The parallelogram has the angle measures shown. Can you conclude that it is a rhombus, a
rectangle, or a square? Explain.

Answer:

Slope is -3/5

Slope intercept form: y<-3/5x+2

Step-by-step explanation:

Your going to have a shaded region, with a dashed line

the y intercept will be (2)

the x intercept will be (3.333,0)

51 Books

I think this is what you're looking for?

Answer:

What's this question? Oh my gosh!

Answer:

It is very difficult to know because you did not include the function g(x), you only gave us f(x).

Given two lists of ordered pairs [x,f(x)] and [x,g(x)]. If for every ordered pair on the f(x) list the reverse is on the g(x) list the functions are inverses.

f(0) = 5 so for (0,5) on the f(x) list then (5,0) must be on the g(x) list

f(1) = 7 so for (1,7) on the f(x) list then (7,1) must be on the g(x) list

f(2) = 9 so for (2,9) on the f(x) list then (9,2) must be on the g(x) list

So even though you didn’t list g(x), g(x) = (x/2) - 5/2

Well, we know that if we have an ordered pair of points (a,b) that satisfy a function y=f(x), then the inverse function will necessarily have a set of points (b,a).

We can choose any set of point that satisfy our first function f(x). x=3 => f(3)=11 so our set of points will be (3,11). Now if g(x) is and inverse function of f(x), when we calculate g(11) it should be equal to 3. Let's see:

g(11) = (11-5)/2 = 3. It works.

We have proven that f(x) and g(x) are the inverses of each other.

Answer:

gradient = 2

Step-by-step explanation:

Calculate the gradient (slope) m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (1, 0) and (x₂, y₂ ) = (6, 10) ← 2 points on the line

m = [tex]\frac{10-0}{6-1}[/tex] = [tex]\frac{10}{5}[/tex] = 2

Answer:

solution,                                                                                                                                     cp=Rs150                                                                                                                                        profit=Rs12                                                                                                                              Now,                                                                                                                                                   profit percent=profit% of cp                                                                                              or,profit percent=12/100 x Rs150                                                                                                Therefore,profit percent =18%

Step-by-step explanation:

Answer:

8%

Step-by-step explanation:

We know that

Profit% = Profit/CP × 100

=> 12/150 × 100

=> 12/15 × 10

=> 4/5 × 10

=> 8%

The two equations that can be used to find the height are as follows

12 / 4 = h  /5

5 / 4 = h  / 12

We have given that,

Amelia is 5 feet tall and casts a 4-foot shadow. A tree next to her casts a 12-foot shadow.

Similar triangles are not necessarily the same in size. Corresponding angles of similar triangles are congruent. The sides of a similar triangle are a ratio to each other.

The tree casts a shadow of 12 ft. Let's establish the proportion base on similar triangles. The height of the tree is h. Therefore,

h / 12 = 5 / 4

Therefore, h / 12 = 5 / 4

cross multiply

4h = 60

divide both sides by 4

h = 60 / 4

h = 15 ft

Therefore, the two equations that can be used to find the height are as follows

12 / 4 = h  /5

5 / 4 = h  / 12

To learn more about the triangle visit:

https://brainly.com/question/17335144

#SPJ1

Answer:

i am on ttm

Step-by-step explanation:

12/4=h/5

5/4=h/12

Answer:

$750

Step-by-step explanation:

did the problem

Answer:

$28.50

Step-by-step explanation:

21 ÷ 14 = 1.5

19 · 1.5 = 28.50

Hope this helps!!

