Answer:
No, the mass will never come to rest
Explanation:
It is so because even at arbitrarily small distance it will experience some amount of force (irrespective of how small the value of force is).
This does not allow the mass to become stationary or in a equilibrium state as it is still subject to some amount of force.
Hence, the the mass will never come to rest
An empty container is filled with helium to a pressure P at a temperature T. Neon, which has atoms that are 5 times more massive than those of helium, is then added to the container until the new pressure in the container is 2P at the same temperature T. The ratio of the average speed of the helium atoms to the average speed of the neon atoms is:_________
a. 25 to 1
b. 5 to 1
c. 5to 1
d. 2to 1 E
e. 1 to 1
The ratio of the average speed of the helium atoms to the average speed of the neon atoms is 5 to 1 C.
We have that for the Question, it can be said that the ratio of the average speed of the helium atoms to the average speed of the neon atoms is
5:1
Option B
From the question we are told
An empty container is filled with helium to a pressure P at a temperature T. Neon, which has atoms that are 5 times more massive than those of helium, is then added to the container until the new pressure in the container is 2P at the same temperature T. The ratio of the average speed of the helium atoms to the average speed of the neon atoms is:_________
a. 25 to 1
b. 5 to 1
c. 5to 1
d. 2to 1
e. 1 to 1
Generally the equation for the average speed of Molecules is
mathematically given as
[tex]For Helium\\\\C_h=\frac{8P_hV_h}{\pim_h}\\\\Neon gas\\\\C_n=\frac{8P_nV_n}{\pim_n}\\\\Where\\\\Ph=P_n\\\\Vh=Vn\\\\[/tex]
[tex]\frac{C_h}{C_n}=\frac{\frac{8P_hV_h}{\pim_h}}{\frac{8P_nV_n}{\pim_n}}[/tex]
[tex]\frac{C_h}{C_n}=\sqrt{\frac{\frac{1}{5}}{{\frac{1}{5}}}[/tex]
[tex]\frac{C_h}{C_n}=\sqrt{\frac{5}{1}[/tex]
Therefore
The ratio of the average speed of the helium atoms to the average speed of the neon atoms is
5:1
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Which one of the statements below is true about mechanical waves?
They must travel in empty space.
They can travel in a vacuum.
Both sound and light are examples of mechanical waves.
They require a medium to travel through.
Answer:
The answer is B
Explanation:
32. Assume the helium-neon lasers commonly used in student physics laboratories have power outputs of 0.500 mW. (a) If such a laser beam is projected onto a circular spot 1.00 mm in diameter, what is its intensity
Answer:
636.6 W/m²
Explanation:
From the given information:
The area of the circular spot can be calculated as:
A = πr²
A = π(0.5 × 10⁻³ m)²
A = 7.85 × 10⁻⁷ m²
The intensity can be determined by using the formula:
[tex]I = \dfrac{P}{A}[/tex]
[tex]I = \Big ( \dfrac{0.500 \ mW}{\pi (0.5 \times 10^{-3} \ m )^2} \Big) \Big( \dfrac{10^{-3} \ W}{1\ mW} \Big)[/tex]
[tex]I = \dfrac{0.500 \times 10^{-3} }{\pi(0.25 \times 10^{-6} )}[/tex]
I = 636.6 W/m²
how would a small bar magnet be oriented when placed at position x ? option c is wrong.
Answer:
B
Explanation:
A sphere with the same mass and radius as the original cylinder, but a smaller rotational inertia, is released from rest from the top of the ramp. KS and KC are the sphere's and cylinder's total kinetic energy at the bottom of the ramp, respectively. How do KS and KC compare, and why
Answer:
The Kinetic energy of Sphere is higher than the cylinder.
( KS > KC )
Explanation:
Given - A sphere with the same mass and radius as the original cylinder, but a smaller rotational inertia, is released from rest from the top of the ramp. KS and KC are the sphere's and cylinder's total kinetic energy at the bottom of the ramp, respectively.
To find - How do KS and KC compare, and why ?
Proof -
We know that,
The total energy of an object = Potential energy + linear kinetic energy + rotational kinetic energy.
