the ratio of length and breadth of a room is 4:3. If the room is 12 m long. Find is breadth​

Answers

Answer 1

Answer:

Step-by-step explanation:

ratio of length to breadth=4:3

let breadth be x m

4/3=12/x(do cross multiplication)

3*12=x*4

36=4x

36/4=x

9=x

therefore breadth= 6m


Related Questions

What does the digit 7 represent in 701, 280?
O Seven hundred
O Seventy thousand
Seven hundred thousand
Seven thousand

Answers

Answer: seven hundred thousand

Answer:

The 7 represents the 10,000

Step-by-step explanation:

Its not the hundred because the 2 in 280 is

If 2^2x = 2^3, what is the value of x?

Answers

Answer:

x=2

Step-by-step explanation:

A man drove a total round trip distance of 646.25 miles. His car used 12 gallons of gas in one direction and 11.5 on the return trip. What was his average mileage for the entire trip?​

Answers

Answer: 27.5

Step-by-step explanation:

What is the distance between the points (6, 4) and (-3, 17)?
A) 22
B) √250
C) 125
D) √88

Answers

D IS THE CORRECT ANSWER

Hey luvs!

The endpoints of AB are A(1,4) and B(5,-1). What are the coordinates of the point that divides AB in the ratio
2:3?

Answers

Answer:

I don't know I'm sorry.............

Multiply 4/5 by 10 ​, and then multiply that product by 17 .

Answers

Answer:

your answer is 406.

Step-by-step explanation:

4/5 x 10 will equal to 8. 8 times 17 equals 406.

An architect is creating a scale drawing of a school computer lab. The length of the lab is 32 feet and the width of the lab is 48 feet. If each 16 feet of the lab equals 2 centimeters on a scale drawing, which of the following drawings is the scale drawing of the computer lab?

Answers

Answer:

The answer is B

Step-by-step explanation:

Length:

32ft. / 16ft. = 2

2 x 2cm. = 4 cm.

Width:

48ft. / 16ft. = 3

3 x 2cm. = 6cm

Answer:

b

Step-by-step explanation:

what is the distance between the first integer that is less than square root 40 amd the first integer that is greater than square root of 125?​

Answers

Answer:

6

Step-by-step explanation:

[tex]\sqrt{40} = 6.32 so 6 \\\sqrt{125} = 11.18 so 12\\12 - 6 = 6[/tex]

LINK=REPORT

(4^2)^3=

A. 4^5
B. 4^6
C. 8^5
D. 16^5


(5^2)(5^3)=

A. 5^5
B. 5^6
C. 10^5
D. 25^5


(3^4)(3^5)=

A. 3^9
B. 9^9
C. 3^20
D. 6^20


Which is equivalent to 2^3•2^-5?

A. 2^-15
B. 2^-8
C. 2^-2
D. 2^2

If you answer all four of them and they are right I will give brainliest!

Answers

Answer:

a) 4^6

b) 5^5

c)3^9

d)2^-2

Step-by-step explanation:

When raising a number to a power and then to another power, you can multiply the exponents.

When multiplying numbers with the same base to different exponents, you can add the exponents.

question number nine answer

Answers

Answer:9

Step-by-step explanation:

Answer:

I think it's either A or D

100 POINTS!!!!!! HELP
Question 23
Max and Jay are among 12 contestants in the school spelling bee. If the top two finishers win prizes, what is the probability both Max and Jay will be the two prize winners?
A
1766
B
136
C
166
D
1132

Answers

A - 1766! I hope this helps

Write the word sentence as an inequality.

Three times a number h is at least -12 .

Answers

Answer:

Step-by-step explanation:

3h<-12

Answer:

3h [tex]\geq[/tex] -12

Step-by-step explanation:

"3 multiplied by a number h" = 3h // "Is at least" = [tex]\geq[/tex] // -12 = -12

Combine these and you get 3h [tex]\geq[/tex] -12

Omg please help this is IMPORTANT

Answers

Answer:

first one is correct and second also but in third it is incorrect and fourth is correct so C is incorrect

Answer:

C

Step-by-step explanation:

the quotient of a number means n divided by or n/

and twelve plus four, means that is the second part of the expression

n/ 12+4 would be correct instead of 12/n +4

I need help answering this question please help

Answers

40

Or at least that what my calculator says.