The answer 120 MESSAGES

Answer:

y = x/2 + -3

Step-by-step explanation:

x - 2y = 6

Subtract x from both sides

-2y = -x + 6

Divide both sides by -2

y = x/2 + -3

Answer:

y = 1/2x - 3

Step-by-step explanation:

Subtract x both sides

-2y = 6 + (-x)

Divide -2 both sides

y = -3 + 1/2x

y = 1/2x - 3

Answer:

2

Step-by-step explanation:

i^2 = -1

i^4 = 1

i^20 repeats the cycle 5 times, making i^20 = 1

Answer:

the answer is D) i

Step-by-step explanation: i got it wrong to the bozo who said 1 and it says the answer is i

Answer:

Step-by-step explanation:

S = 2

T = -2

so in S - T = 4. 2 - -2 = 4

IN S + T = 2  S + - 2 = 2

Answer:

Step-by-step explanation:

Given polynomial:

Group as follows:

As we see all terms have (x² + 1) as factor apart from the last one.

It means the remainder is - x

Correct choice is C

Answer: Check out the diagram below for the filled out table

Equation is y = 1.5x

Box for row one = 330

Box for row two = 1000

Box for row three = 1.5

===========================================================

Explanation

The point (x,y) = (200,300) is on the blue diagonal line. It indicates that x = 200 grams of fish have y = 300 calories. Divide the two values to get the slope

slope = y/x = 300/200 = 1.5

This trick only works because the line is going through the origin. Otherwise, we'd have to use the slope formula.

The slope of 1.5 is the constant of proportionality. It tells us the equation is y = 1.5x. Whatever x is, multiply by 1.5 to get y.

So if x = 220, then y = 1.5x = 1.5*220 = 330

220 grams of fish have 330 calories. We'll write 330 in the box of the first row of the table.

-----------------

We can use this idea in reverse. If we know the calorie count (y), then we can divide by 1.5 to get the number of grams (x).

y = 1.5x

1500 = 1.5x

1.5x = 1500

x = 1500/(1.5)

x = 1000

Therefore, 1000 grams of fish have 1500 calories. We'll write 1000 in the box of the second row.

------------------

The third row of the table is going to follow the same steps as the first row.

y = 1.5x

y = 1.5*1

y = 1.5

One gram of fish produces 1.5 calories

The filled out table is shown below. I've merged the two screenshots you posted into one image, and filled out the boxes.

Answer:

5

Step-by-step explanation:

Answer:

1200 I THINK

Step-by-step explanation:

Answer :-

Step by step explanation :-

Here,

The intrest payable on 100$ for 1 year = 12 $

The interest payable on 10,000$ borrowed for 1 year

so, at the eand of the year , he has to give an amount of $ ( 10,000 + 1200 )

m∠C = 31

m∠D = 83

M∠E = 66

Hope this is helpful!

-8.1

Step-by-step explanation:

[tex] \frac{ - 4}{9} x + 2.4 = 6[/tex]

Times all by 9 to get rid of fraction

[tex] - 4x + 21.6 = 54[/tex]

Take 21.6 away from both sides

[tex] - 4x = 32.4[/tex]

Divide by -4

[tex]x = - 8.1[/tex]

Answer: -8 1/10

Step-by-step explanation:

Answer:

5/8 * 100 = 62.5 %

Answer:

Step-by-step explanation:

Given:

x1 = -1

x2 = 6

y1 = 2

y2 = 3

Solution:

m = ( y2 - y1 ) / ( x2 - x1 )

m = ( 3 - 2 ) / ( 6 - -1 )

m = 1 / ( 6 + 1 )

m = 1/7

Then,

y - y1 = m ( x - x1 )

y - 2 = 1/7 ( x - -1)

y - 2 = 1/7 ( x + 1 )

y - 2 = 1/7x + 1/7

y = 1/7x + 1/7 + 2

y = 1/7x + 15/7

Answer:

Step-by-step explanation:

The line which 3x represents is twice as big as the 48. That's because both sides other than the base are bisected.

3x = 2 * 48

3x = 96            Divide by 3

3x/3 = 96/3     Combine

x = 32

Answer:

A= L x W

A= 25.75 X 10.2

A= 262.65

Step-by-step explanation:

THE AREA OF KATHLEEN'S VEGETABLE GARDEN

Well, it says that 34 kids like physics and since there is 100 students, we know 34% of the kids like physics. This means 66% like biology.

