Use the graph method to solve the system of Linear equations:
2x + y = 3 and x + y = 3
A) (-1.5, 0)
B) (0, -1.5)
C) (0,3)
D) (3, 0)

The percentage of motorists falling in each category, in the long term, are as follows:

High-risk category = 70%

Low-risk category = 30%

Data and Calculations:

Risk Profile Categories of Motorists

                                                       High Risk      Low Risk

Probability of remaining

 in the same category                      50%              10%

Probability of moving to another

 category                                          50%              90%

Probability a motorist falling in the high-risk category = (50% x 50%) + (50% x 90%)

= 25% + 45%

= 70%

Probability a motorist falling in the low-risk category = (50% x 50%) + (50% x 10%)

= 25% + 5%

= 30%

Thus, the probability of a motorist falling in the high-risk category is 70%, while the probability of a motorist falling in the low-risk category is 30%.

Learn more about probability here: https://brainly.com/question/24756209

By Green's theorem (all the conditions are met), we have

[tex]\displaystyle \int_C \sqrt y \, dx + \sqrt x \, dy = \iint_D \frac{\partial(\sqrt x)}{\partial x} - \frac{\partial(\sqrt y)}{\partial y} \, dx \, dy[/tex]

where D is the interior of the path C, or the set

[tex]D = \left\{ (x, y) : 0 \le y \le \dfrac{x^2}2 \text{ and } 0 \le x \le 2 \right\}[/tex]

So, the line integral reduces to the double integral,

[tex]\displaystyle \frac12 \int_0^2 \int_0^{\frac{x^2}2} x^{-\frac12} - y^{-\frac12} \, dy \, dx[/tex]

[tex]\displaystyle = \frac12 \int_0^2 x^{-\frac12}\left(\frac{x^2}2\right) - 2\left(\frac{x^2}2\right)^{\frac12} \, dx[/tex]

[tex]\displaystyle = \frac12 \int_0^2 \frac12 x^{\frac32} - \sqrt 2 \, x \, dx[/tex]

[tex]\displaystyle = \frac14 \int_0^2 x^{\frac32} - 2\sqrt 2 \, x \, dx[/tex]

[tex]\displaystyle = \frac14 \left(\frac25\cdot2^{\frac52} - \sqrt2\cdot2^2\right) = \boxed{-\frac{3\sqrt2}5}[/tex]

Answer:

year 3:25 A,C,E

Step-by-step explanation:

Hay cero milésimas en los parámetros dados.

El valor posicional se refiere al valor representado por un dígito en un número sobre la base de su posición en el número.

De los parámetros dados:

Si sumamos los valores juntos, podremos determinar la cantidad de milésimas que tenemos:

= 2200+515+176.5

= 2891.5

Por tanto, podemos concluir que hay cero milésimas en los parámetros.

Obtenga más información sobre el valor posicional aquí:

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she will drive 754 miles in 13 hrs.

Answer:

E

Step-by-step explanation:

[tex]\sqrt{\dfrac{64}{49}} = \dfrac{\sqrt{64}}{\sqrt{49}} = \dfrac 87[/tex]

Answer:

E

Step-by-step explanation:

Answer:

  x -2y = -4

Step-by-step explanation:

The slope of the line between points C and D is ...

  m = (y2 -y1)/(x2 -x1)

  m = (7 -13)/(5 -2) = -6/3 = -2

The slope of the perpendicular line is the opposite reciprocal of this: -1/(-2) = 1/2. The point-slope equation of the desired line is ...

  y -k = m(x -h) . . . . line with slope m through point (h, k)

  y -1 = 1/2(x -(-2))

We can rearrange this to standard form.

  2y -2 = x +2 . . . . . multiply by 2

  -4 = x -2y . . . . . . . subtract 2y+2

  x -2y = -4 . . . . . . standard form equation of the desired line

Answer:

5

Step-by-step explanation:

You divide your number by the denominator and then times it by the numerator

Answer: 384

Step-by-step explanation:

Answer: the cost would be 2398.19

Step-by-step explanation: hope this helps:)

Answer: changes over time

Step-by-step explanation: it is always decreasing

Answer:

[tex]\sqrt{242}[/tex]

Answer: It is f(x)= -3/2x-2

Step-by-step explanation: f(x) is the same as y. The formula for a line is slope-intercept form (y=mx+b). The -2 is the y-intercept, and the line intercepts the graph at -2. The slope is -3/2 because it rises 3 and goes to the left -2.

11/12

Answer:

1. find the least common denominator (LCD) of 2/3, 1/4 in other words, find the Least Common Multiple (LCM) of 3,4

Least Common Multiple (LCM) of 3,4 LCD = 12

Least Common Multiple (LCM) of 3,4 LCD = 122.

Least Common Multiple (LCM) of 3,4 LCD = 122.Make the Denominators the Same As The LCD.

Least Common Multiple (LCM) of 3,4 LCD = 122.Make the Denominators the Same As The LCD.2_x_4_ + _1 x 3__

Least Common Multiple (LCM) of 3,4 LCD = 122.Make the Denominators the Same As The LCD.2_x_4_ + _1 x 3__3 x 4 4x3

Least Common Multiple (LCM) of 3,4 LCD = 122.Make the Denominators the Same As The LCD.2_x_4_ + _1 x 3__3 x 4 4x33. Simplify denominators are Now The Same.

