the solubility of sugar is 30 degree Celsius at 220 what does it mean​

Answer:

11 km/s

Explanation:

v=s/t

v=825km/75s

v=11km/s

Answer:

you couldn't do this on your own or search it up on google

Answer:

q + d = 50

25q + 10d = 980

Explanation:

The equation that can be employed to determine the number of quarters(q), as well as, dimes(d) that Yodelin has would be:

q + d = 50...(1)

25q + 10d = 980...(2)

Multiplying (1) by 25

25q + 25d = 1250 ...(3)

25q + 10d = 980...(4)

subtracting (4) from (3)

15d = 270

d = 18

q = 50 - 18

    = 32

The system of the equations could be

q + d = 50

25q + 10d = 980

Since Yodelin has fifty quarters and dimes. Their total value is $9.80.

So here the equations be

q + d = 50...(1)

25q + 10d = 980...(2)

Now we have to Multiplying (1) by 25

So,

25q + 25d = 1250 ...(3)

25q + 10d = 980...(4)

Now

subtracting (4) from (3)

15d = 270

d = 18

So,

q = 50 - 18

   = 32

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Answer:

Resultant is 152 N at 28.5 degrees south to the 100 N force

Explanation:

The answer is " The orange and gray toy boats experienced the strongest force because both gained the same force as they sped up the blue boat lost force so it slow down

Explanation:

Trust me I did this one for an assignment

The boat that will experience the strongest force is the boat that has the highest speed.

According to Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.

F = ma

[tex]F = \frac{mv}{t}[/tex]

where;

The force experienced by the boats is directly proportional to the velocity of their motion. Since the boats have the same mass, the force experienced by each boat will depend on the speed with which the boat moves.

Thus, the boat that will experience the strongest force is the boat that has the highest speed.

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Answer:

The skier is experimenting a net force of 0 newtons in both cases. ([tex]v_{1} = 15\,\frac{km}{h}[/tex], [tex]v_{2} = 20\,\frac{km}{h}[/tex])

Explanation:

According to Newton's First Law, an object is in equilibrium when it is either at rest or moving at constant velocity, which means that net force is equal to 0 newtons.

Therefore, the skier is experimenting a net force of 0 newtons in both cases.

Answer:

C) he had more power running than walking

Explanation:

saw it on a quizlet. not 100% sure tho

Hiro walks up a flight of stairs in his apartment building. Later in the day, he runs up the same flight of stairs so He had more power running than walking.

In physics, power is the amount of energy transferred or converted per unit of time. In the International System of Units, the unit of power is the watt, equal to one joule per second. In older works, power is sometimes called activity. Power is a scalar quantity.

Power is related to other quantities; for example, the power involved in moving a ground vehicle is the product of the traction force on the wheels and the velocity of the vehicle.

The output power of a motor is the product of the torque that the motor generates and the angular velocity of its output shaft

Since we know that Hiro will run on stairs to minimize the time of reaching his home so if time decreases then he has to increase his power as power is the ratio of work and time.

Hence Hiro walks up a flight of stairs in his apartment building. Later in the day, he runs up the same flight of stairs so He had more power running than walking.

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Answer:

C. 110 m/s2

Explanation:

Force = Mass x Acceleration

Since we have the force and the mass, we can rearrange this equation to solve for acceleration by dividing both sides by mass:

Force/Mass = (Mass x Acceleration)/Mass

Acceleration = Force/Mass

Now we just have to plug in our values and calculate!

Acceleration = 48.4/0.44

Acceleration = 110m/s/s

It is option C. 110 m/s2

Hope this helped!

Answer:

theres no

Explanation:

picture or anything so... ur question doesnt make sense

Answer:

A

Explanation:

The acceleration of an object is directly proportional to its net force.

[tex]a = \frac{f}{m} [/tex]

Answer:

Correct choice: A. The acceleration is directly proportional to the net force

Explanation:

Newton's Second Law of Motion

According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force F and inversely proportional to the object's mass m:

[tex]\displaystyle a=\frac{F}{m}[/tex]

Correct choice: A. The acceleration is directly proportional to the net force

11

Explanation:

There are 11 protons in a sodium atom

Answer:

The answer is D.

Explanation:

Answer:

(a). The decay constant is [tex]1.55\times10^{-5}\ s^{-1}[/tex]

The half life is 11.3 hr.

(b). The value of N₀ is [tex]2.38\times10^{11}\ nuclei[/tex]

(c). The sample's activity is 1.87 mCi.