Answer:

297 J

Step-by-step explanation:

The key to this problem lies with aluminium's specific heat, which as you know tells you how much heat is needed in order to increase the temperature of

1 g

of a given substance by

1

∘

C

.

In your case, aluminium is said to have a specific heat of

0.90

J

g

∘

C

.

So, what does that tell you?

In order to increase the temperature of

1 g

of aluminium by

1

∘

C

, you need to provide it with

0.90 J

of heat.

But remember, this is how much you need to provide for every gram of aluminium in order to increase its temperature by

1

∘

C

. So if you wanted to increase the temperature of

10.0 g

of aluminium by

1

∘

C

, you'd have to provide it with

1 gram



0.90 J

+

1 gram



0.90 J

+

...

+

1 gram



0.90 J



10 times

=

10

×

0.90 J

However, you don't want to increase the temperature of the sample by

1

∘

C

, you want to increase it by

Δ

T

=

55

∘

C

−

22

∘

C

=

33

∘

C

This means that you're going to have to use that much heat for every degree Celsius you want the temperature to change. You can thus say that

1

∘

C



10

×

0.90 J

+

1

∘

C



10

×

0.90 J

+

...

+

1

∘

C



10

×

0.90 J



33 times

=

33

×

10

×

0.90 J

Therefore, the total amount of heat needed to increase the temperature of

10.0 g

of aluminium by

33

∘

C

will be

q

=

10.0

g

⋅

0.90

J

g

∘

C

⋅

33

∘

C

q

=

297 J

I'll leave the answer rounded to three sig figs, despite the fact that your values only justify two sig figs.

For future reference, this equation will come in handy

q

=

m

⋅

c

⋅

Δ

T

, where

q

- the amount of heat added / removed

m

- the mass of the substance

c

- the specific heat of the substance

Δ

T

- the change in temperature, defined as the difference between the final temperature and the initial temperature of the sample

The key to this problem lies with aluminium's specific heat, which as you know tells you how much heat is needed in order to increase the temperature of

1 g

of a given substance by

1

∘

C

.

In your case, aluminium is said to have a specific heat of

0.90

J

g

∘

C

.

So, what does that tell you?

In order to increase the temperature of

1 g

of aluminium by

1

∘

C

, you need to provide it with

0.90 J

of heat.

But remember, this is how much you need to provide for every gram of aluminium in order to increase its temperature by

1

∘

C

. So if you wanted to increase the temperature of

10.0 g

of aluminium by

1

∘

C

, you'd have to provide it with

1 gram



0.90 J

+

1 gram



0.90 J

+

...

+

1 gram



0.90 J



10 times

=

10

×

0.90 J

However, you don't want to increase the temperature of the sample by

1

∘

C

, you want to increase it by

Δ

T

=

55

∘

C

−

22

∘

C

=

33

∘

C

This means that you're going to have to use that much heat for every degree Celsius you want the temperature to change. You can thus say that

1

∘

C



10

×

0.90 J

+

1

∘

C



10

×

0.90 J

+

...

+

1

∘

C



10

×

0.90 J



33 times

=

33

×

10

×

0.90 J

Therefore, the total amount of heat needed to increase the temperature of

10.0 g

of aluminium by

33

∘

C

will be

q

=

10.0

g

⋅

0.90

J

g

∘

C

⋅

33

∘

C

q

=

297 J

I'll leave the answer rounded to three sig figs, despite the fact that your values only justify two sig figs.

For future reference, this equation will come in handy

q

=

m

⋅

c

⋅

Δ

T

, where

q

- the amount of heat added / removed

m

- the mass of the substance

c

- the specific heat of the substance

Δ

T

- the change in temperature, defined as the difference between the final temperature and the initial temperature of the sample

In your case, aluminium is said to have a specific heat of

0.90

J

g

∘

C

.

So, what does that tell you?

Answer:

$168

Step-by-step explanation:

1  dozen = 12

proportions

12 books ⇔ $144

14 books ⇔ $B

B = 144*14/12

B = $168