the star thuban in draco group of answer choices lies as the center of the precession cycle. lies halfway between the bowls of the big and little dippers. is used to locate the vernal equinox. is brighter than polaris. was an excellent north pole star in 3,000 bc.

The distance travelled by the student is 1600m and the displacement is 0.

Displacement is the direction from the beginning point and the length of a straight path from the starting point to the finishing point, whereas distance is the length of a path that connects two places.

Displacement is a vector quantity that does not take into consideration the actual path taken; instead, it quantifies the distance between the beginning point and the finishing position.

Given:

Track length = 400m

No. of rounds = 4

To find:

Distance, d = ?

Displacement, D = ?

Formula:

Distance, d = Track length x No. of rounds

Displacement, D = End point – Start point

Calculations:

d = 400 x 4

d = 1600m

D = 0 since the start and end point are same.

Result:

The distance travelled is 1600m with 0 displacement.

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Electron transport chain use NADH and FADH2 molecules formed in Glycolysis and Krebs Cycle processes.

The third stage of cellular respiration is the electron transport chain. In cellular respiration, high-energy electrons are transported by NADH and FADH2 to the electron transport chain. In photosynthesis, NADPH transports energetic electrons to the electron transport chain.

Krebs cycle or the TCA cycle, the process of oxidizing acetyl-CoA, which is produced from proteins, carbs, and lipids, releases stored energy.

The process by which glucose is broken down to provide energy is known as glycolysis. It generates two pyruvate molecules, ATP, NADH, and water. There is no need for oxygen throughout the process, which occurs in the cytoplasm of a cell. Both aerobic and anaerobic respiration experience it.

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According to  the given statement The force exerted by the string on the object is 2.7 N.

Any item travelling in a circular direction has a tangential velocity, which is its linear speed. On a turntable, a point in the centre moves less distance in a full rotation than a point near the outside edge.

Tangential velocity is determined by dividing the circle's circumference by the time required for one complete rotation: 2*pi*r/t. The formula V = w * r, where w (omega) is the angular velocity of the rotating object and r is the radius of the circle, also relates it to angular velocity.

m = 0.9 kg

r = 3m

v = 3m/s

Force (f) = mv2/r

Now ,putting values

force (f) = [tex]\frac{0.9 k g \times\left(3 \mathrm{~ms}^{-1}\right)^2}{3 \mathrm{~m}}[/tex]

F = 2.7 N

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If the charge on object A is doubled then the electric field will remain unchanged in any of the cases. It is so because the question is asking us whether the electric field which the object is experiencing is changing or not, but in actuality, due to charge change, the magnitude of the electric field is changing only.

The electric field's magnitude may be easily determined by calculating the force per charge on the test charge. The electric field would exert a force on the item when its charge doubled since it is inversely proportional to the electric charge. so won't have any effect.

The field is supposed to have a direction corresponding to the force that it would exert on a positive test charge. The electric field emanates from a positive point charge in an outward direction, and from a negative point charge in an inward direction.

A charge is a characteristic that describes how many more or fewer electrons than protons a matter unit has.

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Answer:

110cm

Explanation:

displacement= final position- initial position

= 120cm-10cm

= 110cm

While the flashlight light has no effect, the UV source's light discharges the electroscope.

According to Planck's formula, the energy of the particles that make up a beam of light is connected to their frequencies. The photons and atoms collide when that beam strikes a metal. The photoelectric effect is created by a collision when a photon's frequency is high enough to remove an electron.

One electron interacts with each photon. The incident photon's energy is employed to both liberate the surface-bound electrons and give the expelled electrons energy.

Because it offers insights into the properties of solids as well as the properties of atoms and molecules, the photoelectric effect is extensively researched in the fields of quantum chemistry, condensed matter physics, and solid-state chemistry.

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Complete Question -

In which one of the following cases is the displacement of the object directly proportional to the elapsed time?

