Subtract 2w + 4 ​​from​ 3w + 6 please help!!

Answer:

Step-by-step explanation:

(a) [tex]\int x^n e^{5x^4+1} \ dx[/tex]

Suppose [tex]5x^4 + 1 = f[/tex]

by differentiation;

[tex]\implies \ 20 x^3 dx = df --- (1)[/tex]

Suppose n = 3

Then, the integral

[tex]I = \int x^ 3 e^{5x^4 + 1} \ dx[/tex]

[tex]= \int e^f \ \dfrac{df}{20}[/tex]

[tex]= \dfrac{1}{20} \int e^f \ dt[/tex]

[tex]= \dfrac{1}{20} e^f + C[/tex]

recall that [tex]f = 5x^4 + 1[/tex]

Then;

[tex]\mathbf{ I = \dfrac{1}{20}e^{5x^4+1}+C}[/tex]

(b) [tex]\int \dfrac{cos (\dfrac{1}{x^3})}{x^n } \ dx[/tex]

suppose; [tex]\dfrac{1}{x^3} = f[/tex]

[tex]x^3 = f[/tex]

[tex]\implies -3x^{-4} \ dx = df[/tex]

[tex]\implies \dfrac{1}{x^4} \ dx =-\dfrac{1}{3} df[/tex]

If n = u, then the integration is:

[tex]I = \int \dfrac{1}{x^4} \ cos (\dfrac{1}{x^4}) \ dx[/tex]

[tex]= \int -\dfrac{1}{3} \ cos \ f \ df[/tex]

[tex]= -\dfrac{1}{3} \int \ cos \ f \ df[/tex]

[tex]= -\dfrac{1}{3} \ sin \ f + C[/tex]

Since;  [tex]x^3 = f[/tex]

Then;

[tex]\mathbf {I = -\dfrac{1}{3} \ sin \ \Big( \dfrac{1}{x^3}\Big) + C}[/tex]

(c) [tex]\int \dfrac{x+n}{x^2 + 8x -4} \ dx[/tex]

Suppose  [tex]x^2 + 8x - 4 = f[/tex]

Then, by differentiation of both sides

[tex](2x + 8) \ dx = df[/tex]

[tex](x + 4) \ dx = \dfrac{1}{2} \ df[/tex]

Suppose n = 4 in integration, then:

[tex]I = \int \dfrac{(x + 4) }{x^2 +8x -4} \ dx[/tex]

By substitution;

[tex]I = \int \dfrac{1}{2}\dfrac{1}{f} \ df[/tex]

[tex]= \dfrac{1}{2} \ \ { In |f|} + C[/tex]

[tex]\mathbf{= \dfrac{1}{2} \ \ { In |x^2+8x -4|} + C}[/tex]

The suitable substitutions of n are 3,4,4 respectively.

The process of finding integrals is called integration.

a)[tex]f(x)=\int\limits {x^3e^{5x^4+1} } \, dx[/tex]

Suppose

[tex]5x^4+1 =t\\20x^3 dx =dt[/tex]

So, we need n=3 for easy integration.

[tex]f(x)=\int\limits {x^3e^{5x^4+1} } \, dx[/tex]

[tex]I = \frac{1}{20} \int\limits {e^{t} } \, dt[/tex]

[tex]I=\frac{e^{t} }{20}[/tex]

[tex]I = e^{5x^{4}+1 }/20 +c[/tex]

b)Similarly for [tex]f(x) = \int\limits\frac{cos(\frac{1}{x^3} )}{x^n} \, dx[/tex]

n=4 is needed for easy integration.

I = [tex]\frac{-1}{3} sin(\frac{1}{x^3} ) +c[/tex]

c)For [tex]f(x) = \int\limits \frac{x+n}{x^{2} +8x-4} \, dx[/tex]

n=4 is needed for easy integration.

[tex]I = \frac{1}{2} log(x^{2} +8x-4)[/tex]

Hence, the suitable substitutions of n are 3,4,4 respectively.

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Answer:

A

Step-by-step explanation:

It is letter A I got 100!

Answer:

A

Step-by-step explanation:

EDGE 2021

Answer: 3.2x = 48

Step-by-step explanation: So that means x = 15.

Answer: Total cost would be 10,320

Step-by-step explanation: Hope this helps

Answer:

Amount contributed by Oscar = $8

Step-by-step explanation:

Given that:

Amount spent on gift = $36

Amount contributed by Moriah = $12

Let,

x be the amount contributed by each of them.

Thus,

Gift total = Contribution of all

36 = x+x+x+12

36 = 3x+12

3x+12 = 36

3x=36-12

3x=24

Dividing both sides by 3

[tex]\frac{3x}{3}=\frac{24}{3}\\x=8[/tex]

Hence,

Amount contributed by Oscar = $8

Hi.. U should do like this

4/5 mile in 50 min

X mile in 60 min

X=5/4 mile

Answer:

5 milesss

:)))

Answer:

[tex]\mathrm{No\: solutions}[/tex]

Step-by-step explanation:

Since Connor has worked 12 hours walking dogs, he's earned [tex]12\cdot 8 = \$96[/tex] from walking dogs. He still needs to earn [tex]\$160-\$96=\$64[/tex]. As stated in the problem, he makes $12 an hour landscaping, therefore the minimum number of whole hours he must work to fulfill his requirements is [tex]\lceil{ \frac{64}{12} \rceil = 6\: \mathrm{hours}[/tex]. However, the problem states he can only work a maximum of 15 hours. He would have to work [tex]12+6=18[/tex] to fulfill his requirements and therefore he will not be able to meet his requirements with the restrictions given.

