The graph provided represents voltage and current data for resistor R. What is the resistance of R?



Question 15 options:

4.5 Ω


0.50 Ω


2.0 Ω


9.0 Ω

The ratio of their amplitudes is 3.

The relation between energy and amplitude is as follows:

[tex]E_{1} = \frac{1}{2} KA_{1} ^{2}[/tex]

[tex]E_{2} =\frac{1}{2} KA_{2} ^{2}[/tex]

As, we know , one oscillation has 3.0 times the energy of a second one of equal frequency and mass i.e.,

[tex]E_{1} = 3E_{2}[/tex]

So, [tex]\frac{1}{2} KA_{1} ^{2} = 3(\frac{1}{2}KA_{2} ^{2} )[/tex]

[tex]A_{1} ^{2} = 3A_{2} ^{2}[/tex]

[tex]\frac{A_{1}^{2} }{A_{2}^{2} } = 3[/tex]

Therefore,  the ratio of their amplitudes is 3.

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The final velocity of the bicycle with initial velocity 7.6m/s and acceleration 4.2 m/s² is 28.4 m/s.

What is Velocity?

velocity is defined as the displacement per unit time.

What is Acceleration?

Acceleration is defined as the rate of change of velocity per unit time

i.e.

acceleration = (final velocity (v)-initial velocity)/time taken (t)

given:

initial velocity of the bicycle (u) = 7.6m/s

acceleration of the bicycle (a)=4.2m/s²

displacement of the bicycle=89m

using newtons third law of motion :

v²-u²=2×a×s

using the given value in question we get

v² = (7.6)²+2×4.2×89

v=28.4 m/s

the final velocity of the bicycle with initial velocity 7.6m/s and acceleration 4.2 m/s² is 28.4 m/s.

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If the voltage of the power supply is increased by a factor of 3 and the resistance was held constant, the new current will be 0.008 A or 8 mA

Power is the rate at which work is done. Electrical power is measured in Watt.

Given that a circuit is wired with a power supply, a resistor and an ammeter (for measuring current). The ammeter reads a current of 24 mA Determine the new current if the voltage of the power supply was increased by a factor of 3 and the resistance was held constant

Let the

From the power formula, power will always be constant. That is, initial power will be the same with new power

Since P = IV

24/1000 V = I × 3V

0.024V = 3IV

V cancels out

3I = 0.024

I = 0.024/3

I = 0.008 A

Therefore, the new current will be 0.008 A.

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Answer:

There are a few ways that traffic lights can sense the presence of a car. One way is by using inductive loops that are installed on the road. These loops detect changes in the magnetic field caused by a car passing over them. Another way is by using infrared sensors that detect the heat signature of a car.

Explanation:

Hope this helps!

Answer: The world population increased from 1 billion in 1800 to around 8 billion today. The world population growth rate declined from around 2% per year 50

Explanation:

The bike is travelling at 22.5 m/s after 2.5 s

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

a = (v – u) / t

a = (15 – 0) / 5

a = 3 m/s²

a = (v – u) / t

3 = (v – 15) / 2.5

Cross multiply

v – 15 = 3 × 2.5

v – 15 = 7.5

Collect like terms

v = 7.5 + 15

v = 22.5 m/s

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Distance is the overall motion of an object with no regard to its path. we can define distance as how much floor an item has included no matter it's beginning or ending point.

Given,

Distance = 100km

             =100000

Speed =100m/sec

Distance=speed × time

Time= [tex]\frac{distance}{speed}[/tex]

Time =100000/100

time =1000 sec

Distance is a numerical or on occasion qualitative size of how far apart items or factors are. In physics or regular usage, the space might also check with a physical length or an estimation primarily based on other standards.

Displacement is described because of the alternate the function of an item. it's miles a vector amount and has a course and value. it's miles represented as an arrow that points from the beginning role to the very last function. as an example- If an item moves from A role to B, then the item's function modifications.

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Answer:

The pelican was travelling at approximately [tex]9.5\; {\rm m\cdot s^{-1}}[/tex] when it dropped the fish.

The fish hit the water at approximately [tex]16\; {\rm m\cdot s^{-1}}[/tex].

(Assumption: air resistance on the fish is negligible; [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex].)

