The speed of sound is 344 m/s. You have built a really fantastic car that can really go fast. If the car can accelerate at 22.4 m/s how much time till you reach the speed of sound? How many kilometers will you travel before you reach that speed?

2,302.74 J is the heat generated.

Current electricity is the electricity produced by the movement of electrons. Static electricity is the electricity that accumulates on a substance's surface. Power plants and batteries are used to produce the current electricity.

Electric current in a wire, where electrons serve as the charge carriers, is a measurement of the amount of charge that moves through any point of the wire in a given amount of time.

The mass of the aluminum is m = 0.25 kg.

The difference in temperature is T=10 C.

The following is a list of aluminum's specific heat capacities:

c=921.096 J/kg∘C

Therefore, we apply the following formula in this instance:

Q=mcΔT

We replace with:

Q=(0.25kg)(921.096J/kg∘C)(10∘C)

Thus, we will receive the heat produced:

Q=2,302.74 J

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The speed of the ball at launch is 23m/s.

After 0.5 seconds, the ball initially passed the pole.

Then it will again reach the top of the pole after 4.1 seconds.

Consequently, the ball's travel time above the pole is

Δt  = 4.1 - 0.5 = 3.6sec

Now the time it will take to reach the highest point from the top of the pole is given as t = Δt/2 = 1.8sec.

Now the total time to reach the top from the bottom is given as 2.3sec.

After 0.5 seconds, the ball initially passed the pole.

Consequently, the ball's travel time above the pole is

[tex]v_{f} - v_{i} = at[/tex]

[tex]v_{i}=22.54m/s[/tex]

also the speed after 0.5 s is

[tex]v_{f} = 17.64m/s[/tex]

So, the speed of the ball at launch is 23m/s.

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The magnitude of the total displacement is 20.28 m.

The angle of the total displacement with the x axis is 70.5⁰.

The total displacement of the player is calculated as follows.

Apply cosine rule as shown below;

d² = d₁² + d₂² - 2d₁d₂ cos(θ)

d² = (24.1)² + (7.9²) - (2 x 24.1 x 7.9) cos(52.5)

d² = 411.42

d = √411.42

d = 20.28 m

Apply sine rule as shown below;

d/sinD = d₂/sinD₂

20.28/sin(52.5) = 7.9/sinD₂

25.562 = 7.9/sinD₂

sinD₂ = 7.9/25.562

sinD₂ = 0.309

D₂ = sin⁻¹(0.309)

D₂ = 18⁰

angle with x axis =  18⁰ + θ

                            =  18⁰ +  52.5⁰

                            = 70.5⁰

Thus, the magnitude of the total displacement is 20.28 m.

The angle of the total displacement with the x axis is 70.5⁰.

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The Net magnetic field will be at the left in case I, right in Case II, In-between in Case III, and Nowhere in Case IV and V.

Case I

As the current in both wires is not equal, the net magnetic field will not be zero in the middle. It will be zero somewhere near the 3 A current carrying wire and farther from the 9A current carrying wire. Which is to the Left.

Case II

It is similar to the case I, as the current in both wires is not equal, and the net magnetic field will not be zero in the middle. It will be zero somewhere near the 3 A current carrying wire and farther from the 9A current carrying wire. Which in this case is to the Right.

Case III

As the current in both wires is the same and equal to 3 A, the net magnetic field will be zero in the middle. Which is in Between.

Case IV

As the current flowing in the wire is opposite in the direction, the magnetic field will always be in the same direction. So the magnetic field will be zero Nowhere.

Case V

It is similar to the above case IV, as the current flowing in the wire is opposite in the direction, and the magnetic field will always be in the same direction. So the magnetic field will be zero Nowhere.

Therefore, the Net magnetic field will be at left in case I, right in Case II, In-between in Case III, and Nowhere in Case IV and V.

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In order to determine the amount of time it would take the arrow to travel upward, we would have to first determine its initial velocity by using the second equation of motion.

