The reaction system CO(g) + 2 H2(g) = CH3OH(g) is at equilibrium. When H2 is added to the container, the reaction shifts to the right the partial pressure of Co does not change and the partial pressure of CH3OH decreases

The pressure of the gas at the new location is approximately 7.92 atm.

To solve this problem using the formula provided, we need to plug in the given values for the initial state (denoted by subscript 1) and the final state (denoted by subscript 2) of the gas:

p₁v₁t₁ = p₂v₂t₂

where:

p₁ = 4.0 atm (initial pressure)

v₁ = 5.5 L (initial volume)

t₁ = 300 K (initial temperature)

p₂ = ? (what we are solving for)

v₂ = 2.0 L (final volume)

t₂ = 250 K (final temperature)

We can rearrange the equation to solve for p₂:

p₂ = p₁v₁t₁ / v₂t₂

Substituting the given values:

p₂ = (4.0 atm) x (5.5 L) x (300 K) / (2.0 L) x (250 K)

p₂ = 7.92 atm

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Answer:

its 9.2 atm

Explanation:

Answer: 11.04 atm

Explanation:

P1/T1 = P2/T2 this is the Gay-Lussac law

Temperature must be in kelvin

P2=P1T2/T1

8.7 X 352.85 /278.05

A reason that Lewis electron dot diagram only show electrons in the outermost orbital of an atom

(d) Only outer shell electrons can be involved in chemical bonds.

The Lewis electron dot diagram shows only the valence electrons or outer shell electrons of an atom because these are the electrons that are involved in chemical bonding.

In a chemical reaction, atoms try to achieve a stable electron configuration by either gaining, losing, or sharing electrons. The valence electrons are located in the highest energy level of an atom and are the ones that are involved in chemical bonding with other atoms.

Therefore, the Lewis dot diagram is a visual representation of the valence electrons of an atom, which shows how the valence electrons are shared, gained, or lost in chemical bonding.

Thus, option (d) is the correct answer.

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complete question

Which of the following is a reason that Lewis electron dot diagram

only show electrons in the outermost orbital of an atom?

(a) Outer- shell electrons have energy than inner-shell electrons.

(b) Lewis electron dot diagram would get too complicated if each atom showed all of its electrons.

(C) inner-shell electrons cannot be proven to exist and thus should not be included  in a Lewis electron dot structure.

(d) Only outer shell electrons can be involved in chemical bonds.​

According to the question there are 1.235 moles of Ca3Si2 in 325 g of the compound.

Material is something that can be seen, felt, and/or interacted with. It is the physical substance of which a thing is composed. Materials can be made up of elements, compounds, and/or mixtures of these. Examples of materials include metals, plastics, rubber, wood, paper, cloth, glass, and water. Each material has unique properties such as strength, weight, color, texture, and durability. The choice of material used in a design or product is important as it affects the cost, performance, and overall success of the item. Manufacturers must consider the properties of the materials they choose and how they will interact with each other in order to create a successful product.

The molar mass of Ca3Si2 is 263.01 g/mol. This means that there are 1.235 moles of Ca3Si2 in 325 g of the compound.

To calculate this, we first need to calculate the mass of one mole of Ca3Si2. This can be done by dividing the molar mass of the compound (263.01 g/mol) by 1. This gives us a result of 263.01 g/mol.

We can then use this value to calculate the number of moles in 325 g of Ca3Si2. This is done by dividing the mass of the compound (325 g) by the mass of one mole of Ca3Si2 (263.01 g/mol). This gives us a result of 1.235 moles.

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If 1.90 g of silver are produced from the reaction, then 0.0176 moles of copper(II) nitrate are also produced.

