Suppose a ball is thrown vertically upward (positive direction) from an initial height LaTeX: h_0 with initial velocity LaTeX: v_0. Find the position function LaTeX: s(t) of the ball after LaTeX: t seconds assuming the gravitational acceleration LaTeX: g is a positive constant pointing downward (negative direction).

Answers

Answer 1

After time t, the position function of the ball is determined as [tex]y(t) = h_0\ +\ v_0t \ - \ \frac{1}{2} gt^2[/tex]

The given parameters;

initial velocity of the ball, = [tex]v_0[/tex]initial position of the ball, = [tex]h_0[/tex]acceleration due to gravity, = g

The position function of the ball after time t, is calculated as follows;

[tex]y(t) = h_0\ +\ v_0t \ - \ \frac{1}{2} gt^2[/tex]

The negative sign of acceleration of due to gravity is because the ball is moving upward against gravity.

Thus, after time t, the position function of the ball is determined as [tex]y(t) = h_0\ +\ v_0t \ - \ \frac{1}{2} gt^2[/tex]

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Related Questions

What is the intensity of the electromagnetic light waves coming from the Sun just outside of the atmosphere of Venus, Earth and Mars

Answers

The sun emits electromagnetic waves with a power of  

4.0 ∗ 10  (26)  W.

A 20-N falling apple encounters a 4-N of air resistance. The magnitude of the net force on the apple is?

A. 0n
B.4n
C.16n
D. 20n
E. None of the above

Answers

Answer:

C

Explanation:

Pls brainliest

Which statement describes electromagnetic waves with wavelengths grater than 700 nanometers

Answers

Answer:

They take the form of heat, I think thats it but I cant see if you put down any answers

Explanation:

Answer:a

Explanation:

they form hear

Standing at a crosswalk, you hear a frequency of 550 Hz from the siren of an approaching ambulance. After the ambulance passes, the observed frequency of the siren is 475 Hz. Determine the ambulance's speed from these observations. (Take the speed of sound to be 343 m/s.)

Answers


There are six steps to this process , I uploaded step one and as you can see you can get all six on Quizlet:). Good luck

What is the difference between real and apparent weightlessness?

Answers

Answer:

In space we feel weightlessness because the earth's gravity has less effect on us. The Earth's gravitational attraction at those altitudes is only about 11% less than it is at the Earth's surface. If you had a ladder that could reach as high as the shuttle's orbit, your weight would be 11% less at the top.

Explanation:

Hope this helps:)

Seven friends equally split a restaurant bill that
comes to $93.17. How much does each person pay?

Answers

Answer:

$13.31

Explanation:

We know that the bill comes to $93.17 and that 7 people will split the bill equally

We can just use the equation

bill = $93.17/7

bill = $13.31

If an electron moves in a direction perpendicular to the same magnetic field with this same linear speed,
what is the radius of its circular orbit?

Answers

Answer:

An effect begins to alter movement, and the direction of moves in the circular path is known as centripetal force. Its measurable unit is Newton or Kilogram meter per square of the second. The product of mass and square of velocity divided by the radius of path travel by the body provide s the term centripetal force.

Explanation:

Answer:

An effect begins to alter movement, and the direction of moves in the circular path is known as centripetal force. Its measurable unit is Newton or Kilogram meter per square of the second. The product of mass and square of velocity divided by the radius of path travel by the body provide s the term centripetal force.

Explanation:

Find the first three harmonics of a string of linear mass density 2.00 g/m and length 0.600 m when it is subjected to tension of 50.0 N.

Answers

Hi there!

We can use the following equation to find the frequency of each harmonic:

[tex]f_n = \frac{n}{2L} \sqrt{\frac{T}{\lambda}}[/tex]

n = nth harmonic

L = length of string (m)

T = Tension of string (N)

λ = linear density (kg/m)

Begin by converting the linear mass density to kg:

2.00g /m · 1 kg / 1000g = 0.002 kg/m

Now, we can use the equation to find the first three harmonics.

First harmonic:

[tex]f_1 = \frac{1}{2(0.6)} \sqrt{\frac{50}{0.002}} = \boxed{131.76 Hz}[/tex]

Second harmonic:

[tex]f_2 = \frac{2}{2(0.6)} \sqrt{\frac{50}{0.002}} = \boxed{263.52Hz}[/tex]

Third harmonic:

[tex]f_3 = \frac{3}{2(0.6)} \sqrt{\frac{50}{0.002}} = \boxed{395.28Hz}[/tex]

Clothes stick together when you pull them out of the dryer because


clothing is a conductor.


clothing is an inductor.


they are not charged.


of static electricity.

Answers

it is because of static electricity

What is the cause of plate tectonics on Earth?


The magnetic field


Tides in the ocean


Convection in the mantle


Volcanic eruptions

Answers

Answer:

im pretty sure the answer is C

How long will it take a car, starting from rest, accelerating at 2 meters per second square to travel the same distance that another car traveling at a constant rate of 20m/s will travel?