8/12 + 3/12

4. join the denominators

__8+3_____

12

5. Answer 11/12

Btw the Lines are Just For Separating numbers.

Answer: B

Step-by-step explanation: Function A starts at 0,2 and function B starts at 2,2

Answer:

It is C

Step-by-step explanation:

"No; Function A has an initial value of 2, and Function B has an initial value of 1. So, the functions do not have the same initial value."

Answer:

A) slope is 1

B) Slope is 3

C) slope is 0.5

Step-by-step explanation:

Using Rise over run method and mx+b

Answer:

d. Line UR and Line VW are parallel

Step-by-step explanation:

If they were to continue going straight, they would not touch, making them parallel.

I hope this helps!

Answer:

y = 6x - 4

General Formulas and Concepts:

Algebra I

Slope-Intercept Form: y = mx + b

Step-by-step explanation:

Step 1: Define

Identify variables.

m = 6

y = -4

Step 2: Find Equation

Answer:

[(P - (2 x l)] / 2

Step-by-step explanation:

[Perimeter - ( 2 x length) ] / 2

(64 - 2x22)/2 = 10 pulgadas de ancho

Answer:

y = 0.5x + 3

Step-by-step explanation:

Similar triangles may or may not have congruent sides, but the ratio of the corresponding sides will always be congruent.

(3) Corresponding sides of △MNP and △RST

Given that △MNP ∼△RST.

This means that, the corresponding sides are:

(4) The equal measures

Given that △ABC ∼△TUV

This means that, the corresponding angles are equal, but corresponding sides are not.

So, the equal measures are:

The unequal measure is:

(c) Scale mapping

The scale mapping is given as:

[tex]Ratio = 1\ in : 100\ mi[/tex]

The above scale means that 1 inches on the scale represents 100 miles of the actual distance.

Take for instance, 5 inches would represent 500 miles.

500 is 5 times 100

Hence, the actual distance between two towns 100 times the map distance between the two towns

Read more about similar triangles at:

https://brainly.com/question/14285697

Answer:

The answer is 20,880

Step-by-step explanation:

This won't be a very long explanation. What I did was add 18,000 plus 16% and I got 20,880.

Hope this helps!  

Have a nice day/night/afternoon.  

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Khalil uses the method of similar triangles to find the distance across the river, [tex]\overline{PR}[/tex]

Reasons:

The distances between the formed the sight-lines are;

[tex]\overline{RB}[/tex] = 185 feet

[tex]\overline{OC}[/tex] = 275 feet

The distance between the point close to the river and the next point further from the river [tex]\overline{RO}[/tex] = 150 feet

In triangles ΔPRB and ΔPOC, we have;

∠PRE = ∠POC = 90° Given

∠PER ≅ ∠PCO By corresponding angle formed between two parallel lines and a common transversal.

∴ ΔPRE is similar to ΔPOC by Angle-Angle, AA, similarity theorem

Which gives;

[tex]\displaystyle \frac{\overline {PR}}{\overline {PO}} = \mathbf{\frac{\overline {RE}}{\overline {OC}}}[/tex]

Let x represent the distance across the river, we have;

[tex]\overline{PR}[/tex] = x

[tex]\overline{PO}[/tex] = 150 + x

Which gives;

[tex]\displaystyle \frac{x}{150 + x} = \frac{185}{275}[/tex]

275·x = 185 × (150 + x) = 27,750 + 185·x

275·x - 185·x = 27,750

90·x = 27,750

[tex]\displaystyle x = \frac{27,750}{90} = \mathbf{308.\overline 3}[/tex]

Therefore, the distance across the river, x = [tex]\mathbf{\overline{PR}}[/tex] = [tex]\underline{308.\overline 3 \ feet}[/tex]

Learn more about similar triangles here

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Answer:

30 feet tall flag pole

Step-by-step explanation:

Answer:

Answer:

[tex]x=\frac{75}2[/tex]

Step-by-step explanation:

Give letters, as in the attached image.

The triangles ABE and CDE are similars (AAA). In particular [tex]AE:CE=BE:DE \rightarrow 46:30=(x+20):x \rightarrow 46x=30(x+20) \rightarrow 23x=15x+300 \rightarrow 8x=300\rightarrow x=\frac{75}2[/tex]

[tex]\text{Given that,}\\\\(x_1,y_1) = (-1,-2)~~ \text{and}~~ (x_2,y_2) = (-2,2)\\\\\text{Slope, m =} \dfrac{y_2-y_1}{x_2 -x_1} = \dfrac{2 -(-2)}{-2-(-1)} = \dfrac{2+2}{-2+1} = \dfrac{4}{-1} = -4[/tex]

Step-by-step explanation:

first we use Pythagoras to get t :

c² = a² + b²

with c being the Hypotenuse.

so,

t² = r² + s² = 10² + 31² = 100 + 961 = 1061

t = sqrt(1061)

and then we use the law of sine :

a/sin(A) = b/sin(B) = c/sin(C)

with the angles being opposite of their related sides.

so, r/sin(R) = t/sin(T) = t/sin(90) = t/1 = t

sin(R) = r/t = 10/sqrt(1061) = 0.30700278...

R = 17.8786966... ≈ 17.9°