A chemical reaction occurs when moving molecules hit each other, breaking their bonds and producing an exchange of atoms that form new products. Another way a chemical reaction can occur is through the vibration of substances; when they do so with sufficient energy, they can be broken down into smaller molecules.

we need to use the balanced chemical equation,

3Cu(NO3)2 + 2Al → 3Cu + 2Al(NO3)3

we can see that 3 moles of Cu(NO3)2 react with 2 moles of Al to produce 3 moles of Cu. Therefore, the molar ratio of Cu(NO3)2 to Cu is 3:3 or 1:1.

m(Ag) = 1.90 g

M(Ag) = 107.87 g/mol

n(Ag) = m(Ag) / M(Ag)

n(Ag) = 1.90 g / 107.87 g/mol

n(Ag) = 0.0176 mol

The molar ratio of Cu(NO3)2 to Cu is 1:1, the moles of Cu produced in the reaction is also 0.0176 mol. So, the number of moles of Cu(NO3)2 produced is also 0.0176 mol.

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Answer:

Based on the information provided, it seems that Mateo subscribes to the situational theory of leadership. This theory suggests that the most effective leadership style depends on the situation at hand, and that a good leader will be able to adapt their leadership style to suit the needs of their team. Mateo is specifically looking for someone who can keep the team focused and on track, indicating that he recognizes the importance of tailoring his leadership approach to the situation.

Answer: 484.94 K

Explanation:

T2 = T1 X V2 / V1

Temperature must be in kelvin so 543 + 273.15 =816.15

816.15 X 51.1 / 86

Answer: We can use the combined gas law to solve this problem:

(P₁V₁/T₁) = (P₂V₂/T₂)

where P is pressure, V is volume, and T is temperature in Kelvin.

We know that P₁ = P₂ (the pressure is assumed to be constant), and we are given V₁, T₁, and V₂. We can solve for T₂:

(P₁V₁/T₁) = (P₂V₂/T₂)

T₂ = (P₂V₂/T₁) * (T₁/P₁V₁)

We need to convert the initial temperature from Celsius to Kelvin:

T₁ = 543 + 273 = 816 K

Substituting the values:

T₂ = (1 atm * 86 mL / 816 K) * (51.1 mL / 1 atm * 86 mL)

T₂ = 0.0629 * 51.1 * 1000 = 3217 K

Therefore, the marshmallow would need to be heated to a temperature of 3217 K for its volume to change from 86 mL to 51.1 mL.

Enjoy (:

We must change the coefficients in front of the chemical formulae in order to balance equation. The balanced equation is as follows: 4O2 + 6H2O + 6NaCl + Al2O3 + 2NH3 = 6Na + 2AlN2 + 15CI.

When a chemical equation is balanced, coefficients change. Never alter the subscript. A coefficient is a multiplier for whole numbers. to correct an equation in chemistry.

You can only alter the coefficients in an equation when you balance it. The coefficients are shown by the numerals in front of the molecule. The lower numbers found following atoms are called subscripts. When balancing chemical equations, these cannot be altered!.

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The half-life for the reaction is 0.693/k. It will take approximately 1.386/k seconds for the concentration of A to decrease to 25% of its initial concentration. It will take approximately 2.218/k seconds for the concentration of A to decrease to 0.78 M. If the initial concentration of A is 0.150 M, the concentration of A after 5 half-lives is 0.00938 M, and after 10 half-lives it is 0.00059 M.

The decomposition of A is a first-order reaction with a rate constant of k at a certain temperature. The rate law for this reaction is given by:

Rate = k[A]

The half-life for a first-order reaction is given by the equation:

t1/2 = 0.693/k

Substituting the given rate constant into this equation gives the half-life for the reaction.

To calculate how long it will take for the concentration of A to decrease to 25% of its initial concentration, we can use the equation:

[tex]ln\frac{A_{t} }{A_{0}} = -k_{t}[/tex]

Substituting 0.25[A]0 for [A]t and the given rate constant into this equation, we can solve for t.

Similarly, to calculate how long it will take for the concentration of A to decrease to 0.78 M, we can use the same equation and substitute 0.78 M for [A]t and the given rate constant into the equation.

