The table and the graph each show a different relationship between the same two variables, x and y:



How much more would the value of y be in the table than its value on the graph when x = 11?
Group of answer choices
A. 100
B. 165
C. 395
D. 440

Answer:

2y-x-1

Step-by-step explanation:

use zero property

(-2x. +2x) =0

=6y-x+5-4y-6

collect like terms

6y-4y=2y

=2y-x+5-6

calculate the difference

+5-6=-1

=2y-x-1

good day :)

Answer:

x = -3

Step-by-step explanation:

4(2 - 4x) - 3x = 65

Distribute the 4.

8 - 16x - 3x = 65

Combine like terms.

8 - 19x = 65

-19x = 57

Divide by -19 to isolate x.

x = 57/-19

x = -3

Check.

4(2 - 4(-3)) - 3(-3) = 65

4(2 - (-12) + 9 = 65

4(14) + 9 = 65

56 + 9 = 65

65 = 65

The solution of the given linear equation 4(2 - 4x) - 3x = 65 is  -3.

Two algebraic expressions separated by an equal symbol in between them and with the same value of the expression are called equations.

Example = 2x +4 = 12

here, 4 and 12 are constants and x is variable.

The solution of the equation 4(2 - 4x) - 3x = 65 is calculated as:

4(2 - 4x) - 3x = 65

Multiply the expressions inside the brackets,

8 - 16x -3x = 65

8 - 19x = 65

Subtract 8 from both the sides,

-19x = 65- 8

-19x = 53

Divide both side by -19

[tex]x = \dfrac{-53}{19}[/tex]

Thus, the value of x is -3.

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9514 1404 393

Answer:

  4)  6x

  5)  2x +3

Step-by-step explanation:

We can work both these problems at once by finding an applicable rule.

  [tex]\text{For $f(x)=ax^n$}\\\\\lim\limits_{h\to 0}\dfrac{f(x+h)-f(x)}{h}=\lim\limits_{h\to 0}\dfrac{a(x+h)^n-ax^n}{h}\\\\=\lim\limits_{h\to 0}\dfrac{ax^n+anx^{n-1}h+O(h^2)-ax^n}{h}=\boxed{anx^{n-1}}[/tex]

where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.

This can be referred to as the power rule.

Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:

  lim[h→0](f(x+h)-f(x))/h = 2ax +b

__

4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.

5. The gradient of x^2 +3x +1 is 2x +3.

__

If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.

Answer:

x=b-8a/8

x=b+8a/a

x=2-2c/c

Answer:

g(h(- 8)) = 119

Step-by-step explanation:

Evaluate h(- 8), then substitute the result obtained into g(x), that is

h(- 8) = (- 8)² - 2 = 64 - 2 = 62, then

g(62) = 2(62) - 5 = 124 - 5 = 119

Answer:

yes Whyy?

Step-by-step explanation:

walalang Sagot mo yan HAHAHAHAH

Answer:

14217

Step-by-step explanation:

(7÷3)×6093=

14217

Answer:

55.53

Step-by-step explanation:

45.12

5.2%= 1.052

new price= original(1+5.2%)

x=45.12(1.052)

×=47.46624+17%

=55.53

After the arrival of 5 marriages, the total women will be 9.

Function : In mathematics, a function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function

Expression : A mathematical expression is made up of terms (constants and variables) separated by mathematical operators

Equation : A mathematical equation is used to equate two expressions.

Given is that at a party the number of women was 4 times the number of men after the arrival of 5 marriages the percentage of men at the party became due 6%

Assume that the initial number of men are [x]. Then, the number of women will be y = 4x.

After the arrival of 5 marriages -

y + 5 = 4x + 5

and

x = 6% of y

x = (6/100) x y

x = (3/50)y

So, we can write -

y + 5 = (12/50) + 5

y = 12/50

So -

x = (12/50) x (50/3)

x = 4

After the arrival of 5 marriages, the total women will be -

x + 5 = 9

Therefore, after the arrival of 5 marriages, the total women will be 9.

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{Question in english language is -

At a party the number of women was 4 times the number of men after the arrival of 5 marriages the percentage of men at the party became due 6% what is the number of women after the arrival of 5 marriages}

Answer:

[tex]\displaystyle v > \frac{-28}{5}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Step-by-step explanation:

Step 1: Define

[tex]\displaystyle \frac{-10}{7}v > 8[/tex]

Step 2: Solve for v

Here we see that any value v greater than [tex]\displaystyle \frac{-28}{5}[/tex] would work as a solution to the inequality.

Answer:

NEVER INTERSECT

Hope this Helps

Answer:

The value of x is 14.75 ⇒ (2)

Step-by-step explanation:

In the given figure

∵ The vertices of the quadrilateral BCED lie on the circumference of circle A

→ By using the 1st rule above

∴ BCED is a cyclic quadrilateral

∵ ∠B and ∠E are opposite angles in the cyclic quadrilateral BCED

→ By using the 2nd rule above

∴ m∠B + m ∠E = 180°

∵ m∠B = 6x + 10

∵ m∠E = 81.5°

∴ 6x + 10 + 81.5° = 180°

→ Add the like terms on the left side

∴ 6x + 91.5 = 180

→ Subtract 91.5 from both sides

∵ 6x + 91.5 - 91.5 = 180 - 91.5

∴ 6x = 88.5

→ Divide both sides by 6 to find x

∴ x = 14.75

Answer:

1. Look at the screenshot below.

2. If a line intersects a parabola at a point, the coordinates of the intersection point must satisfy the equation of the line and the equation of the parabola.

