What does it mean for a bacteria or protist to be photosynthetic?
O They are responsible for disease growth.
o They are only responsible for the decomposition of compost.
They are a primary producer of biomass in the ocean.
They are multi-cellular organisms.

Answer:

In recent years, the concept of the circular economy and related policies have tackled resource use, production, consumption and waste at a high level.

Explanation:

hope it helps a lil

Answer:

In harsh winter, usually there's less food, therefore, rabbits will not be able to find enough food and the population of rabbits will decrease.

Answer:

Lightning is not considered a form of precipitation but rather a discharge of electricity.

Answer:carbon cycle

Explanation:

Answer:

it would be stored in plants in animals

Explanation:

those are one of our main sources of oxygen

Answer: In order:

1. Ingestion

2. Decomposition

3. Fossilization

4. Combustion

Explanation:

Answer:

A

Explanation:

not 100% sure but it seems to be the only sensible answer

If mitosis DID NOT happen... the organism would stay as a single cell. The life we know it now... wouldn't exist as we have multi-cellular stuff.

Answer:

organic selection

Explanation:

Answer:

Mainly because if a disorder is dominant, then it will be manifested by all who have the gene. If the disorder is severe, then it will reduce the chances of the individual surviving to grow up and reproduce (unless the disorder only manifests symptoms in later life). If they do reproduce, then 50% of their offspring will inherit the gene, and be at a similar disadvantage in reproduction. Thus, there is likely to be selection against the gene. By contrast, a recessive disorder is only manifested if both parents pass on the abnormal gene, and an individual with one gene for the disorder is usually at no disadvantage. Thus, there is much less selection against abnormal recessive disorders.

A lack of trees, a lack of biodiversity, and extreme circumstances are what most clearly identify the tundra.

The polar ice caps and the boreal woodlands (also known as taiga), it is located. Extremely low temperatures and barren, icy terrain define the tundra biome. The arctic tundra and the alpine tundra are the two different forms of tundra.

The Tundra Biome: The Ice Deserts of the World. The tundra is the coldest biome, with an average annual temperature of less than 5°C and yearly precipitation of less than 100 mm, most of it snow.

Only a few number of plants and animals can even thrive on the tundra due to its extreme weather conditions. The Finnish term "tunturia" is where the word "tundra" originates.

Therefore, a lack of trees, a lack of biodiversity, and extreme circumstances are what most clearly identify the tundra.

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Answer:

D

Explanation:

as only one phosphate is removed hence the name ADP which stands for adenineDIphosphate. Hope this make sense :)

Answer:

D.

Explanation:

Yes The two peptides will separate from each other in an electric field when the pH is 7.0

The two peptides wil drift/separate from each other when the pH is 7.0 because of the reaction of trypsin enzyme and also the difference in charge between HbA and Hbs

Considering charge of each peptide

Since The isoelectric point of normal Hba is 6.9 and Hbs possess two fewer negative charges per hemoglobin molecules

The Hbs is more hydrophobicity than HbA due to the substitution of glutamic acids of HbS by valine residue.

Considering Electrophoresis

At a lower pH level Hbs shows a slower moving band than Hba

while a higher pH level the HbS peptide is less negatively charged while the carboxyl group of HbA is more negatively charged and Hba moves faster as well as an acidic pH.

Hence we can conclude that the two peptides will separate from each other in an electric field when the pH is 7.0

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Answer:

D is the correct answer

Explanation:

ur welcome :3

Answer:

Sorry about that

Explanation:

Ansew heheheheheheh

Explanation:

thats nice :)

also hi hru

Answer:

Arctic, Antarctic, and Alpine

Arctic, Antarctic, and alpine

Answer:

I think it's either mutase or dehydrogenase, but I'm not exactly sure why. I haven't taken a chemistry class yet, so I don't know too much about it TBH.

Answer:

habitat

Explanation:

The ecological levels do not describe interacting biotic and abiotic factors in an area's habitat. The correct option is D.

A habitat is a place where physical or biotic factors are presented. This is a place where all the factors are present to live a species with all suitable conditions.

Habitat of different species is different. They live in their suitable habitat to grow and reproduce accordingly. If a species is moved from its habitat, then it may have difficulties in surviving.