24. Identify the center and radius of the circle given the equation (x +15)2 + (7 - 9)2 = 25 .
a. Center: (-15, 9), Radius: 5
b. Center: (15, -9), Radius: 25
c. Center: (-15, -9) Radius: 5
d. Center: (15,9) Radius: 25

Answers

Answer:

a. Center: (-15, 9), Radius: 5

Step-by-step explanation:

Equation of a circle:

The equation of a circle of center [tex](x_0, y_0)[/tex] and radius r is given by:

[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]

In this question, we have that:

[tex](x + 15)^2 + (y - 9)^2 = 25[/tex]

Comparing both equations:

[tex]x - x_0 = x + 15[/tex]

[tex]x_0 = -15[/tex]

And

[tex]y - y_0 = y - 9[/tex]

[tex]y_0 = 9[/tex]

The center is [tex](-15,9)[/tex].

For the radius:

[tex]r^2 = 25[/tex]

[tex]r = \sqrt{25} = 5[/tex]

The correct answer is given by option a.

Find the surface area of the following figures.

with solution please. T-T​

Answers

Answer:

I will do 1 2 3 and 5 for you:

Since a cube has a given length of 5, we know that all sides will be the same therefore your lengths will be the same.

There are 6 sides of a cube so,

5 x 5 = 25 area of one flat surface.

Now 25(an area of one flat surface) x 6(flat surfaces) = 150 cm for question 1

We need to find area of the two circles:

3(given radius)^2(radius being squared) x 3.14(pi)

3 x 3 = 9

9(after radius being squared) x 3.14(pi) = 28.26(area of one circle)

28.26 x 2 = 56.52 (area of 2 circles)

Now we need to find the round surface, but first we need to find circumference:

2 x 3.14 x 3 = 18.84

18.84(circumference) x 5(height) = 94.2 (area of round surface)

Now lets add all the given areas to find surface area:

56.52 + 94.2 = 150.72 cm^2 is your answer for question 2

2 x 4 = 8

8 x 2 = 16

4 x 5 = 20

20 x 2 = 40

2 x 5 = 10

10 x 2 = 20

Add all given areas:

16 + 40 + 20 = 76 cm^2 is your answer for question 3

452.16 cm^2

4 x 3.14 x 6^2

4 x 3.14 x 36 = 452.16 cm^2 is your answer for question 4

8 x 4 = 32, 32 divided by 2 = 16

since there are 4 sides,

4 x 16 = 64

Don't forget the bottom!

4x 4 = 16

Lets add the given areas:

64 + 16 = 80 for question 5

no links Pwease help this is very important I will give you brain thing if its correct ♡

Answers

Answer:

B, C

Step-by-step explanation:

i’m so confused.. a little help?

Answers

Answer:

Triangle has a greater perimeter.  

Step-by-step explanation:

Triangle perimeter = 21cm

Add the sides.

Square perimeter = 16cm

Add the sides (since it's a square the sides are the same.)

What is the volume of a cube that has a side of 4 units?

Answers

Answer: 64units³

Step-by-step explanation:

The volume of a cube will be gotten by multiplying the value of its side thrice. This means that for example if the cube has a side of xcm, the volume will be:

= x × x × x

= x³

In this case, since the cube has a side of 4 units, the volume will be:

Volume of cube = 4³

Volume of cube = 4 × 4 × 4 = 64unit³

Explain how you use a net to find the surface area of a prism.​

Answers

Answer:

Hello, Here is your answer.

Finding the areas of each of the rectangles and squares of the net of a rectangular prism and adding up those areas gives the surface area or total surface area of the prism. For example, if the length of one side of the cube 4 units then the area of one its face is 4 × 4 = 16 square units.

Answer:

Step-by-step explanation:

By drawing a net, you can see each face of the prism. You can find the areas of each face and then add them together to find the total surface area.

Given LP, LM = (3x + 1), MN = (4x –3), NP = (6x – 5), and LM =NP.
M
AN
What is the length of MP?

Answers

Answer:

[tex]MP = 12[/tex]

Step-by-step explanation:

Given

[tex]LM = (3x + 1), MN = (4x -3), NP = (6x - 5)[/tex]

[tex]LM = NP[/tex]

Required

Find MP

We have:

[tex]LM = NP[/tex]

This gives:

[tex]3x + 1 = 6x - 5[/tex]

Collect like terms

[tex]3x - 6x = -1-5[/tex]

[tex]-3x = -6[/tex]

Solve for x

[tex]x = 2[/tex]

MP is calculated as:

[tex]MP = MN + NP[/tex]

[tex]MP = 4x - 3 + 6x - 5[/tex]

Collect like terms

[tex]MP = 4x + 6x - 3 - 5[/tex]

[tex]MP = 10x - 8[/tex]

Substitute [tex]x=2[/tex]

[tex]MP = 10*2 - 8[/tex]

[tex]MP = 20 - 8[/tex]

[tex]MP = 12[/tex]

Two parallel lines cut by a transversal are shown. What is the value of X, in degrees?

