Solve for the value of z

Answer:

Thats cool man.

Step-by-step explanation:

I think its 16 but im not completly sure

Answer:

the answer is b) (10.67,11.93)

Step-by-step explanation:

hope this helps

Answer:

60.4

Step-by-step explanation:

90-29.6= 60.4

complimentary means either of two angles whose sum is 90°.

This is the answer hope it helps

The area of the square field is 4840 hectares.

Perimeter of the square is defined as addition the lengths of the square's four sides.

Perimeter of the square equation is 4a

Where, a is length of the square

Given data as :

Perimeter of the square field = 880 m

Side of the square = Perimeter/4

Side of the square = 880/4

Side of the square = 220 m

So, length of each side of the square is 220 m

Area of square = Side × Side

Area of square = 220 m  × 220 m

Area of square = 48400 square meters

Area of square = 48.4 square kilometers

As we know that 1 sq km = 100 hectares

So, 48.4 km = 48.4 × 100 = 4840 hectares

Hence, the area of the square field is 4840 hectares.

Learn more about Perimeter of square here:

https://brainly.com/question/11495285

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Answer:

B.[tex]22^{\circ}[/tex]

Step-by-step explanation:

We are given that HMS is an isosceles triangle.

Angle M is the vertex angle.

[tex]m\angle M=(2x+6)^{\circ}[/tex]

[tex]m\angle H=(9x+7)^{\circ}[/tex]

[tex]\angle H=\angle S[/tex]

By definition of isosceles triangle

We have to find the measure of angle M.

[tex]\angle M+\angle H+\angle S=180^{\circ}[/tex]

By using sum of angles of triangle property

Substitute the values

[tex]2x+6+9x+7+9x+7=180[/tex]

[tex]20x+20=180[/tex]

[tex]20x=180-20[/tex]

[tex]20x=160[/tex]

[tex]x=\frac{160}{20}=8[/tex]

Using the value of x

[tex]m\angle M=2(8)+6[/tex]

[tex]m\angle M=22^{\circ}[/tex]

Hence, option B is correct.

Answer:

G)

Step-by-step explanation:

3% of 8000 is 240

now multiply it by 4 (years) and you get 940

Answer:

true

Step-by-step explanation:

.................

Answer:

3,098

Step-by-step explanation:

when you do the ,ath you will get it

The distance between two points is given by the expression,

[tex]d = \sqrt{ {(y2 - y1)}^{2} + {(x2 - x1)}^{2} } [/tex]

Plugging in our values,

[tex]d \: = \sqrt{ {(1 - 9)}^{2} + {( - 4 - - 1)}^{2} } \\ d \: = \sqrt{ {( - 8)}^{2} + {( - 3)}^{2} } \\ d \: = \sqrt{64 + 9} \\ d = \sqrt{73} [/tex]

So, the distance between the points in it's exact radical form is

[tex] \sqrt{73} \: units[/tex]

Answer:

Solution given:

-2x²+7x-6=0

2x²-7x+6=0

Comparing above equation with ax²+bx+c

we get

a=2

b=-7

c=6

By using Vieta's theorem

X1+X2=[tex] \frac{-b}{a} [/tex]=[tex] \frac{7}{2} [/tex]

again

X1X2=[tex] \frac{c}{a} [/tex]=[tex] \frac{6}{2} [/tex]=3

Answer:

57 7/9

Step-by-step explanation:

I used a fraction calculator.

Answer: first 30 second  is 60

Step-by-step explanation:

Answer:

30,60

Step-by-step explanation:

Answer:

495 cbin

Step-by-step explanation:

Volume of a box = l*w*h

V=5*9*11

V=495

Answer:

[tex]a^2(ab^{3}-b^{2}-c^{2})[/tex]

Step-by-step explanation:

Given

[tex]a^{3}b^{3}-a^{2}b^{2}-a^{2}c^{2}[/tex]

Required

Factor

[tex]a^{3}b^{3}-a^{2}b^{2}-a^{2}c^{2}[/tex]

Factor out [tex]a^2[/tex]

[tex]a^2(ab^{3}-b^{2}-c^{2})[/tex]

The expression cannot be further factored

Answer:

A (obviously)

Step-by-step explanation:

Info Given

Answer:

A = Not a paired sample

B = paired sample

C = Not a paired sample

Step-by-step explanation:

Paired samples also commonly referred to as dependent samples are often characterized by having to different data points which are taken at different times, location and so on. Such that each pair of data points or observation can be matched based on the basis of the subject or sample name usually for the sake of analysing if any statistical difference exists between the occurrence of each observation.

