Answer:
False
Explanation:
When weak bases dissociate, an equilibrium is established rather than dissociating 100%. So OH- and metal ions are partially ionized.
What is it called when a gas turns into a liquid
Answer:
condensation
Explanation:
The process of a gas becoming a liquid is called condensation.
☁️ Answer ☁️
Condensation
"Condensation is the name of the process through which gas turns into a liquid. Three common states of matter exist: solids, liquids and gases. Matter, however, can change its state with the addition or subtraction of energy. The energy is usually in the form of heat. "
Hope it helps.
Have a nice day noona/hyung.
Calculate the moles of argon gas at STP in 33 L. Round answer to 2 significant figures.
Answer:
1.5 mol
Explanation:
Step 1: Given data
Volume of argon gas: 33 LStandard temperature: 273.15 KStandard pressure: 1 atmStep 2: Calculate the moles corresponding to 33 L of argon at standard temperature and pressure (STP)
At STP, 1 mole of argon gas occupies 22.4 L.
33 L × 1 mol/22.4 L = 1.5 mol
In what industry do fertilizers and pesticides wash off and contaminate water supplies?Construction Oil Transportation Agriculture
Answer:
The answer is agriculture.
Explanation:
Answer: Agriculture
Explanation:
I got it right on my exam
Convert 5.28 x 1019 molecules of C6H1206 to grams.
Answer:
[tex]m=0.0158g[/tex]
Explanation:
Hello there!
In this case, it is possible to comprehend these mass-particles problems by means of the concept of mole, molar mass and the Avogadro's number because one mole of any substance has 6.022x10²³ particles and have a mass equal to the molar mass.
In such a way, for C₆H₁₂O₆, whose molar mass is about 180.16 g/mol, the referred mass would be:
[tex]m=5.28x10^{19}molecules*\frac{1mol}{6.022x10^{23}molecules}*\frac{180.16g}{1mol}\\\\m=0.0158g[/tex]
Best regards!
what blood vessels and chambers of the heart does a molecule of glucose absorbed through the gut passes on its way to an active muscle in the leg
Answer:
Blood capillaries
Explanation:
The walls of capillaries are just one cell thick. Capillaries therefore allow the exchange of molecules between the blood and the body's cells - molecules can diffuse across their walls. This exchange of molecules is not possible across the walls of other types of blood vessel.
Considering change of state descriptions, select the name of the change of state for when energy is absorbed. Group of answer choices sublimation freezing condensation deposition
Answer: Sublimation
Explanation:
Sublimation : It is a process in which a solid directly changes to gaseous phase by providing heat.
Freezing is a process in which a liquid changes into solid phase when allowed to cool.
Condensation is a process in which a gas changes into liquid phase when allowed to cool.
Deposition is a process in which a gas deposits as solid phase when allowed to cool.
Thus change of state where energy is absorbed is sublimation.
In a given compound, the mass of sulfur (S) is 40.05 g and the mass of oxygen (O) is 59.95 g. What is
the empirical formula of the compound
Answer:
[tex]SO_3[/tex]
Explanation:
Hello there!
In this case, according to the definition of the empirical formula as the smallest representation of the molecular formula of a chemical compound; for us to determine it, we first need to calculate the moles of sulfur in 40.05 g and those of oxygen in 59.95 g as shown below:
[tex]n_S=\frac{40.05g}{32.07g/mol}= 1.25molS\\\\n_O=\frac{59.95g}{16.00g/mol}=3.75molO[/tex]
Now, we perform the following mole ratios to figure out the subscripts in the empirical formula, by dividing over the fewest number of moles:
[tex]S=\frac{1.25}{1.25}=1 \\\\O=\frac{3.75}{1.25}=3[/tex]
Therefore, the empirical formula turns out:
[tex]SO_3[/tex]
Best regards!
A student in the lab accidentally poured 45 mL of water into a graduated cylinder containing 15 mL of 3.0 M HCL. What is the concentration of the new solution?
Answer:
The correct approach is "1 M".
Explanation:
The given values are:
Volume of HCL,
V₁ = 45 ml
In prepared solution,
V₂ = 15 ml
Concentration,
C₁ = ?
C₂ = 3.0 M
As we know,
⇒ [tex]V_1C_1=V_2C_2[/tex]
or,
⇒ [tex]C_1=\frac{V_2C_2}{V_1}[/tex]
On substituting the values, we get
⇒ [tex]=\frac{15\times 3}{45}[/tex]
⇒ [tex]=\frac{45}{45}[/tex]
⇒ [tex]=1 \ M[/tex]
please help me out!! 10 points <3
Answer:it’s b
Explanation:I took. The test and got 100
Answer:
a- i know the other person said that it was b but i looked it but and it seems to be A. whoops-
Explanation:
__Zn+__HCI → _ZnCl2 + __H2
Answer:
1Zn+ 2HCI → 1ZnCl2 + 1H2
Which salt preparation uses a burette and a pipette
potassium chloride from potassium hydroxide and hydrochloric acid
A compound is found to contain 37.32 % phosphorus , 16.88 % nitrogen , and 45.79 % fluorine by
mass.
Question 1: The empirical formula for this compound is :
Question 2: The molar mass for this compound is 82.98 g/mol.
The Molecular formula for this compound is:
Answer: 1. The empirical formula is [tex]PNF_2[/tex]
2. The molecular formula is [tex]PNF_2[/tex]
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of P = 37.32 g
Mass of N = 16.88 g
Mass of F = 45.79 g
Step 1 : convert given masses into moles.
Moles of P =[tex]\frac{\text{ given mass of P}}{\text{ molar mass of P}}= \frac{37.32g}{31g/mole}=1.20moles[/tex]
Moles of N =[tex]\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{16.88g}{14g/mole}=1.20moles[/tex]
Moles of F =[tex]\frac{\text{ given mass of F}}{\text{ molar mass of F}}= \frac{45.79g}{19g/mole}=2.41moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For P = [tex]\frac{1.20}{1.20}=1[/tex]
For N = [tex]\frac{1.20}{1.20}=1[/tex]
For F =[tex]\frac{2.41}{1.20}=2[/tex]
The ratio of P: N: F= 1: 1: 2
Hence the empirical formula is [tex]PNF_2[/tex]
The empirical weight of [tex]PNF_2[/tex]= 1(31)+1(14)+2(19)= 82.98 g.
The molecular weight = 82.98 g/mole
Now we have to calculate the molecular formula.
[tex]n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}=\frac{82.98}{82.98}=1[/tex]
The molecular formula will be=[tex]1\times PNF_2=PNF_2[/tex]
calorimetry and specific heat lab report can someone please write this for me
If anyone still needed help on this, someone wrote out the student table on brainly.com, look up Lab: Calorimetry and Specific Heat.
The page should say something along the lines of please Please i need it Lab: Calorimetry and Specific Heat
This one should help you a lot more. Good luck.
Answer:
If anyone still needed help on this, someone wrote out the student table on brainly.com, look up Lab: Calorimetry and Specific Heat.
The page should say something along the lines of please Please i need it Lab: Calorimetry and Specific Heat
This one should help you a lot more. Good luck.
Explanation:
visible light travels from place to place as a
Answer:
Light can travel in three ways from a source to another location: (1) directly from the source through empty space; (2) through various media; (3) after being reflected from a mirror.
Explanation:
Atoms in the same GROUP have the same...
A . Size
B. Temperature
C. Number of energy levels
D. Reactivity
Answer:
reactivity
Explanation:
for example atoms in group 7 react by gaining 1 electron to become stable but they do not have the same number of energy levels
A solution contains 1.817 mg of CoSO4 (155.0 grams/mole) per mL. Calculate the volume (in mL) of 0.009795 M Zn2 needed to titrate the excess complexing reagent after the addition of 70.00 mL of 0.009005 M EDTA to a 20.00 mL aliquot of the Co2 solution.
Answer:
85.952 ml [tex]Zn^2^+[/tex] needed to titrate the excess complexing reagent .
Explanation:
Lets calculate
After addition of 80 ml of EDTA the solution becomes = 20 + 70 = 90 ml
As the number of moles of [tex]CoSO_4[/tex] =[tex]\frac{Given mass }{molar mass}[/tex]
=[tex]\frac{1.817}{155}[/tex]
=0.01172
Molarity = [tex]\frac{no. of moles}{volume of solution}[/tex]
=[tex]\frac{0.01172}{20}[/tex]
=0.000586 moles
Excess of EDTA = concentration of EDTA - concentration of CoSO4
= 0.009005 - 0.000586
= 0.008419 M
As M1V1 ( Excess of EDTA ) = M2V2 [tex](Zn^2^+)[/tex]
[tex]0.008419\times100ml=0.009795\times V2[/tex]
[tex]V2=\frac{0.008419\times100}{0.009795}[/tex]
V2 =85.952 ml
Therefore , 85.952 ml [tex]Zn^2^+[/tex] needed to titrate the excess complexing reagent .
A gas has a volume of 10 L at 200 K and a pressure of 1.5 atm . What would the volume of the gas be at 300 K and 2atm of pressure ?
Answer:
jeyjeyjetnetney
Explanation:
thmrhmrhmrum
Use the following Balanced Equation to complete the question: 2 Al + 6 HBr → 2 AlBr3 + 3 H2
If you have 10 moles of Al how many moles of H2 can be produced?
*Will give Brainly!*
When P4O10(s) reacts with H2O(l) to form H3PO4(aq) , 453 kJ of energy are evolved for each mole of P4O10(s) that reacts. Write a balanced thermochemical equation for the reaction with an energy term in kJ as part of the equation.
Answer:
P4O10 + 6H2O → 4H3PO4 ΔH = 453 kJ
Explanation:
A thermochemical reaction is one in which the amount of heat gained/evolved is written as part of the reaction equation.
A thermochemical equation helps us to judge whether an equation is endothermic or exothermic. For an endothermic reaction, ΔH is positive while for an exothermic reaction ΔH is negative.
Since, the reaction of one mole of P4O10(s) with H2O(l) to form H3PO4(aq) evolves 453 kJ of energy for each mole of P4O10(s) that reacts. Then we can write;
P4O10 + 6H2O → 4H3PO4 ΔH = 453 kJ
Hydrogen chloride dissolved in water yields hydrochloric acid. What is the
molar concentration of HCl if 3.65 g of hydrogen chloride is dissolved in 500 mL of
water?
Answer:
1500ml
Explanation:
molarity=3.65⋅g36.5⋅g⋅mol−1500⋅mL×10−3⋅L⋅mL−1=0.200⋅mol⋅L−1
Plzz help me well mark brainliest if you are correct
Answer:
A. non renewable energy sources cannot be used over again and renewable energy sources can be used again
Answer:
A. Nonrenewable energy sources cannot be used over again. Renewable energy sources can be used again.
Explanation:
What is the value of the equilibrium constant K ?
Answer:
K = 0.0209
Explanation:
K = [tex]\frac{[H_{2}][I_{2}]}{[2HI]^{2}}[/tex]
K = [tex]\frac{[4.35 x 10^{-2} ][2.79 x 10^{-2} ]}{[0.241]^{2} }[/tex]
K = 0.0208958
K = 0.0209
Titrations provide a method of quantitatively measuring the concentration of an unknown solution.
a. Trueb. False
Answer: True
Explanation:
Titration is a quantitative technique where a solution of known concentration is used to determine the concentration of an unknown solution. The titrant (the known solution) is added from a burette to a known quantity of the the unknown solution until the reaction is complete.
By knowing the volume of titrant, we can determine the concentration of the unknown.
Thus the statement Titrations provide a method of quantitatively measuring the concentration of an unknown solution is True .
What is orbit? A. An increase in centripetal motion and mass friction. B. Resistance of an object to avoid friction. C. Gravity causing a curved path as an object tries to go straight. D. How well an object floats.
Answer:
C. gravity causing a curved path as an object tries to go straight.
gases are really _______ and molecules are full of _______, bouncing around constantly
Answer:Gases are really spread out and the atoms and molecules are full of energy - , bouncing around constantly.
Explanation:
why is space cold ???
Because the space is ultimate thermos.
g At elevated temperatures, molecular hydrogen and molecular bromine react to partially form hydrogen bromide: H 2 (g) Br 2 (g) 2HBr (g) A mixture of 0.682 mol of H 2 and 0.440 mol of Br 2 is combined in a reaction vessel with a volume of 2.00 L. At equilibrium at 700 K, there are 0.516 mol of H 2 present. At equilibrium, there are ________ mol of Br 2 present in the reaction vessel.
Answer: At equilibrium , there are 0.274 moles of [tex]Br_2[/tex]
Explanation:
Moles of [tex]H_2[/tex] = 0.682 mole
Moles of [tex]Br_2[/tex] = 0.440 mole
Volume of solution = 2.00 L
Initial concentration of [tex]H_2[/tex] = [tex]\frac{0.682}{2.00}=0.341 M[/tex]
Initial concentration of [tex]Br_2[/tex] = [tex]\frac{0.440}{2.00}=0.220 M[/tex]
Equilibrium concentration of [tex]H_2[/tex] = [tex]\frac{0.516}{2.00}=0.258 M[/tex]
The given balanced equilibrium reaction is,
[tex]H_2(g)+Br_2(g)\rightleftharpoons 2HBr(g)[/tex]
Initial conc. 0.341 M 0.220 M 0 M
At eqm. conc. (0.341-x) M (0.220-x) M (2x) M
Given : (0.341-x) M = 0.258 M
x= 0.083 M
Thus equilibrium concentartion of [tex]Br_2[/tex] = (0.220-0.083) M = 0.137 M
Thus moles of [tex]Br_2[/tex] at equilibrium = [tex]0.137M\times 2.00L=0.274mol[/tex]
At equilibrium , there are 0.274 moles of [tex]Br_2[/tex]
What's the bond between two atoms of hydrogen?
Answer:There is a iin dipole attraction between two hydrogen atom
Explanation:
The same atoms have the ion dipole attraction between them the same atoms repel each other
The process of breaking a compound down into its elements is called
rearrangement
recombination
decomposition
dessication
A 1.om sample of dry air at
at 25°c at 786mmHg contains 0.925g Nitrogen Plus other gases including oxygen, argon and carbon dioxide. what is the partial pressure of Na with the air sample.
Answer:
Is the question not supposed to be what is the partial pressure of Nitrogen not Sodium