The part of the moon that is visible will appear to grow and shrink during the lunar cycle. This occurs in the direction of _____ to _____.

Answers

Answer 1

Answer:

left to right

Explanation:

give me brain pls

Answer 2

Answer:

of the moon to .......


Related Questions

Which of the following is NOT a function of the lens in the eye?
It can perform minor adjustments for distance.
It flattens when light rays from distant objects are to be focused.
It is a light receptor that generates nerve signals that are sent to the brain.
It maintains its spherical shape to view nearby objects.

Answers

Answer:

it is a light receptor that generates nerve signals that are sent to the brain

Explanation:

the lens are like the glasses, this means that is used to see things better. You just put them in your eye and that's all it's not connected to the brain

Answer:

c

Explanation:

A converging-diverging nozzle has a throat area of 10 cm2 and an exit area of 28.96 cm2 . A normal shock stands in the exit when the back pressure is sea-level standard. If the upstream tank temperature is 400 K, estimate (a) the tank pressure and (b) the mass fl ow

Answers

The tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.

The given parameters:

Throat area of the nozzle, [tex]A^*[/tex] = 10 cm² = 0.001 m²The exit area of the nozzle, A = 28.96 cm² = 0.002896 m²Air pressure at sea level = 101.325 kPa

The ratio of the areas of the converging-diverging nozzle is calculated as follows;

[tex]= \frac{A}{A^*} \\\\= \frac{0.002896}{0.001} \\\\= 2.896[/tex]

From supersonic isentropic table, at [tex]\frac{A}{A^*} = 2.896[/tex], we can determine the following;

[tex]M_e = 2.6 \ kg/s\\\\\frac{P_o}{P_e} = 19.954[/tex]

The tank pressure is calculated as follows;

[tex]\frac{P_o}{P_e} = 19.954 \\\\P_e = \frac{P_o}{19.954} \\\\P_e = \frac{101.325 \ kPa}{19.954} \\\\P_e = 5.08 \ kPa[/tex]

Thus, the tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.

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A physics professor leaves her house and walk along the sidewalk toward campus. After 5 min it starts to rain and she returns home. Her distance from her house as a function of time shown in figure: 1. At which of the labelled point is her velocity (a) zero? (b) Constant and positive? (c) constant and negative ? (d) Increasing in magnitude? (e) Decreasing in magnitude?

Answers

Answer: I think its zero-

I dont really know about this...

help me i have little time left i will give brainliest

Answers

Answer:

Explanation:

Conservation of momentum

Initial momentum is zero

3.0(6.0) + 7.0v = 0

v = -18/7 = - 2.57142857...

|v| = 2.6 m/s

Two rods of mass m, length L are stuck together to form an X shape and spun around the center. What is the rotational inertia

Answers

The shapes of XLMA ain’t digestive monkeys monkeys have a digestive system of a hippopotamus Mr. hippopotamus want to eat I am yams or sweet potatoes they are potatoes are sweeter than the normal potato

a car moving at 5 m/s accelerates at a rate of 10 m/s2 for 25 seconds. How far does it move during this time?

Answers

Answer:

t is time in s For example, a car accelerates in 5 s from 25 m/s to 3 5m/s. Its velocity changes by 35 - 25 = 10 m/s. Therefore its acceleration is 10 ÷ 5 = 2 m/s2

Explanation:

Lisa runs up 4 flights of stairs in 22 seconds. She weighs 510 Newtons. If each flight rises 310 cm: (a) What is her change in potential energy? (b) What average power (watts) was required during the 22 s?

Answers

The change in potential energy is 6324 Joules while the power is 263.5 Watts.

Potential energy is the amount of energy possessed by a body due to its position relative to another object.

a) Potential energy = weight * height = 510 N * 4 flight * 3.1 m per flight

Potential energy = 6324 Joules

b) Power = Energy / time = 6324 Joules / 22 seconds = 263.5 Watts

The change in potential energy is 6324 Joules while the power is 263.5 Watts.

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Consider the following force:
A horse is pulling forward on a wagon with a force of 200 N.
According to Newton's third law, what other force must be happening?
The horse is pushing backward on the wagon with a force of 200 N.
The ground is pushing backward on the horse with a force of 200 N.
The wagon is pulling backward on the horse with a force of 200 N.