To determine the concentration of A after a certain amount of time has passed, we can use the equation: [A]t = [A]₀ [tex]e^{-kt}[/tex]

Substituting the given rate constant and the time elapsed into this equation will give us the concentration of A at that time.

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a) The independent variable was the surface area of the limestone (large chips, small chips, and powder).

b) The dependent variable was the rate of the reaction, measured in cm³ of carbon dioxide produced per second.

c) i) Four variables that must be controlled are:

ii) These variables must be controlled to ensure that the only variable affecting the reaction rate is the surface area of the limestone.

The relationship between surface area and the rate of a reaction is that the rate of a reaction increases as the surface area of the reactants increases.

The missing rates can be calculated using the formula:

Rate = Volume of carbon dioxide produced ÷ Time taken to produce it

Size of limestone Time taken (s) Volume of carbon dioxide produced (cm³) Rate (cm³/s)

Large chips 150 50 0.33

Small chips 110 50 0.45

Powder 15 50 3.33

e) The powder had the biggest surface area.

f) The time taken for the reaction to occur decreases as the surface area of the limestone increases.

g) The reaction rate increases as the surface area of the limestone increases.

h) Changing the surface area of the limestone increases the frequency of collisions between the reactant particles (limestone and hydrochloric acid). This increase in the frequency of collisions results in an increase in the reaction rate.

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4. The molar mass of KOH is 56.11 g/mol. Using the formula for molarity, M = moles of solute/liters of solution, we can calculate the number of moles of KOH in the solution:

moles of KOH = 112 g / 56.11 g/mol = 1.997 mol

Then, we divide the moles of KOH by the volume of the solution in liters:

M = 1.997 mol / 2.00 L = 0.999 M

Therefore, the molarity of the solution is 0.999 M, which is approximately 1.00 M.

Answer: C) 1.00 M

5. Using the same formula for molarity, we can first calculate the number of moles of KNO3 in the solution:

moles of KNO3 = 404 g / 101 g/mol = 4.00 mol

Then, we divide the moles of KNO3 by the volume of the solution in liters:

M = 4.00 mol / 2.00 L = 2.00 M

Therefore, the molarity of the solution is 2.00 M.

Answer: A) 2.00 M

6. The molar mass of KF is 58.10 g/mol. Using the same formula for molarity, we can calculate the number of moles of KF in the solution:

moles of KF = 116 g / 58.10 g/mol = 1.999 mol

Then, we divide the moles of KF by the volume of the solution in liters:

M = 1.999 mol / 1.00 L = 1.999 M

Therefore, the molarity of the solution is 1.999 M, which is approximately 2.00 M.

Answer: A) 2.00 M

7. The volume of the solution is given in milliliters, so we need to convert it to liters:

2,000 milliliters = 2.000 liters

The concentration of a solution is defined as the number of moles of solute per liter of solution. One mole of CaCl2 has a mass of 40.08 + 2(35.45) = 110.98 g. Therefore, the number of moles of CaCl2 in the solution is:

moles of CaCl2 = 1 mol

We can now calculate the concentration of the solution:

M = 1 mol / 2.000 L = 0.500 M

Therefore, the concentration of the solution is 0.500 M.

Answer: C) 0.25 M

8. The molarity of the HCl solution is given as 3.0 M. Using the formula for molarity, we can calculate the number of moles of HCl in 0.50 L of solution:

moles of HCl = M x L = 3.0 mol/L x 0.50 L = 1.5 mol

Therefore, there are 1.5 moles of HCl in 0.50 L of solution.

Answer: C) 1.5

9. We need to use the formula for molarity to determine how many moles of KOH are required to make a 2.00 M solution in 250. mL of solution:

M = moles of KOH / liters of solution

2.00 M = moles of KOH / 0.250 L

moles of KOH = 0.500 mol

Then, we can use the formula:

mass = moles x formula mass

mass of KOH = 0.500 moles x 56.0 g/mol = 28.0 g

Therefore, the answer is (C) 28.0 g.

10. According to the Solubility Guidelines chemistry reference table, the least soluble compound in water is (B) Ca3(PO4)2.

