Starting point (1, 4) Show me the new coordinates of the point (1, 4) after it is:
Reflected over the line y = x.
Reflected over the line y = −x.
Rotated through 90°clockwise about the origin.
Rotated through 90°counterclockwise about the origin

Answer:

The equation has one solution.

A value of x that makes the equation true is 5, which when substituted into the equation and simplified makes the equation turn into 10=10

A value of x that makes the equation false is 6, which when substituted into the equation and simplified makes the equation turn into 12=10

Step-by-step explanation:

2x=10

Divide both sides by two:

2x/2=10/2

x=5. There is no other solution to the equation, because 5 is the only possible answer.

Answer: B

Step-by-step explanation:

The prime numbers here are outcomes 2, 3, and 5.

Therefore, we must add the frequency numbers for these prime numbers:  

                36 + 44 + 30 = 110

Out of 200 dice rolls, 110 were prime numbers. This can be represented as:

              110/200 = 11/20 (fraction form)

                             = 0.55 (decimal form)

Therefore, the answer is b. 0.55

Answer:

12mm since its supposed to be for larger rectangles

Step-by-step explanation:

Answer:

s= √99 in.

Step-by-step explanation:

Answer:

Apple costs $0.26

and orange costs $0.32

sorry i don't have time to explain but if u have doubts don't hesitate to ask

Answer:

c

Step-by-step explanation:

a. 88%

b. 80%

Step-by-step explanation:

198/225=.88

180/225=.80

Answer:

Omg  im a big fan anything for you the answer is d

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

.

9514 1404 393

Answer:

  (a)  2021

Step-by-step explanation:

The expression can be simplified.

  [tex]\displaystyle\frac{a^4+b^4+2a^2b^2+a^3b+ab^3}{a^2+b^2}+ab=\frac{(a^2+b^2)^2+ab(a^2+b^2)}{a^2+b^2}+ab\\\\=a^2+b^2+ab+ab=(a+b)^2\\\\=(\sqrt{2021})^2=\boxed{2021}[/tex]

Answer:

the blue block 'side' is 10

the pink block ' bottom' is 9

the cream 'side' block is 13 (length)

the green back triangle next to the blue side is also 10

and the other side of the green back triangle is 8

Answer:

3/8

Step-by-step explanation:

5/8 - 1/4

L.C.M =8

5-2=3

=3/8

Answer:

8

Step-by-step explanation:

I can't see the pic.

Answer: thank you

Step-by-step explanation:

Answer:

Thanks!

Step-by-step explanation:

Answer:  V≈804.25

Step-by-step explanation:

V=πr2h

3=π·82·12

3≈804.24772

Answer:

1.21212121212 or average of basically 1 meter per second

Step-by-step explanation:

Formula: distance over time

Take distance and  divide that by time you would get the answer.

Answer:

$63.89

Step-by-step explanation:

just multiply 59.99 by 1.065

Answer:

a=101.223

Step-by-step explanation:

use SOCATOA

or an online calculator

https://www.calculator.net/triangle-calculator.html?vc=x&vx=z&vy=y&va=39&vz=125&vb=90&angleunits=d&x=59&y=16

Answer:

D

Step-by-step explanation:

The mean, median, and mode all are 3

Answer:

(4,11/2)

Step-by-step explanation:

5x-2y=9

12x-8y=4

A quick look will tell us that neither the x- nor the y- coefficient is the same in both equations, so combining the two by addition or subtraction. We can see that 2 is a multiple of 8, since 2 x 4 = 8. We should multiply the first equation by 4.

4(5x-2y=9)

Now we need to decide if we should add or subtract the equations.

20x-8y=36

12x-8y=4

Since we need to have a -8 and a +8 to eliminate the variables, we should subtract them. Change all the signs of the second equation and combine.

20x-8y=36

-12x-8y=4

----------------

8x=32

Divide both sides by 8 to get the x-value:

[tex]\frac{8x}{8} = \frac{32}{8}[/tex]

x=4

Now that we have our x-value, we need to plug in the y-value.

5x-2y=9

5(4)-2y=9

20-2y=9

-2y=-11

y=11/2

So our solution is (4,11/2)

Let's check our work.

