Recoil is noticeable if you throw a heavy ball while standing on roller skates. If instead you go through the motions of throwing the ball but hold onto it, your net recoil velocity will be

Answers

Answer 1

Answer:

Since there is no external force, there is no change (movement) in the center of mass. Internally, the center of mass might change position, but the external result is still zero net velocity.

The net recoil velocity must be zero.


Related Questions

A 2,000 kg car, initially traveling at a speed of 15 m/s, is accelerated by a constant force of 10,000 N for 3 seconds. The new speed of the car is

Answers

Mass (m) = 2000 KgInitial velocity (u) = 15 m/sForce (F) = 10000 NTime (t) = 3 sLet the acceleration be a.We know, F = ma,Therefore, 10000 N = 2000 Kg × a or, a = 10000 N ÷ 2000 Kg = 5 m/s^2Let the final velocity be v.By using the equation of motion, v = u + at, we getv = 15 m/s + 5 m/s^2 × 3 sor, v = 15 m/s + 15 m/s = 30 m/s

Answer:

The new speed of the car is 30 m/s.

Hope you could get an idea from here.

Doubt clarification - use comment section.

Two hockey players are skating toward each other on a frictionless ice. One is moving at 1 m/s while the other is traveling at 2 m/s. The players collide and stick together. Find their combined speed.

Answers

Their combined speed will be 1m/s

Given the following parameters;

The velocity of the first hockey player is 1m/s.The velocity of the second hockey player is 2m/s.

If the player collides and stick together, the combined speed is expressed as;

Combined speed = differences in velocityCombined speed = 2m/s - 1m/sCombined speed = 1m/s.

Hence their combined speed will be 1m/s

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a truck in a traffic circle travels in a circular path at constant speed v0 while passing through region x of the circle, as shown in figure 1 above. a diagram representing the forces exerted on the truck in region x is shown in figure 2. at a later time a car with less mass than the truck passes through region x at the same speed and the same distance from the center of the traffic circle as the truck. the coefficient of friction between the car’s tires and the ground is the same as that for the truck’s tires and the ground. which of the following diagrams could represent the forces exerted on the car in region x compared to the truck in region x ? assume that the length of each arrow is proportional to the magnitude of the force represented by the arrow.

Answers

The Diagram that represents the forces exerted on the car in region x when compared to the truck in region X is :  Diagram C

Given that the mass of the car is less than the mass of the truck the force due to gravity will be greater on the truck than it could be on the car

i.e. | Fg |car  <  | Fg | truck

also : | Fₙ | car  <  | Fₙ | truck

Since the gravitational force on the car is less than the gravitational force on the truck

| Ff | car < | Ff | truck

where : Ff = frictional force

             Fg = force due to gravity

             Fn  normal force

Therefore from the diagrams attached below the correct diagram that represents the forces exerted on the car in region x when compared to the truck in region X is :  Diagram C.

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Attached below is the missing data related to your question


How would you describe the motion of a transverse wave

Answers

transverse wave, motion in which all points on a wave oscillate along paths at right angles to the direction of the wave's advance. Surface ripples on water, seismic S (secondary) waves, and electromagnetic (e.g., radio and light) waves are examples of transverse waves.

What is the kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4 m/s? (Formula: ) 3 J 6 J 12 J 24 J.

Answers

The kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4m/s is 6J.

HOW TO CALCULATE KINETIC ENERGY:

The kinetic energy of a moving body can be calculated by using the following formula:

K.E = ½mv²

Where;

K.E = kinetic energy (J)m = mass (kg)v = velocity (m/s)

According to this question, a toy truck has a mass of 0.75 kg and a velocity of 4 m/s. The kinetic energy is calculated as follows:

K.E = ½ × 0.75 × 4²

K.E = 8 × 0.75

K.E = 6J

Therefore, the kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4m/s is 6J.

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the maximum displacement of a particle by a wave is called

Answers

The answer is amplitude

How do you un rewrap something?

Answers

wrap it back up……….

Two sections of genetic material from a fruit fly are shown in the diagram.
X
-Eye color
-Wing shape
What does the diagram reveal about the inherited traits of fruit flies?
А Inherited traits are controlled by tissues, which are found in organs.
B
Inherited traits are controlled by organs, which are found in tissues.
с
Inherited traits are controlled by genes, which are found in chromosomes.
OD
Inherited traits are controlled by chromosomes, which are found in genes.