11. Based on the Solubility Guidelines chemistry reference table, the compound that will not dissolve in a saturated solution is (A) AgCl(aq).

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The following solutions are buffers:

A solution made by mixing 100 ml of 0.100 M HCOOH and 50 ml of 0.100 M KCl, and a solution made by mixing 100 ml of 0.100 M HCOOH and 500 ml of 0.100 M NaOH.

Let's learn more about buffer solutions:

1. Buffer solutions can withstand or resist pH changes, even when adding a strong acid or base. A buffer solution comprises a weak acid and its conjugate base or a weak base and its conjugate acid. The pH change is insignificant when an acid or a base is added to a buffer solution.

2. The chemical equation for the ionization of HCOOH in water is as follows:

HCOOH + H2O ⇌ H3O+ + HCOO-

The salt made from the acid and the base in the buffer solution must be able to act as a source of ions to neutralize either the excess H3O+ ions or OH- ions introduced into the solution. For example, KCl and NaOH are used in the buffer solutions listed above, as they produce K+ and Na+ ions, which can interact with HCOO- ions in the first buffer and HCOO- ions and HCOOH molecules in the second buffer.

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Therefore, the 20g of C has more atoms than the 70g of Zn.

To determine which sample has the most atoms, we need to use Avogadro's number, which is the number of atoms in a mole. Avogadro's number is approximately 6.022 x 10^23 atoms/mole.

First, we need to determine how many moles of each substance we have. We can do this by dividing the given mass by the molar mass of the element. The molar mass of carbon (C) is approximately 12 g/mol, and the molar mass of zinc (Zn) is approximately 65 g/mol.

For 20g of C:

moles of C = 20 g / 12 g/mol ≈ 1.67 moles

For 70g of Zn:

moles of Zn = 70 g / 65 g/mol ≈ 1.08 moles

Now, to determine the number of atoms, we can multiply the number of moles by Avogadro's number.

For 20g of C:

number of atoms = 1.67 moles x 6.022 x 10^23 atoms/mole ≈ 1.00 x 10^24 atoms

For 70g of Zn:

number of atoms = 1.08 moles x 6.022 x 10^23 atoms/mole ≈ 6.50 x 10^23 atoms

Therefore, the 20g of C has more atoms than the 70g of Zn.

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the pH of the 0.32 M solution of the weak acid with a Ka of 9.2 ×

[tex] {10}^{ - 6} [/tex]

at 25°C is 2.92.

To calculate the pH of a weak acid solution, we need to use the dissociation constant of the acid (Ka) and the concentration of the acid (molarity) in the solution.

HA + H2O ⇌ H3O+ + A-

Ka = [H3O+][A-] / [HA]

Solve for x using the quadratic formula, since this is a quadratic equation:

x = [H3O+] = √(Ka*[HA]) = √(9.2 ×

[tex] {10}^{ - 6} [/tex]

* 0.32) = 1.20 × 10^-3 M

Calculate the pH using the formula:

pH = -log[H3O+] = -log(1.20 ×

[tex] {10}^{ - 3} [/tex]

) = 2.92

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Initially, retrosynthesis The target molecule is the ultimate outcome of this process, and the intermediates and raw materials utilised to create the product are determined by a stepwise breakdown.

The chemical route can also be established using a retrosynthetic investigation.

Second step: retrosynthesis of CH3,CH2;CH2;CHO

To create a pathway where starts off as a two-carbon compound.

Step 3: CH3,CH2,CH2;CHO synthesis

The entire synthetic pathway of manufacturing depends on the retrosynthetic analysis.

Hydrocarbons with the carbonyl substituents are known as aldehydes. A hydrogen atom is also present in the material to which the quintuple oxygen is bonded. Aldehydes' carbonyl atoms are thus present at the hydrocarbon's terminal elements.

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                                     "Complete question"

Deeply Devise a synthesis of CH3CH2CH2CHO from two-carbon starting materials. Be sure to answer all parts of the question Step 1: Intermediate 1?