Since the equation of the line is y = c, where c is a constant, the y-coordinate of the intersection point must be c.

It follows then that substituting c for y in the equation for the parabola will result in another true equation: c = −x^2 + 5x.

Subtracting c from both sides of c = −x^2 + 5x and then dividing both sides by −1 yields 0 = x^2 − 5x + c.

The solution to this quadratic equation would give the x-coordinate(s) of the point(s) of intersection.

Since it’s given that the line and parabola intersect at exactly one point, the equation 0 = x^2 − 5x + c has exactly one solution.

A quadratic equation in the form 0 = ax^2 + bx + c has exactly one solution when its discriminant b 2 − 4ac is equal to 0. In the equation 0 = x^2 − 5x + c, a = 1, b = −5, and c = c.

Therefore, (−5)^2 − 4(1)(c ) = 0, or 25 − 4c = 0.

Subtracting 25 from both sides of 25 − 4c = 0 and then dividing both sides by −4 yields c = 25/4 .

Therefore, if the line y = c intersects the parabola defined by y = −x^2 + 5x at exactly one point, then c = 25/4 .

Either 25/4 or 6.25

Answer:

So, hour 0 and charge is 0. hour 1 is 25, hour 2 is 50, hour 3 is 75, hour 4 is 100 and hour 5 is 125

Step-by-step explanation:

For every hour, add 25 in each box.

Answer:

-6.3n + 8.6

Step-by-step explanation:

you add the terms together

Answer: -6.3n + 8.6

Step-by-step explanation:

Answer:

2-

Step-by-step explanation:

[tex]x = 10 \\ 3(10) + 5y = 20 \\ 30 + 5y = 20 \\ 5y = - 10 \\ y = - 2[/tex]

Answer:

x= 10

Step-by-step explanation:

8x+30=110

8x+30-30=110-30

8x=80

8x/8=80/8

x=10

Answer:

x=10

Step-by-step explanation:

Vertical angles are always congruent, those to angles are vertical angles so they are congruent.

Set them equal to each other:

110=8x+30                 subtract 30 from both sides

80=8x                        divide by 8 on both sides

x=10

Hope this helps :)

Answer:

24ab

Step-by-step explanation:

The multiple of 8, 2, 4ab, 3a, and 6b would be all the variables multiplied together right?

Then you see that:

8 can be divided by both 2 and 4 (2 x 2 x 2)

2 is 2 x 1

4ab can be 2 x 2ab

3a is the same as 3 x a

and

6b can be 2 x 3b

Now if you find the lowest common multiples (LCM's) of each variable with another you'll get your answer.

LCM of 8, 2 and 4ab is 2 times 2 times 1 times 2ab which equals 8ab

LCM of 3a and 6b is 3a times 2 times b which equals 6ab

and the

LCM of 8ab and 6ab is 2 times 2ab times 4 times 3 which equals 24ab.

Answer:

The answer is C

Step-by-step explanation:

Answer:

1/8

Step-by-step explanation:

Alligators have a greater IQR because there were some very long alligators (high outliers)

D: Alligators have a greater IQR because there were some very long alligators (high outliers)

Use the interquartile rule to find outliers and calculate the interquartile range of data.

Multiply the interquartile range (IQR) by 1.5 (a constant used to identify outliers). 44 Adds 1.5x (IQR) to the 4th interquartile range. Numbers larger than this are suspected of being outliers.

Subtract 1.5x (IQR) from the first interquartile range.

If you subtract 1.5xIQR from the first quartile, data values ​​smaller than this number are considered outliers. If you add 1.5 x IQR to the third interquartile, data values ​​larger than this number are considered outliers.

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Answer:

There we go!!!

Answer:

see explanation

Step-by-step explanation:

Given f(x) then the derivative f'(x) is

f'(x) = lim(h tends to 0 ) [tex]\frac{f(x+h)-f(x)}{h}[/tex]

      = lim ( h to 0 ) [tex]\frac{4(x+h)^2-2-(4x^2-2)}{h}[/tex]

      = lim ( h to 0 ) [tex]\frac{4(x+h)^2-2-4x^2+2}{h}[/tex]

      = lim( h to 0 ) [tex]\frac{4x^2+8hx+4h^2-4x^2}{h}[/tex]

      = lim( h to 0 ) [tex]\frac{8hx+4h^2}{h}[/tex]

      = lim ( h to 0 ) [tex]\frac{4h(2x+h)}{h}[/tex] ← cancel h on numerator/ denominator

      = lim ( h to 0 )  4(2x + h) ← let h go to zero

f'(x) = 8x

Answer: 3 1/3

Step-by-step explanation:

Im assuming the big ol "X" is a multiply sign.

The answer is three and one third.

Answer:

her bonus will be a big paycheck of 99999