Explanation:

During the descent:

Since acceleration in the vertical direction is constant, make use of the SUVAT equation [tex]x = (1/2)\, a\, t^{2} + v_{0}\, t[/tex] to find the duration [tex]t[/tex] of the descent:

Rearrange this equation to find the duration of the descent, [tex]t[/tex]:

[tex]\begin{aligned} t &= \sqrt{\frac{2\, x}{a}} \\ &= \sqrt{\frac{2 \times 7.8\; {\rm m}}{9.81 \; {\rm m\cdot s^{-2}}} \\ &\approx 1.261\; {\rm s}\end{aligned}[/tex].

The vertical speed of the fish right before impact would be:

[tex]\begin{aligned} v_{y} &= a\, t \\ &\approx 9.81\; {\rm m\cdot s^{-2}} \times 1.261\; {\rm s} \\ &\approx 12.37\; {\rm m\cdot s^{-1}} \end{aligned}[/tex].

In the horizontal direction, the speed of the fish was constant- same as the initial speed of the pelican. The fish travelled a horizontal distance of [tex]x = 12.0 \; {\rm m}[/tex] within the [tex]t \approx 1.26\; {\rm s}[/tex] of the descent. As a result, the horizontal velocity of the fish would be:

[tex]\begin{aligned} v_{x} &= \frac{x}{t}\\ &\approx \frac{12.0\; {\rm m}}{1.261\; {\rm s}} \\ &\approx 9.52\; {\rm m\cdot s^{-1}} \end{aligned}[/tex].

Hence, the initial speed of the pelican would be approximately [tex]9.5\; {\rm m\cdot s^{-1}}[/tex].

Thus, right before impact:

Apply the Pythagorean Theorem to find the overall velocity of the fish at that moment:

[tex]\begin{aligned} v &= \sqrt{{v_{x}}^{2} + {v_{y}}^{2}} \\ &\approx \sqrt{{(9.52\; {\rm m\cdot s^{-1}})}^{2} + {(12.37\; {\rm m\cdot s^{-1}})}^{2}} \\ &\approx 16\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

In other words, the fish would hit the water at approximately [tex]16\; {\rm m\cdot s^{-1}}[/tex].

The distance traveled by the object from its initial position is 384 cm.

Distance is the sum of an object's movements, regardless of direction. Without respect to the object's starting or finishing positions, distance can be defined as the amount of space it has traveled.

An object is moving in a straight path.

The speed of the object from its initial position is 12.8 cm/s.

The object is moving for 05 minutes.

Then, t = 0.5 min = 0.5 × 60 = 30 seconds.

Now, the speed of an object is the distance of the object per unit time.

Therefore,

s = d / t

d = s × t

d = ( 12.8 cm/s ) × ( 30 s )

d = 384 cm

Hence, the object's position from its initial position is 384 cm.

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Your weigh on the star methuselah is 38 pounds.

For example, if you weigh 100 pounds on Earth, you would weigh only 38 pounds on Mercury. That's because Mercury weighs less than Earth, and therefore its gravity would pull less on your body.

The element mercury has the atomic number 80 and the symbol Hg. Formerly called hydrargyrum from the Greek words Hydor (water) and Argyros, it's also known as quicksilver (silver). the sole other metallic element that is known to be liquid at standard circumstances for temperature and pressure is the halogen bromine, while metals like cesium, gallium, and rubidium melt just above temperature. Mercury may be a heavy, silvery d-block element.

Worldwide deposits of mercury, primarily as cinnabar, are found (mercuric sulfide). Grinding either synthetic mercuric sulfide or natural cinnabar yields the red color vermilion.

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There is no such things as an exact measurement there can never be a perfect instrument or measurer.

The term measurement has to do with the process of obtaining the value of a quantity. We know that measurements are done in order to give us an idea of the magnitude of a quantity. In every measurement, there is an instrument that is used for the measurement. For instance, if I want to measure length, I may have to use a meter rule to do it.

Now, there are two ways that error could be introduced into a measurement;

1) By the instrument that is used

2) By the error of the measurer

Hence, there is no such things as an exact measurement there can never be a perfect instrument or measurer.

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Answer:

the magnitude of b 3A

Explanation:

2b 1 a

(a) The position-time equations for fishing boat is x = 3.4t + 40.8

(b) The time taken for the speedboat to catch up with the fishing boat is 7.1 seconds.