⇒E = mgh + [tex]\frac{1}{2} mv^{2}[/tex] + [tex]\frac{1}{2} l\omega^{2}[/tex]
Now,
Mass of sphere = m
Radius of sphere = r
So,
The moment of inertia of a uniform solid sphere = [tex]\frac{2}{5} mr^{2}[/tex]
Also,
Mass of cylinder = m
Radius of cylinder = r
So,
The moment of inertia of a uniform solid cylinder = [tex]\frac{1}{2} mr^{2}[/tex]
Now,
Total energy for the sphere , Es = mgh + [tex]\frac{7}{10} mv^{2}[/tex]
Total energy for the cylinder, Ec = mgh + [tex]\frac{3}{4} mv^{2}[/tex]
As they always have the same total energy,
So, for height h of the sphere's velocity has to be higher.
Therefore,
The Kinetic energy of Sphere is higher than the cylinder.
Answer:
KS < KC
Explanation:
g A velocity selector consists of crossed electric and magnetic fields. The electric field has a magnitude of 480 N/C and is in the negative z direction. What should the magnetic field (magnitude and direction) be to select a proton moving in the negative x direction with a velocity of 3.50 cross times 10 to the power of 5 m/s to go un-deflected
Answer:
B = 1.37 mT
Explanation:
Given that,
The magnitude of the electric field, E = 480 N/C
The speed of the proton, [tex]v=3.50 \times 10^5\ m/s[/tex]
We need to find the magnitude of the magnetic field. In a velocity selector, the electric field is balanced by the magnetic field. So,
[tex]qE=qvB[/tex]
Where
B is the magnetic field
[tex]B=\dfrac{E}{v}\\\\B=\dfrac{480}{3.5\times 10^5}\\\\B=1.37\times 10^{-3}\ T\\\\or\\\\B =1.37\ mT[/tex]
So, the magnetic field is equal to 1.37 mT.
A police siren of frequency fsiren is attached to a vibrating platform. The platform and siren oscillate up and down in simple harmonic motion with amplitude Ap and frequency fp. Use v for the speed of sound. Part A Find the maximum sound frequency that you would hear at a position directly above the siren. At what point in the motion of the platform is the minimum frequency heard
Answer:
he maximum frequency occurs when the denominator is minimum
f’= f₀ [tex]\frac{343}{343 + v_s}[/tex]
Explanation:
This is a doppler effect exercise, where the sound source is moving
f = fo [tex]\frac{v}{v-v)s}[/tex] when the source moves towards the observer
f ’=f_o [tex]\frac{v}{v+v_{sy}}[/tex] Alexandrian source of the observer
the maximum frequency occurs when the denominator is minimum, for both it is the point of maximum approach of the two objects
f’= f₀ [tex]\frac{343}{343 + v_s}[/tex]
The wireless system is operating at 2GHz. A base station and a mobile unit are separated by 16km. The maximum gain of the transmitting antenna at the base station is 20dB. The input power to the transmitter is 100W, and the power received by the antenna is 5nW. The antennas are aligned, and there are no re ections or loses. What will be the received power if the distance between the mobile unit and the base station increases to 20km?
If everything else remains constant, then the received signal power is simply an inverse-square function of its distance from the transmitter.
That is, down 6dB when distance is doubled etc.
If distance increases from 16 to 20, then received power decreases by the factor of (16/20)^2.
That's (0.8)^2 = 0.64
New receive power is 5x0.64 = 3.2 nW
=. ===== ==========
Here's how I do it at my job:
Initial RSL = 5nW ~ - 53 dBm
loss = 20log(20/16)= 20log(1.25)~1.94dB
New RSL = - 54.94 dBm or ~ 3.2 nW .
Which of the following best describes
pollutants?
A. harmful substances in the air, water, or soil
B. radioactive particles that pass through the atmosphere
C. oxygen molecules that are released by plants
D. beneficial substances that increase overall health
Answer:
A. harmful substances in the air, water, or soil
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a
Ten 2.2 v cells each having an internal
resistance of o.1ohms in are connected in series
to a load of 21ohm. Determine
pd at the battery terminals
Answer:
22Volts
Explanation:
The pd at the terminal is known as the emf
Since there are Ten 2.2V cells
Terminal voltage = number of cells * pd of one cell
Terminal voltage = 10 * 2.2
Terminal voltage = 22V
Hence the pd at the battery terminals is 22Volts
Question Set: Waves and Wave Properties
Answer:
The basic properties (parts) of a wave include: frequency, amplitude, wavelength and speed. Frequency is a measure of how many waves pass a point in a certain amount of time.
Assignment: Calculating Speed Investigation
Data Analysis:
Note: Please submit your data table with this assignment.