5x-2y=9

5(4)-2(11/2)=9

20-22/2=9

20-11=9

9=9

12x-8y=4

12(4)-8(11/2)=4

48-88/2=4

48-44=4

4=4

Our solution is correct.

Answer:

x=4,y=11/2

Step-by-step explanation:

5x−2y=9

12x−8y=4

​In order to solve by elimination, coefficients of one of the variables must be the same in both equations so that the variable will cancel out when one equation is subtracted from the other.

5x−2y=9,12x−8y=4

To make 5x and 12x equal, multiply all terms on each side of the first equation by 12 and all terms on each side of the second by 5.

12×5x+12(−2)y=12×9,5×12x+5(−8)y=5×4

Simplify.

60x−24y=108,60x−40y=20

Subtract 60x−40y=20 from 60x−24y=108 by subtracting like terms on each side of the equal sign.

60x−60x−24y+40y=108−20

Add 60x to −60x. Terms 60x and −60x cancel out, leaving an equation with only one variable that can be solved.

−24y+40y=108−20

Add −24y to 40y.

16y=108−20

Add 108 to −20.

16y=88

Divide both sides by 16.

y=11/2

Substitute 11/2 for y in 12x−8y=4. Because the resulting equation contains only one variable, you can solve for x directly.

12x−8x11/2=4

Multiply −8 times 11/2.

12x−44=4

Add 44 to both sides of the equation.

12x=48

Divide both sides by 12.

x=4

The system is now solved.

x=4,y=11/2

The solution of the equation 8b = 56 is 7. And the solution of Harmony is 448. So, Harmony is incorrect.

The allocation of weights to the important variables that produce the calculation's optimum is referred to as a direct consequence.

The equation is given below.

8b = 56

Simplify the equation, then we have

8b = 56

b = 56 / 8

b = 7

The solution of the equation 8b = 56 is 7. And the solution of Harmony is 448. So, Harmony is incorrect.

More about the solution of the equation link is given below.

https://brainly.com/question/545403

#SPJ2

Answer:

h(2)= 4.5

Step-by-step explanation:

h(x)=2.25x

h(2)=2.25(2)

= 4.5

Answer:

Hi! The answer to your question is 4.5

Step-by-step explanation:

To find h(2) we just have to find x in the equation and replace it with a 2

h(x)=2.25(2)

h(x)=2.25(2)=4.5

※※※※※※※※※※※※

⁅Brainliest is greatly appreciated!⁆

- Brooklynn Deka

Hope this helps!!

Answer:

The calculated value Z = 2.5 > 1.96 at 0.05 level of significance

The null hypothesis is rejected

The Alternative hypothesis is rejected

The EMS director wants to service goal of 12 minutes or less is being achieved

Step-by-step explanation:

Step(i):-

Given that the size of the random sample = 40

Given that the mean of the sample (x ⁻) = 13.25

Given that the standard deviation of the Population = 3.2 minutes

Level of significance = 0.05

The mean of the Population (μ) = 12

Step(ii):-

Null hypothesis:-H₀: (μ) = 12

Alternative Hypothesis: H₁ : μ < 12

Test statistic

                  [tex]Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }[/tex]

                  [tex]Z = \frac{13.25-12 }{\frac{3.2}{\sqrt{40} } }[/tex]

                  Z = 2.5

The tabulated value Z₀.₀₅ = 1.96

The calculated value Z = 2.5 > 1.96 at 0.05 level of significance

The null hypothesis is rejected

The Alternative hypothesis is rejected

Final answer:-

The EMS director wants to service goal of 12 minutes or less is being achieved

Answer:

[tex]\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0[/tex]

Step-by-step explanation:

We want to write the trignometric expression:

[tex]\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0[/tex]

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

[tex]\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)[/tex]

Take the secant of both sides:

[tex]\displaystyle \sec(\theta)=\frac{u}{10}[/tex]

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

[tex]\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}[/tex]

By substitutition:

[tex]\displaystyle= \sin(2\theta)[/tex]

Using an double-angle identity:

[tex]=2\sin(\theta)\cos(\theta)[/tex]

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

[tex]\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)[/tex]

Simplify. Therefore:

[tex]\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0[/tex]