The position-time equations for fishing boat will be obtained by applying the principle of relative velocity as follows;

Let the time when the speedboat catches up = t

let the total time spent by fishing boat = t + 12

x = 3.4(t + 12)

x = 3.4t + 40.8

fishing boat is moving at a constant speed = 3.4 m/s

speed boat started moving 12 seconds later,

distance between the boats = 3.4 m/s  x 12 s = 40.8 m

v = u + at

v = 2.8 + 1.7t

set up the following equation to determine the time when the two boats meet.

vt - x = 40.8

t(2.8 + 1.7t) -  (3.4t + 40.8) = 40.8

2.8t + 1.7t² - 3.4t - 40.8 = 40.8

1.7t² - 0.6t  - 81.6 = 0

solve the quadratic equation using formula method as shown below;

a = 1.7, b = -0.6, c = -81.6

t = 7.1 seconds

Thus, the time taken for the speedboat to catch up with the fishing boat is 7.1 seconds.

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The skateboarder will travel a distance of 9.19 m

We know that,

a = ( v - u ) / t

Δv = ( v + u ) / 2 ( If acceleration is constant )

Δv = d / t

where,

a = Acceleration

v= Final velocity

u = Initial velocity

t = Time taken

d = Displacement

Δv = Average velocity

Given that,

u = 1.8 m / s

a = 1.5 m / s²

t = 2.5 s

a = ( v - u ) / t

1.5 = ( v - 1.8 ) / 2.5

v = 3.75 + 1.8

v = 5.55 m / s

Δv = ( 5.55 + 1.8 ) / 2

Δv  = 3.675 m / s

d = Δv * t = 3.675 * 2.5

d = 9.19 m

If the initial and final velocity is known, average velocity can be calculated by taking the average value of initial and final velocity, if the acceleration is constant.

Therefore, the skateboarder will travel a distance of 9.19 m

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According to the given statement The dimension of a, b and c is LT⁻² , L and T.

She took exact measurements of the room's length, width, height, and depth in one direction (for example, the distance between the ceiling and the floor of a room). The space was unexpectedly small in all three of its dimensions. Dimensions include length, breadth, and height. One dimension is that of a line, two dimensions are those of a square, and three dimensions are those of a cube (3D).

According to the principle of dimensional homogenity

Dimension of v = dimension of at  =  dimension of  b/t+c

​Dimension of a =   [tex]\frac{[\mathrm{v}]}{[\mathrm{t}]}=\frac{\mathrm{LT}^{-2}}{\mathrm{~T}}=\left[\mathrm{LT}^{-2}\right][/tex]

Dimension of b = [v][t]=[LT −1 T]=[L]

Dimension of c = [t]=[T]

According to the given statement The dimension of a, b and c is LT⁻² , L and T.

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The number of electrons that must be removed from object A and placed on object B is 1.24 * [tex]10^{19}[/tex]

We know that,

E = k [tex]q_{1}[/tex] [tex]q_{2}[/tex] / r²

where,

E = Electrostatic force

k = Coulomb's constant

[tex]q_{1}[/tex], [tex]q_{2}[/tex] = Point charges

r = Distance between two charges

Given that,

[tex]q_{1}[/tex] = 2 + ne C

[tex]q_{2}[/tex] = - 2 - ne C

r = 3 cm

k = 9 * [tex]10^{9}[/tex] N m² / C²

E = - 68 N ( Since it is attractive )

- 68 = 9 * [tex]10^{9}[/tex] ( 2 - ne ) ( - 2 + ne ) / ( 3 * [tex]10^{-2}[/tex] )²

68 * [tex]10^{-4}[/tex] / 3 * [tex]10^{9}[/tex] = ( 2 - ne )²

2.27 * [tex]10^{-12}[/tex] = ( 2 - ne )²

1.5 * [tex]10^{-6}[/tex] = 2 - ne

ne = 1.98

n = 1.98 / 1.6 * [tex]10^{-19}[/tex] = 1.24 * [tex]10^{19}[/tex]

The given problem is an electrostatic attractive force because the two point charges are unlike charges. If the charges are like, then the electrostatic force will be repulsive.

Therefore, the number of electrons that must be removed from object A and placed on object B is 1.24 * [tex]10^{19}[/tex]

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The final speed of the race car, given the data is 49 m/s (Option C)

The acceleration of an object is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

With the above formula, we can determine the final velocity of the car. Details below:

a = (v – u) / t

0.8 = (v – 33) / 20

Cross multiply

v – 33 = 0.8 × 20

v – 33 = 16

Collect like terms

v = 16 + 33

v = 49 m/s

Thus, the final velocity of the car is 49 m/s (Option C)

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The resultant displacement is 32.4 m due west of south.