1. Write your original hypothesis here.
2. Calculate the average time for vehicle 1 from the information in your data table. Show all work.
3. Calculate the average time for vehicle 2 from the information in your data table. Show all work.
4. Calculate the average speed for vehicle 1 from the information in your data table. Show all work, including the formula used.
5. Calculate the average speed for vehicle 2 from the information in your data table. Show all work, including the formula used.
Conclusion:
Think about this information and then write a conclusion based on the data of this experiment. Don’t forget to connect the conclusion to the original hypothesis.
Were you able to support your hypothesis or not? Be sure to base your answer on the data you collected. Consider whether your conclusion is the only explanation for the data you collected or if there could be alternate explanations. Don’t forget to mention any scientific laws or theories you have studied that would apply to this experiment.
Follow-up Questions:
1. If your experiment did not seem to match the expected results, what did you learn from the experience?
2. Instantaneous speed is the rate of motion of an object at a particular moment in time. What change(s) to the experimental procedure would be necessary if you wanted to gather data on instantaneous speed?
and as for the data can you please make your own
Answer:
Assignment: Calculating Speed Investigation
Data Analysis:
Note: Please submit your data table with this assignment.
1. Write your original hypothesis here.
2. Calculate the average time for vehicle 1 from the information in your data table. Show all work.
3. Calculate the average time for vehicle 2 from the information in your data table. Show all work.
4. Calculate the average speed for vehicle 1 from the information in your data table. Show all work, including the formula used.
5. Calculate the average speed for vehicle 2 from the information in your data table. Show all work, including the formula used.
Conclusion:
Think about this information and then write a conclusion based on the data of this experiment. Don’t forget to connect the conclusion to the original hypothesis.
Were you able to support your hypothesis or not? Be sure to base your answer on the data you collected. Consider whether your conclusion is the only explanation for the data you collected or if there could be alternate explanations. Don’t forget to mention any scientific laws or theories you have studied that would apply to this experiment.
Follow-up Questions:
1. If your experiment did not seem to match the expected results, what did you learn from the experience?
2. Instantaneous speed is the rate of motion of an object at a particular moment in time. What change(s) to the experimental procedure would be necessary if you wanted to gather data on instantaneous speed?
and as for the data can you please make your own
Explanation:
Assignment: Calculating Speed Investigation
Data Analysis:
Note: Please submit your data table with this assignment.
1. Write your original hypothesis here.
2. Calculate the average time for vehicle 1 from the information in your data table. Show all work.
3. Calculate the average time for vehicle 2 from the information in your data table. Show all work.
4. Calculate the average speed for vehicle 1 from the information in your data table. Show all work, including the formula used.
5. Calculate the average speed for vehicle 2 from the information in your data table. Show all work, including the formula used.
Conclusion:
Think about this information and then write a conclusion based on the data of this experiment. Don’t forget to connect the conclusion to the original hypothesis.
Were you able to support your hypothesis or not? Be sure to base your answer on the data you collected. Consider whether your conclusion is the only explanation for the data you collected or if there could be alternate explanations. Don’t forget to mention any scientific laws or theories you have studied that would apply to this experiment.
Follow-up Questions:
1. If your experiment did not seem to match the expected results, what did you learn from the experience?
2. Instantaneous speed is the rate of motion of an object at a particular moment in time. What change(s) to the experimental procedure would be necessary if you wanted to gather data on instantaneous speed?
and as for the data can you please make your ownWhich sentence uses a superlative adjective correctly?
Anthony is running more quickly than anyone else on the field.
Shalon is a very talented pianist.
That is the best chocolate cake I have ever tasted.
Ani is the better gymnast of the two.
Which statement best compares and contrasts the purpose of "PROSERPINE" to that of "How Old Man Winter Was Driven Back"?
The Greek myth explains the creation of the earth, while the Iroquois myth also explains why there is evil in the world.
The Greek myth explains the creation of the earth, while the Iroquois myth also explains the creation of the moon.
The Greek myth explains the changing of the seasons as well as the existence of the underworld, while the Iroquois myth also explains the changing of the seasons.
The Greek myth explains the creation of the moon, while the Iroquois myth explains the creation of the sun.
