Rectangle ABCDABCDA, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle: A(-2, 2)A(−2,2)A, left parenthesis, minus, 2, comma, 2, right parenthesis, B(6, 2)B(6,2)B, left parenthesis, 6, comma, 2, right parenthesis, C(6, 3)C(6,3)C, left parenthesis, 6, comma, 3, right parenthesis, and D(-2, 3)D(−2,3)D, left parenthesis, minus, 2, comma, 3, right parenthesis.
What is the area of rectangle ABCDABCDA, B, C, D?

The area of rectangle ABCD with the given vertices is: 8 units².

Area of rectangle = (length)(width).

Given the following vertices:

Area = (length)(width) = (AB)(BC)

AB = |-2 - 6| = 8 units

BC = |2 - 3} = 1 unit

Area of rectangle = (8)(1) = 8 units².

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Answer: 8

Step-by-step explanation:

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