Answers

Option C

Newton’s third law states that when two objects interact, they will exert an equal and opposite force on each other

So if the horse pulls the wagon, the wagon will also pull the horse

A small ball with a mass of 0.6 kg and a velocity of 12 m/s hits another ball with the same mass. The firs forward and hits a third ball with a mass of 0.2 kg. If the system is closed, what is the velocity of the third ball?

4 m/s

36 m/s

30 m/s

1.44 m/s​

Answers

I think is 30m/s I am not sure

Who actually asked Abraham to sacrifice his son?

Answers

I think god did ??? I searched it up okay

God asked him to scarface his sons life

the driver of a 2.0 × 10³ kg red car traveling on the highway at 45m/s slams on his brakes to avoid striking a second yellow car in front of him, which had come to of because locking ahead.After the brakes are applied a constant friction force of 7.5 × 10³ N acts on the car ignore air resistance.

a₎ Determine the least distance should the brakes be applied to avoid a collision with the other vehicle?

Answers

Answer:

Explanation:

a = F/m = 7500/2000 = 3.75 m/s²

v² = u² + 2as

s = (v² - u²) / 2a

s = (0² - 45²) / (2(-3.75))

s = 270 m

a spring with a spring constant of 65 n/m is displaced -94cm. what is the magnitude of the force exerted by the spring

Answers

Answer:

Explanation:

F = kx = 65 N/m(0.94 m) = 61.1 = 61 N

In this image F1 is equal to 100 N and F2 is equal to 50 N. What is the net force?

Answers

Answer:

net force would be 50 N right

Explanation:

Ginny is snowboarding down a ski slope. Her total mass (including the snowboard) is 68.5 kg. When she reaches the bottom of the slope, she is moving at 6.55 m/s. The coefficient of friction between the snowboard and the ground is 0.088 . How fast will Ginny be moving 2 seconds after reaching the bottom of the slope?
1) 5.71 m/s
2)5.91 m/s
3)4.82 m/s
4)4.08 m/s

Answers

Answer:

Explanation:

Assuming the run out at the bottom of the slope is horizontal

μ = Ff/N = Ff/mg

Ff = μmg

a = Ff/m = μmg/m = μg

v = u + at

v = u + μgt

v = 6.55 - 0.088(9.81)(2)

v = 4.82 m/s

After reaching the bottom of the slope, it will take a speed of 4.8m/s to reach. So, the correct option is (C).

What is Friction?

Friction is the force which opposes the relative motion of solid surfaces, fluid layers, and material elements that are sliding against each other. There are many types of friction like

Dry frictionFluid frictionLubricated friction Skin friction Internal friction

Friction can be expressed as

Ff = μFN

where, Ff is the force of friction (N)

μ is the coefficient of friction.

FN is the normal force

As per the above equation, it is actually the normal force, not the weight, which is responsible for friction.

For given information,

Assuming the bottom of the slope is horizontal

So, μ = Ff/N = Ff/mg

Ff = μmg

a = Ff/m = μmg/m = μg

v = u + at (u- initial speed, v= final speed, a= acceleration and t= time)

v = u + μgt (g= acceleration due to gravity)

u = 6.55 - 0.088(9.81)(2)

u = 4.82 m/s

Thus, after reaching the bottom of the slope, it will take a speed of 4.8m/s to reach. So, the correct option is (C).

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) Water flows through the system shown below. Estimate the volumetric flow rate if friction
losses are negligible.

Answers

The volumetric flow rate if friction is negligible = 0.00197 m³/sec

Given data :

P₁ = 7 atm  =  709.275 kPa

P₂ = 1.5 atm = 151.988 kPa

d₁  = 0.74 cm = 0.0074 m

d₂ = 1.20 cm  = 0.0120 m

h = 82 m

density of water ( p ) = 1000 kJ/m³

Estimate the volumetric flow rate

given that friction losses are negligible

V₁² - V₂² = [tex]\frac{2(P_{2} - P_{1}) }{p} + 2g(h )[/tex]

             = 2( 151.988 - 709.275 )  + 2 * 9.81 * 82

             = 2 ( - 557.287 ) + 1608.84

             = - 1114.574 + 1608.84  =  494.266

V₁² - V₂² =  494.266 ----- ( 1 )