The term displacement has to do with the change in the position of a body in a particular direction. Displacement is a vector quantity. We have to find the resultant displacement algebraically;

Hence;

Resultant displacement = √((26.5)^2 + 18.7)^2

Resultant displacement = 32.4 m due west of south

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Answer:

The speed of the boat, in m/s, with respect to Earth, is vBE = 7.52 m/s.

Explanation:

vBE = vBW + vWE

vBE = 7.18 m/s + 2.29 m/s

vBE = 7.52 m/s

That would be the proportion between the difference and the total of the two amplitudes (when they are in phase, or as they say, "add coherently") (when they are out of phase or "add destructively").

The amplitude of a wave is the maximum displacement of a particle on the medium from its rest point. The distance between the rest and the crest can be thought of as the amplitude. Measuring the amplitude from the rest position to the trough position is another method of determining it.

The height between the center line and the peak is known as the amplitude (or to the trough). Alternatively, we might multiply the height from highest to lowest places by 2.

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Answer: a place in space where gravity pulls so much that even light can not get out.

Answer:

black holes are holes that can suck this world with its high gravity

Baseball will  hit the wall due to less height from the The Green Monster  wall.

from the data, we have in

velocity of x direction is 25 m/s

velocity of y direction is 20.5 m/s

now, the horizontally:

velocity=distance/time

time=distance/velocity

time=94.5/25

t=3.76sec

now for vertically: we will apply kinematics equation

s=ut+[tex]\frac{at^2}{2}[/tex]

now putting the values,

s=77.08-69.27

s=7.80m

now,

the initial height from baseball hit=0.9m

now, total height=0.9+7.80

s=8.7

8.7 m is less than wall height

so it will hit the wall

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There are many reasons. The easiest solution is because the rain that we remember acidic has a low pH; it has a better amount of hydrogen ions.

Acid rain manipulation implies three adjustments a notably extra complicated and cumbersome regulatory program beneath the Clean Air Act, new emission manipulation prices for initial rollback requirements and next offsets, and on account of these, new impediments to utility and commercial plant creation, expansion, and modernization.

The Acid Rain application (ARP) has brought widespread discounts in sulfur dioxide (SO2) and nitrogen oxide (NOX) emissions from fossil fuel-fired strength flora, full-size environmental and human fitness blessings, and a ways lower-than-anticipated prices.

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Answer: gravity of earth = 9.8 n/s , new weight of the body on other planet = mg = 1.913 ×6×9.8=112..5

Explanation:

Answer:An antenna is an array of conductors, that is connected to the receiver or transmitter.

It transmits and receives radio waves in the horizontal directions or in a particular direction.

It may include a parasitic elements, and reflectors that can serve to direct the radio waves into a beam like pattern or some other patter.

Explanation:

It will not capture modulated radio waves.

Answer:

(a) The electric potential at a point midway between the charges is 160 V.

(b) The potential energy of the pair of charges is -2.4x10⁻⁷ J.

What is electrical potential energy?

The effort necessary to assemble a system of point charges by bringing them close together, as in the system from an infinite distance, is defined as the electric potential energy of the system. Alternatively, the electric potential energy of any given charge or system of charges is defined as the total work performed by an external agent in moving the charge or system of charges from infinity to the current configuration without acceleration.

Explanation:

The electric potential at a point between two point charges Q₁ = +6.00nC and Q₂ = -2.00 nC separated by 45.0 cm is found to be 160 V and the potential energy of the pair of charges is -2.4 x 10⁻⁷ J.

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Answer:

Velocity is distance + direction / time

so your answer is

75 km north / 1.5 hours

75/1.5  km north/ hours =

50 km / hours north

Based on the data attached, the option of the conclusion that could be made from this data is option B. It snows less in Green Bay than in Kalamazoo on average.

.

The term snows is known to be a kind of a small white crystals of ice that is known to be formed as a result of  direct water vapor of the air.

It is known to be a measure or a mass of snowflakes that is said to have  fallen to earth.

Therefore, from the data, one can see that the snow fell a lot in Buffalo and from it one can also see that Kalamazoo has almost times 2 of the snow in Green Bay.

Therefore, Based on the data attached, the option of the conclusion that could be made from this data is option B. It snows less in Green Bay than in Kalamazoo on average.

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Answer:

There are 640 acres in 1 square mile I think