A)a ball rolls with constant velocity

B)a ball at rest is given a constant acceleration

C)a ball rolling with velocity  given a constant acceleration

D)a bead falling through oil experiences a decreasing acceleration

E)a rocket fired from the earth's surface experiences an increasing acceleration

A ball rolls with a constant speed is the displacement of the object without delay proportional to the elapsed time.

An item's position adjustments if it movements on the subject of a reference body, inclusive of whilst a passenger actions to the returned of an plane or a lecturer moves to the right on the subject of a whiteboard. Displacement describes this shift in location. Displacement is a vector and shows that an item has moved or has been displaced. This shows that it has both a route and a significance and that it can be visualized as an arrow pointing from the starting place to the finishing region.

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The speed of the rocket is 3000 km/h.

Distance is the sum of an object's movements, regardless of direction. Without respect to the object's starting or finishing positions, distance can be defined as the amount of space it has traveled.

A scalar quantity, speed is defined as the size of the change in an object's location over time or the size of the change in an object's position per unit of time.

The distance traveled by rocket is 6000 km.

The time is taken by the rocket is 2 hours.

The speed of an object is defined as the distance traveled by the object per unit of time.

Therefore,

Speed = distance / time

S = d / t

S = 6000 km / 2 hr

S = 3000 km/h

The speed of the rocket is 3000 kilometers per hour.

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A boat is stationary at  12 meters away from a dock. The boat then begins to move toward the dock with an acceleration of 50 m/s². How long will it take the boat to reach the dock?

Answer:

Explanation:

Given that

To find

So according the question

We have,

Now, for finding time travelled by boat to reach dock we can use the second equation of motion i.e.

         s = ut + [tex]\frac{1}{2}[/tex] at²

     where,

         s = Distance.

          u = Initial velocity.

          t = Time.

          a = Acceleration.          

Now, putting all given values in second equation of motion,

So, we get

          s = ut + [tex]\frac{1}{2}[/tex] at²

         12 = 0t + [tex]\frac{1}{2}[/tex] ×5× t²

         12×2 = 5t²

         t² = [tex]\frac{12 \times 2}{5}[/tex]

         t = [tex]\sqrt{\frac{24}{5}}[/tex]

         t = [tex]\sqrt{{4.8}}[/tex]

        t = [tex]2.19[/tex] s.

Answer:

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The steelhead lands on the top of waterfall when it is descending so the time taken is 1.36 seconds.

A waterfall is a factor in a river or movement in which water flows over a vertical drop or collection of steep drops.  

Waterfalls are formed in a variety of ways, but the most common  is for a river to flow over a top layer of elastic rock before dropping into soft rock. This rock will erode faster, resulting in a higher drop.  Waterfalls have been studied for their impact on the species that live in and around them. Over the years, people have developed a unique relationship with waterfalls by seeing them, exploring them, and naming them. They can pose a formidable obstacle to navigation along the river.

Using ,S= u*t + (1/2)at​2​​​​

         1.8 = 8t - [(1/2)*9.8*t​​​​​​2​​​​​]

By ,solving this quadratic equation we get, t= 0.27 s or t= 1.36 s

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FALSE

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Answer: a. 6.5 m/s

b. s=10.83 seconds

Explanation:

a. 3+7(0.5)=

3+3.5=6.5 m/s

b. s=seconds

6.5-0.6s=0

6.5-0.6s+0.6s=0+0.6s

6.5=0.6s

6.5=3s/5

6.5*5=3s*5/5

3s=32.5

s=32.5/3

s=65/6

s=10.83 seconds

(a)The net charge on the sphere is 3.38×[tex]10^{-9}[/tex] C.

(b) The charge inside sphere is positive and distributed symetrically inside the sphere .

(a) As we know the electric field is given as,

E = kq / [tex]r^{2}[/tex]

Plugging in the values we get,

575 = 8.99×[tex]10^{9}[/tex] q / [tex]0.230^{2}[/tex]

8.99×[tex]10^{9}[/tex]q = 30.41

q = 3.38×[tex]10^{-9}[/tex] C

So, the net charge on the sphere is 3.38×[tex]10^{-9}[/tex] C.