Read the passages:
from "How Old Man Winter Was Driven Back"
"I, too, am powerful, and I am young! I do not fear you. When I touch the earth, it grows soft and warm. Every living thing stirs in its sleep,—birds and bees, flowers and trees, animals and men. When I speak, the sleeping sun awakes. See! Already he begins to send down his arrows. Hasten! that they may not find you, on the trail to the North Sky."
from "How the World Was Made"
Even some of the trees went to sleep. Only the cedar, the pine, the spruce, the holly, and the laurel were awake all seven nights. Therefore they are always green. They are also sacred trees. But to the other trees it was said, “Because you did not stay awake, therefore you shall lose your hair every winter.”
Which best uses textual evidence to compare and contrast these two myths?
Both myths show the change in seasons as a violent battle.
In "How Old Man Winter Was Driven Back," the change in
A train whistle produces a sound at a frequency of 600 Hz. If the train is moving toward a stationary observer at a constant speed, which of the following may be the frequency of the whistle as detected by the observer?
A pulley in the shape of a solid cylinder of mass 1.50 kg and radius 0.240 m is free to rotate around a horizontal shaft along the axis of the pulley. There is friction between the pulley and this shaft. A light, nonstretching cable is wrapped around the pulley, and the free end is tied to a 2.00 kg textbook. You release the textbook from rest a distance 0.900 m above the floor. Just before the textbook hits the floor, the angular speed of the pulley is 10.0 rad/s. What is the speed of the textbook just before it hits the floor
Answer:
the speed of the textbook just before it hits the floor is 2.4 m/s
Explanation:
Given the data in the question;
mass of pulley = 1.50 kg
radius of pulley = 0.240 m
mass of text book = 2.0 kg
height from which text book was released = 0.9 m
angular speed of the pulley = 10.0 rad/s
the speed of the textbook just before it hits the floor = ?
the speed of the textbook v = angular speed of the pulley × radius of pulley
we substitute
v = 10.0 rad/s × 0.240 m
v = 2.4 m/s
Therefore, the speed of the textbook just before it hits the floor is 2.4 m/s
A form of oxygen with three atoms of
oxygen bonded together instead of two is
called what?
A. triple oxygen
B. ozone
C. oxygen-3
D. trioxygen
Answer:
ozone, letter b
ozone is basically an allotrope of oxygen having three atoms instead of two.
Guys can you please help me with this
Please solve it.... Urgent
Answer:
a) ferromagnetic type, b) superconductor or ferromagnetic
Explanation:
In substances, magnetism is the result of the magnetic moments of the electrons in their orbits and of the spin.
These two let us take interacting magnetic between them, if the sum of these magnetic moments is maximum we have a material of the ferromagnetic type, which is represented in figure a, where all the magnetic moments are aligned in one direction and this type of material is a magnet permanent.
Figure b shows a material where the magnetic moments have a circular shape, so the total moment is zero.The type of substrate material can have several possibilities
* The most test is that the substrate material is a superconductor where the marked areas are the superconducting magnetic areas and the areas without spine are the normal areas
* Another possibility is that the material is ferromagnetic, that is, there are several magnetic sub-networks in different orientation, resulting in a random field, the material is not a permanent magnet
Coherent monochromatic light of wavelength l passes through a narrow slit of width a, and a diffraction pattern is observed on a screen that is a distance x from the slit. On the screen, the width w of the central diffraction maximum is twice the distance x. What is the ratio a>l of the width of the slit to the wavelength of the light
Answer:
λ = a
Explanation:
This is a diffraction exercise that is described by the expression
a sin θ = m λ
sin θ = m λ/ a
the first zero of the diffraction occurs for m = 1
sin θ = λ / a
angles are generally very small and are measured in radians
sin θ = θ = y / x
we substitute
[tex]\frac{y}{x} = \frac{\lambda}{a}[/tex]
the width of the central maximum is twice the distance to zero
w = 2y
in the exercise indicate that this width is equal to twice the distance to the screen (2x)
W = 2x
2y = 2x
we substitute
1 = λ/ a
λ = a
we see that the width of the slit is equal to the wavelength used.
A car travels 60km in 45 minutes. At the same average speed, how far will it travel in 1 hour 30 minutes?
Suppose we replace both hover pucks with pucks that are the same size as the originals but twice as massive. Otherwise, we keep the experiment the same. Compared to the pucks in the video, this pair of pucks will rotate View Available Hint(s) Suppose we replace both hover pucks with pucks that are the same size as the originals but twice as massive. Otherwise, we keep the experiment the same. Compared to the pucks in the video, this pair of pucks will rotate four times as fast. at the same rate. one-fourth as fast. twice as fast. one-half as fast.
