Veronica is looking for a reliable website with information about how old you have to be to use social media. What should she look for?

Im not sure but the person above is right x :)))


Explanation dudjdb

Answer:

In Python:

cents = int(input("Cents: "))

dollars = int(cents/100)

quarters = int((cents - 100*dollars)/25)

dimes = int((cents - 100*dollars- 25*quarters)/10)

nickels = int((cents - 100*dollars- 25*quarters-10*dimes)/5)

pennies = cents - 100*dollars- 25*quarters-10*dimes-5*nickels

if not(dollars == 0):

   if dollars > 1:

       print(str(dollars)+" dollars")

   else:

       print(str(dollars)+" dollar")

if not(quarters == 0):

   if quarters > 1:

       print(str(quarters)+" quarters")

   else:

       print(str(quarters)+" quarter")

if not(dimes == 0):

   if dimes > 1:

       print(str(dimes)+" dimes")

   else:

       print(str(dimes)+" dime")

if not(nickels == 0):

   if nickels > 1:

       print(str(nickels)+" nickels")

   else:

       print(str(nickels)+" nickel")

if not(pennies == 0):

   if pennies > 1:

       print(str(pennies)+" pennies")

   else:

       print(str(pennies)+" penny")

   

Explanation:

A prompt to input amount in cents

cents = int(input("Cents: "))

Convert cents to dollars

dollars = int(cents/100)

Convert the remaining cents to quarters

quarters = int((cents - 100*dollars)/25)

Convert the remaining cents to dimes

dimes = int((cents - 100*dollars- 25*quarters)/10)

Convert the remaining cents to nickels

nickels = int((cents - 100*dollars- 25*quarters-10*dimes)/5)

Convert the remaining cents to pennies

pennies = cents - 100*dollars- 25*quarters-10*dimes-5*nickels

This checks if dollars is not 0

if not(dollars == 0):

If greater than 1, it prints dollars (plural)

   if dollars > 1:

       print(str(dollars)+" dollars")

Otherwise, prints dollar (singular)

   else:

       print(str(dollars)+" dollar")

This checks if quarters is not 0

if not(quarters == 0):

If greater than 1, it prints quarters (plural)

   if quarters > 1:

       print(str(quarters)+" quarters")

Otherwise, prints quarter (singular)

   else:

       print(str(quarters)+" quarter")

This checks if dimes is not 0

if not(dimes == 0):

If greater than 1, it prints dimes (plural)

   if dimes > 1:

       print(str(dimes)+" dimes")

Otherwise, prints dime (singular)

   else:

       print(str(dimes)+" dime")

This checks if nickels is not 0

if not(nickels == 0):

If greater than 1, it prints nickels (plural)

   if nickels > 1:

       print(str(nickels)+" nickels")

Otherwise, prints nickel (singular)

   else:

       print(str(nickels)+" nickel")

This checks if pennies is not 0

if not(pennies == 0):

If greater than 1, it prints pennies (plural)

   if pennies > 1:

       print(str(pennies)+" pennies")

Otherwise, prints penny (singular)

   else:

       print(str(pennies)+" penny")

   

Answer:

juan duhhhhh hehehe

Explanation:

Answer: A dragon name could be name Holls and at level 14 and can breathe fire

Explanation:

Answer: They can ship 32 puzzle cubes in the box.

Explanation: So the volume of each puzzle cubes = side³

=(4)³ cubic inches.

Then the volume of the box is= (8×12×16) cubic inches.

(8×12×16)/4^3= 32

Please Help! Unit 6: Lesson 1 - Coding Activity 2
Instructions: Hemachandra numbers (more commonly known as Fibonacci numbers) are found by starting with two numbers then finding the next number by adding the previous two numbers together. The most common starting numbers are 0 and 1 giving the numbers 0, 1, 1, 2, 3, 5...
The main method from this class contains code which is intended to fill an array of length 10 with these Hemachandra numbers, then print the value of the number in the array at the index entered by the user. For example if the user inputs 3 then the program should output 2, while if the user inputs 6 then the program should output 8. Debug this code so it works as intended.

The Code Given:

import java.util.Scanner;

public class U6_L1_Activity_Two{
public static void main(String[] args){
int[h] = new int[10];
0 = h[0];
1 = h[1];
h[2] = h[0] + h[1];
h[3] = h[1] + h[2];
h[4] = h[2] + h[3];
h[5] = h[3] + h[4];
h[6] = h[4] + h[5];
h[7] = h[5] + h[6];
h[8] = h[6] + h[7]
h[9] = h[7] + h[8];
h[10] = h[8] + h[9];
Scanner scan = new Scanner(System.in);
int i = scan.nextInt();
if (i >= 0 && i < 10)
System.out.println(h(i));
}
}