Boyle's Law states that the pressure of a gas is inversely proportional to its volume when the temperature is constant.

Mathematically, Boyle's Law can be expressed as P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.

Here's an example problem with a solution that uses Boyle's Law:

Example problem:

A sample of gas has a volume of 5.0 L at a pressure of 2.0 atm. If the pressure is increased to 4.0 atm, what will be the new volume of the gas?

Solution:

According to Boyle's Law, P1V1 = P2V2, where P1 = 2.0 atm, V1 = 5.0 L, and P2 = 4.0 atm.

Substituting these values into the equation, we get:

(2.0 atm)(5.0 L) = (4.0 atm)(V2)

Simplifying the equation, we get:

10 L atm = 4.0 atm V2

Dividing both sides by 4.0 atm, we get:

V2 = 10 L atm / 4.0 atm

V2 = 2.5 L

Therefore, the new volume of the gas is 2.5 when the pressure is increased to 4.0 atm.

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The reason why the reaction rate for reactants is defined as the negative of the change in reactant concentration concerning time, whereas for products, it is defined as the change in reactant concentration concerning time (with a positive sign) is because a reaction rate is a measure of the speed at which a reaction takes place.

Let's understand it in depth:

The reaction rate is determined by how fast the reactants are being used up or consumed and how quickly the products are being formed. If the reactants are being used up rapidly and the products are being formed slowly, the reaction rate will be slower than if the reactants were being used up slowly and the products were being formed rapidly. In general, the rate of a chemical reaction is expressed as the change in concentration of one or more of the reactants or products over a given time.

To calculate the reaction rate, you need to measure the change in concentration of one or more of the reactants or products over time. If the concentration of the reactant decreases over time, the reaction rate is expressed as a negative number. On the other hand, if the concentration of the product increases over time, the reaction rate is expressed as a positive number.

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Answer:

Polyatomic - Yes, (NH4)2CO3 contains polyatomic ions.

Metalloid - No, (NH4)2CO3 does not contain any metalloids.

Acid - No, (NH4)2CO3 is a salt, not an acid.

High Melting Point - No, (NH4)2CO3 has a relatively low melting point of around 58 °C.

Soluble in Water - Yes, (NH4)2CO3 is soluble in water.

Contain Anions and Cations - Yes, (NH4)2CO3 contains both anions (CO3^2-) and cations (NH4+).

Multivalent - No, (NH4)2CO3 does not contain any multivalent ions.

Therefore, the properties that apply to (NH4)2CO3 are 1, 5, and 6. The numerical response in ascending order is: 1, 5, 6.

Explanation:

Answer:

brother answer is this photo

The molar mass of the unknown acid is 152 g/mol.

Let's calculate this using titration data:

As per the given data of titration:

To determine the molar mass of the unknown acid, the following steps can be followed:

Step 1: Find the number of moles of NaOH solution used

n = M × V = 0.0700 mol/L × 0.0163 L = 0.00114 mol

Step 2: Write the balanced chemical equation for the reaction between the unknown acid and NaOH. The equation is:

HA + NaOH → NaA + H2O

Step 3: Determine the number of moles of HA from the number of moles of NaOH used. Since the unknown acid is diprotic, the number of moles of HA is half the number of moles of NaOH used. Therefore, the number of moles of HA is: 0.00114 mol/2 = 0.00057 mol

Step 4: Determine the concentration of the unknown acid in the volumetric flask using the formula:

C = n/V

where C is the concentration in mol/L, n is the number of moles of HA, and V is the volume of the volumetric flask in L.