Answer:

These two corners are [tex]\sqrt{13}[/tex] units apart.

Step-by-step explanation:

Distance between two points:

Suppose we have two points, [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]. The distance between them is given by:

[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Approximately how far apart are the two corners?

We have to find the distance between the points (-5,-2) and (-8-3). So

[tex]D = \sqrt{(5-(-8))^2+(-2-(-3))^2} = \sqrt{13}[/tex]

These two corners are [tex]\sqrt{13}[/tex] units apart.

Answer:

The answer is 154.8 ml

Step-by-step explanation:

In this question, the amount of pure acid is 18% of the total solution, that is, 18% of 860 milliliters. So

0.18*860 = 154.8 ml

The answer is 154.8 ml

Answer:

[tex](-4, 1) \: and \: (-4,7)[/tex]

Step-by-step explanation:

[tex]the \: shortest \: distance \: between \: two \: points \: can \: be \: used \: here \to \\ were : d = \sqrt{ (x_{2} -x_{1} ) {}^{2} + (y_{2} -y_{1} ) {}^{2} } \\checking \: for \: the \: pair \to \: (-4, 1) \: and \: (-4,7) \\ d = \sqrt{ (( - 4)-( - 4)) {}^{2} + (7 -1 ) {}^{2} } \\ d = \sqrt{ (- 4 + 4) {}^{2} + (6) {}^{2} } \\ d = \sqrt{ (0) {}^{2} + (6) {}^{2} } \\ d = \sqrt{ (6) {}^{2} } \\ \underline{ \boxed{d = 6}}[/tex]

Solution :

Let the three places be 1, 2, 3, 4, 5, 6, 7, 8

a). Number of the cases when a general manager is the next to a vice president is equal to 7 and the these 2 can be arranged in 21 ways. So the total number of ways = 7 x 2

                  = 14

[(1,2)(2,1) (2,3)(3,2) (3,4)(4,3) (4,5)(5,4) (5,6)(6,5) (6,7)(7,8) (8,7)(7,6)]

Therefore the required probability is

  [tex]$=\frac{14}{8!}$[/tex]

 = [tex]$\frac{14}{40320} = 0.000347$[/tex]

b). The probability that the marketing director to be placed in the leftmost position is

   [tex]$=\frac{7!}{8!}$[/tex]

  [tex]$=\frac{1}{8} = 0.125$[/tex]

c). The two events are not independent because

   [tex]$P(A \cap B) \neq P(A) \times P(B)$[/tex]

  [tex]$\frac{12}{8!} \neq \frac{14}{8!} \times \frac{1}{8}$[/tex]

where A is the case a and B is the case b.

(a) The possibility of the general manager is next to the vice president is [tex]\frac{1}{4}[/tex].

(b) The possibility of the marketing director is in the leftmost position is [tex]\frac{1}{8}[/tex].

(c) So, the two events are dependent on each other.

Probability is a measure of the likelihood of an event to occur. Many events cannot be predicted with total certainty. We can predict only the chance of an event to occur i.e. how likely they are to happen, using it. The probability of all the events in a sample space adds up to 1.

Total people in company A and company B is [tex]=8[/tex]

Overall ways in which these [tex]8[/tex] people can be lined up[tex]=8![/tex]

                                                                                        [tex]=40320[/tex]

(a) The probability that the general manager is next to the vice president is[tex]=P(A)[/tex]

Now, we can combine the general manager and vice president as one, then the total people in both the company will become [tex]7[/tex].

by arranging these [tex]7[/tex] people in one line [tex]=7![/tex]

                                                                [tex]=5040[/tex]

Again, combine the general manager and vice president in one line[tex]=2![/tex]

                                                                                                                [tex]=2[/tex]

Therefore, [tex]P(A)=\frac{5040\times 2}{40320}[/tex]

                          [tex]=\frac{10080}{40320}[/tex]

[tex]P(A)=\frac{1}{4}[/tex]

(b) The probability that the marketing director is in the leftmost position is[tex]=P(B)[/tex]

Now, fixing the position of marketing director in the leftmost.

arranging the [tex]7[/tex] other people in [tex]7![/tex] ways [tex]=5040[/tex]

Therefore,[tex]P(B)=\frac{5040}{40320}[/tex]

                          [tex]=\frac{1}{8}[/tex]

[tex]P(B)=\frac{1}{8}[/tex]

(c) Assuming event B already occurred which means that the position of marketing director is already fixed in the leftmost position.

