The time between arrivals of customers at an automatic teller machine is an exponential random variable with a mean of 4 minutes. Round yours answers to 4 decimal places. (a) What is the probability that more than three customers arrive in 10 minutes

Answer:

0.7788 = 77.88% probability that more than three customers arrive in 10 minutes

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

[tex]f(x) = \mu e^{-\mu x}[/tex]

In which [tex]\mu = \frac{1}{m}[/tex] is the decay parameter.

The probability that x is lower or equal to a is given by:

[tex]P(X \leq x) = \int\limits^a_0 {f(x)} \, dx[/tex]

Which has the following solution:

[tex]P(X \leq x) = 1 - e^{-\mu x}[/tex]

The probability of finding a value higher than x is:

[tex]P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}[/tex]

In this question, we have that:

The time between arrivals of customers at an automatic teller machine is an exponential random variable with a mean of 4 minutes, and we have three customers, which means that [tex]m = 3*4 = 12, \mu = \frac{1}{12} = 0.0833[/tex]

(a) What is the probability that more than three customers arrive in 10 minutes

This is P(X > 3). So

[tex]P(X > 3) = e^{-0.0833*3} = 0.7788[/tex]

0.7788 = 77.88% probability that more than three customers arrive in 10 minutes

I really need to know theese and rhe rest plsss

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