For the instances given above ;

a.) this isn't a paired sample, because Professor Quick and Professor Quacks students are different, hence each student has only one reading and as such a match of the two test scores cannot be made on the basis of student name or identity. Hence, it is not a paired sample

B.) This is a paired sample, two different readings are available for each students ; one at the beginning, the other at the end. Hence, it is a paired sample

C.) This is not a paired sample, because the subjects used to obtain the weight of 10 year old in 1994 aren't the same samples used in 2009

Answer:

84

Step-by-step explanation:

f(1)=4^1 - 1 = 3

f(4) = 4^4 - 1 = 255

rate of change = [tex]\frac{f(x_2)-f(x_1)}{x_2-x_1}[/tex]

(255 - 3) / (4 - 1) = 252 / 3 = 84

9514 1404 393

Answer:

Step-by-step explanation:

Reflection over the y-axis and translation 3 right is modeled by the transformation ...

  (x, y) ⇒ (-x +3, y)

Then the image end points are ...

  A(2, -5) ⇒ A'(-2+3, -5) = A'(1, -5)

  B(5, -3) ⇒ B'(-5+3, -3) = B'(-2, -3)

_____

In the attached figure, the reflection is shown as A'B' in light purple. The line after the final translation is shown as A"B" in blue.

Answer:

170

c=a^2+b^2=7^2+11^2≈13.0384 or 170

Step-by-step explanation:

mrk me brainliest please

Answer:

1736.58

Step-by-step explanation:

16.86 x 103 = 1736.58

Answer:

1736.58

Step-by-step explanation:

Answer:

in the first traingle

sinC = 36/39 = 12/13

CosC= 15/39 = 5/13

TanA= 15/36=5/12

this is the values i didnt understand the question so i just find the values

in the second Triangle

SinA=2√5/5

CosA=√5/5

TanB= √5/2√5=1/2

cos 30 = √3/2

sin45=√2/2

tan60= √3

hopefully its helpful iam sorry i didnt understand what they mean in the question my engilish is bad

Sin of c. Sin'-1(36/39)=90

Cos of c cos'-1(15/39)=67.38

Tan of a tan'-1(15/36)=22.62

Sin of a sin'-1(2squarroot5/5)=63.43

Cos od a cos'-1(squareroot5/5)=63.43

Tan of b tan'-1(2squareroot5/squareroot5)=63.43

Cos30 is pie/6 or squareroot of 3 /2

Sin of 45 is pie/4 or squareroot2/2

Tan60 is pie/3 or squareroot3

Answer:

CORRECT ME IF THERE'S WRONG!

Answer:

C. Wave-like and repetitive

Step-by-step explanation:

I calculated it logically

Answer:

[m] slope = -2

[b] y-intercept = -1 ; (0, -1)

[y = mx + b] slope-intercept = -2x – 1

Step-by-step explanation:

Given the algebraic equation 6x + 3y = -3 currently in standard form:

Ax + By = C →

By = C – Ax →

By = -Ax + C →

y = -Ax / B + C / B →

y = (-A / B)x + (C / B) →

y = mx + b →

m = -A / B. b = C / B.

6x + 3y = -3

↓ ↓ ↓

A = 6. B = 3. C = -3.

[Substitute]

m = -A / B. b = C / B

m = -(6) / (3). b = (-3) / (3)

↓ ↓

m = -2. b = -1.

↓. ↓

Slope = -2. y-intercept = -1.

_______________________

Slope is ∆y/∆x [change in y over the change in x] = y2 – y1 / x2 – x1.

The y-intercept is the point where x is 0.

The easiest way to determine this is to substitute 0 in for x in an equation and solve for y.

This means that the y intercept in coordinate form is (0, b).