Note: Since the arrow was projected upward, the acceleration due to gravity would be negative because it indicates deceleration.

From the second equation of motion, we have:

S = ut - ½gt²

39.9 = u(1.87) - ½ × (-10) × 1.87²

39.9 = 1.87u + 17.49

1.87u = 39.9 - 17.49

1.87u = 22.41

u = 22.41/1.87

Initial velocity, u = 11.98 m/s.

Now, we can calculate the amount of time it would take the arrow to travel upward by applying the first equation of motion:

V = u + at

0 = 11.98 + (-10)t

10t = 11.98

t = 11.98/10

Time, t = 1.198 seconds.

In order to calculate the maximum height, we would apply the second equation of motion:

S = ut + ½gt²

S = 11.98(1.198) + ½ × (-10) × 1.198²

S = 14.35 - 7.18

Maximum height, S = 7.17 meters.

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Answer:

[tex]{ \tt{displacement = velocity \times time }} \\ { \tt{ = 2.4 \times 46}} \\ { \tt{ = 110.4 \: m}}[/tex]

The experiment to show the random motion of the particles is the movement of particles in a solution is the simplest representation of motion of particles.

Pick up two glass beakers. Fill one beaker with hot water and the second one with cold water. Add KMnO4 crystals in very small quantities to both. We thus see that KMnO4 particles move faster in hot water than in cold water.

Pick up some iron and  a piece of chalk. We learn that it's quite difficult to work with iron. This leads us to believe that the Forces can affect matter particles. among them. The pressure kept between  particles and the power of the attraction in materials is at its strongest between particles the least in gases.

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Answer:

The FM carrier waves should have different frequencies than the carrier waves, not different amplitudes.

Explanation:

The label at the top of the diagram should be “FM Radio,” not “Cell Phone.

The information provided above demonstrates that the range of the tube's radius within which we are certain is from 23.7 to 24.3.

Accurate findings are desired when any quantity is being measured. Closeness of the measurements to a particular value is referred to as accuracy (like the theoretical value). It is not insignificant that measurements can contain inaccuracies; as a result, the outcome frequently includes a margin error. The sentence above displays the radius's measured value along with its margin of error.

In other words, the aforementioned statement represents a quantity's numerical value along with its tolerance, or the only permissible (and conceivable) values to ensure that the measurement is accurate. The information provided above demonstrates that the range of the tube's radius within which we are certain is from 23.7 to 24.3.

These are all valid radius values, along with all others within this interval. By increasing the number of trials in a measurement, the value for the upper and lower bounds of the error can be decreased.

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The time taken by the ball to reach the maximum height when ball is thrown straight upward is t = 1.5s.

To find the time we must know the distance so to calculate the distance using formula,

v² = u² + 2 as

where,

v is final velocity

u is initial velocity

a is acceleration due to gravity

s is distance

As, we can see,

u = v = 30m/s

a = - 9.8 m/s²

s = ?

So, putting the values we get,

30²m/s = 30²m/s + 2 (9.8 m/s²) s

s = 30²m/s / 30²m/s + 2 (-9.8 m/s²)

s = 19.6

Now after getting to know the distance we can use the formula,

s = d/t

Where,

s is speed

d is distance

t is time

So, putting the values,

t = 30 / 19.6

t = 1.5s

Hence, the time taken by the ball to reach the maximum height is 1.5s.

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(a) The expression for the horizontal acceleration of the cart is

a = (T - μN)/Mc.

(b) The expression for the vertical acceleration of the hanging mass is

a = (T - Mhg)/Mh.

(c) The expression for the acceleration of both cart and the hanging mass is a = (Mhg - μN) / (Mc - Mh).

The horizontal acceleration of the cart is calculated as follows;

The horizontal acceleration of the cart is determined from the net horizontal force acting on the system.