Answers

9514 1404 393

Answer:

  x = 15°

Step-by-step explanation:

Same-side interior angles are supplementary.

  (4x° +12°) + 108° = 180°

  4x° = 60° . . . . . . . . . . . . . . subtract 120°

  x = 15° . . . . . . . . . . . . divide by 4

A circle has a radius of 4 inches. What is
the circumference?
A.25.12 inches
B.12.56 inches

Answers

Answer:

4 x 3.14 x 2 = 25.12 inches

Step-by-step explanation:

Formula of circumference:

3.14(pi) x 2(the number is just always there when finding circumference) x radius(half of your diameter or just your given radius).

The triangle shown below has an area of 20 units squared. Find the missing side if the height is 8

Answers

Answer:

5 units

Step-by-step explanation:

Lets keep the missing side as x

And we also know that the area of Triangle is,

[tex] \frac{1}{2} bh[/tex]

So taking this into consideration we can write a linear equation like this,

[tex] \frac{1}{2} bh = 20[/tex]

Where height is 8,

[tex] \frac{1}{2} \times b \times 8 = 20 \\ 4 \times b = 20 \\ b = \frac{20}{4} \\ b = 5[/tex]

So therefore the missing side is 5

5 because the formula for a triangle is (l w) divide by two and you get the area so when you do the formula backwards you get 5

Determine the decision criterion for rejecting the null hypothesis in the given hypothesis​ test; i.e., describe the values of the test statistic that would result in rejection of the null hypothesis. We wish to compare the means of two populations using paired observations. Suppose that d​3.125, ​2.911, and n​8, and that you wish to test the hypothesis below at the​ 10% level of significance. What decision rule would you​ use? ​: 0 against ​: 0

Answers

Answer:

Decision Rule

The critical region for one tailed test with 7 d.f is t > 1.415 for

H0 : ud ≤ 0 against the claim Ha: ud > 0

Step-by-step explanation:

The data given is

Population mean = ud= 0

Sample difference mean = d`= 3.125

Sample difference standard deviation = sd= 2.911

Sample size= n= 8

Formulate the null and alternate hypotheses as

H0 : ud ≤ 0 against the claim Ha: ud>0

The significance level ∝= 0.1

The degrees of freedom = n-1 = 8-1 = 7

The critical region for one tailed test with 7 d.f is t > 1.415

The test statistic is

t= d`- ud/ sd/ √n

Putting the values

t= 3.125-0 / 2.911/√8

t= 3.125/1.0292

t= 3.036

since the calculated value of t falls in the critical region we reject the null hypothesis .

The number of red tiles in a sack is 5 more than 3 times the number of green tiles in the sack. The
sack contains 35 red tiles, How many green tiles does the sack contain?
Pls help I need this pls help have a good day

A.12
B.10
C.9
D.not here

Answers

Answer:

B. 10

Step-by-step explanation:

10 x 3 = 30+5 = 35

Can someone help! This is due right now and I'm a little confused! Thank you!

Answers

Answer:

a) 10 cucumbers

b) two fifth x, or 2/5x

c) 15 vegetables

What does area mean? When you are asked to find the
area what are you doing?

Answers

Answer:

you want to muliply the length and width to find area.

Step-by-step explanation:

HELP ME PLEASEEEEEEEEEEEEEEEEEEE

Answers

Answer:

The second answer choice

Step-by-step explanation:

The pyramid shown is a triangular pyramid. A triangular pyramid consist of 4 faces; 1 triangular base and 3 triangular lateral faces.

Hence, the correct answer would be the second choice.

I need help with the solutions for 19,20,21 thank you

Answers

Answer:

GIVEN :-

Coordinates of points are :-

(-5 , 12)(2 , 8)(3 , -6)

TO FIND :-

All the trigonometric values of given points

FACTS TO KNOW BEFORE SOLVING :-

It's important to know that :-

In 1st quadrant (0° to 90°) , all the trigonometric values are positive .In 2nd quadrant (90° to 180°) , except sin & cosec , rest all trigonometric values are negative.In 3rd quadrant (180° to 270°) , except tan & cot , rest all trigonometric values are negative.In 4th quadrant (270° to 360°) , except cos & sec , rest all all trigonometric values are negative.

