uniform solid sphere has a mass of 1.765 kg and a radius of 0.854 m.a. Find the torque required to bring the sphere from rest to an angular velocity of 317 rad/s, clockwise, in 15.5 s.b. What magnitude force applied tangentially at the equator would provide the needed torque

Answer:

static force

Explanation:

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Answer:

Protists are difficult to characterize because of the great diversity of the kingdom. These organisms vary in body form, nutrition, and reproduction. They may be unicellular, colonial, or multicellular.

Answer:

There are many varying characteristics and exceptions to each type of protist.

They have been previously categorized based on what they are not

Recent studies show that protists have not descended from one common ancestor.

Explanation:

its right i took test :)

Answer:

From an average distance of 886 million miles (1.4 billion kilometers), Saturn is 9.5 astronomical units away from the Sun. One astronomical unit (abbreviated as AU), is the distance from the Sun to Earth. From this distance, it takes sunlight 80 minutes to travel from the Sun to Saturn.

we have that from the Question"The average mean distance of Saturn from the sun is" it can be said that  Tthe average mean distance of Saturn from the sun is

From the Question we are told

The average mean distance of Saturn from the sun is

Generally

The Sun is the star of the milky way galaxy and its distance from every planet in the milky way determines in one way or another its properties and in-habitability

Saturn being a Planet of the milky way we see that Saturn is a significant distance away from sun

A distance of 1427 x 10^6 km or 886 696 691 miles

Therefore

The average mean distance of Saturn from the sun is

A distance of 1427 x 10^6 km or 886 696 691 miles

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Answer:

Explanation:

From the information given;

mass of the crate m = 41 kg

constant horizontal force = 135 N

where;

[tex]s_1 = 15.0 \ m \\ \\ s_2 = 12.0 \ m[/tex]

coefficient of kinetic friction [tex]u_k[/tex] = 0.28

a)

To start with the work done by the applied force [tex](W_f)[/tex]

[tex]W_F = F\times (s_1 +s_2) \times cos(0) \ J[/tex]

[tex]W_F = 135 \times (12 +15) \times cos(0) \ J \\ \\ W_F = (135 \times 37 )J \\ \\ W_F =4995 \ J[/tex]

Work done by friction:

[tex]W_{ff} = -\mu\_k\times m \times g \times s_2 \\ \\ W_{ff} = -0.320 \times 41 \times 9.81 \times 12 \ J \\ \\ W_{ff} = -1544.49 \ J[/tex]

Work done  by gravity:

[tex]W_g = mg \times (s_1+s_2) \times cos (90)} \ J \\ \\ W_g = 0 \ j[/tex]

Work done by normal force;

[tex]W_n = N \times (s_1 + s_2) \times cos (90) \ J[/tex]

[tex]W_n = 0 \ J[/tex]

b)

total work by all forces:

[tex]W = F \times (s_1 + s_2) + \mu_k \times m \times g \times s_2 \times 180 \\ \\ W = 135 \times (15+12) \ J - 0.320 \times 41 \times 9.81 \times 12[/tex]

W = 2100.5  J

c) By applying the work-energy theorem;

total work done = ΔK.E

[tex]W = \dfrac{1}{2}\times m \times (v^2 - u^2)[/tex]

[tex]2100.5 = 0.5 \times 41 \times v^2[/tex]

[tex]v^2 = \dfrac{2100.5}{ 0.5 \times 41 }[/tex]

[tex]v^2 = 102.46 \\ \\ v = \sqrt{102.46} \\ \\ \mathbf{v = 10.1 \ m/s}[/tex]

Answer:

The answer should be D

Explanation:

Answer:

I know that story where the hare sleeps

Answer:

The energy of each photon can be transformed into kinetic energy and as this energy does not change, the energy of both photoelectrons remains constant,

Explanation:

The photoelectric effect was explained by Einstein, who assumed that the lz is made up of particles called photons each of a given energy, therefore the photoelectric effect can be explained as a collision of particles.

From this explanation we see that the intensity is proportional to the number of existing particles, when we double the intensity we double the number of particles, but the energy of each particle does not change, therefore if we use the conservation of energy.

The energy of each photon can be transformed into kinetic energy and as this energy does not change, the energy of both photoelectrons remains constant, only the number of electrons expelled changes.

Answer:

[tex]\huge\boxed{T = 0.025\ seconds}[/tex]

Explanation:

Given:

Frequency = f = 40 Hz

Required:

Time period = T = ?