Answers

the answer is c, inherited traits are controlled by genes, which are found in chromosomes

What type of bond is found in pure gold?
A) Metallic
B) Ionic
C)Covalent
D)Diatomic

Answers

Pure gold is a metallic bond as well as silver, iron and platinum

The type of bond found in pure gold is metallic bonding, indicated by metallic bonds. Therefore option A is correct.

Metallic bonding occurs between metal atoms, such as gold, and is characterized by the sharing of electrons among a sea of delocalized electrons.

In metallic bonds, the valence electrons of metal atoms are not strongly bound to any particular atom but are free to move throughout the metal lattice.

This sharing of electrons gives rise to properties such as high electrical and thermal conductivity, malleability, and ductility, which are characteristic of metals like gold.

Unlike ionic or covalent bonds, metallic bonds do not involve the transfer or sharing of electrons between different elements.

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yes that.
Read the excerpt below and then answer the question that follows:
The Book of Dragons
Chapter III The Deliverers of Their Country, an excerpt
By E. Nesbit

It all began with Effie's getting something in her eye. It hurt very much indeed, and it felt something like a red-hot spark—only it seemed to have legs as well, and wings like a fly. Effie rubbed and cried—not real crying, but the kind your eye does all by itself without your being miserable inside your mind—and then she went to her father to have the thing in her eye taken out. Effie's father was a doctor, so of course he knew how to take things out of eyes.

When he had gotten the thing out, he said: "This is very curious." Effie had often got things in her eye before, and her father had always seemed to think it was natural—rather tiresome and naughty perhaps, but still natural. He had never before thought it curious.

Effie stood holding her handkerchief to her eye, and said: "I don't believe it's out." People always say this when they have had something in their eyes.

"Oh, yes—it's out," said the doctor. "Here it is, on the brush. This is very interesting."

Effie had never heard her father say that about anything that she had any share in. She said: "What?"

The doctor carried the brush very carefully across the room, and held the point of it under his microscope—then he twisted the brass screws of the microscope, and looked through the top with one eye.

"Dear me," he said. "Dear, dear me! Four well-developed limbs; a long caudal appendage; five toes, unequal in lengths, almost like one of the Lacertidae, yet there are traces of wings." The creature under his eye wriggled a little in the castor oil, and he went on: "Yes; a bat-like wing. A new specimen, undoubtedly. Effie, run round to the professor and ask him to be kind enough to step in for a few minutes."

"You might give me sixpence, Daddy," said Effie, "because I did bring you the new specimen. I took great care of it inside my eye, and my eye does hurt."

The doctor was so pleased with the new specimen that he gave Effie a shilling, and presently the professor stepped round. He stayed to lunch, and he and the doctor quarreled very happily all the afternoon about the name and the family of the thing that had come out of Effie's eye.

But at teatime another thing happened. Effie's brother Harry fished something out of his tea, which he thought at first was an earwig. He was just getting ready to drop it on the floor, and end its life in the usual way, when it shook itself in the spoon—spread two wet wings, and flopped onto the tablecloth. There it sat, stroking itself with its feet and stretching its wings, and Harry said: "Why, it's a tiny newt!"

The professor leaned forward before the doctor could say a word. "I'll give you half a crown for it, Harry, my lad," he said, speaking very fast; and then he picked it up carefully on his handkerchief.

"It is a new specimen," he said, "and finer than yours, Doctor."

It was a tiny lizard, about half an inch long—with scales and wings.

So now the doctor and the professor each had a specimen, and they were both very pleased. But before long these specimens began to seem less valuable. For the next morning, when the knife-boy was cleaning the doctor's boots, he suddenly dropped the brushes and the boot and the blacking, and screamed out that he was burnt.

And from inside the boot came crawling a lizard as big as a kitten, with large, shiny wings.

"Why," said Effie, "I know what it is. It is a dragon like the one St. George killed."

And Effie was right. That afternoon Towser was bitten in the garden by a dragon about the size of a rabbit, which he had tried to chase, and the next morning all the papers were full of the wonderful "winged lizards" that were appearing all over the country. The papers would not call them dragons, because, of course, no one believes in dragons nowadays—and at any rate the papers were not going to be so silly as to believe in fairy stories. At first there were only a few, but in a week or two the country was simply running alive with dragons of all sizes, and in the air you could sometimes see them as thick as a swarm of bees. They all looked alike except as to size. They were green with scales, and they had four legs and a long tail and great wings like bats' wings, only the wings were a pale, half-transparent yellow, like the gear-boxes on bicycles.