Explanation:

Given that,

Activity [tex]R_{0}=10\ mCi[/tex]

Time [tex]t_{1}=4\ hours[/tex]

Activity R= 8 mCi

(a). We need to calculate the decay constant

Using formula of activity

[tex]R=R_{0}e^{-\lambda t}[/tex]

[tex]\lambda=\dfrac{1}{t}ln(\dfrac{R_{0}}{R})[/tex]

Put the value into the formula

[tex]\lambda=\dfrac{1}{4\times3600}ln(\dfrac{10}{8})[/tex]

[tex]\lambda=0.0000154\ s^{-1}[/tex]

[tex]\lambda=1.55\times10^{-5}\ s^{-1}[/tex]

We need to calculate the half life

Using formula of half life

[tex]T_{\dfrac{1}{2}}=\dfrac{ln(2)}{\lambda}[/tex]

Put the value into the formula

[tex]T_{\dfrac{1}{2}}=\dfrac{ln(2)}{1.55\times10^{-5}}[/tex]

[tex]T_{\dfrac{1}{2}}=44.719\times10^{3}\ s[/tex]

[tex]T_{\dfrac{1}{2}}=11.3\ hr[/tex]

(b). We need to calculate the value of N₀

Using formula of [tex]N_{0}[/tex]

[tex]N_{0}=\dfrac{3.70\times10^{6}}{\lambda}[/tex]

Put the value into the formula

[tex]N_{0}=\dfrac{3.70\times10^{6}}{1.55\times10^{-5}}[/tex]

[tex]N_{0}=2.38\times10^{11}\ nuclei[/tex]

(c). We need to calculate the sample's activity

Using formula of activity

[tex]R=R_{0}e^{-\lambda\times t}[/tex]

Put the value intyo the formula

[tex]R=10e^{-(1.55\times10^{-5}\times30\times3600)}[/tex]

[tex]R=1.87\ mCi[/tex]

Hence, (a). The decay constant is [tex]1.55\times10^{-5}\ s^{-1}[/tex]

The half life is 11.3 hr.

(b). The value of N₀ is [tex]2.38\times10^{11}\ nuclei[/tex]

(c). The sample's activity is 1.87 mCi.

Answer:

Static stretching.

Explanation:

It is static stretching because it is a form of stretching which u can do actively for a period of time and you hold position for about 30 to 60 seconds which allow the muscles and connective tissues to lengthen. It is done after work out with out movement in order to loosen up muscles so as to gain flexibility.

sectors are the amount of resources

Answer:

the answer to your question is b a mirror fogs up when someone takes a hot shower.

The process of conversion of gaseous water to its liquid form is called condensation. The fogs formed on the mirror from the hot shower is an example of condensation.

Condensation is the process of cooling up of water vapor to liquid water. Water vapor condenses when it cools. Condensation can be best understood from the reason behind raining.

When water vaporizers from resources and cools from the sky, and the vapor condenses to form liquid droplets. Similarly we can observe water droplets in the window pane due to the similar effect.

The water vapor arises from the hot shower condenses in the atmosphere and forms the drops on the mirror. Therefore, the mirror fogs up by the hot shower is an example of condensation.

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Answer:

Explanation:

A: wrong. Mass and weight are different.

B: Wrong. The mass here and the mass on the moon are the same. The weight, which is Mass * the acceleration  is equal to weight.

C: Correct.

D: Wrong. Weight is not measured in Kg. Mass is.

Answer:

Normal, Gravity, Friction, and Air Resistance.

Explanation:

When a moving car skid to stop and its wheels are locked across, then the following forces will be applied on the car:

Normal force: It will act counter to gravity that pushes an object against a surface and acts perpendicular to the contact surface.

Gravity: Gravity force acts in each and every object having mass and it can not be avoidable. So, the gravity force will also apply to the car and attract it to the earth's surface.

Friction: Friction is a force that acts opposite to the motion and stops or slows motion. Friction will be applied to the car that will oppose the motion of the car and stop it.

Air resistance: air resistance is defined as the forces exerted by air that acts opposite to the relative motion of an object. Air resistance will also be applied to the car when it will skid to stop as we are always surrounded by the air.

Hence, the correct answers are "Normal, Gravity, Friction, and Air Resistance."

Answer:

27.1 m/s

Explanation:

Given that at a race car driving event, a staff member notices that the skid marks left by the race car are 9.06 m long. The very experienced staff member knows that the deceleration of a car when skidding is -40.52 m/s2.

Using third equation of motion,

V^2 = U^2 + 2aS

Since the car is decelerating, the final velocity V = 0

Substitute all the parameter into the equation above,

0 = U^2 - 2 * 40.52 * 9.06

U^2 = 734.22

U = [tex]\sqrt{734.22}[/tex]

U = 27.096

U = 27.1 m/s  approximately

Therefore, the staff member can estimate for the original speed of the race car to be 27.1 m/s if it came to a stop during the skid

Answer:

The distance to come to a halt is approximately 49.53 meters

Explanation:

Thee given parameters are;

The speed of the car, v = 50 mph = 22.35 m/s

The mass of the car, m = 1000 kg

The coefficient of friction,  = 0.514

The force of friction of the brake = Mass × Gravity × Friction = 1000 × 9.81 × 0.514 = 5042.34 N

The initial kinetic energy of the car = 1/2×m×v² = 1/2 × 1000 × 22.35² = 249761.25 J

The work done by the brake = Force of the brake × Distance, d, to come to halt

By conservation of energy, we have;

The work done by the brake = The initial kinetic energy of the car

∴ The initial kinetic energy of the car = Force of the brake × Distance, d, to come to halt

The initial kinetic energy of the car = 249761.25 J = 5042.34 N × Distance, d, to come to halt

∴The distance to come to a halt = 249761.25 J /(5042.34 N) ≈ 49.53 meters

The distance to come to a halt ≈ 49.53 meters.