Answers

20 seconds

Explanation:

Let [tex]x_a[/tex] be the distance traveled by the accelerating car and [tex]x_c[/tex] be the distance traveled by the car moving with a constant velocity. When they cover the same distance, we can write

[tex]x_a = x_c \Rightarrow v_{0a}t + \frac{1}{2}at^2 = v_ct[/tex]

where [tex]v_c[/tex] is the velocity of car moving at a constant rate and a is the acceleration of the accelerating car. Since the accelerating car started from rest, then [tex]v_{0a}[/tex] is zero so our equation above simplifies to

[tex]\frac{1}{2}at^2 = v_ct[/tex]

Note that the variable t cancels out so solving for t, we get

[tex]\frac{1}{2}at = v_c \Rightarrow t = \dfrac{2v_c}{a}[/tex]

Plugging in the given values,

[tex]t = \dfrac{2(20\:\text{m/s})}{2\:\text{m/s}^2} = 20\:\text{s}[/tex]

The amount of work done in example B is:​

Answers

Answer:

Explanation:

20 n is an unknown amount

If that is supposed to be 20 N(ewtons)

then W = Fd = 20(15) = 300 J

Answer: it will be 300 newton meters

Explanation:

Why Amphibians are Vanishing

Answers

Answer:Climate change, emerging diseases, and increased exposure to ultraviolet radiation (due to ozone depletion) are all additional factors that could be contributing to falling amphibian populations. ... Instead, amphibians are disappearing thanks to a complex mixture of factors, including: Alien Specie

Explanation:

just look it up........

If m1 is 24 kilograms, m2 is 12 kilograms, and mbar is 10 kilograms, what is the direction of rotation and the sign of the angular acceleration

Answers

From the diagram, the angular speed will increase clockwise, the sign of the angular acceleration will be negative and the direction of rotation will be clockwise direction and the sign of the angular acceleration is negative. The correct answer is option B

Given that two objects of masses m1 and m2 are attached to a seesaw. The seesaw is made of a bar that has length l and is pivoted so that it is free to rotate in the vertical plane without friction. Counterclockwise is considered the positive rotational direction.

If m1 is 24 kilograms, m2 is 12 kilograms, and mbar is 10 kilograms, The moment of object m1 will be equal to the moment of object m2 without the Mbar

Let assume that the length L of the seesaw is 9 cm.

Anticlockwise moment = 24 x 9/3 = 72Nm

Clockwise moment = 12 x 2(9/3) = 72 Nm

With the consideration of mass of the bar Mbar, this will add to clockwise moment of the seesaw.

Therefore, the direction of rotation will be clockwise direction.

Angular acceleration is positive when object is speeding up and negative when slowing down. Also, angular acceleration is positive when speed increases in an anticlockwise direction and negative when speed increases in the clockwise direction.

From the diagram, since the angular speed increase clockwise, the sign of the angular acceleration will be negative.

We can conclude that the direction of rotation will be clockwise direction and the sign of the angular acceleration is negative.

The correct answer is option B

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Jane plans to fly from Binghamton, New York, to Springfield, Massachusetts, about 280 km due east of Binghamton. She heads due east at 280 km/h for one hour but finds herself at Keene, which is 294 km from Binghamton in a direction 17.8 degrees north of due east. What was the wind velocity

Answers

Answer:

90m/h N

Explanation:

we consider janes velocity to the positive X axis so Vj=280km/s

and the final position a dot in on the graph r=294km, we find the x and y components:

294*cos(17.8)=280 X+ confirming our theory

294*sin(17.8)=90 Y+ or N and that's the winds' velocity.

A cyclist on a training ride records the distance she travels away from home. The data only shows the first150 minutes of the ride before her cycling computer ran out of battery.

Answers

Answer:

A) 58 km

B) 30 mins

Explanation:

In pic details

graph in pic

Amy uses 20 N of force to push a lawnmower 10 meters. How much work does she do?

Answers

Answer:

200J

Explanation:

work done = force x distance

                  = 20 x 10

                  = 200J

What is the average SPEED/VELOCITY of a car that traveled 1 complete lap around an oval track that’s 5000m long in 1000s

Answers

Answer:

5 m/s

Explanation:

5000/1000=5 m/s

:))

The symbol or variable to used find initial velocity is

Answers

Answer:

v down exponenet 1 brainlest

Explanation:

Answer:

v0 [vee nought] is the initial velocity when time=0

6. How are the temperature of the universe and Cosmic Microwave Background (CMB) related?

A. Astronomers use the temperature of CMB as the warmest temperature in the universe

B. Astronomers calculate the temperature of the universe based on the coldest part of the CMB

C. Astronomers consider the temperature of the universe to be the temperature of CMB

D. Astronomers never consider the temperature of CMB when looking at the temperature of the universe​

Answers

Answer:

I think the answer is (A)...

Hope this helps!

which materials are good for constructing bridges and tall buildings​

Answers

Answer:

Cement, iron, and steel all work great!