Based on the rising action in the bolded paragraphs, what do we know about Daddy? (5 points)

He is calm and curious.
He is angry and upset.
He is hysterical.
He is uninterested and bored.

Answers

believe in fairy stories. At first there were only a few, but in a week or two the country was simply running alive with dragons of all sizes, and in the air you could sometimes see them as thick as a swarm of bees. They all looked alike except as to size. They were green with scales, and they had four legs and a long tail.

Explanation:

YOUR WELCOME :)

Answer:

its "calm and curious"

Explanation:

hope tis helps!!!

what is the second longest wavelength for a standing wave on a wire with one fixed end and one open end that is 3.0 m long?

Answers

Is there any multiple choice answers? Any options?

define nuclear energy​

Answers

Answer:

Nuclear energy is the energy stored in atoms that can produce electricity.

Hope that helps. x

What is the momentum of a 5 kg object that has a velocity of 1. 2 m/s? 3. 8 kg • m/s 4. 2 kg • m/s 6. 0 kg • m/s 6. 2 kg • m/s.

Answers

Answer:

6 kg.m/s

Explanation:

Momentum is the product of mass and velocity. So,

p = mv

Here,

p denotes momentum [?]m denotes mass [5kg]v denotes velocity [1.2 m/s]

→ p = 5 kg × 1.2 m/s

→ p = (5 × 1.2) kg.m/s

→ p = (5 × 12/10) kg.m/s

→ p = 12/2 kg.m/s

p = 6 kg.m/s

Therefore, momentum of the object is 6 kg.m/s.

The momentum of a 5kg object that has a velocity of 1.2m/s is 6.0kgm/s.

MOMENTUM:

Momentum of a substance is the product of its mass and velocity. That is;

Momentum (p) = mass (m) × velocity (v)

According to this question, an object has a mass of 5kg and velocity of 1.2m/s. The momentum is calculated thus:

Momentum = 5kg × 1.2m/s

Momentum = 6kgm/s.

Therefore, the momentum of a 5kg object that has a velocity of 1.2m/s is 6.0kgm/s.

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Plz help!

A person walks the path shown
below. The total trip consists of
four straight-line paths. At the end of the walk, what is the person's
resultant displacement measured from the starting point?

Answers

The analytical method for the sum of vectors allows to find the result for the sum of the vectors is:

The resulting vector has a modulus of R = 239.99 m and an angle of θ= 212.8º

The displacement is a vector quantity, therefore vector algebra must be used to perform the addition of vectors, in general there are two methods:

Graphic. In this case, the origin of a vector is placed at the tip of the previous one and the resulting vector goes from the origin of the first vector to the tip of the last, this method is not very precise. Analytical. In this method the vectors are decomposed into a coordinate system, the sum of the components is performed and the resulting vector is built, this method is very expensive.

Indicate in  the graph a Cartesian coordinate system, let alone the West - East axis coincide with the x axis. Let's use trigonometry to decompose the vectors.

Vector A.

         Aₓ = 100.0 m  

Vector B.

         B_y = -300.0 m  

The negative sign indicates that it goes in the negative direction of the y-axis

Vector C.

We use trigonometry.

The angle measured from the positive side of the x-axis counterclockwise is

        θ = 180 + 30 = 210

       

        sin 210 = [tex]\frac{C_y}{C}[/tex]

        cos 210 = [tex]\frac{C_x}{C}[/tex]

        C_y = C sin 210

        Cₓ = C cos 210

         C_y = 150.0 sin 210 = -75.0 m

         Cₓ = 150.0 cos 210 = -129.9 m

Vector D.

The angle from the positive side of the x-axis counterclockwise.

        θ = 180-60 = 120º

       sin 120 = [tex]\frac{D_y}{D}[/tex]  

       cos 120 = [tex]\frac{D_x}{D}[/tex]  

       D_y = D sin 120

       Dₓ = D cos 120

       D_y = 200.0 sin 120 = 173.2 m

       Dₓ = 200.0 cos 120 = -100.0 m

we add the component with algebraic sum.

       x = Aₓ + Cₓ + Dₓ

       y = B_y + C_y + D_y

       x = 100 - 129.9 -100 = -129.9 m

       y = -300 - 75.0 + 173.2 = -201.8 m

We construct the resulting vector.

