Answer:
The volume of 8.625 g of sulphur dioxide at RTP is approximately 3,230.84 cm³
Explanation:
The question requires the determination of the volume occupied by the gas based on the molar volume of a gas at STP
The given parameters of the sulphur dioxide, SO₂, gas are;
The mass of the given SO₂ gas = 8.625 g
The molar mass of SO₂ = 64.07 g/mol
The number of moles, 'n', in the given sample of SO₂ gas = Mass of SO₂/(Molar Mass of SO₂)
∴ The number of moles of SO₂ in the gas sample = 8.625 g/(64.07 g/mol) ≈ 0.134618386 moles
The molar volume of a gas at RTP is approximately 24 dm³/mole
24 dm³ = 24,000 cm³
∴ The molar volume of a gas at RTP is approximately 24,000 cm³/mole
The volume occupied by a gas at RTP = (The number of moles of the gas) × (The Molar Volume of a gas at RTP)
∴ The volume occupied by the 8.625 g of SO₂ gas at RTP = 0.134618386 moles × 24,000 cm³/mole ≈ 3,230.84 cm³
The volume occupied by the 8.625 g of SO₂ gas at RTP ≈ 3,230.84 cm³.
Use the periodic table to determine which of the
following could be an isotope of bromine (Br).
Check all that apply.
Z = 79, A = 196
Z = 35, A = 79
A = 79, N =44
D Z = 44, N = 44
DONE
Which of the following has the smallest atomic radius?
a B
b Al
c F
d N
e Ga
Answer:
c. F
Explanation:
As you go top to bottom down a column of the periodic table, atomic radius increases.
As you go left to right across a period of the periodic table, atomic radius decreases.
Knowing this trend, that means that the smallest atomic radius would be located in the top right of the periodic table. The closest element to that point is fluorine, or answer C.
which one of these is NOT a unit for a reaction rate. 1) g/mL 2) M/min
Hold the slides for observation