A small 1240-kg SUV has a wheelbase of 3.2 m. If 67% of its weight rests on the front wheels, how far behind the front wheels is the wagon's center of mass

Answers

Answer:

Explanation:

Let d be the distance to the center of mass from the front wheels

Sum moments about the front wheel contact point to zero

1240(9.8)[d] - 1240(9.8)(1 - 0.67)[3.2] = 0

1240(9.8)[d] = 1240(9.8)(1 - 0.67)[3.2]

                d = (1 - 0.67)[3.2]

                d = 1.056 m

The second hand on a clock is 3.00 cm long. What is the speed of the outermost tip of that second hand

Answers

In 60 minutes or 3600 seconds, the tip of the minute hand traverses the circumference of a circle with radius 3.00 cm, so it moves with a tangential speed of

(3.00 cm)/(3600 s) ≈ 0.00083 cm/s = 8.3 μm/s

A ball is thrown vertically down from the edge of a cliff with a speed of 4 m/s, how high is the cliff, if it took 12 s for the ball to reach the ground?

I need the Formula

Answers

Hi there!

We can use the equation:

d = v₀t + 1/2at²

Where:

v₀ = initial velocity downward

a = acceleration due to gravity

t = time

Plug in given values:

d = 4(12) + 1/2(9.8)(12²)

d = 48 + 705.6 = 753.6 m

Which of the vectors in the graph below is the negative of the vector v
A. a
B. d
C. c
D. b

Answers

Answer:

Option c.

Explanation:

A straight wire in a magnetic field experiences a force of 0.011 N when the current in the wire is 2.3 A. The current in the wire is changed, and the wire experiences a force of 0.051 N as a result. What is the new current

Answers

Answer:

A straight wire in a magnetic field experiences a force of 0.022 N when the current in the wire is 1.1 A. The current in the wire is changed ...

1 answer

·

Top answer:

The magnetic force that acts on the wire in the first case can be written as

Explanation:

How much did the pressure drop in the storm's center from November 9, 1200z, until November 11, 0000z

Answers

The pressure dropped by 24 MB in the storm's center from November 9, 1200z, until November 11, 0000z.

Using the attached map below, in the morning of November 9, the pressure situated at the storm's center = 1000 MB isobar located at the center.

Meanwhile, on November 11, 0000z the pressure situated at the storm's center = 976 MB isobar  

The difference in this pressure is regarded as the pressure drop in the storm's center and it is determined as follows;

= 1000 MB - 976 MB

= 24 MB

Therefore, we can conclude that the pressure drop by 24 MB in the storm's center from November 9, 1200z, until November 11, 0000z.

Learn more about pressure drop in an isobaric process here:

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100 J of work was done to lift a 10-N rock and set it at Position A near the edge of a cliff.
1. If the 100 Joules of work lifted the rock to the top of the cliff, how much potential energy did the rock gain?
2. At point C, the rock's potential energy will be
3. The rock's kinetic energy at point A is
4. At point B, some of the rock's potential energy will be changed to Kinetic energy
5. What is the mass of the rock?
6. What is the rock's velocity just before it hits the ground?
The rock to the right is sitting at the top of a ramp. I wonder how much work it required to get that rock up there.

Answers

Answer:

lol

Explanation:

A race car, starting from rest, travels around a circular turn of radius 22.5 m. At a certain instant the car is still speeding up, and its angular speed is 0.541 rad/s. At this time, the car’s total acceleration vector (centripetal plus tangential) makes an angle of 39.0 with respect to the car’s velocity. What is the magnitude of the car’s total acceleration

Answers

Answer:

Explanation:

The answer:

https://www.chegg.com/homework-help/questions-and-answers/race-car-starting-rest-travels-around-circular-turn-radius-247-m-certain-instant-car-still-q402991

Total acceleration of car is 148.31 m/s².

What is centripetal acceleration?

Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any item travelling in a circle with an acceleration vector pointing in the direction of the circle's center.

Given parameters:

Radius of the circular path: r = 22.5 m.

Angular speed: ω = 0.541 rad/s.

So, centripetal acceleration; α = ω²r = (0.541)² × 22.5 m/s² = 6.58 m/s².

Tangential acceleration: [tex]\alpha_t[/tex] = αr = 6.58 × 22.5 = 148.16 m/s².

Hence, total acceleration = √(α² + [tex]\alpha_t[/tex]²) = √(6.58² +148.16²) = 148.31 m/s².

Learn centripetal acceleration here:

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5 kg block of iron is heated to 800°C. It is placed in the tub containing 2 L of water at 15°C. Assuming all the water is brought to the boil rapidly, calculate the mass of water which boils off. (The specific heat capacity of iron 800°C is 220 J kg-1 K-1)

Answers

Answer:

Heat Loss = 5 kg * 700 deg K * 220 J / (kg*deg K) = 7.70E5 J

Since there are 4.186 J/cal

Heat Loss = 7.70E5J / 4.186 J/cal = 1.84E5 cal

Heat Gain = 2000 g * 85 deg K / cal / (deg K g) + M * 540 cal/g

Heat Gain = 1.70E5 cal + M * 540 cal/g

M = (1.84 - 1.70) E5 g / 540

25.9 g

25.9 g or 25.9 cm^3 or .0259 L   of water will boil away

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