(b) We can conclude that the charge inside sphere is positive and distributed symetrically inside the sphere .

The complete question is: The electric field everywhere on the surface of a charged sphere of radius 0.230 m has a magnitude of 575 N/C and points radially outward from the center of the sphere. (a) What is the net charge on the sphere? (b) What can you conclude about the nature and distribution of charge inside the sphere?

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When the friction coefficient between a road and the tyre of a vehicle is 4/3, the maximum incline that the road may have would be 16° so that when brakes are applied, the vehicle stops within 5 m.

The ratio of the frictional force to the normal force is called as the coefficient of friction (COF), which has no dimensions. The ratio that is present between the normal force pressing two surfaces together and the frictional force preventing motion between the two surfaces.

It is mostly represented by using the Greek letter mu (μ) Those materials are said to be as lubricous only if their COF is less than 0.1.

The present Surface roughness and the kind of COF are related to the nature of the materials.

Then we see that,

S=5m,

Friction coefficient (μ)=4/3,

g=10m/[tex]s^{2}[/tex]

speed u=36km/h=10m/s

v=0 a=[tex]\frac{v^{2}-u^{2} }{2s}[/tex] = [tex]\frac{0-10^{2} }{2*5}[/tex] = 10 m/[tex]s^{2}[/tex]

Then,

R−mgcosθ = 0

⇒ R = mgcosθ

then, ma+mgsinθ−μR = 0

⇒ ma+mgsinθ−μmgcosθ = 0

⇒ a + gsin[tex]\theta\\[/tex] - μgcosθ = 0

⇒ 10 + 10sinθ - [tex]\frac{4}{3}[/tex] x 10cosθ = 0

⇒ 30+30sinθ -40cosθ = 0

⇒ 4cosθ - 3sinθ = 3

⇒ 4[tex]\sqrt{1-sin^{2}\theta }[/tex] = 3+3sinθ

if we square both sides, we have,

sinθ = [tex]\frac{18+\sqrt{18^{2}-4(25)(-7) } }{2*25}[/tex]

= 14/50 = 0.28

⇒ θ = [tex]sin^{-1}[/tex] (0.28) = 16°

Hence maximum inclination

θ= 16°

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The oscillation angular frequency of a drop with half of the first drop's radius is 4ω

Surface tension is the tension force exerted on an object by the surface of a liquid.

Angular frequency is the frequency of oscillation of a rotating object. It is given in rad/s.

Given that

Since the energy of the drop is conserved, using the law of conservation of angular momentum, we have

Iω = I'ω' where

So, Iω = I'ω'

Making ω' subject of the formula, we have

ω' = Iω/I'

ω' = mr²ω/mr'²

ω' = r²ω/r'²

Given that the drop is half of the first drop's radius, r' = r/2

So, ω' = r²ω/r'²

ω' = r²ω/(r/2)²

ω' = r²ω/r²/4

ω' = 4ω

So, the oscillation angular frequency of a drop with half of the first drop's radius is 4ω

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The snapshot of light as the cart moves with constant velocity is represented by a graph with uniform displacement at each time interval.

The change in displacement with time is uniform at constant velocity. The displacement of the supplied moving item grows at the same pace.

The beginning velocity equals the ultimate velocity at constant velocity.

v₁ = v₂

The object's acceleration at constant velocity is zero since the velocity change with time is zero.

As a result, we may deduce that the graph with equal displacement at each time interval reflects a snapshot of light as the cart moves at a constant speed.

A moving object's displacement-time graph shows the distance traveled by a moving item as time passes. A vector quantity is displacement. The slope or gradient of this graph represents the velocity of the item. The displacement-time graph, also known as the position-time graph, describes an object's motion. In this graph, the displacement of the moving item is displayed on the y-axis as a dependent variable, while time is shown on the x-axis as an independent variable.

