The number of bus riders was recorded on one route. The data have these values: minimum = 18, lower quartile = 22,
median = 26, upper quartile = 29, and maximum = 37.
Which box plot represents the data?
15 16 17 18
19 20 21 22 23 24 25 26 27 28 29 30 31
31 32 33 34 35 36
15 16 17 18
19 20 21
22
20
24
25
26
27
20
20
20
31
32
33 34 35
15 16 17 18 19 20 21
18 19 20 21 22 23 24 25 26 27
25 26 27 28 29 30 31 32 33 34
32 33 34 35 36 37
O
20
15 16 17 18
21 22 23 24 25
26 27
20
29
35
33 34

The Number Of Bus Riders Was Recorded On One Route. The Data Have These Values: Minimum = 18, Lower Quartile

Answers

Answer 1

Answer:

The answer is B

Step-by-step explanation:

I took the test

Answer 2

The box plot that represents the number of bus drivers with the given five-number summary is: option B (see image attached below).

How to Graph A Box Plot?

A box plot is graphed to indicate the five-number summary as:

Minimum is represented by the value at the extreme end of the left whiskerLower quartile is at the beginning of the edge of the rectangular boxMedian is at the vertical line dividing the boxUpper quartile is at the end of the edge of the rectangular boxMaximum is represented by the value at the extreme end of the right whisker.

Given the five-number summary of the number of bus riders as: minimum = 18, lower quartile = 22, median = 26, upper quartile = 29, and maximum = 37, the box plot that represents the data is: Option B (see image attached below.

Learn more about box plot on:

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The Number Of Bus Riders Was Recorded On One Route. The Data Have These Values: Minimum = 18, Lower Quartile

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Step-by-step explanation:

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Step-by-step explanation:

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How do we find the factors of x2 – 64
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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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2

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Answers

Answer:   -18b + 72

Step-by-step explanation:

6(12 - 3b)

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Questions (a,b), 1 (a,b)

Answers

a )

First of all we need to find the value of x ,

because the angles are written in terms of the variable x .

______________________________________

Let's find the value of x :

STV angle & SUV angle have same measure because both of them are the front angle of SV arc .

[tex]STV angle \: = SUV angle \: \: = \frac{SV \: arc}{2} \\ [/tex]

So :

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[tex]3x = 2x + 20[/tex]

Subtract sides minus 2x

[tex]3x - 2x = 2x + 20 - 2x[/tex]

Collect like terms

[tex]x = 2x - 2x + 20[/tex]

[tex]x = 20[/tex]

Thus the measure of angle T equals :

[tex]measure \: of \: angle \: T = 3x - 5 \\ [/tex]

Now just need to put the value of x which we found :

[tex]measure \: of \: angle \: T \: = 3 \times (20) - 5 \\ [/tex]

[tex]measure \: of \: angle \: T \: = 60 - 5[/tex]

[tex]measure \: of \: angle \: T \: = 55°[/tex]

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b )

angle S & angle V are also have same measure because they both are the front angles to the TU arc .

And we need to find the value of x again in this part exactly like we did for a .

[tex]angle \: \: S = angle \: \: V[/tex]

As the question told :

[tex]angle \: \: S = 3x[/tex]

and ,

[tex]angle \: \: V = x + 16[/tex]

Thus :

[tex]3x = x + 16[/tex]

Subtract sides minus x

[tex]3x - x = x + 16 - x[/tex]

Collect like terms

[tex]2x = x - x + 16[/tex]

[tex]2x = 16[/tex]

Divide sides by 2

[tex] \frac{2x}{2} = \frac{16}{2} \\ [/tex]

Simplification

[tex]x = 8[/tex]

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[tex]measure \: \: of \: \: angle \: \: S = 3x[/tex]

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[tex]measure \: \: of \: \: angle \: \: S = 24°[/tex]

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Mrs. Bruce wants to put in a swimming pool with a deck around the perimeter of the pool. The pool will be rectangular shaped and will have dimensions of 12 feet by 20 feet. The deck around the perimeter will be uniformed in width and have a total area of 68 square feet. Find the width of the deck.

Hint: Draw and accurately label a sketch of the deck and pool in the space below.

Answers

Answer:

I think! 3.5 feet wide

Step-by-step explanation:

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The width of the deck is approximately 2.65 feet.


How to calculate the width?

To solve the problem, we need to first find the total area of the pool and deck combined, and then subtract the area of the pool to find the area of the deck.

The total area of the pool and deck can be represented as follows:

(12 + 2x) x (20 + 2x)

where x is the width of the deck.

The area of the pool is:

12 x 20 = 240

So, the area of the deck can be found by subtracting the area of the pool from the total area:

(12 + 2x) x  (20 + 2x) - 240 = 68

Expanding the left side and simplifying, we get:

4x²+ 64x - 208 = 0

Dividing both sides by 4, we get:

x²+ 16x - 52 = 0

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x = (-b ± √(b² - 4ac)) / 2a

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Plugging in these values, we get:

x = (-16 ± √(16² - 4(1)(-52))) / 2(1)

x = (-16 ± √(960)) / 2

x = (-16 ± 4√(15)) / 2

x = -8 ± 2√(15)

Since the width of the deck cannot be negative, we can discard the negative solution, and we are left with:

x = -8 + 2√(15)

So, the width of the deck is approximately 2.65 feet.

To know more about an area follow

https://brainly.com/question/29119126

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Answers

Answer:

5

Step-by-step explanation:

13² - 12² = 25

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H can’t diff go lbvvhk icon into

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Answers

Answer:

m<PRS+m<PRQ=m<QRS.

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Answers

-2x+5 is the equation of the line

488, 460, 520, 544, 535
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Answers

Answer:

84

Step-by-step explanation:

To find the range, find the difference between the largest value and the smallest value.

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