Now, trying to find out the probability of the general manager next to the vice president is event A. it comes different because we are not allowed to arrange rest [tex]7[/tex] people, we have to fix the position of one person that causes the repetition of probability.

So, the two events are dependent on each other.

Learn more about the topic of Probability: https://brainly.com/question/26959834

Answer:

a) The z-score for a backyard structure costing $2300 is -0.57.

b) The z-score for a backyard structure costing $4900 is 1.29

c) A backyard structure costing $2300 costs 0.57 standard deviations below the mean, while a backyard structure costing $4900 costs 1.29 standard deviations above the mean. Since both are within 2 standard deviations of the mean, none is an outlier.

d) Since this combination costs more than 2 standard deviations from the mean, yes, it should be considered an outlier.

Step-by-step explanation:

Z-score:

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If the z-score is more than two standard deviations from the mean(lesser than -2 or more than 2), the score X is considered an outlier.

In this question, we have that:

[tex]\mu = 3100, \sigma = 1400[/tex]

a. What is the z-score for a backyard structure costing $2300?

We have to find Z when [tex]X = 2300[/tex]. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{2300 - 3100}{1400}[/tex]

[tex]Z = -0.57[/tex]

The z-score for a backyard structure costing $2300 is -0.57.

b. What is the z-score for a backyard structure costing $4900?

We have to find Z when [tex]X = 2300[/tex]. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{4900 - 3100}{1400}[/tex]

[tex]Z = 1.29[/tex]

The z-score for a backyard structure costing $4900 is 1.29

c. Interpret the z-scores in parts (a) and (b). Comment on whether either should be considered an outlier.

A backyard structure costing $2300 costs 0.57 standard deviations below the mean, while a backyard structure costing $4900 costs 1.29 standard deviations above the mean. Since both are within 2 standard deviations of the mean, none is an outlier.

d. If the cost for a backyard shed-office combination built in Albany, California, is $13,000, should this structure be considered an outlier?

We have to find the z-score when X = 13000. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{13000 - 3100}{1400}[/tex]

[tex]Z = 7.07[/tex]

Since this combination costs more than 2 standard deviations from the mean, yes, it should be considered an outlier.

Answer:

a number 12

Step-by-step explanation:

duh bro

Answer:

greater than

Step-by-step explanation:

2/2 = 1

3/2 = 1 1/2

Answer: 4n^2

Step-by-step explanation: -3n^2 - (-7n^2) = -3n^2 + 7n^2= 4n^2. When adding and subtracting the exponents stay the same only the coefficients are subtracted or added

Answer:

45

Step-by-step explanation:

4.50 × 10 =45!

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Answer:

$15

Step-by-step explanation:

$4.50 time 3 = $13.50 (9 lbs)

$4.50 divided by 3 = $1.50 (1 lb)

$1.50 plus $13.50 = $15

Answer:

im sure its D.)

Step-by-step explanation:

Answer:

you have to put -160 over -16 then divide and your answer will be 10

so x=10. I hope this helps :)

Answer:

Hey

Step-by-step explanation:

Write the fraction in simplest form

[tex] - \frac{29}{18} [/tex]

[tex] \frac{8}{9} - \frac{5}{2} [/tex]

Find the difference between 8/9 and 5/-2

[tex] \frac{8}{9} - \frac{5}{2} [/tex]

[tex] \frac{8 \times 2}{9 \times 2} - \frac{5 \times 9}{2 \times 9} [/tex]

[tex] \frac{16}{18} - \frac{45}{18} [/tex]

[tex] \frac{16 - 45}{18} [/tex]

[tex] \frac{ - 29}{18} [/tex]

[tex] - \frac{29}{18} [/tex]

apply distributive property AKA (A • 9b)+(A • 13)

9Ab + 13A

I hope this helps :)

Answer: x > - 18

Step-by-step explanation:

Answer:

0.627

Step-by-step explanation:

Answer:

quadrant 3

Step-by-step explanation:

Answer:

carios has greater angle

Step-by-step explanation:

hope this helps

Answer: It's the third one down

Step-by-step explanation:

Answer:

Slope of a line passing through ([tex]x_{1}[/tex],[tex]y_{1}[/tex]) and ([tex]x_{2} , y_{2}[/tex]) is given by:

[tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1}}[/tex]

Now,

Slope of line L, (m) = [tex]\frac{-3-(-1)}{-2-2}[/tex] = 0.5

Slope of line M, (n) = [tex]\frac{-1-1}{W-1}[/tex] = [tex]\frac{-2}{W-1}[/tex]

If the lines L and M are parallel to each other,

m = n

or, 0.5 = [tex]\frac{-2}{W-1}[/tex]

or, 0.5 (W - 1) = -2

or, W - 1 = -4

or, W = -3

Therefore the required value of W is -3.

Answer:8,5 recirpoal is 5,8

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given this quadratic expression.

x² – 10x + c = 0

We are to find the value c that will make the expression a perfect square'

Using the completing the square method

Add the square of the half of coefficient of x

Coefficient of x = -10

Half of -10 = 1/2(-10) = -5

Square of -5 = (-5)^2 = 25

Hence the value of c to complete the expression is 25