Explanation:
Newton’s law of gravitation, statement that any particle of matter in the universe attracts any other with a force varying directly as the product of the masses and inversely as the square of the distance between them.
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Please find attached photograph for your answer
A car travels 140 miles in 3 hours. What is its velocity?
Answer:
46.67 miles/s
Explanation:
...........
A transverse wave vibrates its medium __________ to the forward motion of the wave, and a longitudinal wave vibrates its medium __________ to the forward motion of the wave.
perpendicular; circularly
parallel; circularly
parallel; perpendicular
perpendicular; parallel
Answer:
Perpendicular ; Parallel
a 5.2kg bowling ball is accelerated from rest to a velocity of 12 m/s as the bowler covers 5.0m of approach before releasing the ball. what force is exerted on the ball during this time?
Answer:
74.88N
Explanation:
From the question,
F = ma................... Equation 1
Where F = force exerted on the ball, m = mass of the ball, a = acceleration
But,
v² = u²+2as.............. Equation 2
Where v = final velocity, u = initial velocity, s = distance.
Given: v = 12 m/s, u = 0 m/s (from rest), s = 5.0 m
Substitute into equation 2 and solve for a
12² = 0²+2×a×5
144 = 10a
10a = 144
a = 144/10
a = 14.4 m/s²
Also Given: m = 5.2 kg,
Substitute into equation 1
F = 5.2×14.4
F = 74.88 N
Hence the force exerted on the ball is 74.88 N
Write the SI unit of time and temperature
Answer:
The SI unit of time is second (s) and temperature is Kelvin (K)
Explanation:
hope it is helpful to you
Which of the following correctly defines the speed of a wave?
O A. v=1
B. A = vf
O C. v= f 2
OD. =v2
Answer:
V = f x λ
Explanation:
The options are confusing
An electromagnetic wave with frequency 65.0Hz travels in an insulating magnetic material that has dielectric constant 3.64 and relative permeability 5.18 at this frequency. The electric field has amplitude 7.20×10−3V/m. What is the wavelength of the wave?
Answer:
The wavelength of the wave is [tex]1.06\times10^6 m[/tex]
Explanation:
Lets calculate
We know an electromagnetic wave is propagating through an insulating magnetic material of dielectric constant K and relative permeability [tex]K_m[/tex] ,then the speed of the wave in this dielectric medium is [tex]\nu[/tex] is less than the speed of the light c and is given by a relation
[tex]\nu=\frac{c}{\sqrt{KK_m} }[/tex] --------- 1
In case the electromagnetic wave propagating through the insulating magnetic material , the amplitudes of electric and magnetic fields are related as -
[tex]E_m_a_x= \nu B_m_a_x[/tex]
The magnitude of the 'time averaged value' of the pointing vector is called the intensity of the wave and is given by a relation
[tex]I = S_a_v[/tex]
[tex]\frac{E_m_a_xB_m_a_x}{2K_m\mu0}[/tex]----------- 3
now , we will find the speed of the propagation of an electromagnetic wave by using equation 1
[tex]\nu=\frac{c}{\sqrt{KK_m} }[/tex]
Putting the values ,
=[tex]\nu= \frac{3.00\times10^8}{\sqrt{(3.64)(5.18)} }[/tex]
=[tex]0.6908\times10^8m/s[/tex]
= [tex]6.91\times10^7m/s[/tex]
Now , using this above solution , we will find the wavelength of the wave -
[tex]\lambda=\frac{\nu}{f}[/tex]
Putting the values from above equations -
[tex]\frac{6.91\times10^7m/s}{65.0Hz}[/tex]
[tex]\lambda= 1.06\times10^6 m[/tex]
Hence , the answer is [tex]\lambda= 1.06\times10^6 m[/tex]
What is the relationship between the valence electrons of an atom and the chemical bonds the atom can form?
Answer:
Valence electrons are outer shell electrons with an atom and can participate in the formation of chemical bonds. In single covalent bonds, typically both atoms in the bond contribute one valence electron in order to form a shared pair. The ground state of an atom is the lowest energy state of the atom.
the moon's mass is ____?
