the three Newton's Law of motion and that is the second Law Of Newton's laws of motion.

The second Law Of Newton's laws of motion states that the acceleration of an object is directly proportional to the applied force and inversely proportional to the object's mass.

(1). Now, to the question: " How are you and your friends applying Newton's second law of motion here? "

The pushing of the car by you and your friends is the applied force and when the car moves, it means that the velocity has changed thus causing the movement or acceleration.

According to the law, the more the Force, the more the acceleration.

(2). For the second part of the question, " What if the car you were traveling in was a large SUV?"

From the law stated above we see that the acceleration is inversely proportional to the mass, thus if the car is a large SUV, It means that more force is needed to change the car's velocity.

Answer:

When a friend joins you in pushing the small car, the net force on it increases. Therefore, it starts to move. The mass of a SUV is much greater than that of a small car. You would thus need the help of more friends to help push it.

Explanation:

Plato/Edmentum

16. True/False: Protons are exchanged between objects by induction

Answers

False: only electrons move through induction.

Why should you never do an exercise such as the bench press without a spotter?​

Answers

Answer:

you could hurt yourself

Explanation:

Answer

You should never do an exercise such as the bench press without a spotter because you could hurt yourself or push your self too much.

Explanation:

If a substance has a density of 2.7g/cm3 and a mass of 86.4g, what is its volume?

Answers

Answer:

32cm³

Explanation:

Given parameters:

  Density of substance  = 2.7g/cm³

   Mass of substance  = 86.4g

Unknown:

Volume of substance  = ?

Solution:

Density is the mass per unit volume of a substance.

    Density  = [tex]\frac{mass}{volume}[/tex]

Since the unknown is volume we solve for it;

   mass  = density x volume

   86.4 = 2.7 x volume

    volume  = [tex]\frac{86.4}{2.7}[/tex]   = 32cm³

PLSSSSSSSS ASAP!!!!!!
If the distance and time of an object are given, and I need to find speed, I will *


1.add the distance and time

2.divide the distance and time

3.multiply the distance and time

Answers

Answer:

2. divide the distance and time

speed=distance÷time

How do you find the distance a object has traveled

Answers

Answer: Got this from a web search... Change the answer up a bit

Explanation:

The distance travelled is the path taken by a body to get from an initial point to an end point in a given period of time, at a certain velocity. If the velocity is constant: Distance = time * velocity. d = v*t.

Answer:

I researched and found it to be TIME * VELOCITY ( d= v*t)

Explanation:

When I use * I just mean multiply. So its time 'multiplied by velocity' in order to get 'distance'

A mover applies a net force of 28 N to a sofa that has a mass of 70 kg.
What will the sofa's acceleration be?

Answers

Answer: .4 m/s^2= acceleration

Explanation:

f = m*a

We can rearrange this equation to solve for acceleration. Therefore,

a=f/m

a= 28N/70kg

a= 0.4 m/s^2

Which information did the Glomar Challenger study in 1968?

Answers

-Glomar Challenger studies about the "age of rocks in various places in the ocean" in 1968.

(Glomar Challenger was a "deep sea research vessel" for marine geology and oceanography studies)

hope this helps!! :))

Answer:

c

Explanation:

i took the test

How long would it take Jesse with an acceleration of -2.50 m/s2 to bring his bicycle with an initial velocity of 13.5 m/s to a complete stop?

Answers

Answer: 5.4 seconds

Explanation:

The time taken to stop the bicycle is 5.4 seconds. The final velocity is zero. Then, the distance travelled by the bicycle is 36.45 m.

What is acceleration ?

Acceleration is a physical quantity that, measures the rate of change in velocity. It is a vector quantity thus having both magnitude and direction. It can be defines as the ratio of change in velocity to the change in time.

Given initial velocity = 13.5 m/s

final velocity is zero since the bicycle is stopping.

then Δt = Δv/a

Δt = 13.5 m/s/ 2.50 m/s² = 5.4 seconds.

Hence, the bicycle will take 5.4 s to complete stop.

The distance covered within this time can be determined using the equation as follows:

s = ut + 1/2 at²

where u is the initial velocity

s =  (13 m/s × 5.4 s) + (-2.50 m/s² ×5.4 s ×5.4 s) = 36.4 m.

Therefore, the bicycle will travel up to 36.4 m before stopping.

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1. Which of the following provides a correct answer for a problem that can be solved using the kinematic equations?
A A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's final
position is 32 m.
B A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's final
velocity is 16 m/s
C A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's travels a
distance of 16 m
A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's final
velocity is 24 m/s
E A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's final
position is 30 m.
1 of 14
2
3
5 6 7 8
9

Answers

Answer:

12

Explanation:

12

The planet's hawks and block their near each other in the door again system the dworkin's have very advanced technology and a dork and scientist want to increase the pull of gravity between the 2 planets which proposals with the scientists make to accomplish this goal check all that aply

Answers

Answer: A,B, and E

Explanation: Just checked I got them right:)

The shortest path between two points is:

1) displacement

2) breadth

Answers

Answer:

the shortest path between two points is displacement..

Explanation:

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The shorts path between two points is displacement.

Who am I answer key

Answers

Answer:

huh

Explanation:

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