C = 0.00057 mol/0.250 L = 0.00228 mol/L

Step 5: Determine the molar mass of the unknown acid using the formula:

M = mRT/PV

where M is the molar mass in g/mol, m is the mass of the unknown acid in g, R is the gas constant (0.08206 L·atm/K·mol), T is the temperature in Kelvin (assumed to be 298 K), P is the pressure in atm (assumed to be 1 atm), and V is the volume of the volumetric flask in L.M = 0.095 g × 0.08206 L·atm/K·mol × 298 K/1 atm × 1 L/0.250 L × 0.00228 mol/L = 152 g/mol

Therefore, the molar mass of the unknown acid is 152 g/mol.

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After 72 days, a 1050 mg sample of Iodine-131 would have decayed to approximately 46.87 mg.

A half-life is the time it takes for half of a sample of a radioactive isotope to decay. It is a characteristic property of each isotope and can be used to predict how long it will take for a given sample to decay to a certain amount. The amount of an isotope remaining after a certain amount of time can be calculated using the half-life and the formula N = N0 * (1/2)^(t/T).

Iodine-131 is used in medical treatments because it emits beta particles that can destroy cancerous cells. Its short half-life is an advantage because it allows for a higher dose of radiation to be delivered to the tumor while minimizing the amount of radiation exposure to healthy tissues. After a few weeks, the Iodine-131 decays to a negligible amount and the patient is no longer radioactive.

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Yes, the equilibrium shifted after the AgNO₃ was added and Ag₂S having a larger Ksp value as compared to CdS.

The addition of AgNO₃ provides Ag⁺ ions, which react with S₂⁻ ions in the solution to form insoluble Ag₂S, causing the equilibrium to shift towards the products. This results in the formation of a black precipitate, indicating the presence of Ag₂S.

Ag₂S has a larger Ksp value compared to CdS. This is because Ag₂S has a lower solubility product constant (Ksp) than CdS, which means it is less soluble in water. The Ksp value for Ag₂S is 8.5 x 10⁻⁵¹, while the Ksp value for CdS is 4.0 x 10⁻²⁷. Therefore, Ag₂S has a larger Ksp value and is less soluble in water than CdS.

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Answer:

The law of multiple proportions states that when two elements combine to form more than one compound, the mass ratios of the elements in the compounds can be expressed as small whole numbers.

Let's assume that the metal M combines with oxygen to form two different oxides, which are represented by the formulas MOx and MOy, where x and y are the number of oxygen atoms in each oxide.

According to the problem, the two oxides contain 11.1% and 20.0% of oxygen, respectively. We can convert these percentages to mass ratios as follows:

Mass ratio of oxygen in MOx = 11.1 g / 100 g of oxide

Mass ratio of oxygen in MOy = 20.0 g / 100 g of oxide

We can simplify these ratios by dividing each by their lowest common factor, which is 1.1:

Mass ratio of oxygen in MOx = 10 g / 91 g of oxide

Mass ratio of oxygen in MOy = 20 g / 100 g of oxide = 20 g / 91 g of oxide

These ratios can be expressed as small whole numbers by multiplying them by a factor that makes the denominator equal to a whole number. We can multiply the ratio for MOx by 10 to get:

Mass ratio of oxygen in MOx = 100 g / 910 g of oxide

We can multiply the ratio for MOy by 5 to get:

Mass ratio of oxygen in MOy = 100 g / 910 g of oxide

Now we can see that the mass ratios of oxygen in the two oxides are in a small whole number ratio of 1:1, which is consistent with the law of multiple proportions. This means that the metal M forms two different oxides in a ratio of small whole numbers, and that the composition of the oxides is determined by the ratio of the masses of the elements involved.

Explanation:

In the wave mechanical model, atoms of protons are separated into multiple orbitals and sublevels in addition to surrounding the nucleus at their fundamental energy levels. An atom's framework is the Bohr Model.

Niels Bohr, a scientist, proposed the idea in 1913. According to this theory, electrons move in discrete circular orbits, or shells, around an atom's nucleus. The students are taught about many atomic models in this lesson, including Dalton's, Thomson's, Rutherford's, and Bohr's models.

A positively charged sphere that has had negatively charged electrons inserted into it makes up an atom. An molecule throughout its entirety is electrically neutral because the magnitudes of electrons and protons are equal. Atoms make up all physical matter. The same element's atoms are structure.