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Based on the calculations, the instantaneous acceleration of this object at time, t = 2 seconds is equal to 2 m/s^2.

Velocity can be defined as the distance covered by an object per unit of time. This ultimately implies that, velocity is a vector quantity because it has both magnitude and direction. Also, velocity can be measured as meter per seconds.

Mathematically, the velocity of any physical object can be calculated by using this formula:

Velocity = displacement/time

An instantaneous acceleration can be defined as a continuous function of time which gives the ratio of change in velocity of a physical object. Mathematically, instantaneous acceleration can be calculated by taking the derivate of the velocity function.

Taking the derivate of the velocity function, we have:

Velocity, v = 4 + 0.5t^2

dv/dt = 0 + (0.5 × 2)×t^{2-1}

dv/dt = t

Substituting the value of time (t), we have:

Instantaneous acceleration, dv/dt = t

Instantaneous acceleration, dv/dt = 2 m/s^2.

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Complete Question:

An object moving in a straight line has a velocity v in meters per second that varies with time t in seconds according to the following function: v = 4 + 0.5t^2

The instantaneous acceleration of the object at t = 2 seconds is:

answer choices

2 m/s^2

4 m/s^2

5 m/s^2

6 m/s^2

8 m/s^2

The magnitude of the electric field at point p is [tex]\frac{2kQ}{a\sqrt{4a^{2} + L^{2} } }[/tex].

An electric field is a physical field that surrounds electrically charged particles and acts as an attractor or repellent to all other charged particles in the vicinity. It can also refer to a system of charged particles' physical field.

The human body is affected by low-frequency electric fields in the same way that they are affected by other charged-particle-containing materials. The distribution of electric charges at conductive materials' surfaces is affected by electric fields acting on such materials. They make the body conduct current to the ground.

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The angular frequency of the emf for the inductor and resistor to have the same peak voltage (i.e. for R and XL to be the same) is R/L.

The above situation represents Alternating Current(AC).

An alternating current is a type of current that reverses its direction after fixed intervals of time.

The following formulas are used in the case of AC,

XL = ωL

XC= 1/Cω

Here L and C represent inductance and capacitance respectively.

It is  given that XL = R

Hence, ωL = R

ω = R/L

Hence, the angular frequency(ω) of the emf for the inductor and resistor to have the same peak voltage (i.e. for R and XL to be the same) is R/L.

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The correct option is (D) The iodine gets extracted into to the organic solvent, and the potassium iodide remains in the water.

During extraction, the iodine gets extracted into to the organic solvent, and the potassium iodide remains in the water.

For extraction, the principle of like dissolve like is followed.

There are two solvents - water which is polar and dichloromethane (or hexane) which are nonpolar.

We need to extract iodine [tex]I_{2}[/tex] and potassium iodide (KI).

[tex]I_{2}[/tex] is a non-polar molecule that is formed by covalent bonding. But KI is an ionic molecule that exhibits ionic behavior by giving [tex]K^{+}[/tex] and [tex]I^{-}[/tex] ions in aqueous media. Also, there is a difference in their electronegativity. Thus, [tex]I_{2}[/tex] will be extracted in an organic solvent and KI remains soluble in water.

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The complete question is:

"In this experiment, you start with plain dichloromethane (or hexane), and a solution of iodine and potassium iodide in water. what happens during the extraction process?

(a) Both the potassium iodide and the iodine remain in the water

(b) Both the potassium iodide and the iodine get extracted into the organic solvent

(c) The potassium iodide gets extracted into the organic solvent, and the iodine remains in the water

(d) The iodine gets extracted into to the organic solvent, and the potassium iodide remains in the water"

The vector tangential to the circle because the vector indicates the direction of the force on the object.

Centripetal force is the force acting on an object in circular motion directed towards the axis of rotation.

In a circular motion, the direction of the velocity vector is the same as the direction of the object's motion, the velocity vector is directed tangent to the circle as well.