SOLUTION :-

Q1)

Plot (-5,12) on the cartesian plane and name it 'A'Drop a perpendicular to x-axis from 'A' and name the point 'B' where the perpendicular meets x-axis.Join the point A with the origin 'O'.

You'll notice a right-angled ΔABO formed (∠B = 90°) in the 2nd quadrant of the plane whose :-

length of perpendicular of triangle (AB) = 12 unitslength of base of triangle (OB) = 5 unitslength of hypotenuse (OA) = 13 units

Let the angle between OA & positive x-axis be θ.

⇒ ∠AOB = 180 - θ

So ,

[tex]\sin (AOB) = \sin(180 - \theta) = \sin \theta = \frac{12}{13}[/tex][tex]\cos(AOB) = \cos (180 - \theta) = -\cos \theta = -\frac{5}{13}[/tex][tex]\tan(AOB) = \tan(180 - \theta) = -tan \theta = -\frac{12}{5}[/tex][tex]\csc(AOB) = \csc(180 - \theta) = \csc \theta = \frac{1}{\sin \theta} = \frac{13}{12}[/tex][tex]\sec(AOB) = \sec(180 - \theta) = -\sec \theta = -\frac{1}{\cos \theta} = -\frac{13}{5}[/tex][tex]\cot(AOB) = \cot(180 - \theta) = -\cot \theta = -\frac{1}{\tan \theta} = -\frac{5}{12}[/tex]

Q2)

Plot (2,8) on the cartesian plane and name it 'A'Drop a perpendicular to x-axis from 'A' and name the point 'B' where the perpendicular meets x-axis.Join the point A with the origin 'O'.

You'll notice a right-angled ΔABO formed (∠B = 90°) in the 1st quadrant of the plane whose :-

length of perpendicular of triangle (AB) = 8 unitslength of base of triangle (OB) = 2 unitslength of hypotenuse (OA) = 2√17 units

Let the angle between OA & positive x-axis be θ.

⇒ ∠AOB = θ

So ,

[tex]\sin(AOB) = \sin \theta = \frac{8}{2\sqrt{17} } = \frac{4}{\sqrt{17} }[/tex][tex]\cos(AOB) = \cos \theta = \frac{2}{2\sqrt{17}} = \frac{1}{\sqrt{17}}[/tex][tex]\tan(AOB) = \tan \theta = \frac{8}{2} = 4[/tex][tex]\csc(AOB) = \csc \theta = \frac{1}{\sin \theta} = \frac{\sqrt{17}}{4}[/tex][tex]\sec(AOB) = \sec \theta = \frac{1}{\cos \theta} = \sqrt{17}[/tex][tex]\cot (AOB) = \cot \theta = \frac{1}{\tan \theta} = \frac{1}{4}[/tex]

Q3)

Plot (3,-6) on the cartesian plane and name it 'A'Drop a perpendicular to x-axis from 'A' and name the point 'B' where the perpendicular meets x-axis.Join the point A with the origin 'O'.

You'll notice a right-angled ΔABO formed (∠B = 90°) in the 4th quadrant of the plane whose :-

length of perpendicular of triangle (AB) = 6 unitslength of base of triangle (OB) = 3 unitslength of hypotenuse (OA) = 3√5 units

Let the angle between OA & positive x-axis be θ . [Assume it in counterclockwise direction].

⇒ ∠AOB = 360 - θ

So ,

[tex]\sin(AOB) = \sin(360 -\theta) = -\sin \theta = -\frac{6}{3\sqrt{5} } = -\frac{2}{\sqrt{5} }[/tex][tex]\cos(AOB) = \cos(360 - \theta) = \cos \theta = \frac{3}{3\sqrt{5} } = \frac{1}{\sqrt{5} }[/tex][tex]\tan(AOB) = \tan(360 - \theta) = -tan \theta = -\frac{6}{3} = -2[/tex][tex]\csc(AOB) = \csc(360 - \theta) = -\csc \theta = -\frac{1}{\sin \theta} = -\frac{\sqrt{5} }{2}[/tex][tex]\sec(AOB) =\sec (360 - \theta) = \sec \theta = \frac{1}{\cos \theta} = \sqrt{5}[/tex][tex]\cot(AOB) = \cot(360 - \theta) = -\cot \theta = -\frac{1}{\tan \theta} = -\frac{1}{2}[/tex]
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