Answer:
7.35..kg
Explanation:
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Mass of trolley (m):
(1)
0,9
kg
Mass
m xa
Acceleration
(a)
(mos)
Applied
Force (N)
0
4,04
O112
Tabulate your measurements in the table below.
At from A to B (s)
Average
Kg
At (s)
1
2
3
Hanger only
4,07 4,00
HOS
Hanger +
1 mass piece
10
3,09
3,04 3,10
3,14
Hanger +
2 mass pieces
ao
2,00
Hanger +
3 mass pieces 30
1196
1,91
Hanger +
4 mass pieces
168 1,69 1,TO 1,69
(5)
0,21
2,1 x 103 0, 098
O #4
8,8X10
2,22 2,14
0, 196
01 SS
0102
o zau
0103
01392
0/ 70
(5)
(5)
QUESTIONS AND ANALYSIS
1.
In this experiment identify the...
1.1
independent variable
(1)
1.2 dependent variable
3 E
1.3
controlled variable
Ар со
2.
3
Describe how the effect of friction was minimised in the experiment.
(1)
Use the recorded data to plot a graph that will show the relationship
between the acceleration and the applied force on the trolley. Use a (8)
graph paper.
Ilse the cranh to determine the mass of the trolley.
(4)
Answer:
ij
Explanation:
it took 500 n of force to push a car 4 meters. how much work was done?
Answer:
2000J
Explanation:
The formula for work is W=Force x Distance
W=FxD
W=500N x 4m
W=2,000 Joules
Which is a property of every
mixture?
Plz Helpp
A vehicle has a Kinetic Energy of 75000 J and is moving at a velocity of 5 m/s. What is the mass of the vehicle?
300
could i get brainiest
A 150 g pinball rolls towards a springloaded launching rod with a velocity of 2.0 m/s to the west. The launching rod strikes the pinball and causes it to move in the opposite direction with a velocity of 10.0 m/s. What impulse was delivered to the pinball by the launcher?
Answer:
I = 1.8 N s, it is directed towards the right
Explanation:
For this exercise we use the relationship between momentum and moment
I = Δp
F t = p_f - p₀
in this case the initial velocity is v₀ = - 2,0 m / s and final velocity v_f = 10,0 m / s, we assume the positive right direction
I = m (v_f - v₀)
let's calculate
I = 0.150 (10.0 - (-2.0))
I = 0.150 (10 + 2)
I = 1.8 N s
as the impulse is positive it is directed towards the right
What is the instantaneous velocity of the hummingbird at t=1s?
The distance - time graph of the humming bird is missing, so i have attached it.
Answer:
Instantaneous velocity = 0.5 m/s
Explanation:
From the attached graph, at time t = 1 s, the corresponding distance is 0.5 m.
Instantaneous velocity is the velocity at that point.
Thus;
Instantaneous velocity = 0.5/1
Instantaneous velocity = 0.5 m/s
A Scooter travelling at 10m/s speed up to 20m/s in 4 sec.find the acceleration of scooter
Answer:
2.5 m/s²
Explanation:
Given,
Initial speed ( u ) = 10 m/s
Final speed ( v ) = 20 m/s
Time ( t ) = 4 seconds
To find : Acceleration ( a ) = ?
Formula : -
a = ( v - u ) / t
a = ( 20 - 10 ) / 4
= 10 / 4
= 5 / 2
a = 2.5 m/s²
Therefore,
The acceleration of the scooter is 2.5 m/s²
If the harmonic is 66 Hz, find the fundamental frequency
Please help me with 17 and 18!!!!!! (It's related to 16) It's due today!!!!! NO LINK PLEASE!!!!!!!!
Answer:17: A wave can be defined as follows: It is important to realize that a wave is quite a different object than a particle. A baseball thrown though a window transfers energy from one point to another, but this involves the movement of a material object between two points.
Explanation:
18: In this way, we classify waves into electromagnetic and mechanical waves. The main difference between mechanical and electromagnetic waves is that electromagnetic waves do not require a medium to propagate whereas mechanical waves require a medium in order to propagate.
PLEASE HELP ME I AM TIMED!