T - μN = Mca

where;

a = (T - μN)/Mc

T - Mhg = Mha

where;

a = (T - Mhg)/Mh

If the acceleration of the cart and the hanging mass are equal, our final equation becomes;

From first equation;

a = (T - μN)/Mc

Mca = T - μN

Mca + μN = T

From second equation;

a = (T - Mhg)/Mh

Mha = T - Mhg

Mha + Mhg = T

Solve the two equation together;

Mca + μN = Mha + Mhg

Mca - Mha = Mhg - μN

a(Mc - Mh) = Mhg - μN

a = (Mhg - μN) / (Mc - Mh)

Thus, the expression for the acceleration of both cart and the hanging mass is a = (Mhg - μN) / (Mc - Mh).

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To determine how classroom temperature affected test performance of students an experiment was conducted with each group of students in hot room, cold room and a room with normal temperature.

• Dependent variable- Test performance

• Independent variable- Room temperature

• Control variables/Constants - Group of students

• Control group – Students in the room with normal temperature

Test performance depends on the temperature of the room.

Room temperature is an independent variable that does not depend on any factor

Students were the constants in the experiment

Among the students, students in normal temperature room is the control group as they were placed just to check the correctness of the experiment.

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The magnitude of the given vectors for B - 3A expression is determined as 105.5 m.

The magnitude of a vector is the length of the vector. The magnitude of the vector a is denoted as |a|.

The magnitude of a vector represents the absolute value of the given vector.

The magnitude of the expression B - 3A is calculated as follows;

B - 3A = 26.5 - 3(44)

B - 3A = 26.5 - 132

B - 3A =  -105.5

|B - 3A| = 105.5

Thus, the magnitude of the given vectors for B - 3A expression is determined as 105.5 m.

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At distance of 40/7 m from A the particles will collide.

Let particles collide at C

And let distance AC = x and BC = y

then, x+y = 20

As the equation used for distance required here is: s= ut +1/2 a[tex]t^{2}[/tex] and  here u=0

Then, 1/2 (2)[tex]t^{2}[/tex]  +1/2 (5)[tex]t^{2}[/tex]  =20  

7/2[tex]t^{2}[/tex]  =20

[tex]t^{2}[/tex] = 40/7

Now

x= 1/2 (2)[tex]t^{2}[/tex] = 40/7 m

Therefore, at distance of 40/7 m from A the particles will collide.

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The narration style in the para is third person omniscient

As it narrates the whole incident which is going on.

What is third person omniscient?

The most flexible and open POV available to writers is third person omniscient. An omniscient narrator is one who has all knowledge and all sight, as the name suggests.

The narrator may occasionally access the consciousness of a few or many different characters while the narration is taking place outside of any one particular character.

Some authors employ this viewpoint to build a more "godlike" or purposefully "authorial" persona that enables them to offer dispassionate commentary on the action. Detailed location descriptions that contribute to the mood or atmosphere of a scene may be an example of this, as well as philosophical tangents that serve to develop concepts that only loosely link to the action of the story.

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Answer: Bias

Explanation:

The correct answer is to describe an object's perceived size and describing its position in space. Degrees (°) are used to express angles. A complete circle has 360 °, whereas a straight angle has 90 °. For instance, there is a 90° angle between the horizontal direction (toward the horizon) and the vertical direction (directly above you). The full moon's angular diameter in the sky is around 1/ 2°.

Triangle Units

Divide a complete circle into 360 degrees. Divide a degree into 60 arcminutes, also known as minutes of arc (abbreviated as 60 arcmins or 60'). Divide an arcminute into 60 arcseconds, also known as seconds of arc (abbreviated as 60 arcsec or 60).

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The correct answer is :

In octal,

Decimal         16  17   18  19  20  21  22 23  24  25  26  27  28  29  30 31  32

Octal             20  21  22  23 24  25 26 27  30  31   32  33  34  35  36 37  40

Hexadecimal 10   11   12  13  14   15  16  17   18   19   1A   1A   1C  1D  1E  1F  20

Decimal   8  9  10 11  12 13  14  15  16  17  18  19  20 21  22  23 24 25 26 27 28

Base13     8  9  A  B  C  10  11  12  13   14  15  16  17  18  19   1A  1B  1C 20 21 22

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The time taken for the object to travel the given height is determined as 12.48 seconds.