The car will cover 49.65 m distance before stopping due to application of brake.

Given data:

The mass of car is, M = 1000 kg.

The initial speed of car is, u = 50.0 mph = (50)(0.447 m/s) = 22.35 m/s.

The coefficient of static friction is, [tex]\mu = 0.514[/tex].

The given problem can be solved using the third kinematic equation of motion. Which is,

[tex]v^{2}=u^{2}+2as[/tex] ....................................................(1)

Here, v is the final speed, v = 0 (Because car is finally stopping)

s is the distance covered before stopping and a is the magnitude of acceleration.

Now, since frictional force opposes the motion. Then,

[tex]F = f\\\\ma = \mu \times m \times g\\\\a = 0.514 \times 9.8\\\\a =5.03 \;\rm m/s^{2}[/tex]

Substituting the values in equation (1) as,

[tex]0^{2}=23.35^{2}+2(-5.03)s\\\\s = \dfrac{2500}{2 \times 5.03}\\\\ s=49.65 \;\rm m[/tex]

Thus, the car will cover 49.65 m distance before stopping due to application of brake.

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Answer:

A

Explanation:

big brain

During this quick stop, some of the mechanical energy (his motion) was changed into heat energy.

Energy is the ability to do work. There are different types of energy such as Heat energy, light energy, kinetic energy, and gravitational energy.

Heat is the energy that moves from one body to another when temperatures are different. Heat passes from the hotter to the colder body when two bodies with differing temperatures are brought together.

The joule is a unit of energy that serves as the SI unit for heat (J). The calorie (cal), which is defined as "the amount of heat necessary to raise the temperature of one gram of water from 14.5 degrees Celsius to 15.5 degrees Celsius," is another common unit of heat measurement.

Therefore, During this quick stop, some of the mechanical energy (his motion) was changed into heat energy.

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Answer:

its should be 2.0 and 4.5 on it

Answer:

100

Explanation:

The final velocity of the object after the force acts is 2.5 meters per second.

To calculate the final velocity of the object after the force acts, we can use Newton's second law of motion, which states that:

Force = Mass × Acceleration

We need to find the acceleration of the object first. Since the object was initially at rest, its initial velocity (u) is 0 m/s.

The force acting on the object is 500 N, and the mass of the object is 0.20 kg. We can rearrange the equation to find the acceleration (a):

Acceleration (a) = Force / Mass

a = 500 N / 0.20 kg

a = 2500 m/s²

Now, we can use the kinematic equation to find the final velocity (v) of the object:

Final velocity (v) = Initial velocity (u) + (Acceleration × Time)

The initial velocity (u) is 0 m/s (since the object was initially at rest), and the time interval (t) is 0.001 second.

Final velocity (v) = 0 m/s + (2500 m/s² × 0.001 s)

v = 0 m/s + 2.5 m/s

v = 2.5 m/s

Hence, the final velocity of the object after the force acts is 2.5 meters per second.

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Answer:

F=-100N; a=1.3m/s^2

Explanation:

Force is being made by student, so wall counteracts that force by not moving so it is equally opposite.

The force of the wall pushing back on the student would be 100 Newtons, and the acceleration of the student as she moves away from the wall would be 1.33 m/s²

Newton's third law of motion state that for every action force there exists a complementary reaction force that balances it.

As given in the problem a student is on a skateboard facing a wall. The student and skateboard have a mass of 75 kilograms. The student pushes off of the wall with a force of 100 Newtons,

The force of the wall pushing back the student = 100 Newtons

The acceleration of the student = 100/75

                                                     =1.33 m/s²

Thus, The student would be pushed back against the wall by a force of 100 Newtons, and she would accelerate away from the wall at a rate of 1.33 m/s².

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Answer:

(a). The distance is 207 m.

(b). The initial velocity is 45.0 m/s

(c). The maximum height is 103.3 m

Explanation:

Given that,

Time = 4.60 s

We need to calculate the initial velocity

Using equation of motion

[tex]v=u-gt[/tex]

Put the value into the formula

[tex]0=u-9.8\times4.60[/tex]

[tex]u=45.0\ m/s[/tex]

We need to calculate the distance

Using formula of distance

[tex]d=v\times t[/tex]

Put the value into the formula

[tex]d=45\times4.60[/tex]

[tex]d=207\ m[/tex]

We need to calculate the maximum height

Using equation of motion

[tex]v^2=u^2-2gh[/tex]

Put the value into the formula

[tex]0=(45.0)^2-2\times9.8\times h[/tex]

[tex]h=\dfrac{(45.0)^2}{2\times9.8}[/tex]

[tex]h=103.3\ m[/tex]

Hence, (a). The distance is 207 m.

(b). The initial velocity is 45.0 m/s

(c). The maximum height is 103.3 m