Answer:
they all need a source of oxygen
Answer:
B
Explanation:
Two identical charged pith balls are brought together to touch each other. They are then
allowed to move freely. The charge on pith ball A is –30 nC and on pith ball B is – 5 nC.
What is the charge on each after they separate?
Answer:
-17.5 nC
Explanation:
charge A = -30 nC
charge B = -5 nC
After adding them it would be the average of the two charges because of the getting same voltage difference. so
c = (-30+(-5)) / 2 nC
c= -17.5 nC
answer is -17.5 nC
a body is moving with uniform acceleration, has initial velocity 45km/hr. and acceleration 20cm/s^2. find its velocity after 25 seconds
Which best describes the energy of a sound wave as it travels through a medium?
It increases.
lt decreases.
It remains the sam.
It depends on the medium,
Answer:
it depends on the medium :D
If there is a ball sitting on top of a hill with 100J of GPE. How much KE should there be at the bottom of the hill if there is no friction?
Please help, I do NOT need any links.
Answer:
P since without a host the parasite won't be able to survive they would start decreasing as well but if the hosts were no more then they would go extinct. But since it is just decreasing then it should be P
If an object possesses 500 J of potential energy, how much work is needed to lift this object?
a) 500 J
b) 250 J
c) 150 J
d) 1000 J
Answer:
a) 500 J
Explanation:
Potential energy can be defined as an energy possessed by an object or body due to its position.
Mathematically, potential energy is given by the formula;
[tex] P.E = mgh[/tex]
Where,
P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
In Science, the potential energy possessed by an object or body is the same as the work done by the object or body.
Since we know that the object possessed 500 Joules of potential energy; it would ultimately require to do a work of 500 Joules to lift the object.
Mathematically, work done = force * distance
But force = mass * acceleration due to gravity
F = mg; d = h
Substituting into the work done formula, we have;
Hence, Workdone = Fd = mgh
The 500-N force F is applied to the vertical pole as shown(1) Determine the scalar components of the force vector F along the x'- and y'-axes. (2) Determine the scalar components of F along the x- and y'-axes.
Solution :
Given :
Force, F = 500 N
Let [tex]$ \vec F = F_x\ \hat i + F_y\ \hat j$[/tex]
[tex]$|\vec F|=\sqrt{F_x^2+F_y^2}$[/tex]
∴ [tex]$F_x=F \cos 60^\circ = 500 \ \cos 60^\circ = 250 \ N$[/tex]
[tex]$F_y=-F \cos 30^\circ = -500 \ \cos 30^\circ = -433.01 \ N$[/tex] (since [tex]$F_y$[/tex] direction is in negative y-axis)
[tex]$F=250 \ \hat i - 433.01 \ \hat j$[/tex]
So scalar components are : 250 N and 433.01 N
vector components are : [tex]$250 \ \hat i$[/tex] and [tex]$-433.01\ \hat j$[/tex]
1. Scalar components along :
x' axis = 500 N, since the force is in this direction.
[tex]$F_{x'}= F \ \cos \theta = 500\ \cos \theta$[/tex]
Here, θ = 0° , since force and axis in the same direction.
So, cos θ = cos 0° = 1
∴ [tex]$F_{x'}=500 \times 1=500\ N$[/tex]
[tex]$F_{y'}= F \ \sin \theta = 500\ \sin 0^\circ=500 \times 0=0$[/tex]
[tex]$F_{y'}=F\ cos \theta$[/tex] but here θ is 90°. So the force ad axis are perpendicular to each other.
[tex]$F_{y'}=F\ \cos 90^\circ= 500 \ \cos 90^\circ = 500 \times 0=0$[/tex]
∴ [tex]$F_{x'}= 500\ N \text{ and}\ F_{y'}=0\ N$[/tex]
2. Scalar components of F along:
x-axis :
[tex]$F_x=F\ \cos \theta$[/tex], here θ is the angle between x-axis and F = 60°.
[tex]$F_x=500 \times \cos60^\circ=250\ N$[/tex]
y'-axis :
[tex]$F_{y'}=F\ \cos \theta$[/tex], here θ is the angle between y'-axis and F = 90°.
