The polygons are similar. Find the value of x

Complete Question

Luke has a cylinder with a radius of 5 inches and a height of 6 inches. What is the volume of his cylinder in cubic inches?

Answer:

471.24 cubic inches

Step-by-step explanation:

The formula for the volume of a cylinder =

πr²h

r = Radius = 5 in

h = Height = 6 in

Hence,

Volume = π × (5 in)² × 6 in

= 471.24 cubic inches

Therefore, the volume of his cylinder in cubic inches = 471.24 cubic inches

Answer:

Decreased I think because they bumped into the other person

Step-by-step explanation:

Answer:

increased

 i just heard my brother say it because he's in highschool. TwT

Answer:

Yes because you would need to divide first before subtracting

Step-by-step explanation:

Answer:

yes, because of PEMDAS

divison always comes before subtraction

Respuesta: 3/2= 1 1/2

Answer:

1 1/2 or 1.5

Step-by-step explanation:

To divide a fraction, use the phrase, "keep, change, flip"

We keep the first fraction as it is, change the sign to multiplication, and flip the second fraction to its multiplicative inverse.

So 3/4 divided by 1/2 becomes:

3/4 x 2/1

= 6/4 = 1 1/2

24...

8x3=24

6x4=24

Thats the soonest theyll play together.

Answer:

-6/7 -rational and real

3120- natural, whole,integers, rational,real

5.123456...- rational and real

√2- real

0 - whole, integers, rational real

Answer:

24

Step-by-step explanation:

Answer: Equals 24! Have a great day!

Answer:

c

Step-by-step explanation:

Answer:I think the answer is x=27

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

its undefined because 3/0.

Answer:

1) g < -6

2) x < -5

3) f < 2

4) y ≤ -2

5) p ≥ 2

Answer:

1) N^2 + 1

2) 5*N - 9

3) n*5 + 1    (con n entero)

4) n*2 + 1    (con n entero)

Step-by-step explanation:

1)  El cuadrado de un número aumentado en 1.

Podemos definir a N como el número.

El cuadrado de N es:

N^2

Y a esto lo tenemos que aumentar en 1, entonces tenemos:

N^2 + 1

Esto es el cuadrado de un número aumentado en 1.

2)  Cinco veces un número menos 8.

Esto es:

5*N  (5 veces un número)

Y a esto le restamos 8, para obtener:

5*N - 8

3) El número siguiente a un múltiplo de 5

Un multiplo de 5 se escribe como:

n*5

Donde n es un número entero.

El numero siguiente es:

n*5 + 1

4) Un número impar.

Bien, sabemos que un número par es un multiplo de 2.

Entonces:

n*2 es un número par.

Entonces, n*2 + 1 tiene que ser un numero impar.

En este caso la expresión algebraica es:

n*2 + 1

Answer:

164

Step-by-step explanation:

Answer:

Step-by-step explanation:

hello :

27 ×32 = 3x×2y

means : 27 ×32 = 6xy

xy= (27 ×32)/6

xy = 144

but : 144 =12² = (4×3)²=(2²×3)²

144=2^4 ×3²

so : xy = 2^4 ×3²

if  x and y the integere numbers so x and y are the divisors of 144

1  , 144,  2 ,72 , 4 , 36 , 8  18 , 3 , 48  , 6  , 24 , 9 , 16 , 12

Answer:

B) 24

Step-by-step explanation:

This angle adds to 90 degrees, so to solve for x you need this equation:

(2x) + 42 = 90

Subtract 42 from both sides to get:

2x = 48

Divide 2 from both sides to get:

x = 24

Hope it helps!!!

Answer:

-7

Step-by-step explanation:

Answer:

-7

Step-by-step explanation:

Answer:

23°

Step-by-step explanation:

For this scenario say point G is the center point,

If we look to the left, we see angle FGE has a value of 23

and in this case angle CGD is a congruent angle to FGE therefore the two angles must be the same

so therefore angle CGD should be 23 degrees

Answer:

-Entire triangle region : 120 sq.cm

-Area of semi circle : 100.53 sq.cm

-Entire composite figure : 220.53 sq.cm

Step-by-step explanation:

Area of triangle = ½ × base × height

= ½ × (8+8) × 15

=½ × 16 × 15

= 120 sq.cm

[tex]area \: of \: semi \: circle = \frac{1}{2} \pi {r}^{2} \\ = \frac{1}{2} \times \pi \times {8}^{2} \\ = \frac{1}{2} \times \pi \times 64 \\ = 32\pi[/tex]

=100.530.......