Answer:
w = w₀ / 2 the angular velocity is half the initial value.
Explanation:
We can analyze this exercise as if we added another disk to obtain a disk with twice the mass, for which if the system is two disks, the angular tidal wave is conserved
initial instant.
L₀ = I₀ w₀
final moment
L_f = I w
the moment is preserved
L₀ = L_f
I₀ w₀ = I w
the moment of inertia of a disk is
I = ½ m R²
we substitute
½ m R² w₀ = ½ (2m) R² w
w = w₀ / 2
for the case of a disk with twice the mass, the angular velocity is half the initial value.
Which lists the springs in order of increasing spring constant?
W, Y, X, Z
OW, Y, Z, X
O Z, X, Y, W
OX,Z,Y, W
Answer:
is there supposed to be a picture?
Explanation:
The correct order of the springs in increasing spring constant is: W, Y, X, Z. The correct option is A.
What is the spring constant?Spring constant, also known as force constant or stiffness, is a measure of the resistance of a spring to deformation when a force is applied to it. It is defined as the amount of force required to stretch or compress a spring by a given distance.
The formula for the spring constant is:
k = F/x
Where
k = is the spring constant,
F = is the applied force,
x =is the displacement or deformation of the spring.
The unit of spring constant is newtons per meter (N/m) in the SI system of units, or pounds per inch (lb/in) in the Imperial system.
A higher spring constant means that a spring is stiffer and requires more force to be stretched or compressed by a given distance. A lower spring constant means that a spring is more flexible and requires less force to be stretched or compressed by a given distance. The spring constant is an important property of springs, which are used in various applications, such as in suspension systems, mattresses, and mechanical watches.
Here in the Question,
In order to determine the order of increasing spring constant, we need to compare the given springs and see which one requires more force to stretch or compress.
Therefore, The correct order of the springs in increasing spring constant is: W, Y, X, Z. This is because the spring constant increases as we move from W to Z.
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2. What does SCA stand for? (1 Point) Student Conservation Association h Securities Class Action Sudden Cardiac Arrest Solar Cell Array:',)
Answer:
sudden cardiac arrest
Explanation:
HELP HELP HELP HELP HELP PLEASEEE HELP ME WITH MY OTHER QUESTIONS TOO!! PLEASE
Help please & actually answer thank youu :)
Answer:
highest KE and lowest GPE = Dhighest GPE and lowest KE = Asome KE and some PE = BThe indices of refraction for her contact lens, cornea, and the fluid behind her cornea are 1.6, 1.4, and 1.3, respectively. Light is incident from air onto her contact lens at an angle of 30 ∘∘ from the normal of the surface. At what angle is the light traveling in the fluid behind her cornea?
Answer:
[tex]23^{\circ}[/tex]
Explanation:
n = Refractive index of air = 1
[tex]n_1[/tex] = Refractive index of contact lens = 1.6
[tex]n_2[/tex] = Refractive index of cornea = 1.4
[tex]n_3[/tex] = Refractive index of fluid = 1.3
From Snell's law
[tex]n\sin30^{\circ}=n_1\sin\theta\\\Rightarrow \theta=\sin^{-1}\dfrac{1\sin30^{\circ}}{1.6}\\\Rightarrow \theta=18.21^{\circ}[/tex]
[tex]n_1\sin\theta=n_2\sin\theta_1\\\Rightarrow \theta_{1}=\sin^{-1}\dfrac{1.6\times \sin18.21^{\circ}}{1.4}\\\Rightarrow \theta_1=20.92^{\circ}[/tex]
[tex]n_2\sin\theta_1=n_3\sin\theta_3\\\Rightarrow \theta_3=\sin^{-1}\dfrac{1.4\sin20.92^{\circ}}{1.3}\\\Rightarrow \theta_3=22.62^{\circ}\approx 23^{\circ}[/tex]
The angle is the light traveling in the fluid behind her cornea is [tex]23^{\circ}[/tex].
The angle is the light traveling in the fluid will be 23⁰. Light is traveling in a particular direction with an angle.
