Two mechanics worked on a car. The first mechanic worked for 20 hours, and the second mechanic worked for 5 hours. Together they charged a total of $2750.
What was the rate charged per hour by each mechanic if the sum of the two rates was $205 per hour?

-Whats the First mechanic: $ -----per hour

-Whats the Second mechanic: $ ---- per hour ​

Answers

Answer 1
I answer this question before this is the solution just change the total of $2750:

Two mechanics worked on a car, The first mechanic worked for 20 hours and the second mechanic worked for 5 hours together they charged a total of $1150.

Let's make,
mechanic #1's rate = x
mechanic #2's rate = y

* Their rate is dollars per hour ($/hr)

mechanic #1 worked for 20 hours (hr × $/hr = $)
20x = money earned by mech#1

and mechanic #2 worked for 5 hours
5y = money earned by mech#2

together they charged a total of $1150. So the amount of money earned by both mechanics.

20x + 5y = 1150

the sum of the two rates was $95 per hour.

x + y = 95

which means
x = 95 - y

plug (95 - y) in for "x" in the other equation to get everything in terms of one variable.

20(95 - y) + 5y = 1150

solve for y

1900 - 20y + 5y = 1150
1900 - 15y = 1150
-15y = 1150 - 1900
-15y = -750
y = -750/-15
y = 50 $/hr

Now use this to solve for x

x + y = 95
x + 50 = 95
x = 95 - 50
x = 45 $/hr

mech#1 charged 45$/hr
mech #2 charged 50$/hr

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

The path of a race will be drawn on a coordinate grid like the one shown below. The starting point of the race will be at (−5.3, 1). The finishing point will be at (1, −5.3).


Part A: Use the grid to determine in which quadrants the starting point and the finishing point are located. Explain how you determined the locations. (6 points)

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Answers

The Cartesian coordinate plane, specify locations by a pair of coordinates that indicate the magnitude in perpendicular, x, and y directions

The correct responses are;

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Reasons:

The location of the start point of the race = (-5.3, 1)

Location of the finishing point = (1, -5.3)

Part A: The signs of the x and y-values in the quadrants are;

[tex]\begin{tabular}{|cc|c|}Quad II, x -ve, y +ve&&Quad I, x, and y are +ve\\&&\\Quad III, x -ve, y -ve&&Quad IV, x +ve, y -ve\end{array}\right][/tex]

The coordinates of the starting point is (-5.3, 1), therefore, given that the x-

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The quadrant of the starting point is the second quadrant.

The coordinates of the finishing point is (1, -5.3), the x-value is positive and

the y-value is negative, which indicates that the quadrant of the finishing

point is quadrant IV (the fourth quadrant).

The quadrant of the finishing point is the fourth quadrant.

Part B: The location of the checkpoint is; (5.3, 1)

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Step-by-step explanation:

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Hi,

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= (4x² + 6xy + 9y²) - (4x² - 6xy + 9y²)

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i don’t believe you attached any pictures to this question so i don’t know exactly what kinds of different servings you want, however some examples would be

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\

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Hey there!

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[Jo is correct] whereas Mia is incorrect because she misunderstood the question.

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Step-by-step explanation:

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Step-by-step explanation:

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20*2=40                                 30

40*2=80                                 45

80*2=160                                 60

160*2=320                                 1hr 15

320*2=640                                 1hr 30

In 90 minutes the population to grow to 700 organisms.

Given that,

A strand of bacteria has a doubling time of 15 minutes.

If the population starts with 10 organisms.

We have to determine,

How long would it take for the population to grow to 700 organisms?

According to the question,

A strand of bacteria has a doubling time of 15 minutes.

If the population starts with 10 organisms.

In 15 minutes strand of bacteria has a doubling time the population starts with 10 organisms.

[tex]\rm = 10 \times 2 = 20 \ bacteria[/tex]

In 15 minutes 20 bacteria for the population to grow.

In 30 minutes strand of bacteria has a doubling time the population starts with 20 organisms.

[tex]\rm = 20 \times 2 = 40 \ bacteria[/tex]

In 30 minutes 40 bacteria for the population to grow.

In 45 minutes strand of bacteria has a doubling time the population starts with 40 organisms.

[tex]\rm = 40 \times 2 = 80 \ bacteria[/tex]

In 45 minutes 80 bacteria for the population to grow.

In 60 minutes strand of bacteria has a doubling time the population starts with 80 organisms.

[tex]\rm = 80 \times 2 = 160 \ bacteria[/tex]

In 60 minutes 160 bacteria for the population to grow.

In 75 minutes strand of bacteria has a doubling time the population starts with 160 organisms.

[tex]\rm = 160 \times 2 = 320 \ bacteria[/tex]

In 75 minutes 320 bacteria for the population to grow.

In 90 minutes strand of bacteria has a doubling time the population starts with 320 organisms.

[tex]\rm = 320 \times 2 = 640 \ bacteria[/tex]

In 90 minutes 640 bacteria for the population to grow.

In 120 minutes strand of bacteria has a doubling time the population starts with 640 organisms.

[tex]\rm = 640 \times 2 = 1280 \ bacteria[/tex]

In 120 minutes 1280 bacteria for the population to grow.

Hence, In 90 minutes the population to grow to 700 organisms.

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Answers

three points would include (0,0), (6,10), (9,15) (-3,-5)

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Answers

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Step-by-step explanation:

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Answers

[tex]x + 104 + 28 = 180 \\ (140 + 28 = 132) \\ x = 132[/tex]

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It would be 0.2

Mark as brainliest

Answer:

it will probably be 1/5

hope I am correct and sorry if not.

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