Time of motion of an object is the total time taken by the object to travel a given height or distance.

The time of motion of the boulder is calculated as follows;

h = vt + ¹/₂gt²

where;

1300 = 43t  +  0.5(9.8)t²

1300 = 43t + 4.9t²

4.9t² + 43t - 1300 = 0

solve the quadratic equation using formula method as shown below;

a = 4.9, b = 43, c = -1300

t = 12.48 seconds

Thus, the time taken for the object to travel the given height is determined as 12.48 seconds.

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The precise way a researcher measures and defines a variable is known as the operational definition.

The researcher measures the dependent variable and the independent variable is manipulated and controlled by the researcher ( Experimenter ). The concept of operational definition is applied in various fields such as Philosophy, Science, Business, computing etc.

To explain this clearly, let's consider an example in which the researcher tries to define sleep deprivation. In this sleep deprivation is the independent variable and factors causing sleep deprivation such as food, lifestyle, etc are dependent variables.

Therefore, the precise way a researcher measures and defines a variable is known as the operational definition.

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The centripetal acceleration of the Ferris wheel with radius of 14.0 m is determined as 2.57 m/s².

Centripetal acceleration,  is the acceleration of a body moving a circular path.

The centripetal acceleration of the Ferris wheel is calculated as follows;

a = v²/r

where;

a = (6²) / (14)

a = 2.57 m/s²

Thus, the centripetal acceleration of the Ferris wheel is determined as 2.57 m/s².

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The complete question is below:

A Ferris wheel has a radius of 14 m, the linear speed of a passenger on the rim is 6 m/s .Find the centripetal acceleration of the Ferris wheel.

The mass of the cart is 30kg

Using Newton's formula which states that Force is given as product of mass and acceleration.

The force is given to be 60N

The acceleration is given to be 2 m/s^2

Using the formula

F=ma

Putting the values of formula,

60 = m x 2

m = 30 kg

Hence the mass of the cart is 30kg

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Answer:

I think it's B but I'm not 100% sure

The maximum speed of the stone tied to the string is 5.32 m/s.

The mass of the stone is m = 1.2 kg.

The mass is tied to a string and it swung in a vertical radius of r = 0.85 cm.

The tension on the string is T = 40 N.

The centripetal force of a body moving in a circle of radius r is given as:

T = ( mv² / r )

Where T is the tension, m is the mass of the body and r is the radius of the circle.

Then,

v² = ( T × r ) / m

v = √ [ T × r / m ]

v = √ [ 40 × 0.85 / 1.2 ]

v = √ [ 34 / 1.2 ]

v = √28.3

v = 5.32 m/s

The maximum speed of the stone before the string breaks is 5.32 m/s.

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As we go up the y-axis, the number of sprouted bean seeds increase (option B).

Graph is a data chart intended to illustrate the relationship between a set (or sets) of numbers (quantities, measurements or indicative numbers) and a reference set.

In a graph, there are two axes as follows;

According to this question, a graph of number of sprouted bean seeds on the y-axis is plotted against temperature on the x-axis.

We can observe that as we go up the y-axis, the number of sprouted bean seeds increase.

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The spring constant is 542 N/m.

The height the ball reaches is 37.5 m.

The angular speed of the ball is calculated as follows;

ω = 2π/T

ω = (2π) / (0.13)

ω = 48.33 rad/s

The spring constant is calculated as follows;

ω = √(k/m)

ω² = k/m

ω²m = k

(48.33² x 0.232) = k

542 N/m

v = ωL

v = 48.33 x 0.56 m

v = 27.1 m/s

h = v²/2g

h = (27.1²) / (2 x 9.8)

h = 37.5 m

Thus, the spring constant is 542 N/m.

The height the ball reaches is 37.5 m.

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