What is snell law?"The ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant, for the light of a given color and for a given set of media,
The given data in the problem is;
n is the refractive index of air = 1
n₁ is the refractive index of contact lens = 1.6
n₂ is the refractive index of cornea = 1.4
n₃ is the refractive index of fluid = 1.3
According to Snell's law. The formula for Snell's law is
[tex]\rm n sin30^0 = n_1 sin\theta \\\\ \theta = sin^{- 1}(\frac{1sin30^0}{1.6} )\\\\ \theta = 18.21 ^0[/tex]
For contact lenses;
[tex]\rm n_1sin\theta = n_2 sin\theta_1 \\\\ \theta_1 = sin^{-1}\frac{1.6 \times sin 18.21^0}{1.4} \\\\ \theta_1 =20.92 ^0[/tex]
For fluid;
[tex]n_2 sin\theta_1 = n_2 sin \theta_3\\\\ \theta_3 = sin^{-1}\frac{1.4 sin 20.92^0}{1.3} \\\\ \theta_3 = 22.62 ^ 0 =23^0[/tex]
Hence the angle is the light traveling in the fluid will be 23⁰.
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Niobium metal becomes a superconductor when cooled below 9K. Itssuperconductivity is destroyed when the surface magnetic fieldexceeds 0.100 T. Determine the maximum current a 2.00-mm-diameterniobium wire can carry and remain superconducting, in the absenceof any external magnetic field.
Answer:
the maximum current is 500 A
Explanation:
Given the data in the question;
the B field magnitude on the surface of the wire is;
B = μ₀i / 2πr
we are to determine the maximum current so we rearrange to find i
B2πr = μ₀i
i = B2πr / μ₀
given that;
diameter d = 2 mm = 0.002 m
radius = 0.002 / 2 = 0.001 m
B = 0.100 T
we know that permeability; μ₀ = 4π × 10⁻⁷ Tm/A
so we substitute
i = (0.100)(2π×0.001 ) / 4π × 10⁻⁷
i = 500 A
Therefore, the maximum current is 500 A
Which one of the following statements is not true of free falling object
Answer:
FORCE as for my answer....
PROJECT: VIRTUAL LABS — CIRCUITS
Answer:
Table A
Measuring Current as a Function of Voltage with a 20 Ω Resistor
Voltage
(V)
Current: Calculated
(A)
Current: Experimental
(A)
1 0.05 0.05
5 0.25 0.25
10 0.50 0.50
20 1.00 1.00
50 2.50 2.50
Table B
Measuring Current as a Function of Resistance at 25 V
Resistance
(Ω)
Current: Calculated
(A)
Current: Experimental
(A)
10 2.50 2.50
20 1.25 1.25
100 0.25 0.25
200 0.12 0.12
Table C
Measuring Current in a Parallel Circuit
Resistor Set
(Ω)
Total
Resistance
(Ω)
Calculated
Current
(A)
Observed
Current
(A)
Observed Current
through Each Resistor
(A)
20, 20, 20 6.67 3.75 3.74 1.25, 1.25, 1.25
20, 20, 200 9.52 2.63 2.62 1.25, 1.25, 0.12
Voltage needed to raise current to 3.75 A (20, 20, 200 resistor set):
Calculated: 35.7
Observed: 36
Table D
Calculating Power of Circuit ComponentsTeacher Guide (continued)
Observed Total Current
(A)
Current through Each Bulb
(A)
Power Usage per Bulb
(W)
2.00 0.67 6.7
Explanation:
got this from the teachers guide
Please answer the one you know!
3.
Two Cars, A and B, (starting, at the same time, from the same point) are moving
with average speeds of 40 km/h and 50 km/h, respectively, in the same direction.
Find how far will Car B be from Car A after 3 hours.
Answer:
car B will be 30 Km ahead of car A.
Explanation:
We'll begin by calculating the distance travelled by each car. This is illustrated below:
For car A:
Speed = 40 km/h
Time = 3 hours
Distance =?
Speed = distance / time
40 = distance / 3
Cross multiply
Distance = 40 × 3
Distance = 120 Km
For car B:
Speed = 50 km/h
Time = 3 hours
Distance =?
Speed = distance / time
50 = distance / 3
Cross multiply
Distance = 50 × 3
Distance = 150 Km
Finally, we shall determine the distance between car B an car A. This can be obtained as follow:
Distance travelled by car B (D₆) = 150 Km
Distance travelled by car A (Dₐ) = 120 Km
Distance apart =?
Distance apart = D₆ – Dₐ
Distance apart = 150 – 120
Distance apart = 30 Km
Therefore, car B will be 30 Km ahead of car A.