It also indicate the direction of the centripetal force.

Thus, the vector tangential to the circle because the vector indicates the direction of the force on the object.

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Answer:

It is the law of f=ma because the lighter the trolley is, the easier it is to push it, because it doesn't have as much mass,

Explanation:

Can I have brainliest? It would help me out, if not thanks anyways! Hope this helped and have a nice day :)

A 60-kilogram individual ascends an 80 m-high building's roof by walking up from the ground. Once at the peak, the human has a potential energy of 44027.28 J.

This is our formula

Gravitational ability strength = mgh  

here (GPE = mgh)

mg = 60.0 kg

h = 80

mg = 60.0 kg

in view that we're searching for pressure and the SI Unit for force is "N," we must convert this to force (N).

consequently, we will multiply 60.0 via nine.81.

60.0 × 9.81 = 588.6

Now that will be

⇒ mg = 588.6 N

⇒ h = 80

GPE = (588.6) × (80) = 47088 J

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The acceleration of the object is 5.3 cm/[tex]s^{2}[/tex] and is directed towards the negative x - axis.

We have an object moving with uniform acceleration along the + x axis.

We have to determine of the acceleration of object after 3.25 seconds.

According to the question -

initial velocity = u = 11 cm/s along +x axis.

Now, using the second equation of motion -

[tex]$S=ut +\frac{1}{2}at^{2}[/tex]

S = x(2) - x(1) = - 5 - 2.91 = - 7.91 = 7.91 cm along -x axis.

u = 11 cm/s

Substituting the values -

7.91 = 11 x 3.25 + 0.5 x 3.25 x 3.25  x a

7.91 = 35.75 + 5.3a

a = - 5.3 cm/[tex]s^{2}[/tex]

Hence, the acceleration of the object is 5.3 cm/[tex]s^{2}[/tex] and is directed towards the negative x - axis.

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Answer:

8.49673 minutes ≈ 8.5 minutes

Explanation:

Acceleration, a is defined as the rate of change in velocity divided by the change in time to attain that velocity

[tex]\mathsf a = \dfrac{\Delta v}{\Delta t} \\\\\textsf {where } \mathsf {\Delta v = v-v_0} \textsf{ v being final velocity and v_0 initial velocity}[/tex], v = final velocity and v₀ the initial velocity
and Δt is the time required to attain final velocity

Δt = number of seconds since launch = t since t₀ = 0

Therefore,
[tex]a = \dfrac{v-v_0}{t}[/tex]

The space shuttle's initial velocity is 0 m/s and its final velocity must be 7800 m/s to escape earth's gravity

So v - v₀ = 7800 - 0 = 7800 m/s, t - t₀ = t = 0 = t seconds
a = 15.3 m/s²

We have the equation

a = 7800/t

a is given as 15.3 m/s² so
15.3 = 7800/t

t  = 7800/15.3 = 509.80392 seconds

To convert to minutes, divide by 60
509.80392/60 = 8.49673 minutes ≈ 8.5 minutes

12 m from the point of impact when the key is released, the speed of the boat is 4.0m/s.

Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is traveling along a path. In other words, velocity is a vector, whereas speed is a scalar value. Let’s take an example, 15km/hr shows the speed of a vehicle but 15km/hr east shows the velocity of the vehicle. Speed of an object can be calculated mathematically in a simple way. Speed of an object can be found by dividing distance traveled by the object by time taken to cover that distance.

The speed of the boat can be given by , v = d/t

Now, d = 12 m and t is the time the key takes to fall into the boat

Taking the initial time(time at which the key is dropped) to be 0 we calculate t when height(y) is 45 m.

y = ½(gt)^2

t =   (2y/g)^(1/2)

t = ((2*45)/9.8)^(1/2)

t = 3.03 s

Therefore, speed of the boat = (distance covered by the boat)/(time taken)

distance  = 12/(3.03)= 4.0 m/s

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Answer:

i cant see the picture clearly can u resend it?

Explanation: