This data set shows the ages of the last 12 winners of a
prestigious film award for Actress in a Leading Role.
61, 32, 33, 45, 29, 62, 22, 44, 54, 26, 28, 60
Calculate the statistics of mean and standard deviation
of the data set. Round to the nearest hundredth, if
necessary.
O mean 38.50 and standard deviation - 14.89
O mean 38.50 and standard deviation = 40
O mean = 41.33 and standard deviation = 40
mean 41.33 and standard deviation - 14.89

Answer:

D. mean is 41.33, and standard deviation is 14.89

Explanation:

Given the data set: 61, 32, 33, 45, 29, 62, 22, 44, 54, 26, 28, 60 of 12 winners.

i. The mean of the data set = [tex]\frac{sum of data set}{number of data set}[/tex]

                                             = [tex]\frac{61 + 32 + 33 + 45 + 29 + 62 + 22 + 44 + 54 + 26 + 28 + 60}{12}[/tex]

                                             = [tex]\frac{496}{12}[/tex]

                                             = 41.3333

The mean of the data set = 41.33

ii. Standard deviation = [tex]\sqrt{\frac{Sum(x_{i} - U) ^{2} }{N} }[/tex]

Where: [tex]x_{i}[/tex] is the value of each data set given, U is the mean, N is the number of data set.

Sum ([tex]x_{i}[/tex] - U) = [tex](61 - 41.33)^{2}[/tex] + [tex](32 - 41.33)^{2}[/tex] + [tex](33 - 41.33)^{2}[/tex] + [tex](45 - 41.33)^{2}[/tex] + [tex](29 - 41.33)^{2}[/tex] + [tex](62 - 41.33)^{2}[/tex] + [tex](22 - 41.33)^{2}[/tex] + [tex](44 - 41.33)^{2}[/tex] + [tex](54 - 41.33)^{2}[/tex] + [tex](26 - 41.33)^{2}[/tex] + [tex](28 -41.33)^{2}[/tex] + [tex](60 - 41.33)^{2}[/tex]

                   = 386.91 + 87.05 + 69.39 + 13.47 + 152.03 + 427.25 + 373.65 + 7.13 + 160.53 + 235.01 + 177.69 + 348.57

                  =  2438.68

Standard deviation =  [tex]\sqrt{\frac{2438.68}{12} }[/tex]

                                = 14.26

Therefore, the statistics mean is 41.33 and standard deviation is 14.89

Answer:

D

Explanation:

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b. Keep the group discussion on track
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