Also given that:

volumetric flow rate ( Q ) = A₁V₁ = A₂V₂

                                          = π / 4 ( 0.0074 )² * V₁   =   π / 4 ( 0.0120 )² * V₂

                                          = 0.000043 V₁ = 0.000113 V₂

∴ V₁ = 2.63 V₂

Back to equation ( 1 )

( 2.63 v₂ )² - V₂² = 494.266

V₂² = ( 494.266 ) / 1.63

∴ V₂ = √303.23 = 17.41  m/sec

Therefore the volumetric flow rate ( Q )

Q = A₂V₂

   =  π / 4  * ( 0.0120 )² * 17.41

   = 0.00197 m³/sec

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1. A 10 kg rocket blast off the ground with an applied force of 150 N, calculate the net force
of your rocket

Answers

The net force on the rocket at the given applied force is 52 N.

The given parameters:

Mass of the rocket, m = 10 kgApplied force, F = 150 N

The net force on the rocket is calculated by applying Newton's second law of motion as follows;

F(net) = F(up) - F(down)

F(net) = 150 - mg

F(net)  = 150 - (10 x 9.8)

F(net) = 150 - 98

F(net) = 52 N

Thus, the net force on the rocket at the given applied force is 52 N.

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Which phrase describes the energy transformation that happens in a
generator?
A. Electrical energy into chemical energy
ООО
B. Electrical energy into mechanical energy
C. Chemical energy into electrical energy
O
D. Mechanical energy into electrical energy
SI

Answers

Answer:

Mechanical energy into electrical energy

Explanation:

Answer:

ExplanMechanical energy into electrical energy

SIation:

13. In which of the following climates does chemical weathering generally occur most
rapidly?
A. Canda
B. Greenland
C. Brazil
D. Algeria

Answers

Brazil would be the correct answer I believe

A first order reaction is 25% completed in 1h minutes. Calculate the time required for its 50% completion.

Answers

It would be 2 hours I think

Water pumps use electrical energy to create mechanical energy needed to move water.
A 1875 W water pump is plugged into a 110 V electrical outlet.

Answers

Answer:

n/a

Explanation:

this question is not feasible

1. The acceleration equation of a certain particle is a=2t, after 4s, its velocity reaches 20m/s, then the initial velocity of the particle movement is ) ms B Sms 2.​

Answers

Answer:

Change in velocity is the integral of all the differential accelerations acting over the period of acceleration.

[tex]20 = u + \int\limits^4_0 {2t} \, dt[/tex]

20 = u + t²[tex]\left \{ {{4} \atop {0}} \right.[/tex]

20 = u + 4² - 0²

20 = u + 16

u = 4 m/s

How should an artistic statement be written?

ОА.

from your own perspective

OB.

in a non-factual, persuasive manner

O C.

as a lengthy and overly extensive essay

OD. by the artist alone with no outside critique

Answers

An artistic statement should be written from your own perspective.

What is an artistic statement ?

An artist's statement, also known as an artist statement, is a written summary of their creative output. The brief essay serves as an explanation of and a defense of their own work for the spectator. As a result, it is didactic, descriptive, or reflective in nature and seeks to inform, connect with an artistic environment, and reveal the inspiration behind the work.

The writing created by the artist aims to contextualize, justify, extend, and/or explain their body of work. It situates—or tries to situate—the piece in relation to art history, art theory, the contemporary art scene, and the times. The statement also demonstrates that the artist is aware of their aims, their practice, its place within the parameters of art, and the debate that surrounds it.

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Use words in the box to complete the diagram, and the definitions below it. Some words will be used
more than once and some words may not be used at all
Hertz
period
metros
dip
seconds
peak
wavelength trough
crest
frequency
amplitudo
oscillation equilibrium line
- the top of a wave
the bottom of a wave
the level if the wave flattened out
a repeated action back and forth or up and down
the number of waves that pass every second (measured in
the time it takes for one complete wave to pass (measured in

Answers

Answer:

There ya go

Explanation:

The correct words to fill the given blanks would be as follows:

- Peak

- Trough

- Equilibrium Line

- Oscillation

- Frequency, Hertz

- Period, seconds

The "peak" is denoted as the highest or maximum point that the wave attains while 'Trough' is characterized as the base of the wave. The 'equilibrium line' is characterized as the extent to which the wave flattens or compresses.Oscillation is defined as the process in which an object moves in the "back and forth motion."Frequency is the amount of occurrences that waves travel in a second which is denoted in the terms of Hertz.Lastly, period is the duration required by wave to accomplish one motion is denoted in terms of seconds.Amplitude is the breadth or magnitude of the waves.