Formula:

[tex]\sf T = 1 / f[/tex]

Solution:

T = 1 / 40

T = 0.025 seconds

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

Answer:

I think Yes because they could have different amounts of energy.

Explanation:

Answer:

athletic

Explanation:

because internet system has been down since we were in few days

Answer:

. It is an extraordinarily rare, silvery-white, hard, corrosion-resistant, and chemically inert transition metal. It is a noble metal and a member of the platinum group.

Explanation:

Answer: Both False

Explanation:

Our Milky Way Galaxy is a spiral galaxy. Some spiral galaxies are what we call "barred spirals" because the central bulge looks elongated

Irregualuar glaxyices are all over  the place

Answer:

1) 204.6663938

2) 19.51219512

3) 368

4) 135.81

5) 43932240

6) 63830.2

7) 2470.8

8) 1.718213058

9) 1005550.526

10) 586.365

Most of the questions you asked were in repeating decimal form.

Explanation:

Answer: I think $20 billion a year it’s worth the cost. The reasoning behind that is because we can conduct research on various things that could help out humanity. Therefore we can conclude that’s spending billions of dollars every year is worth it.

Explanation:

Answer:

F = 2074.13 lb

Explanation:

Given that,

Mass of car, m = 2800 lb = 1270.059 kg

Initial speed, u = 5 mi/h = 2.2352 m/s

Final speed, v = - 1.5 mi/h = -0.67056 m/s  (in opposite direction)

Time, t = 0.4 s

We need to find the magnitude of the average horizontal force (lb) exerted on the car during the impact. It can be calculated as :

[tex]F=m\times \dfrac{v-u}{t}\\\\F=1270.059\times \dfrac{-0.67056 -2.2352 }{0.4}\\\\F=9226.21\ N[/tex]

or

F = -2074.13 lb

So, the required force is 2074.13 lb.

This question is incomplete, the complete question is;

Car B is rounding the curve with a constant speed of 54 km/h, and car A is approaching car B in the intersection with a constant speed of 72 km/h. The x-y axes are attached to car B. The distance separating the two cars at the instant depicted is 40 m. Determine: the angular velocity of Bxy rotating frame (ω).

Answer:

the angular velocity of Bxy rotating frame (ω) is 0.15 rad/s

Explanation:

Given the data in the question and image below and as illustrated in the second image;

distance S = 40 m

V[tex]_B[/tex] = 54 km/hr

V[tex]_A[/tex] = 72 km/hr

α = 100 m

now, angular velocity of Bxy will be;

ω[tex]_B[/tex] = V[tex]_B[/tex] / α

so, we substitute

ω[tex]_B[/tex] = ( 54 × 1000/3600) / 100

ω[tex]_B[/tex] = 15 / 100

ω[tex]_B[/tex] = 0.15 rad/s

Therefore, the angular velocity of Bxy rotating frame (ω) is 0.15 rad/s

Answer:

1. [tex]P_{2}[/tex] = 8 x [tex]10^{4}[/tex] Pa

2. P = 1.5 x [tex]10^{5}[/tex] N/[tex]m^{2}[/tex]

Explanation:

1. From Boyles' law;

[tex]P_{1}[/tex][tex]V_{1}[/tex] = [tex]P_{2}[/tex][tex]V_{2}[/tex]

[tex]P_{1}[/tex] = 1 x [tex]10^{5}[/tex] Pa

[tex]V_{1}[/tex] = 9.6 [tex]m^{3}[/tex]

[tex]V_{2}[/tex] = 12 [tex]m^{3}[/tex]

Thus,

1 x [tex]10^{5}[/tex] x 9.6 =  [tex]P_{2}[/tex] x 12

 [tex]P_{2}[/tex] = [tex]\frac{100000 x 9.6}{12}[/tex]

     = 80000

[tex]P_{2}[/tex] = 8 x [tex]10^{4}[/tex] Pa

2. Pressure, P = ρhg

where: ρ is the density of the fluid, h is the height/ depth and g is the acceleration due to gravity (9.8 m/[tex]s^{2}[/tex]).

Thus,

P = 1020 x 15 x 9.8

  = 149940

P = 1.5 x [tex]10^{5}[/tex] N/[tex]m^{2}[/tex]

I go to k12 too and i am writing this test now too. I am like pretty sure my answer is correct. I guess we can kinda help eachother with this assignment cuz i am sorta stuck too.

I dont know i hope this helped a bit I know its not much i need help with this too.

Answer:

the potential energy decreases as it is converted to kinetic energy.