=100.53 sq.cm (rounded to 2 decimal place)

Area of entire figure = 120 + 100.5353

= 220.53 sq.cm

Hope I could help:))

Answer:

Step-by-step explanation:

Lin’s method

- multiply both x and 2 by  7

7x+14 = 91

- add -14 at both members

7x+14-14 = 91-14

7x = 77

- divide the two members by 7

x = 11

Noah’s method

- divide the two members by 7

x+2 = 13

- add -2 at both members

x+2-2 = 13-2

x = 11

Answer:

The solution is x=11

Step-by-step explanation:

The original equation is

7(x+2)=91

Lin uses the distributive property, which states that

a (x+y) = ax + ay

By applying the property to this case,

7(x+2)=91

7x+14=91

Then we subtract  14 on both sides:

7x+14 - 14 = 91-14

7x=77

Finally, we divide by 7 on both sides:

7x÷7 = 77÷7

x=11

Noah starts by dividing each side by 7, so he gets:

7(x+2)÷7 = 91÷7

x+2= 13

Then he can subtract +2 from both sides:

x+2-2 =13 - 2

x=11

So, they get the same result. The similarity between the two methods is that  they both divide by 7, while the difference is that Lin has to subtract 14, while Noah has to subtract 2.

Answer:

hi

Step-by-step explanation:

i think so...

[tex] \sqrt{30} = 5.47[/tex]

have a nice day

Can you make a different question with an image attached?

[tex] \huge \colorbox{yellow}{Question}[/tex]

[tex]2x + y = 12[/tex]

[tex] \huge \colorbox{yellow}{Answer}[/tex]

[tex]x = y - 3 \: (equation \: 1)[/tex]

[tex]2x + y = 12 \: (equation \: 2)[/tex]

Substituting the value of x in

( equation 2)

[tex]2x + y = 12[/tex]

[tex]2(y - 3) + y = 12[/tex]

[tex]2y - 6 + y = 12[/tex]

[tex]2y + y = 12 + 6[/tex]

[tex]3y = 18[/tex]

[tex]y = 18 \div 3[/tex]

[tex]y = 6[/tex]

Now we get y = 6

Substituting the value of y in

( equation 1 )

[tex]x = y - 3[/tex]

[tex]x = 6 - 3[/tex]

[tex]x = 3[/tex]

Now we get x = 3

[tex] \huge \mathsf\red{Final \: Answer}[/tex]

Answer:

y = -1/2 x + 25

The relationship is linear, but it takes some doing.

Step-by-step explanation:

Remark

This is a very interesting problem. I've never seen one quite like it. There is probably a much better way of solving it, but I did not discover it.  

You have to introduce another variable which I labeled as z.

Let time = x

Let distance = y

Let the step away from the starting point = z   which will be the same for x and y. So 18 and 16 the step away from the start is 3.

So as the time increases, the distance decreases.  What we are going to do sort of resembles a parametric relationship.

t starts with 10

x = 10 + 4*(z - 1)   and increases by 4 with each step

d starts with 20 and decreases by 2 with each step

y = 20 - (z - 1)*2

Now solve for z in each of the forgoing equations.

x = 10 + 4z - 4

x = 6 + 4z

x - 6 = 4z

(x - 6)/4 = z

y = 20 - 2z + 2

y = 22 - 2z

y - 22 = - 2z

(y - 22)/-2 = z                    

Since the zs must be kept the same, the left sides are equated

(x - 6)/4 = (y - 22)/-2               Cross multiply

-2(x - 6) = 4(y - 22)                 Remove the brackets.

-2x + 12 = 4y - 88                   add 88 to both sides.

-2x + 100 = 4y                        Switch the sides

4y = - 2x + 100                       Divide by 4

y = -1/2 x  + 25

Now for sure you have to try this.

Let x = 14

y = -1/2 * 14 + 25

y = -7 + 25

y =  18

Try another one

Let x = 22

y = -1/2 * 22 + 25

y = - 11 + 25

y = 14

Those two at least check.