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An electrician reads a resistance of 65 ohms and when energize the circuit runs 1.77 amps. what voltage to the system run on?

Answers

Answer:

115.05 Volts

Explanation:

We can use Ohm's Law!

V=IR

V= 1.77 * 65

V=115.05 Volts


You hang a light in front of your house using an
elaborate system to keep the 12-kg object in static
equilibrium (Figure 1). What are the magnitudes of the
forces that the ropes must exert on the knot connecting
the three ropes if 02 = 639 and 03 = 45° ?

Answers

The magnitudes of the forces that the ropes must exert on the knot connecting are :

F₁ = 118 N F₂ = 89.21 N F₃ = 57.28 N

Given data :

Mass ( M ) = 12 kg

∅₂ = 63°

∅₃ = 45°

Determine the magnitudes of the forces exerted by the ropes on the connecting knot

a) Force exerted by the first rope = weight of rope

∴  F₁ = mg

     = 12 * 9.81 ≈  118 kg

b) Force exerted by the second rope

applying equilibrium condition of force in the vertical direction

F₂ sin∅₂ + F₃ sin∅₃ - mg = 0  ---- ( 1 )

where: F₃ = ( F₂ cos∅₂ / cos∅₃ ) --- ( 2 )  applying equilibrium condition of force in the horizontal direction

Back to equation ( 1 )

F₂ =  [ ( mg / cos∅₂ ) / tan∅₂ + tan∅₃ ]

   = [ ( 118 / cos 63° ) / ( tan 63° + tan 45° ) ]

   = 89.21 N

C ) Force exerted by the third rope

Applying equation ( 2 )

F₃ = ( F₂ cos∅₂ / cos∅₃ )

    = ( 89.21 * cos 63 / cos 45 )

    = 57.28 N

Hence we can conclude that The magnitudes of the forces that the ropes must exert on the knot connecting are :

F₁ = 118 N, F₂ = 89.21 N, F₃ = 57.28 N

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how is the atomic mass determined?

Answers

Answer:

Atomic mass is defined as the number of protons and neutrons in an atom, where each proton and neutron has a mass of approximately 1 amu (1.0073 and 1.0087, respectively). The electrons within an atom are so miniscule compared to protons and neutrons that their mass is negligible.

Explanation:

Which is the independent variable in the graph of the U.S. population 1800-1900?

1. United States
2. straight lines
3. years
4. population

Answers

Answer:

3. years

Explanation:

The independent variable is the x axis of graph

Someone help me please !!!! Will mark Brianliest !!!!!!!!!!!!!!!!

Answers

The answer is the second one, because in exothermic reactions energy is released.

when a student comned his dry hair for a long time, his hair began to stand up. Which of these has MOST LIKELY happened

Answers

Answer :

His hair got charged due to continuous friction causing them to get attracted to other objects and thus standing up.

Answer:The comb and hair have become charged with opposite charges.

Explanation:When a comb is run through your hair charges pass between your hair and the comb, so the comb becomes charged either positively or negatively, and the hair oppositely charged. When the comb is brought close to paper an opposite charge is induced in the paper, and the opposite charges attract.

Ram jumps onto a cement floor from a height of 1m and comes to rest in 0.1sec.
Then he jumps onto a sand floor from a height of 9m and comes to rest in 1sec.
Find the ratio of forces of cement floor and sand floor.​

Answers

Answer:

3/10 F.

Explanation:

Height ( h ) = 1m

Time taken ( t ) = 0.1 second

Height² ( h² ) = 9m

Time taken² ( t² ) = 1 second

Solution,

F = ma

= m ( v - u ) / t

= m √2gh / t

now,

F/F² = √h/h² × t/t²

F¹ = 3/10 F.

answer !!

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