We use the Pythagorean theorem for the Modulus.

       [tex]R+ \sqrt{x^2 +y^2}[/tex]  

       R = [tex]\sqrt{129.9^2 + 201.8^2 }[/tex]  

       R = 239.99 m

We use trigonometry for the angle.

      tan  θ = [tex]\frac{y}{x}[/tex]

       θ = [tex]tan^{-1} \frac{y}{x}[/tex]  

       θ = [tex]tan^{-1} \frac{201.8}{129.9}[/tex]tan-1 (201.8 / 129.9)

       θ = 57.2º

Since the two coordinates are negative, this angle is in the third quadrant; to measure it from the positive side of the x-axis.

          θ = 270 - θ'

          θ = 270 - 57.2

          θ = 212.8º

In conclusion using the analytical method for the sum of vectors we can find the result for the sum of the vectors is:

The resulting vector has a modulus of R = 239.99 m and an angle of  θ= 212.8º

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what has to increase in order for an object to accelerate?

Answers

Answer:

Answer: B. Explanation: For an object to accelerate the force on it must be increased. According to Newton's second law of motion.

Explanation:

I do Accelerate to good luck

can someone explain please?​

Answers

Hi there!

We can begin by solving for the velocity in which the ball was thrown at using the following:

[tex]v_f^2 = v_i^2 + 2ad[/tex]

At the top of the trajectory, the ball's velocity is equal to 0 m/s, so:

[tex]0 = v_i^2 + 2ad\\\\vi^2 = 2ad \\\\[/tex]

'a' = acceleration due to gravity and 'd' is the max height, so:

[tex]v_i^2 = 2(10)(5)\\\\v_i^2 = 10 m/s[/tex]

Now, we can use the same equation to calculate the final speed at 4.5 m. Remember, the acceleration is NEGATIVE in this instance (taking the negative direction to be in the direction of gravity).

[tex]v_f^2 = 10^2 - 2(10)(4.5)[/tex]

[tex]v_f^2 = 10^2 - 2(10)(4.5)\\\\v_f^2 = 100 - 90 \\\\v_f^2 = 10 \\\\v_f = \boxed{3.1 m/s}[/tex]

Classify the statement below as either Speed or Velocity?

A jeep was driving 40 mph
heading to the grocery store.

Answers

Answer:

Hello There!

It is Speed.

[tex]\Large\bold\red{Reason}[/tex]

Because in the question it is said that at which speed car is travelling.

Speed is a scalar quantity.

If it is velocity then first know this that it is a vector quantity.

It must include both magnitude and direction.

If it is velocity then it would be 40 mph east or west or north or south.

I hope it is helpful to you...Cheers!_____________

What is the change in velocity of a 1068 kg truck that experiences an impulse of 440 N ⋅ s? Include 2 decimal places in your answer.

Answers

Answer:

try 2.4136 as an answer/ good luck

what planets experience an eclipse from the sun

Answers

Answer:

Earth

Explanation:

The sun and the moon come together and they seem like one bonded.

The frequency of a wave is 4hz. If the wavelength is 2m how fast is the water moving?
I need the Formula,Known,Substitute & Solve Answer with Units

Answers

Answer:

This is the answer that I got

Explanation:

Hope it is right.


1. Which of the following types of energy is
potential energy? More than one answer is
possible,
A kinetic energy
B.thermal energy
C.sound energy
D.gravitational energy

Answers

Answer:

Potential energy is stored energy and the energy of position––gravitational energy. There are several forms of potential energy. Electrical Energy is the movement of electrical charges. Everything is made of tiny particles called atoms.

What happens to all light bulbs in a series circuit when one burns out?

Answers

Answer:

In a series circuit, every device must function for the whole circuit to be complete. One bulb burning out in a series circuit breaks the circuit. Even if you take a bulb out,  the entire circuit will still stop operating. There is no closed-loop path for the current to flow through the circuit. For the whole series circuit to be complete, and on, every bulb must be working.

Explanation:

SOMEONE, PLEASE HELP ME AS FAST AS YOU CAN, I WOULD GIVE MORE POINTS BUT THIS IS THE REST OF MY POINT, PLEASE SOMEONE WHO IS SUPER KIND HELP ME.