So habitat is not a place where all biotic and species abiotic factors are present, it is a place where all living factors are present that are necessary for the living of a person. So, it is not the ecological level of  interacting biotic and abiotic factors in an area

Thus, the correct option is D. Habitat.

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Answer:

pH is a measure of the concentration of H3O+ ions in a solution. Adding an acid increases the concentration of H3O+ ions in the solution. ... If an acid is added to a basic solution, the solution becomes less basic and moves toward the middle of the pH scale. This is called neutralizing the base.

Answer:

maybe cab If it's wrong I'm so sorry

Answer:

They absorb the food molecules that result from the external digestion.

Explanation:

Answer:

Make food for the cell

Explanation:

Since the purpose of the chloroplast is to create energy for the cell, should it be damaged it would lose its ability to do so.

Hopefully this is a better answer

Answer:

I believe it is b

Explanation:

Chloroplast help to produce food and uses the suns sun rays or energy given off of it to produce one it’s green color and it well the food

Answer:  It's starts burning body fat.

Explanation:

Answer:

5730 years

Explanation:

In a chemical reaction, including radioactive decay, the half-life of a species is the time taken for the substance to decrease to exactly one-half its initial value.

For a first-order reaction, the half-life of the reactant is

                                                  [tex]t_{\frac{1}{2}} \ = \ \displaystyle\frac{\ln 2}{\lambda} \ \ \ \ \ \ (1)[/tex],

where λ is the reaction's rate constant modeled by the differential equation describing the kinetics of a first-order reaction

                                               [tex]N \ = \ N_{0}e^{-\lambda t} \ \ \ \ \ (2)[/tex],

where N is the remaining amount of substance after time t and [tex]N_{0}[/tex] is the initial amount of substance before the chemical reaction proceeds.

Since the value of λ is constant, rearrange equation (1) with λ as the subject,

                                                       [tex]\lambda \ = \ \displaystyle\frac{\ln 2}{t_{\frac{1}{2}}}[/tex].

Given that only 12.5% of carbon-14 remained after 17190 years assuming that initially there was 100% of carbon -14, substitute in the values into equation (2) and solve for λ (make λ the subject of the equation),

                               [tex]\-\hspace{0.56cm}12.5 \ = \ 100e^{-\lambda \times 17190} \\ \\ \-\hspace{0.5cm} \displaystyle\frac{12.5}{100} \ = \ e^{-17190\lambda} \\ \\ \displaystyle\frac{\ln\displaystyle(\frac{1}{8})}{-17190} \ = \ \lambda \\ \\ \-\hspace{1.05cm} \lambda \ = \ \displaystyle\frac{3\ln2}{17910} \ \ \ \ \ \ \ \ \ \ (\ln \displaystyle\frac{1}{x} \ = \ -\ln x\ ; \ \ln x^{n} \ = \ n\ln x )[/tex]

Equate both λ,

                                            [tex]\displaystyle\frac{\ln 2}{t_{\frac{1}{2}}} \ = \ \displaystyle\frac{3\ln2}{17190} \\ \\ \-\hspace{0.26cm} t_{\frac{1}{2}} \ = \ \ln 2 \ \times \ \displaystyle\frac{17190}{3\ln2} \\ \\ \-\hspace{0.26cm} t_{\frac{1}{2}} \ = \ \displaystyle\frac{17190}{3} \\ \\ \-\hspace{0.26cm} t_{\frac{1}{2}} \ = \ 5730[/tex]

*Note that the above calculations demonstrated that carbon-14 went through 3 half-lives to yield a remaining 12.5% of its original amount, since

                                 [tex]100\% \ \overset{t_{\frac{1}{2}}}\longrightarrow \ 50\% \ \overset{t_{\frac{1}{2}}}\longrightarrow \ 25\% \overset{t_{\frac{1}{2}}}\longrightarrow \ 12.5\%[/tex].

Therefore, if n is the time taken for carbon-14 to half its initial amount trice to remain 12.5% of its initial amount. Then, the half-life of carbon-14 is [tex]\displaystyle\frac{n}{3}[/tex].