Explanation:

As things move, their potential energy converts to kinetic energy to power them along. When a ball rolls down the top of a ramp, all the potential energy it accumulated at the top of the ramp converts to kinetic energy to help it roll down. In other words, its potential energy decreases as its kinetic energy increases.

Answer:

Both.

Explanation:

Given that a block and a ball have the same mass and move with the same initial velocity across a floor and then encounter identical ramps. The block slides without friction and the ball rolls without slipping. 1)Which one makes it furthest up the ramp ?

Since both of them have the same mass and the same initial velocity, then, they will both have the same kinetic energy.

That is,

K.E = 1/2mv^2

Friction is a force that opposes motion. And since the frictional force is zero,

Both of them will accelerate from Newton's law.

F = ma

We can therefore conclude that both of them will make it further up the ramp.

Answer:

Steel

Explanation:

Steel is a metal that magnets stick to because iron can be found inside steel

Answer:Magnets stick to any metal that contains iron, cobalt or nickel.

Explanation:Iron is found in steel, so steel attracts a magnet and sticks to it. Stainless steel, however, does not attract a magnet.

Answer:

Is that your answer

Answer:

Vi = 0

Vf = 12 m/s

ΔV = Vf - Vi

ΔV = 12 m/s

Change in kinetic energy

ΔKE = Kf - Ki

ΔKE = 1/2 mv^2 - 0

ΔKE = 1/2 * 430 kg * (12 m/s)^2

ΔKE = 30,960

ΔKE = 30,960 joules

Work = ΔK

Work = 30,960 J

Answer:

Δθ = 15747.37 rad.

Explanation:

       [tex]\omega_{f1} = \alpha * \Delta t = 2.38*e-3rad/s2*2.04e3s = 4.9 rad/sec (1)[/tex]

       [tex]\omega_{f1}^{2} = 2* \alpha *\Delta\theta (2)[/tex]

       [tex]\theta_{1} = \frac{\omega_{f1}^{2}}{2*\alpha } = \frac{(4.9rad/sec)^{2}}{2*2.38*e-3rad/sec2} = 5044.12 rad (3)[/tex]

       [tex]\theta_{2} =\omega_{f1} * \Delta_{t2} = 4.9 rad/s * 1.48*e3 s = 7252 rad (4)[/tex]

       [tex]\omega_{f2}^{2} - \omega_{o2}^{2} = 2* \alpha *\Delta\theta (5)[/tex]

      [tex]\theta_{3} = \frac{(\omega_{f2})^{2}- (\omega_{f1}) ^{2} }{2*\alpha } = \frac{(2.42rad/s^{2}) -(4.9rad/sec)^{2}}{2*(-2.63*e-3rad/sec2)} = 3451.25 rad (6)[/tex]

Answer:

the external circuit is directed away from the positive terminal and toward the negative terminal of the battery

Answer:

Explanation:

Neutrinos are otherwise called leptons. They are principal particles. A lepton is a rudimentary half-spin molecule that doesn't go through solid reactions. Neutrinos are not usually charged and exceptionally light weighted so they once in a while interface with other matter. Neutrinos are light weighted. Their mass is around 10⁻⁷ kg. A neutrino possesses a small radius, too little to ever be estimated. A little span and very less mass make them imperceptible. Since neutrinos have next to no mass. they travel at almost the speed of light and thus they arrive at the outside of the Sun in only 2 seconds, dissimilar to photons which take convoluted ways to arrive at the Sun's surface in a huge number of years.  

The photon and neutrino, both were made in the Sun's center yet on various occasions. The neutrino is only a couple of minutes old though the photon is around 1,000,000 years of age. At the point when the photon was made in the Sun's center. it needed to venture out to the outside of the Sun. in any case, rather because of its hefty mass and cooperation with other matter, it headed out a crisscross way to the surface. Ordinarily, it was repulsed and it was sent back to the middle where it needed to begin once more. It required a large number of years for a photon to arrive at the outside of the Sun.

Nonetheless, when it arrived at the Sun's surface, it required just 8.8 minutes for the photon to arrive at Earth. The neutrino was anyway made only a couple of minutes prior in the Sun's center. Since it has an entirely irrelevant mass, little size, and no charge, it didn't interface with its environmental factors. So it just required 2 seconds for the neutrino to arrive at the Sun's surface. When it arrived at the Sun's surface, it arrived at the earth in about 8.8 minutes. with the photon. So both, photon and neutrino have various histories as the two of them were made at a hole of around 1,000,000 years.

Answer:

The magnification of an image is equal to the ratio of the image height to the object height.