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The bond enthalpy of the N-N triple bond is 418kj/mol. The correct statement about the N2 molecule is correct is that It requires less energy to break the bonds in molecule A than it does in molecule B.

A molecule is described as a group of two or more atoms held together by attractive forces known as chemical bonds

In chemistry, bond energy (E) or bond enthalpy (H) is the measure of bond strength in a chemical bond which means that the higher the bond enthalpy, the more energy is needed to break the bond and the stronger the bond.

The lower the bond enthalpy, the lesser energy is needed to break the bond and the weaker the bond.

So we can say that the e correct option is A. Since A has a lower energy value compared to B, it would take a lesser amount of energy to break the bonds in A.

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#completye question:

The bond enthalpy of the N-N triple bond is 418kj/mol. Which statement about the N2 molecule is correct?​

A. It requires less energy to break the bonds in molecule A than it does in molecule B.

B.It requires more energy to break the bonds in molecule A than it does in molecule B.

C. Molecule A is more stable than molecule B.

D. Molecule A has stronger bonds than molecule B.

Three different species of microscopic, thread-like worms are responsible for the parasitic disease lymphatic filariasis. Adult worms can only survive in the lymphatic system of humans.

Nowadays, it is indigenous to Madagascar, many Western Pacific Island countries and territories, Sub-Saharan Africa (with the exception of the southernmost region of the continent), and parts of the Caribbean. South America, India, and Southeast Asia are also infrequent regions where Bancroftian filariasis can be found. Brugman spp.

by way of mosquito bites. The mosquito aedes aegypti. When an infected Aedes species mosquito (Ae. aegypti or Ae. albopictus) bites a human, the virus that causes dengue is transmitted.

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The average atomic mass of hydrogen in the periodic table rounds to 1 because hydrogen-1 is the most frequent isotope of hydrogen.

Using the atomic masses of each isotope and their percent abundances, get the average atomic mass. To convert each percentage of abundance to a decimal, divide it by 100. Add the atomic mass of the isotope to this value. To find the average atomic mass, add the atomic masses of each isotope.

One proton, one electron, and no neutron make up the hydrogen atom. Because hydrogen has no neutrons, its mass number is equal to its atomic number, which is 1.

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The middle-placed graph illustrates the appropriate transformation.

Chemical transitions, also called chemical reactions, are the processes by which one or more chemicals are changed into one or more novel and separate substances. In other words, a catalyst involving atom rearrangement is referred to as a chemical transformation.

An transformation is a significant modification of form or appearance. A significant life change can result from an event like acquiring your driver's license, enrolling in college, or getting married. A transformation is indeed a significant, dramatic change.

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Answer: number 2

Explanation:

well you see if the bottom left corner of the shape which we are going to call Q first starts at (5,2) and we move it 4 down then we have (5,-2).

Now for the tricky part if we are moving it 90° counterclockwise around the origin. to put it simple and a easy way to understand is if you just turn your head sideways to the left and just put what you had in the first (top right) box and copy onto the top left box.

So instead of Q being (5,-2), Q would be (2,5).

I hope this helps and if I'm too late and you alertly answered it then I hope this helps anyone else who might have this problem and stumbles upon this.

The correct answer is C. It is rapidly converted to energy when it meets an ordinary electron, resulting in matter-antimatter annihilation.

In the proton-proton chain, the first step involves the fusion of two protons to form a deuterium nucleus (a proton and a neutron) and a positron (antielectron) and a neutrino. The positron is a form of antimatter with the same mass as an electron but with a positive charge. When the positron encounters an ordinary electron, they annihilate each other, releasing energy in the form of gamma rays. This process is known as matter-antimatter annihilation. This conversion of matter into energy is a fundamental concept in physics and is used in various applications, including nuclear power generation and medical imaging. In the context of the Sun, the energy released from these reactions is what powers the Sun and allows it to shine.

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