[tex]$F_{y'}=500 \times \cos90^\circ=500\times 0=0\ N$[/tex]
∴ [tex]$F_{x}= 250\ N \text{ and}\ F_{y'}=0\ N$[/tex]
1.45 L of 16°C water is placed in a refrigerator. The refrigerator's motor must supply an extra 10.7 W power to chill the water to 6°C in 0.7 hr. What is the refrigerator's coefficient of performance?
Answer:
The coefficient of performance of the refrigerator is 2.251.
Explanation:
In this case, the coefficient of performance of the refrigerator ([tex]COP[/tex]), no unit, is equal to the ratio of the heat rate received from the water to the power needed to work, that is:
[tex]COP = \frac{\dot Q_{L}}{\dot W}[/tex] (1)
[tex]COP = \frac{\rho\cdot V\cdot c_{w}\cdot \Delta T}{\dot W \cdot \Delta t}[/tex] (2)
Where:
[tex]\dot Q_{L}[/tex] - Heat rate received from the water, in watts.
[tex]\dot W[/tex] - Power, in watts.
[tex]\rho[/tex] - Density of water, in kilograms per cubic meter.
[tex]V[/tex] - Volume of water, in cubic meters.
[tex]c_{w}[/tex] - Specific heat of water, in joules per kilogram-degree Celsius.
[tex]\Delta T[/tex] - Temperature change, in degrees Celsius.
[tex]\Delta t[/tex] - Cooling time, in seconds.
If we know that [tex]\rho = 1000\,\frac{kg}{m^{3}}[/tex], [tex]V = 1.45\times 10^{-3}\,m^{3}[/tex], [tex]c_{w} = 4187\,\frac{J}{kg\cdot ^{ \circ}C}[/tex], [tex]\Delta T = 10\,^{\circ}C[/tex], [tex]\dot W = 10.7\,W[/tex] and [tex]\Delta t = 2520\,s[/tex], then the coefficient of refrigeration of the refrigerator is:
[tex]COP = \frac{\rho\cdot V\cdot c_{w}\cdot \Delta T}{\dot W \cdot \Delta t}[/tex]
[tex]COP = 2.251[/tex]
The coefficient of performance of the refrigerator is 2.251.
skier accelerates down the hill at a speed of 18 and reaches the bottom of the hill at a speed of 36 in 6 seconds
What an acceleration of the skier
Answer:
3 m/s²
Explanation:
Initial Velocity, u = 18
Final velocity, v = 36
Time, t = 6 seconds
Acceleration is the change in velocity of a body with time. It obtained using the relation :
Acceleration = (v - u) / t
Acceleration = (36 - 18) / 6
Acceleration = 18 / 6
Acceleration = 3m/s²
Hence, acceleration of the skier is 3m/s²
bit.♠ly/3♠vhMu♠vJ remove symbols before searching or it wont work, there was a bug stoping me from attaching the image so there it is
Answer:
k and...
Explanation:
Answer:
no thank you.
explanation: Do not want to
What is meant by uniform motion ? Write with an example.
Answer:
This type of motion is defined as the motion of an object in which the object travels in a straight line and its velocity remains constant along that line as it covers equal distances in equal intervals of time, irrespective of the duration of the time.
Explanation:
In Physics, uniform motion is defined as the motion, wherein the velocity of the body travelling in a straight line remains the same. When the distance travelled by a moving thing, is same at several time intervals, regardless of the time length, the motion is said to be uniform motion.
If the current of a circuit is 1.5 A, and the power is 24 W. what is the resistor?
Answer:
The resistor has a resistance of 10.667 ohms.
Explanation:
By Ohm's Law, voltage ([tex]V[/tex]), in volts, is directly proportional to the current ([tex]i[/tex]), in amperes, and by definition of power ([tex]\dot W[/tex]), in watts, we have the following formula:
[tex]\dot W = i^{2}\cdot R[/tex] (1)
Where [tex]R[/tex] is the resistance, in ohms.
If we know that [tex]\dot W = 24\,W[/tex] and [tex]i = 1.5\,A[/tex], then the resistance of the resistor is:
[tex]R = \frac{\dot W}{i^{2}}[/tex]
[tex]R = 10.667\,\Omega[/tex]
The resistor has a resistance of 10.667 ohms.