Answers

Answer:

1. The formula for speed is speed = distance ÷ time. To work out what the units are for speed, you need to know the units for distance and time

2. 36÷4= 9

(formula) Speed = distance ÷ time

3. Meter (M) centimeter (cm) kilometers (km)

4. Seconds , Hour, Minute

5. 65÷13=5 (object A)

125÷ 25= 5 (object B)

their both Equal of the amount of speed, so they are travelling at the same speed

Hope I helped

With an initial velocity of 20km per hour a car accelerated at 8m/s2 for 10s,what is the position of the car at the end of 10s

Answers

initial velocity=u=20km/h=5.5m/sAcceleration=a=8m/s^2Time=t=10s

[tex]\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2[/tex]

[tex]\\ \sf\longmapsto s=5.5(10)+\dfrac{1}{2}(8)(5.5)^2[/tex]

[tex]\\ \sf\longmapsto s=55+4(5.5)^2[/tex]

[tex]\\ \sf\longmapsto s=55+4(30.25)[/tex]

[tex]\\ \sf\longmapsto s=55+121[/tex]

[tex]\\ \sf\longmapsto s=176m[/tex]

The velocity of an ocean wave is 5m/s. The distance between crests is 3m. What is the frequency of the wave
I need the Formula,Known,Substitute & Solve Answer with Units

Answers

Answer:

1.67m

5m/s

Explanation:

Wavelength of the wave = 3m

Speed of the wave  = 5m/s

The distance between crest and the adjacent trough of water waves is known as the wavelength of a wave.

 To find the frequency ;

        V = f∧

V is the speed of the wave

f is the frequency

∧ is the wavelength

  Insert the parameters and find the frequency;

        f  = V/ ∧   = 5 / 3  = 1.67Hz

The rate at which the wave passed a given point is the speed of the wave and it is 5m/s

Which would ba another example of newtons first law?

Answers

For example, a book resting on a table applies a downward force equal to its weight on the table. According to the third law, the table applies an equal and opposite force to the book.

Which design of the walls would be most desirable help avoid echoes?
A
They should use bumpy walls for all four sides.
B
They should use bumpy walls for only one side.
С
They should use smooth walls for all four sides.
D
They should use smooth walls for only one side.

Answers

Answer:

a

Explanation:

because the sound wont bounce off

What is the boiling point of water?

Group of answer choices

373.15 degrees Fahrenheit

373.15 degrees Celsius

373.15 Kelvin

Answers

Answer:

373.15 Kelvin

Explanation:

Boiling Point of water

= 100 degree Celsius

= (100 + 273.15) Kelvin

= 373.15 Kelvin

The strings in a compound bow behave approximately like a
spring. A bowstring is pulled back 0.60 m with a maximum force of
267 N (AKA a 60-pound draw weight) to shoot an 18 g arrow.
Assume energy is conserved.
a) At what speed would the arrow be launched? (Note: W = FΔd uses the average
force while F = -kx uses the instantaneous force.)

Answers

The speed at which the arrow would be launched is 133.42 m/s

The work-energy theorem asserts that the net work done applied by the forces on a particular object is equivalent to the change in its kinetic energy.

The equation for the work-energy theorem can be computed as:

[tex]\mathbf{W =\Delta K.E}[/tex]

[tex]\mathbf{F\Delta x =\dfrac{1}{2} mv^2}[/tex]

where;

Force (F) = 267 Ndistance Δx = 0.60 mmass (m) = 18 gspeed (v) = ???

From the above equation, let make speed(v) the subject of the formula:

[tex]\mathbf{v = \sqrt{\dfrac{2(F \Delta x)}{m}} }[/tex]

[tex]\mathbf{v = \sqrt{\dfrac{2(267 \times 0.60)}{0.018}} }[/tex]

v = 133.42 m/s

Learn more about the work-energy theorem here:

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If the action force is the swimmer pushing water in the leftward direction, what is the reaction force?

PLEASE ANSWER
CORRECTLY PLS

Answers

According to Newton's Third Law of Motion, to every action, there is an equal and opposite reaction; action and reaction act on different bodies.Here, the action force is in the leftward direction, so the reaction will be in the opposite direction.If the action force is the swimmer pushing water in the leftward direction, then the reaction force is in the rightward direction.And the reaction force will be given by the water on the swimmer.

Answer:

The reaction force is the water pushing the swimmer in the rightward direction.

Hope you could get an idea from here.

Doubt clarification - use comment section.

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