There was a berry-picking contest at the earth day celebration this year. The line plot below shows the number of pints of berries collected by the people participating in the contest.
A. What is the median of the data displaced on the line plot?
B. How many people participated in the contest?
Answers
The work for median is you order the data: 2222113 in Lowest to highest;
1 1 2 2 2 2 3 then find the middle number
The median of the data is 2 and total number of people participated is 13.
The earth day celebration this year. The line plot below shows the number of points of berries collected by the people participating in the contest.
median is the median is the middle value in the set.
number of frequencies are 2,2,1,2,3,1,2
arrange the frequencies in ascending order - 1,1,2,2,2,2,3
median = (n+1/2)th term
= 7+1/2
= 8/2=4th term is the median
median = 2
number of people participated is 13.
Thus,The median of the data is 2 and total number of people participated is 13.
learn more about median here:
https://brainly.com/question/21396105
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720 = x +133+138+148+95+105
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Answer:
1378 -3839=10
Step-by-step explanation:
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2x + 6
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solve for x using an algebraic equation
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Answer:
v
Step-by-step explanation:
.necesito resolver estas operaciones con factorial ayuda por favor
- A= (4ǃ+2ǃ+3ǃ)/(3ǃ+2ǃ)
2. (6ǃ-4ǃ)/2ǃ
2ǃx3ǃx4ǃ/(5ǃ+4ǃ)
R = 10ǃx8ǃ/(6ǃ+5ǃ)
((x+5)ǃ(x+3)ǃ)/((x+4)ǃ+(x+3)ǃ)=6ǃ
Answers
Answer:
A. 4
B. 348
C. 2
D. 174182400
E. x = 2
Step-by-step explanation:
Given - A= (4ǃ+2ǃ+3ǃ)/(3ǃ+2ǃ)
B = (6ǃ-4ǃ)/2ǃ
C = 2ǃx3ǃx4ǃ/(5ǃ+4ǃ)
D = 10ǃx8ǃ/(6ǃ+5ǃ)
E - ((x+5)ǃ(x+3)ǃ)/((x+4)ǃ+(x+3)ǃ)=6ǃ
Proof -
A.
(4! + 2! + 3! )/ (3! + 2!) = [4×3×2! + 2! + 3×2!] / [3×2! + 2!]
= 2! [ 4×3 + 1 + 3] / 2! [3 + 1]
= [12 + 1 + 3] / [4]
= [16] / [4] = 4
⇒(4! + 2! + 3! )/ (3! + 2!) = 4
B.
(6ǃ-4ǃ)/2ǃ = [6×5×4! - 4!] / 2!
= 4! [6×5 - 1] / 2!
= 4×3×2! [ 30 - 1] / 2!
= 12 [29] = 348
⇒(6ǃ-4ǃ)/2ǃ = 348
C.
2ǃx3ǃx4ǃ/(5ǃ+4ǃ) = 2!×3!×4! / [ 5×4! + 4!]
= 2!×3!×4! / 4! [ 5 + 1]
= (2×1) × (3×2×1) / 6
= 12 / 6 = 2
⇒2ǃx3ǃx4ǃ/(5ǃ+4ǃ) = 2
D.
10ǃx8ǃ/(6ǃ+5ǃ) = 10!×8! / [ 6×5! + 5!]
= (10×9×8×7×6×5×4×3×2×1) ×(8×7×6×5!) / 5! [6 + 1]
= (10×9×8×7×6×5×4×3×2×1) ×(8×7×6) / [7]
= (10×9×8×7×6×5×4×3×2×1) ×(8×6)
= 174182400
⇒10ǃx8ǃ/(6ǃ+5ǃ) = 174182400
E.
((x+5)ǃ(x+3)ǃ)/((x+4)ǃ+(x+3)ǃ)=6ǃ
[(x+5)(x+4)(x+3)! (x+3)!] / [ (x+4)(x+3)! + (x+3)! ] = 6!
[(x+5)(x+4)(x+3)! (x+3)!] / (x+3)! [ (x+4)+ 1] = 6!
[(x+5)(x+4)(x+3)! / ( [ x+ 5 ] = 6!
(x+4)(x+3)! = 6!
(x+4)! = 6!
x+ 4 = 6
x = 6 - 4
x = 2
Note :
x! = x(x-1)(x-2).......(4)(3)(2)(1)
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Answer:
C) ( -2, 6)
Step-by-step explanation:
y = -3x
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Answer:
x=4,y=3
Step-by-step explanation:
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Plug that into equation 1
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76-25=17y
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y=3
Plug y=3 into equation 2
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We are having two equations,
4x + 3y = 25 (Equation No 1)x + 5y = 19 (Equation No 2)★ From Equation No 2 :-
>> x + 5y = 19
>> x = 19 - 5y
★ From Equation No 1 :-
Substitute here the value of x which we got above as (19 - 5y).
>> 4x + 3y = 25
>> 4 (19 - 5y) + 3y = 25
>> 4 × (19 - 5y) + 3y = 25
>> 76 - 20y + 3y = 25
>> 76 - 17y = 25
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Answer:
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Step-by-step explanation:
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Answer: Janine is 28. Ingrid is 30.
Answer:
Janine is 28 and Ingrid is 30.
Step-by-step explanation:
Let Janine's age be x years , then Ingrid's age is x+2 years.
From the given information we have the equation:
x/7 + (x + 2)/3 = 14
Multiplying through by the LCM of 3 and 7 (21), we have:
3x + 7(x + 2) = 294
10x + 14 = 294
10x = 294-14 = 280
x = 28, so:
Janine is 28 and Ingrid is 30.
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